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Section 4.1 – Antiderivatives and Indefinite Integration
Reversing DifferentiationWe have seen how to use derivatives to solve various
contextual problems. For instance, if the position of a particle is known, then both the velocity and acceleration can be calculated by taking a derivative:
But what if ONLY the acceleration of a particle is known? It would be useful to determine its velocity or its position at a particular time. For this case, a derivative is given and the problem is that of finding the corresponding function.
23 5 7s t t t ' 6 5s t v t t ' 6v t a t Position Function The derivative of the
Position Function is the Velocity Function
The derivative of the Velocity Function is the Acceleration Function
32a t 'v t a t ''s t a tAcceleration
FunctionWhat function has a
derivative of 32?What function has a
second derivative of 32?
Antiderivative
A function F is called an antiderivative of a given function f on an interval I if:
for all x in I.
Example:
'F x f x
2
2
1 1
1
is an antiderivative of
because '
x x
x
F x f x
F x
The Uniqueness of Antiderivatives
Suppose , find an antiderivative of f. That is, find a function F(x) such that .
23f x x 2' 3F x x
3F x xUsing the Power Rule in
Reverse
Is this the only function whose derivative is 3x2?
3
2
5
' 3
H x x
H x x
3
2
11
' 3
K x x
K x x
3
2' 3
M x x
M x x
There are infinite functions whose derivative is 3x2 whose general form is:
3G x x C C is a constant real number (parameter)
Antiderivatives of the Same Function Differ by a Constant
If F is an antiderivative of the continuous function f, then any other antiderivative, G, of f must have the form:
In other words, two antiderivatives of the same function differ by a constant.
G x F x C
Differential EquationA differential equation is any equation that contains derivatives. If a question asks you to “solve a differential equation,” you need to find the original equation (most answers will be in the form y=).
Example:The following is a differential
equation because it contains the derivative of G:
' 2G x x
The general solution to the differential
equation is:
2G x x C
Example 1Find the general antiderivative for the given function.
5f x x
Using the opposite of the Power Rule, a first
guess might be: 6F x x But: 5' 6F x x
Divide this result by 6 to get x5
If: 616F x x Then: 51
6' 6F x x 5x
General Solution: 61
6F x x C
Example 2Find the general antiderivative for the given function.
sinf x x
Using the opposite of the Trigonometric Derivatives, a
first guess might be: cosF x x But: ' sinF x x
Multiply this result by -1 to get sinx
If: cosF x x Then: ' sinF x x sin x
General Solution: cosF x x C
Example 3Find the general antiderivative for the given function.
35f x x
Using the opposite of the Power Rule, a first
guess might be: 45F x x But: 3' 20F x x
Divide this result by 4 to get 5x3
If: 454F x x Then: 35
4' 4F x x 35x
General Solution: 45
4F x x C
Example 4Find the general antiderivative for the given function.
1x
f x
Using the opposite of the Power Rule, a first
guess might be: 1 2F x x But: 1 21
2'F x x
Multiply this result by 2 to get x-1/2
If: 1 22F x x Then: 1 212' 2F x x 1 2x
General Solution: 2F x x C
1 21
x
Rewrite if necessary
1 2x
Example 5Find the general antiderivative for the given function.
23cos2xf x
Using the opposite trigonometry derivatives:
9 tan 2F x x But: 2' 18sec 2F x x
Multiply this result by 1/2 to get 9sec22x
If: 92 tan 2F x x Then: 29
2' 2 sec 2F x x 29sec 2x
General Solution: 9
2 tan 2F x x C
29
cos 2x
Rewrite if necessary
29sec 2x
Antiderivative NotationThe notation
Means that F is an antiderivative of f. It is called the indefinite integral of f and satisfies the condition that for all x in the domain of f.
f x dx F x C Integral
'F x f x
Variable of Integration
Constant of Integration
Indefinite Integral
New Notation with old ExamplesFind each of the following indefinite integrals.
5.a x dx 616 x C
. sinb x dx cos x C
3. 5c x dx 454 x C
1.x
d dx 2 x C
Basic Integration Rules
Constant Multiple
Sum Rule
Difference Rule
Constant Rule (zero)
cf x dx c f x dx f x g x dx f x dx g x dx
f x g x dx f x dx g x dx
0 dx C
Let f and g be functions and x a variable; a, b, and c be constant; and C is an arbitrary constant.
Basic Integration Rules
Constant Rule (non-zero)
Power Rule
Trigonometric Rule
Trigonometric Rule
a dx ax C
cos sinx dx x C
Let f and g be functions and x a variable; a, b, and c be constant; and C is an arbitrary constant.
111
n nnx dx x C
sin cosx dx x C
Basic Integration Rules
Trigonometric Rule
Trigonometric Rule
Trigonometric Rule
Trigonometric Rule
2sec tanx dx x C
2csc cotx dx x C
Let f and g be functions and x a variable; a, b, and c be constant; and C is an arbitrary constant.
sec tan secx x dx x C csc cot cscx x dx x C
Example 1
Evaluate 5 23 7x x dx Sum and Difference
Rules5 23 7x dx x dx dx
Constant Multiple5 23 7x dx x dx dx
Power and Constant Rules
5 1 2 11 15 1 2 13 7x x x C
6 316 7x x x C Simplify
Example 2
Evaluate 5 4sinx x dxRewrite 1 25 4sinx x dx
Sum Rule1 25 4sinx dx x dx
Constant Multiple Rule1 25 4 sinx dx x dx
3 2103 4cosx x C Simplify
Power and Trig Rules 1 2 11
1 2 15 4 cosx x C
Example 3The graph of a certain function F has slope at
each point (x,y) and contains the point (1,2). Find the function F.
34 5x
34 5x dx Difference Rule
34 5x dx dx Constant Multiple Rule34 5x dx dx
4 5x x C Simplify
Power and Constant Rules3 113 14 5x x C
Integrate:
Use the Initial Condition to
find C:
42 1 5 1 C
2 4 C 6 C
4 5 6F x x x
Example 4A particle moves along a coordinate axis in such a way that
its acceleration is modeled by for time t>0. If the particle is at s=5 when t=1 and has velocity v=-2 at this time, where is it when t=4?
32a t t
32v t t dt 32 t dt 3 113 12 t C
22 1 C
2t C Integrate the acceleration to find velocity:
Use the Initial Condition to find C for velocity:
1C
14 4 4 5s
1.25
2 1s t t dt 2 1t dt dt 2 112 1 1t t C
15 1 1 C
1t t C Integrate the Velocity to find position:
Use the Initial Condition to find C for position:
5C
2 1v t t
1 5s t t t Answer the Question: