Upload
dskumar49
View
223
Download
6
Embed Size (px)
DESCRIPTION
.....
Citation preview
1
DEPARTMENT OF MECHANICAL ENGINEERING
COMPLETE COURSE FILE (Academic year)
Course Title: MATERIAL SCIENCE AND METALLURGY
Contents Page No
1. Course details
1.1 Primary info 1
1.2 Course Content (Syllabus) 2
1.3 Text books 5
1.4 Reference books 5
2. Course plan
2.1 Course learning objectives 6
2.2 Course outcomes 6
2.3 Validation of course outcomes 7
2.4 Mapping of COs with POs 7
3. Assessment
tools and data
3.1 Definition of assessment tools 8
3.2 Assessment data 14
4. Attainment of
CO
4.1 Measuring CO attainment 44
4.2 Remarks 46
********************************
1. Course details
1.1 Primary information:
1. Course Code : 10ME32A
2. L-T-P : 4-0-0
3. Marks (Min/Max)
VTU Exam
Internal Assessment
: 50/125
35/100
0/25
4. Pre-requisite : Physics, Chemistry
5. Teaching Department : Mechanical Engineering
6. Course Duration : 52 Hours
7. Faculty Representative :
8. Course Faculty :
2
1.2 Course Content (Syllabus):
Topic Title Description Topic Level Outcomes
Duration At the end of the topic students will be able to
1. Crystal
Structure
BCC, FCC and HCP Structures
- coordination number
- atomic packing factors
Crystal imperfections
- point, line & surface imperfections
Atomic Diffusion:
- diffusion phenomenon
- Fick’s laws of diffusion
- factors affecting diffusion
1. Draw unit cells for BCC, FCC and HCP crystal
structures.
06 Hours
2. Find the atomic packing factor for BCC, FCC and
HCP crystal structures.
3. Compute the density of metals having FCC, BCC
and HCP crystal structures given their unit cell
dimensions.
4. Name and describe different crystal imperfections.
5. Describe the mechanism of atomic diffusion.
2. Mechanical
Behaviour
Stress-strain diagram showing
- ductile and brittle behaviour of
materials
- linear and nonlinear elastic
behaviour and properties
- mechanical properties in plastic
range; yield strength, offset yield
strength, ductility, ultimate tensile
strength, toughness
Plastic deformation of single crystal
- slip and twinning
1. Explain the ductile-brittle and linear-nonlinear
elastic behaviour of materials.
06 Hours 2. Evaluate the mechanical properties of a material
through stress strain diagram.
3. Identify plastic deformation by slip and twinning
in materials.
3. Failure of
Materials
Fracture:
- Type I, Type II and Type III
Creep:
1. Differentiate failure of materials by fracture, creep
and fatigue. 07 Hours
3
- description of the phenomenon with
examples
- three stages of creep
- creep properties
- stress relaxation
Fatigue:
types of fatigue loading with
examples
mechanism of fatigue
fatigue properties
fatigue testing and S-N diagram
2. Explain the different types of fracture modes,
creep stages and fatigue loading.
3. Explain the phenomenon of creep and its
properties.
4. Explain mechanism of fatigue failure for a material
and plot SN diagram.
4. Solidification
Mechanism of solidification
- nucleation
- crystal growth
- cast metal structures
Phase Diagram I
- solid solutions
- Hume Rothary rule
- substitutional and interstitial solid
solutions
- intermediate phases
- Gibbs phase rule
1. Explain the mechanism of solidification by
nucleation and grain growth for pure metals and
alloys.
07 Hours
2. Enumerate the significance of cast structure of
metals and the methods to control it.
3. Construct phase diagram for simple binary alloys.
4. Identify the formation of interstitial or
substitutional solid solutions and intermediate
phases.
5. Phase
Diagram II
Construction of equilibrium diagrams
involving complete and partial
solubility, lever rule.
Iron carbon equilibrium diagram
- description of phases
- solidification of steels and cast
irons
- invariant reactions
1. Construct the Iron-Carbon equilibrium diagram
and discuss the invariant reactions in it.
06 Hours
2. Interpret the formation of steel and cast irons using
an iron-carbon diagram
4
6. Heat treating
of metals
TTT curves
Continuous cooling curves
Heat treatment techniques
- annealing and its types,
normalizing, hardening,
- tempering, martempering,
austempering
- hardenability and surface hardening
methods like carburizing,
cyaniding, nitriding, flame
hardening and induction hardening
- age hardening of aluminium-copper
alloys
1. Explain the process details of various heat
treatment processes.
