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7/26/2019 Rods and Beams 3
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3 Rod and beam elements
How to analyze structures shown in pictures using
FEM:
2
3 Rod and beam elements
Rod (spar, truss element) and beam, definitions:
Rod elements can only extend or compress
axially (two-force system!)
Beam elements can carry bending moments
and (and torsion in 3D) in additio to axial
loads
rod
rod
beam
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3.1 Rod
The stiffness matrix of a rod element has already been
defined (spring!):
Thus the basic equation is
General definition: columns of stiffness matrix are
nodal loads imposed on the elements resulting unit
displacement in corresponding degree of freedom
and kee in other de rees of freedom zero.
1 1 11
1 1 2
,k k U
K uk k U
N1 N2
A,E
L
U1 U2
2
1
2
1
11
11
F
F
u
u
L
AE
,i
i ekv
i
A Ek
l
4
3.1 Rod
More formal definition comes from integral
where B is strain-displacement matrix, E on
material matrix or constitutive matrix. Matrix B is
obtained by defining the displacement field in the
rod using linear interpolation
where N is so-called shape function matrix.
N1 N2
A,E
L
u1 u2
Nd
u
u
u
L
x
L
xLxu or)(
2
1
V
dVk EBBT
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3.1 Rod
Strain is the gradient of axial displacement, i.e.
Notice that strain-displacement matrix is derivative of
the shape function vector.
Thus the stiffness matrix can be derived as
2
1,
11,
u
u
LLdx
d
dx
dux
dBBdN
111111
/1/1
0 L
AEAdxLL
EL
LdVkL
V
EBBT
6
3.2 2D Beam
2 dimensional Beam element has for degrees of
freedom, i.e. rotations at the end of the beam as
well as transverse displacements:
In the development of the stiffness matrix the
assumption is a prismatic and materially
homogenous beam.
Notice that axial deformations are excluded from
the definition but they can be readily incorporated
in stiffness matrix from rod element previously
defined.
2
2
1
1
v
v
d
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3.2 2D Beam
The stiffness matrix of a two-dimensional prismatic
beam made of homogenous material can be
derived using integral
in which the strain-displacement matrix B is
obtained from curvatured2v/dx2 using third order
polynomial, which describes the displacement field
as:
V
dVEIk BBT
3
4
2
321 xxxv
8
3.2 2D Beam
Using four shape functions, i.e. each for
corresponding dof, leads to formulation
and strain-displacement function B is obtained
from curvature d2v/dx2
2
2
1
1
4321)(
v
v
NNNNxv
BdN
2
2
2
2
dx
d
dx
vd
EI
M
dx
d
2
2Engineering beam theory:
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3.2 2D Beam
The shape functions are obtained from beam theory:
jossa
10
3.2 2D beam
Thus the derivatives of the shape functions shown in
the previous slide result the strain-displacement matrix
And the integration
results
22
22
3
4626
612612
2646
612612
LLLL
LL
LLLL
LL
L
EIdVEIk
V
BBT
T2211
vvd
232232
6212664126
L
x
LL
x
LL
x
LL
x
LB
BdN
2
2
2
2
dx
d
dx
vd
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3.3 Transformation
Stiffness matrix of a rod in local coordinate system (a)
Transformation from local to global system (b)
3.3 Transformation
The global stiffness matrix of a rod can be derived as
where
cos,sin,
22
22
22
22
cs
scsscs
csccsc
scsscs
csccsc
L
AETk'Tk
T
sincos00
00sincosT
11
11
L
AEk'
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3.3 Transformation
Example: calculate the displacements and stresses of
the structure shown in figure, whenA = 300 mm2 for all
rods and E = 200 GPa.
