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 Ruas Jalan S.Parman 1. Kecepat an Arus Bebas FV = (FV0 + FVw ) x FFVSF x FFVS !"#eta$u" % FV0 = && #m'am FVw = * #m'am FFVSF = 0,& FFVS = 0,& FV = (&& + (*) ) x 0,& x 0,& = *-0 #m'am . Kapas"tas = 0 x Fw x FSF x FSP x FS !"#eta$u" % 0 = 1-&0 smp'am Fw = 0, FSF = 1 FSP = 0,/ FS = 0,* = 1-&0 x 0, x 1 x 0,/ x 0,* = 1/0/ smp'am /. !e ra a t Ke enu$an !S = ' !"#eta$u" % = /,0 = 1/0/ !S = = *

Ruas Jalan S Parman

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MASTER

Ruas Jalan S.Parman

Kecepatan Arus Bebas

FV= (FV0 + FVw ) x FFVSF x FFVCS

Diketahui :

FV0= 55 km/jam

FVw = -4 km/jam

FFVSF= 0,95

FFVCS= 0,95

FV= (55 + (-4) ) x 0,95 x 0,95

= 46,02 km/jam

Kapasitas

C= C0 x FCw x FCSF x FCSP x FCCS

Diketahui :

C0= 1650 smp/jam

FCw= 0,92

FCSF= 1

FCSP= 0,93

FCCS= 0,94

C= 1650 x 0,92 x 1 x 0,93 x 0,94

= 1327,03 smp/jam

Derajat KejenuhanDS= Q/CDiketahui :

Q= 3290

C= 1327,03

DS=

= 2,47

FV0 FVw FFVSFFFVCS

C0 FCw FCSF FCSPFCCS