07 Hours
2. Suggest a suitable heat treatment technique for the
desired materials and properties.
7. Ferrous and
non-ferrous
materials
Properties, Composition and uses of
- Grey cast iron, malleable iron, SG
iron and steel
- Copper alloys: brasses and bronzes
- Aluminium alloys: Al-Cu, Al-Si,
Al-Zn alloys
1. State the areas of application of commonly used
engineering materials.
06 Hours
2. Suggest the selection of materials based on the
property requirements
8. Composite
Materials
Definition
Classification
types of matrix materials &
reinforcements
fundamentals of production of FRP's
and MMC's
advantages and application of
composites
1. Explain the production techniques for some
common FRP’s and MMC’s
07 Hours
2. List out the advantages and applications of
composite materials
5
1.3 Text Books:
1. Foundations of Materials Science and Engineering, Smith, 4th Edition McGraw Hill,
2009
2. Materials Science, Shackleford., & M. K. Muralidhara, Pearson Publication – 2007.
1.4 Reference Books:
1. An Introduction to Metallurgy; Alan Cottrell, Universities Press India Oriental Longman
Pvt. Ltd., 1974.
2. Engineering Materials Science, W.C.Richards, PHI, 1965.
3. Physical Metallurgy; Lakhtin, Mir Publications.
4. Materials Science and Engineering, V.Raghavan, PHI, 2002.
5. Elements of Materials Science and Engineering, H. VanVlack, Addison- Wesley Edn.,
1998.
6. Materials Science and Engineering, William D. Callister Jr., John Wiley & Sons. Inc, 5th
Edition, 2001.
7. The Science and Engineering of Materials, Donald R. Askland and Pradeep.P. Phule,
Cengage Learning, 4lh Ed., 2003.
6
2. Course plan
2.1 Course Learning Objectives (CLOs):
1. To impart knowledge on structure property correlations for commonly used engineering
materials.
2. To help the students to understand the mechanical behavior, deformation characteristics
and the modes of failure of materials.
3. To enable the students to understand the effect of solidification mechanism of metals on
the resulting microstructure and properties as well as effect of subsequent heat treatments
on the material properties.
4. To train the students to interpret the iron carbon equilibrium diagram for the formation of
steel and cast irons.
5. To educate the students about the conventional engineering materials, their characteristics
and applications as well as the recent trends in materials such as composites.
6. To kindle an enthusiasm among the students to carry on lifelong learning in the field of
metallurgical and materials science.
2.2 Course Outcomes (COs):
At the end of the course the students will be able to
1. Explain the crystal structure of commonly used engineering materials and their
characteristic properties.
2. Interpret the deformation characteristics and behavior of materials when subjected to
loads till their failure.
3. Explain the solidification mechanism and heat treatment techniques and the control
measures to obtain a suitable microstructure for specific property applications.
4. Indicate the properties, composition and applications of ferrous, non-ferrous materials
and composite materials and suggest a suitable material for specific applications.
7
2.3 Validation of Course Outcomes
Course Outcome POs-Levels Cognitive Level
CO1
Explain the crystal structure of commonly used
engineering materials and their characteristic
properties.
PO1:2 Understanding
(Level 2)
CO2
Interpret the deformation characteristics and
behavior of materials when subjected to loads till
their failure.
PO1:2
PO5:1
Analyzing
(Level 4)
CO3
Explain the solidification mechanism and heat
treatment techniques and the control measures to
obtain a suitable microstructure for specific
property applications.
PO1:3
PO2:1
Applying
(Level 3)
CO4
Indicate the properties, composition and
applications of ferrous, non-ferrous materials and
composite materials and suggest a suitable material
for specific applications.
PO5:2 Understanding
(Level 2)
POs-Levels: 1-Slightly, 2-Moderately, 3-Highly
Cognitive Levels: 1 to 6 as per Bloom’s Taxonomy
2.4 Mapping of COs with POs
PO1
(a)
PO2
(b)
PO3
(c)
PO4
(d)
PO5
(e)
PO6
(f)
PO7
(g)
PO8
(h)
PO9
(i)
PO10
(j)
PO11
(k)
PO12
(l)
PO13
(m)
CO1 X
CO2 X X
CO3 X X
CO4 X
X X X X
8
3. Assessment tools and data
3.1 Assessment tools
The assessment tools to be used for CAY are;
Internal assessment
Assignments
Quizzes
I. Internal Assessment:
Internal Test – I (Date)
Q.No Question Expected Outcome Cognitive
Level Marks
TLO
Measured
1 What is packing factor? Find the packing factor for
FCC?