14
3.3 Transformation
Element numbering, directions of local coordinates,
stiffness matrices and degrees of freedom:
1:C->B
2:B->A
3:C->A
uC vC uB vB
uB vB uA vA
uC vC uA vA
uCvCuBvB
uBvBuAvA
uCvCuAvA
cos,sin,
22
22
22
22
cs
scsscs
csccsc
scsscs
csccsc
L
AETk'Tk
T
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3.3 Transformation
Global stiffness matrix and force vector when loading
and boundary conditions are taken into account:
1:C->B
2:B->A
3:C->A
uC vC uB vB uA vA
A
A
B
B
C
C
v
u
v
u
vu
U
16
3.3 Transformation
Solution and results [mm]:
uB =-1,50 mm
vB =-11,3 mm
vA= - 4,00 mm
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3.3 Transformation
Formulate the stiffness matrix of the structure shown in
figure.E = 210 GPa and cross-section is RHS 100x100x4.
Axial stiffness of beamBC =
The stiffnes matrix of beamAB in global coordinate
system is
and of beamsBD and DC:
B
B
A
A
AB
v
u
v
u
scsscs
csccsc
scsscs
csccsc
L
AE1
22
22
22
22
1 , uk
D
D
B
B
BDBDBDBD
DBBD
BDBDBDBD
BDBD
BDv
v
LLLL
LL
LLLL
LL
L
EI
2
22
22
32 ,
4626
612612
2646
612612
uk
C
C
D
D
DCDCDCDC
DCDC
DCBCDCDC
DCDC
DCv
v
LLLL
LL
LLLL
LL
L
EI
3
22
22
33 ,
4626
612612
2646
612612
uk
D
D
D
B
B
v
v
D
D
B
B
v
v
B
B
A
A
v
u
v
u
1u
18
3.3 Transformation
Taking into account the boundary conditions and the axial
stiffness of beamBC (infinite!) results
22
22
22
22
31
scsscs
csccsc
scsscs
csccsc
L
AE
AB
k
22
22
32
4626
612612
2646
612612
BDBDBDBD
BDBD
BDBDBDBD
BDBD
Bd
LLLL
LL
LLLL
LL
L
EIk
D
22
22
33
4626
612612
2646
612612
DCDCDCDC
DCDC
DCDCDCDC
DCDC
DC
LLLL
LL
LLLL
LL
L
EIk
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3.3 Transformation
Global stiffness matrix is then
C
D
D
B
B
DCDCDC
DCDCBDDCBDBDBD
DCDCBDDCBDBDBD
BDBDBDBD
BDBDBDBDAB
Gv
v
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EI
L
EIs
L
AE
dk ,
42600
2446626
6661212612
02646
0612612
2
222
2223323
22
2323
2
D
20
3.3 Transformation
The solution results
Backsubstitution gives element forces, example is
elementBD:
D
Displacementvector
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3.3 Transformation of 2D beam element
Global stiffness matrix of a 2D beam element, when also
axial stiffness is taken into account is
Tk'Tk T
2
2
2
1
1
1
v
u
v
u
U
100000
0cossin000
0sincos000
000100
0000cossin
0000sincos
T
v1
1
u1
v2 u22
Y
X
22
3.2 2D beam: example
Calculate the maximum displacement and maximum
normal stress in the frame shown in picture. Crane beam
is IPE 300 and column is HEA200. Neglect self-weight.
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3.2 2D beam: exampleElementmodel and degrees of freedom (notice assumptions of model!):
E = 210 GPa
AIPE300 = 5380 mm2
IIPE300 = 83,6E6 mm4
AHEA20 = 5380 mm2
IHEA200 = 36,9E6 mm2
1 2
3
1 2 3
4
mmmmmm
mmmmmm
mmmmmm
mmmmlmlmllll
mmmmlmlmllll
mmmmlmlmllll
llllklklkkkk
llllklklkkkk
llllklklkkkk
kkkkkk
kkkkkk
kkkkkk
G
000000
000000
000000
000
000
000
000
000
000
000000
000000
000000
k
4
4
4
3
3
3
2
2
2
1
1
1
v
u
v
u
v
u
v
u
U
u
v
24
3.2 2D beam: example
Distributed loading, e.g. self-weght in a
beam element
is changed to nodal loads and moments at
nodes:
2
wL
2
wL
12
2wL
12
2wL
w