Refer Appendix – I
(IA Scheme and Solutions)
Remembering 5 1.2
2 What is diffusion? Explain the unsteady state of
diffusion with example?
Understanding 4 1.5
3 Differentiate between ductile and brittle material? Name
five examples for each?
Understanding 5 2.1
4 The unit cell of chromium is cubic and contains 2
atoms. Determine the dimension of the dimension of the
chromium unit cell and atomic radius. Given atomic
weight of chromium=52 & density of chromium=7.19
g/cm3
Applying 3 1.3
5 (a) A Steel rod of 10mm die & 1.5m length is subjected to
an axial tensile test of 10KN. Determine (a) Stress (b)
strain (c) Elongation. Take E=205*106 KN/m
2
Applying 5 2.2
5 (b) Explain any one of this (a) Edge dislocation (b) screw
dislocation.
Understanding 3 2.3
9
Internal Test – II (Date)
Q.No Question Expected Outcome Cognitive
Level Marks
TLO
Measured
1 Explain Hume-Rothary rules governing the formation of
substitutional solid solution
Refer Appendix – I
(IA Scheme and Solutions)
Remembering 5 4.4
2 Explain the mechanism of solidification for pure metals. Understanding 7 4.1
3 a) Draw Fe-Fe3C phase diagram and label all the regions
indicating the invariant reactions with the temperature
and composition for the same.
b) From the above phase diagram calculate the amount of
eutectic present in the pearlite using lever rule.
c) Also sketch the typical microstructure for the
following
(i) eutectoid steel at room temperature
(ii) hypo-eutectic cast iron having 3% carbon at 910
C and at room temperature
Remembering
Understanding
Understanding
8
2
3
5.1
4 a) Explain with neat sketch the different stages of creep
formation?
Understanding 8 3.2
b) What is fatigue failure? Draw S-N curve for steel and
aluminum?
Understanding 5 3.4
Internal Test – III (Date)
Q.No Question Expected Outcome Cognitive
Level Marks
TLO
Measured
1 a) From fundamentals distinguish clearly between alloy
and composites.
Refer Appendix – I
(IA Scheme and Solutions)
Understanding 3 6.2
b) Classify the composites based on the matrix and
reinforcements.
Remembering 3 6.1
2 List down the production methods of metal matrix
composites. Explain any one with neat sketch.
Understanding 5 6.1
3 What is meant by heat treatment? What are its
objectives?
Remembering 4 8.1
10
4 Define hardenabilty. Explain the process which is used
to find the hardenability of steel.
Understanding 5 8.2
5 What is Case hardening? Explain pack carburizing
process.
Understanding 5 8.1
II. Assignments:
A.
No Questions
Cognitive
Level
TLO
Measured
Date of
Submission
1
1. What are the three primary bonds in materials? Which is the strongest? Why? Remembering
Date
2. Find out from the Handbook of materials the melting points of the following metals and
cite the details of the handbook referred.
a) Plain Carbon Steel (0.3 % Carbon)
b) Aluminium
c) Magnesium
d) Copper
understanding
3. How does the mechanical property (strength and ductility) of a material vary with its grain
size? Explain. (Refer Hall-Petch Relation) Understanding 2.1
4. How does the presence of defects in a crystal structure and alloying alter the properties of a
material? Explain. Analyzing 1.4
5. Explain strain hardening. Understanding 2.3
6. Explain how grain boundaries impede dislocation motion and why a metal having small
grains is stronger than one having large grains. Analyzing 2.3
7. Following are the tensile test results of a steel specimen having a 30 mm diameter and 200
mm length. Extension at a load of 50kN = 0.1mm. Load at elastic limit = 230kN.
Maximum load = 300kN. Total extension = 50 mm. Diameter of rod at failure = 20 mm.
Calculate (i) Young's modulus (ii) Ductility
Applying 2.2
8. A low carbon steel rod is subjected to tensile load of 7000 kg. Assuming no volume change
during extension, determine (i) Engineering stress and engineering strain. (ii) True stress
and true strain. The initial diameter of the rod is 13 mm and after application of load
12mm.
Applying 2.3
2
1. What do you mean by alloying? How is it different from a pure metal with reference to
mechanical properties and microstructure? Understanding 4.1
Date 2. Why is undercooling necessary for nucleation? Explain the concept of volume free energy
and surface free energy with its effect on undercooling for homogeneous and
heterogeneous nucleation.
Understanding 4.1
11
3. What is a phase diagram? Why is it necessary? Understanding 4.3
4. Explain phase rule and lever rule with emphasis on a binary eutectic phase diagram. Understanding 4.4
5. Sketch the typical microstructure for the following at room temperature: (a) Pure iron (b) Plain carbon steel with 0.4 % carbon (c) Eutectoid steel (d) Cast iron with 4.5 % carbon
Remembering 5.2
6. Plot the eutectic region of a Fe-Fe3C system and find the eutectic present in an alloy of 3.5
%C at 1000 C. Analyzing 5.1
7. What is an Invariant reaction? Draw the pictorial representation of the following invariant reactions:
(a) Eutectic reaction (b) Eutectoid transformation (c) Peritectic reaction
Analyzing 5.1
III. Quizzes:
Quiz 1
SL
No. Questions Answer
TLO
Measured
1. Repeatable entity of a crystal structure is known as
(a) Crystal (b) Unit cell (c) Grain (d) Lattice
Unit Cell 1.1
2. Atomic packing factor is
(a) Volume fraction of atoms in a unit cell (b) Projected area fraction of atoms on a plane
(c) Distance between two adjacent atoms (d) None
Volume
fraction of
atoms in a unit
cell
1.2
3. Choose the correct lattice parameters for a hexagonal crystal system
(a) a=b=c , α=β= 0deg, γ=120deg (b) a=b≠c , α=β=90deg, γ=120deg
(c) a=b=c , α=β=γ=120deg (d) a=b≠c , α=β=γ=120deg
a=b≠c ,
α=β=90deg,
γ=120deg
1.3
4. Following is not the 2-dimensional imperfection
( ) Di location (b) Grain boundary (c) Twin boundary (d) External surface
Dislocation 1.4
5. The yield strength for a material with well-defined elastic to plastic transition showing an upper and lower
yield point is measured as
(a) stress at 0.2% offset strain (b) average of stresses at upper and lower yield point
average stress at
lower yield
point
2.1
12
(c) average stress at lower yield point (d) stress at upper yield point
6. For a tensile experiment the ductility is measured as
(a) percentage elongation in length (b) percentage reduction in area
(c) both (d) None of the above
both 2.2
7. Plastic deformation results from the following
(a) Slip (b) Twinning (c) Both (d) None
Both 2.3
Quiz 2
SL
No. Questions Answer
TLO
Measured
1 The slow and progressive deformation of a material with time at constant stress is known as Creep 3.1
(a) Fracture (b) Fatigue (c) Creep
2 Usually materials with following crystal structure fail in ductile mode FCC 3.2
(a) HCP (b) FCC (c) BCC (d) None
3 Creep rate in ternary stage Increases 3.3
(a) Decreases (b) Increases (c) Constant (d) None
4 SN curve gives information about Fatigue 3.4
(a) Fatigue (b) Creep (c) Failure (d) All
5 For homogeneous nucleation occurs in the presence of Undercooling
(a) Impurities (b) Undercooling (c) Both (a) & (b) (d) None 4.1
6 As the grain size decreases the hardness of a material Increases 4.2
(a) Decreases (b) Increases (c) Has no effect (d) None
7 A binary phase diagram is a plot of Temp. Vs
Composition
4.3
(a) Temp. Vs Time (b) Temp. Vs
Composition
(c) Temp. Vs Pressure (d) None
8 Eutectoid reaction can be represented as 4.4
(a) (b) (c) (d)
9 Maximum percentage of carbon in austenite is 5.1
(a) 0.02 % (b) 0.8 % (c) 2.1 % (d) 4.3 % 2.1 %
10 The upper critical temperature for steel 5.2
13
(a) varies with carbon
%
(b) is constant (c) depends on rate
of heating
(d) none of these varies with
carbon %
11 Annealing of steel is done
(a) to soften the metal (b) improve
machinability
(c) refine grain size (d) all of these all of these 6.1
12 Suggest a suitable heat treatment to increase hardness without resorting to severe quenching. Martempering 6.2
(a) Annealing (b) Normalizing (c) Martempering (d) Carburizing
13 Bronze is an alloy of Copper & Tin 7.1 & 7.2
(a) Copper & Zinc (b) Copper & Tin (c) Iron & Brass (d) Iron & Zinc
14 Which of the following is a continuous production technique used for production of FRP Pultrusion
(a) Filament winding (b) Vacuum bag moulding (c) Spray up process (d) Pultrusion 8.1
15 The function of a matrix phase in a composite is Both (a) and (b) 8.2
(a) Improve impact and fracture resistance (b) Provide strength and stiffness to composite
(c) Both (a) and (b) (d) None
14
3.2 Assessment data:
I Internal Assessment Marks
Sl. No. USN Name
Marks Scored
Q. No. 1 2 3 4 5 [a] 5 [b]
Max 5 4 5 3 5 3
5 0 1 0 1 2
5 2 5 1 2 2
5 0 0 0 0 1
5 1 5 2 5 1
5 4 5 3 5 3
5 1 NA 0 3 1
5 4 5 3 5 3
5 4 5 2 5 3
5 1 3 0 5 3
4 4 4 3 5 3
5 4 5 3 5 3
5 2 5 0 3 2
NA 1 2 1 NA 3
4 1 5 NA 2 0
3 2 2 0 5 3
5 1 1 0 NA 1
3 3 1 1 1 3
5 4 5 3 5 3
5 1 4 1 4 3
5 4 5 1 5 3
5 1 5 1 NA 3
5 1 5 0 5 3
5 4 5 3 4.5 3
5 1 4 1 1 3
5 2 5 0 1 3
5 4 5 3 5 3
5 4 4 3 5 2
5 1 5 0 2 2
5 4 5 3 3 3
5 1 5 3 5 3
5 1 4 1 2 0
5 4 5 3 5 3
870 289 712 266.5 649 396.5
Average Marks 4.10 1.55 3.39 1.46 3.12 2.02
Avearage Marks (Percentage) 82.08 38.84 67.81 48.81 62.40 67.43
TLO/s which is/are assessed by the question 1.2 1.5 2.1 1.3 2.2 2.3
Total Marks
19
II Internal Assessment Marks
Sl. No. USN Name
Marks Scored
Q. No. 1 2 3 4 [a] 4 [b]
Max 5 7 13 8 5
5 3 NA NA NA
5 6 NA 8 3
5 3 2 NA NA
5 3 12 NA NA
5 4 10 NA NA
5 7 NA NA 5
5 4 NA 8 2
5 5 5 NA NA
0 6 NA 8 2
5 5 5 NA NA
5 5 8 NA NA
5 4 NA 8 4
5 4 NA NA NA
3 5 NA 4 1
5 5 0 NA NA
5 4 10 NA NA
5 6 NA 8 4
5 7 13 NA NA
4 2 4 NA NA
5 3 NA 8 5
5 6 NA 7 1
5 5 NA 8 5
5 7 11 NA NA
5 3 NA 8 3
5 3 NA 6 5
Total Marks 912 912 971.5 700 442.5
Average Marks 4.36 4.51 6.75 5.88 3.75
Avearage Marks (Percentage) 87.27 64.50 51.90 73.53 75.00
TLO/s which is/are assessed by the question 4.4 4.1 3.2 3.4
Average Marks
Avearage Marks (Percentage)
TLO/s which is/are assessed by the question 5.1 & 5.2
24
III Internal Assessment Marks
Sl. No. USN Name
Q. No. 1 [a] 1 [b] 2 3 4 5
Max 3 3 5 4 5 5
0 NA 0 1 NA NA
NA NA NA NA NA NA
3 0 5 1 0.5 4
2 2.5 5 4 NA 5
NA NA NA NA NA NA
NA NA 5 NA NA NA
NA NA NA NA NA NA
2 0 4 1 4 3
NA NA NA NA NA NA
3 1 4 1 1 NA
2 2.5 5 4 5 5
NA NA NA NA NA NA
2.5 2 0 NA 5 NA
2.5 0 4 4 1 1
2.5 1.5 0 4 5 0
1.5 0 4 0 0 0
Total Marks 136 107 197 203.5 349 170
2.00 1.81 2.94 3.04 2.81 2.66
Avearage Marks (Percentage) 66.67 60.45 58.81 75.93 56.29 53.13
TLO/s which is/are assessed by the question 8.2 8.1 8.1 6.1 6.2 6.1
Average Marks
Avearage Marks (Percentage)
TLO/s which is/are assessed by the question
30
Quiz 1 Result
Sl.No. USN Name Quiz score
1 2 3 4 5 6 7
0 0 0 1 0 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 0
1 1 1 0 0 1 1
1 1 1 0 0 1 1
0 0 1 0 1 1 1
1 1 1 1 0 0 0
0 0 0 0 1 1 1
0 1 0 0 0 0 1
0 0 0 0 0 1 1
1 1 1 1 1 1 1
1 1 0 0 0 0 1
0 0 0 1 0 1 1
1 1 0 0 0 0 0
0 0 1 0 0 1 1
0 0 0 0 1 0 1
Average Marks (Percentage) 62% 51% 50% 36% 19% 53% 67%
1.1 1.2 1.3 1.4 2.1 2.2 2.3 TLOs Assessed by the question
34
Quiz 2 Result
Sl. No. USN Name Quiz score
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
0 0 1 1 1 1 1 0 1 1 0 0 0 1 0
0 0 1 1 1 1 0 1 0 0 0 1 0 0 0
0 0 0 1 0 1 0 0 0 0 0 0 1 1 0
1 0 1 1 1 1 1 0 1 1 1 1 1 0 0
1 1 0 1 0 1 1 1 0 0 1 0 1 0 0
USN NameQuiz score
Average Marks (Percentage) 43 33 58 52 48 74 68 34 30 50 44 25 47 21 17
TLOs Assessed by the question 3.1 3.2 3.3 3.4 4.1 4.2 4.3 4.4 5.1 5.2 6.1 6.2 7.1&7.2 8.1 8.2
43
5 5
3 4
4 5
4 5
4 4
Total Marks 586 575
Average Marks 3.93 3.86
Avearage Marks (Percentage) 78.66 77.18
TLO/s which is/are assessed by the question 1.4, 2.1, 2.2, 2.3 4.1, 4.3, 4.4, 5.1, 5.2
Assignment Marks
Sl. No. USN Name
Marks Scored
Assigment No. A1 A2
Q. No. (8 Questions) (7 Questions)
Max 5 5
3 2
5 5
3 4
5 3
5 5
4 3
5 2
5 3
5 5
44
4. Attainment of Course Outcomes
4.1 Measuring CO attainment:
TLO
No. Topic Learning Outcome
Attained
Level of
Bloom's
Taxonomy
Assessment
Tool Used Weightage
Percentage
Average
Assessment
Contribution to CO
Attainment
Attainment
Goal CO1 CO2 CO3 CO4
1.1 Draw unit cells for BCC, FCC and HCP crystal
structures.
Remembering Quiz 1 0.25 62.22 15.56
1.2 Find the atomic packing factor for BCC, FCC
and HCP crystal structures.
Applying IA 1 0.25 82.08 20.52
1.3 Compute the density of metals having FCC, BCC and
HCP
crystal structures given their unit cell dimensions.
Applying
Quiz 1 0.25 49.63 12.41
1.4 Name and describe different crystal imperfections. Remembering Quiz 1 0.25 35.56 8.89
2.1 Explain the ductile-brittle and linear-nonlinear elastic
behaviour
of materials.
Understand
IA 1 0.2 67.81
13.56
2.2 Evaluate the mechanical properties of a material
through
stress strain diagram.
Analyzing
IA 1 0.2 62.40
12.48
2.3 Identify plastic deformation by slip and twinning in
materials.
Understanding IA 1 0.1 67.43
6.74
3.1 Differentiate failure of materials by fracture, creep and
fatigue.
Understanding Quiz 2 0.1 43.14
4.31
3.2 Explain the different types of fracture modes, creep
stages
and fatigue loading.
Understanding
IA 2 0.2 73.53
14.71
3.3 Explain the phenomenon of creep and its properties. Understanding Quiz 2 0.1 57.84
5.78
3.4 Explain mechanism of fatigue failure for a material and
plot SN diagram.
Understanding IA 2 0.1 75.00
7.50
4.1 Explain the mechanism of solidification by nucleation
and grain growth for pure metals and alloys.
Understanding IA 2 0.1 64.50
6.45
4.2 Enumerate the significance of cast structure of metals
and the methods to control it.
Applying Quiz 2 0.1 73.53
7.35
4.3 Construct phase diagram for simple binary alloys. Remembering Quiz 2 0.1 67.65
6.76
45
4.4 Identify the formation of interstitial or substitutional
solid solutions and intermediate phases.
Understanding IA 2 0.1 87.27
8.73
5.1 Construct the Iron-Carbon equilibrium diagram
and discuss the invariant reactions in it.
Understanding IA 2 0.2 51.90
10.38
5.2 Interpret the formation of steel and cast irons
using an iron-carbon diagram
Understanding Quiz 2 0.1 50.00
5.00
6.1 Explain the process details of various heat treatment
processes.
Understanding IA 3 0.2 75.93
15.19
6.2 Suggest a suitable heat treatment technique for
the desired materials and properties.
Understanding IA 3 0.1 56.29
5.63
7.1 State the areas of application of commonly used
engineering materials.
Remembering Quiz 2 0.2 47.06
9.41
7.2 Suggest the selection of materials based on the
property requirements
Understanding Quiz 2 0.2 47.06
9.41
8.1 Explain the production techniques for some
common FRP’s and MMC’s
Understanding IA 3 0.3 60.45
18.14
8.2 List out the advantages and applications of
composite materials
Remembering IA 3 0.3 66.67
20.00
Total Attainment of CO1 57.37
65
Total Attainment of CO2
65.09
65
Total Attainment of CO3
65.49
65
Total Attainment of CO4
56.96 65
46
4.2 Remarks:
Course Coordinator:
Module Coordinator:
(Course & Module Coordinator)
(HOD – Mech Dept)
47
Appendix – I
(IA Scheme & Solutions)
I Internal Assessment - Scheme of evaluation & Solution
Q.No Solution Marks
1. What is packing factor? Find the packing factor for FCC? 5
Atomic Packing Factor
The Atomic Packing Factor (APF) is the fraction of volume in a crystal
structure that is occupied by the atoms.
i.e., APF =
= =
(1)
FCC:
From ABC,
AC2+BC
2= AB
2
2 +
2 =
2
=
Number of atoms per unit cell, = 4
Volume of each atom, =
Volume of a unit cell, =
Therefore,
APF = =
APF = 0.74
i.e., 74 % of the space available in a FCC unit cell is occupied by atoms.
(4)
48
2. What is diffusion? Explain the unsteady state of diffusion with example? 4
Atomic diffusion
From an atomic perspective diffusion may be defined as the mass flow
process by which atoms or molecules migrate from lattice site to lattice site
within a material resulting in the uniformity of composition as a result of
thermal agitation.
(1)
Fick’s second law of diffusion:
Most practical diffusion situations are usually of unsteady state. i.e., the
diffusion flux and the concentration gradient at some particular point in
solid vary with time resulting in net accumulation or depletion of
diffusing species.
Therefore, =
Where,
= rate of composition change
= co ncentration gradient
D = diffusivity, m2/s
Fig: Concentration profile for unsteady state diffusion
If diffusion coefficient is independent of concentration;
= D
i.e., the rate of composition change is equal to the diffusivity times the rate of
concentration gradient.
The solution to the above equation can be obtained by applying appropriate
boundary conditions.
Fort = 0, C = C0 (0 x ∞)
For t > 0, C = Cs (at x = 0) and C = C0 (at x = ∞)
Applying the above boundary conditions the solution can be obtained as,
= 1 – erf
From the above equation may be determined at any time and position if the
parameters and D are known
(3)
3. Differentiate between ductile and brittle material? Name five examples for
each?
5
49
Ductile Brittle
Materials can withstand larger strain
before fracture
Material fracture at lower strain
Large amount of yielding and yield
point in some cases
No yield point and less yielding
Low young’s modulus and ultimate
stress
Comparatively large
Capable of absorbing large quantities
of energy before fracture
Comparatively small
Necking is observed before fracture Catastrophic failure without warning
Ex: steel, aluminum, gold etc Ex: glass, cast iron, concrete etc
4. The unit cell of chromium is cubic and contains 2 atoms. Determine the
dimension of the dimension of the chromium unit cell and atomic radius.
Given atomic weight of chromium=52 & density of chromium=7.19 g/cm3
Solution : chromium = cubic structure
Atomic data= A=52
Density = =7.19 Mgm-3
V=2.401*10
-23 cm
3
w.k.t cubic structure, volume=V=a3
a=0.288nm
3
5.a) A Steel rod of 10mm die & 1.5m length is subjected to an axial tensile test
of 10KN. Determine (a) Stress (b) strain (c) Elongation. Take E=205*106
KN/m2
5
Solution : original dia=do=10mm
Original length=Lo=1.5m=1.5*103mm
Load =P=1KN
E=205*106 kN/m
2
(3)
50
w.k.t (Youngs modulus)
(1)
Elongation (
w.k.t stain( =
(1)
5.b) Explain any one of this (a) Edge dislocation (b) screw dislocation.
Edge Dislocation
It is created in a crystal by insertion of an extra plane of atoms i.e., a half plane
as shown in figure. The edge of the half plane terminates within the crystal, this
is termed as dislocation line. The atoms above the dislocation line are squeezed
together and are in a state of compression while the atoms below are pulled
apart and are in a state of tension. Edge dislocation is represented by the
symbol ┴ for positive dislocation and ┬ for negetive dislocation.
Screw Dislocation
It is said to be formed in perfect crystal when part of the crystal displaces
angularly over the remaining part under the action of shear stress. The upper
front region of the crystal is shifted one atomic distance to the right relative to
the bottom portion. The screw dislocation derives its name from the spiral or
helical path that is traced around the dislocation line by the atomic planes of
atoms. Screw dislocation is represented by the symbol for clockwise or
positive dislocation and for counterclockwise or negtive dislocation.
3
51
II Internal Assessment
Q.No Solution Marks
Answer both questions from Part A and any one from Part B.
Part A
1. Explain Hume-Rothary rules governing the formation of substitutional
solid solution.
5
These are the rules governing the formation of substitutional solid solutions;
1) Crystal structure factor: for complete solid solubility of two elements, they
should have the same type of crystal structure.
2) Relative size factor: the atoms of the solute and the solvent should be
approximately of the same size (difference in radii should be less than
15%).
3) Chemical affinity: the two metals should have very less chemical affinity.
4) Electronegativity (tendency to acquire electrons): the two metals should
have less electronegativity; higher the electronegativity of two elements
greater will be the chance of forming an intermediate phase.
5) Relative valence factor: among the metals, the one with the lower valency
tends to dissolve more of a metal of higher valency than vice versa. For
example, in a Ni-Al system; Ni has valency of 2 which dissolves 5% Al,
but Al has valancy of 3 and dissolves only 0.04% Ni.
(5x1)
2. Explain the mechanism of solidification for pure metals. 7
Solidification in pure metals
Pure metals have a clearly defined melting or freezing point. i.e., it solidifies at
a constant temperature.The evolution of latent heat is associated with
solidification and as a result temperature remains constant. An equilibrium
cooling of pure metal maybe assumed as shown in figure 3.9. It is also seen that
if a pure metal is cooled rapidly or otherwise when it is very pure it may cool
with some amount of undercooling.
52
Dendritic growth
Pure metals solidifying with a negative temperature gradient may result in
uneven projection of interface due to the thermal undercooling. The tip of the
projection is at a region of greater undercooling than the remainder of the
interface and will have a tendency to grow further into the liquid. The solids
grow in a stem perpendicular to the surface. The latent heat evolved tends to
lower the amount of undercooling at the main interface. The protrusion grows
into a spike while the growth of main interface is somewhat retarded. The spike
grows and branches develop on it, this branched structure is known as a
dendrite. The rate of dendritic growth depends upon the amount of
undercooling in the liquid ahead of the advancing dendrite.
Part B
3.a) Draw Fe-Fe3C phase diagram and label all the regions indicating the invariant
reactions with the temperature and composition for the same.
8
(6+2)
3.b) From the above phase diagram calculate the amount of eutectic present in the
pearlite using lever rule.
2
3.c) Also sketch the typical microstructure for the following
(i) eutectoid steel at room temperature
(ii) hypo-eutectic cast iron having 3% carbon at 910 C and at room
temperature
3
4.a) Explain with a neat sketch the different stages of creep formation? 8
Explanation
(4)
53
(4)
4.b) What is fatigue failure? Draw S-N curve for steel and aluminium? 5
Explanation
(2)
(3)
III Internal Assessment
Q.No Solution Marks
1.a) From fundamentals distinguish clearly between alloy and composites. 3
In an alloy, the element getting introduced (solute) dissolves into the metal
getting alloyed (solvent) to form a solid solution. It is a kin to salt dissolving in
water to form a salt solution except that the alloy is in solid form. One cannot
distinguish them.
In the case of composite, the metal forming the base of the composite (matrix)
and the added element remain un dissolved and could be identified. In the case
of metal matrix composite, one finds carbon fibers or a ceramic material in the
matrix of metal.
1.b) Classify the composites based on the matrix and reinforcements. 3
54
Classification based on Reinforcements
2. List down the production methods of metal matrix composites. Explain
any one with neat sketch.
5
For listing out production methods -1 marks
For sketch-2 marks
For explanation-2 marks.
3. What is meant by heat treatment? What are its objectives? 4
Heat treating is a group of industrial and metalworking processes used to alter
the physical, and sometimes chemical, properties of a material. The most
common application is metallurgical.
(1)
55
Objectives – (at least three) (3)
4. Define hardenabilty. Explain the process which is used to find the
hardenability of steel.
5
Definition-1 marks
Sketch-2 marks
Explanation-2 marks
5. What is Case hardening? Explain pack carburizing process. 5
Definition-1 marks
Sketch-2 marks
Explanation -2 marks