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At the core of these observations is a correlation betweenchannel geometry, flow, and sediment supply
The correlation requires that the channels have adjusted to theirwater and sediment supply.
But what if channel is currently adjusting, or perpetually adjusting?
The width of channels increases consistently with the square root of discharge.
The flow that moves the most sediment, over time, tends to just fill the channel and occurs ever year or two.
Using“the stable channel” or “the equilibrium channel” for design? Streams are never in equilibrium!
Especially those we judge to be unacceptably “out of adjustment”The forcing is (always) changing
How do we connect with specific, local, non‐sediment objectives? (if we build it like this … good things will happen. || Surely this is better, right?)
A “rational” approach: break problem down into its pieces: specify drivers, quantify channel response.
A “design approach”: specify objectives and design to meet them (rather than specify design and hope that it solves the problem)
An empirical stable channel is inevitably an intellectual black box.We need to connect objectives to actions, through specific mechanisms
Can we develop a design approach that(1) Specifies desired channel behavior(2) Incorporates sediment transport with uncertainty(3) Accommodates “typical” conditions
Unfortunately, for a rational design approach …(A)We can never forecast future conditions (e.g. water & sediment supply)
with a high degree of accuracy(B) We will never know the exactly correct channel geometry for a river channel
(because there probably isn’t one)
What is the supply of water and sediment?and
What do you want to do with them?
(1) Do you want the bed and banks to be static at a design flow?(2) Do you need to match transport capacity to sediment supply?(3) Both of the above
Channel DesignSpecified
equilibrium dimensions
Specified channel behavior
Account for uncertainty & riskAccommodate typical dimensions
3/2*
3/23/51 0.73 *
Replace in ( 1)( 1)
( 1)( 1)
sc
o
bs o c
Q cs gDB s gD
nQ SQ cB s gDa s D
*
15/3 1*
7/6
Replace with ( 1) rearrange and solve for critical discharge
( 1)
c c
c
bc c
s gDQ
aQ s DnS
2/3
2/3
3/51
3/510.7
Replace in using
so
b
b
b
b
h ghSQh
BUB aQ
SU hn
nQhaQ Sh
nQha S
nQg Sa
hydraulic geometry
Manning’s eqn.
continuity
Threshold ChannelFind critical discharge Qcusing critical Shields Number
Alluvial ChannelFind transport rate using M‐P&M
Estimating uncertaintyIn sediment transport
(i) Threshold channel(critical discharge for incipient motion Qc)
(ii) Alluvial Channel(estimate transport rate Qs from a formula)
The hydraulic problem
Previous Experiments• Jackson & Beschta (1984)• Ikeda & Iseya (1988) Adding sand increases
gravel mobilityEast Fk R., near Boulder WY, bl confluence of Muddy Ck.
Application of sediment transport concepts: Stream response to increased fines input
There are many reasons why sand supply to a gravel-bed river might be increasedfire, urbanization, reservoir flushing, dam removal
What is the effect on transport rates? Channel dynamics? Stream ecology?
7
0
5
10
15
0
5
10
15
y
0
5
10
15
y
0
5
10
15
J06
J14
J21
J27
BOMC
0
5
10
15
64.0
32.0
16.08.0
4.0
2.0
0.7
0.4
0.2
BOMC
Some experimental evidence
• 5 sediments, add sand to gravel
• Sand: 0.5 – 2.0 mm• Gravel: 2.0 – 64 mm• Sand Content:
6, 14, 21, 27, & 34%• 9 or 10 runs with each
sediment, wide range of transport rates
• Depth & width held constant, primary variables are sand content & flow strength
8
0.00001
0.0001
0.001
0.01
0.1
1
10
100
1000
0.1 1 10 100
J06J14J21J27BOMC
Bed Shear Stress (sidewall-corrected; Pa)
Gra
vel t
rans
port
rate
[g /
(m•s
)]Effect of sand content on gravel transport rate
94% Gravel
66% Gravel
Transport increases
even though proportion of gravel in bed decreases
How do we capture effect of sand content on gravel transport rates? 9
0
0.01
0.02
0.03
0.04
0.05
0 0.1 0.2 0.3 0.4 0.5 0.6
rg*
Sand Content of Bed
0.1
1
10
100
0.1 1 10 100Grain Size D (mm)
She
ar s
tress
(P
a)
quartz in water
c
No Motion
Motion
* 0.03( 1)
cc s gD
For D > 4 mm
The sand effect on transport is captured by a reduced critical shear stress for incipient motion of the gravel
< 10% sand~18% sand
>34% sand
0.01
0.1
0.1 1 10 100 1000 10000 100000
*c
*S
FrameworkSupported
MatrixSupported
No Motion
Motion
10
1E-05
0.0001
0.001
0.01
0.1
1
10
0.01 0.1 1
M-P&M2t*c(t*) 3̂
q*
*
0.00001
0.0001
0.001
0.01
0.1
1
10
100
1000
0.1 1 10 100
J06J14J21J27BOMC
Bed Shear Stress (sidewall-corrected; Pa)
Gra
vel t
rans
port
rate
[g /
(m•s
)]
6% sand34% sand
We have captured the effect of sand on gravel transport by reducing the critical shear stress for the gravel
Reducing by a factor of four increases the transport rate by much, much more
*c
11
Sand Content of Bed
0
0.01
0.02
0.03
0.04
0.05
0 0.1 0.2 0.3 0.4 0.5 0.6
(a)
rg*
Field Lab
FrameworkSupported
Matrix Supported
gDsrg
rg
)1(
*
Wilcock, P.R. and Kenworthy, S.T., 2002, A two fraction model for the transport of sand/gravel mixtures, Water Resources Research, 38(10).
Wilcock, P.R., Kenworthy, S.T. and Crowe, J.C., 2001. Experimental study of the transport of mixed sand and gravel, Water Resources Research
Wilcock, P.R., 1998. Two-fraction model of initial sediment motion in gravel-bed rivers, Science 280:410-412
This changes our approach to
predicting sediment transport rates:
A fundamental parameter depends on
bed grain size
(also found in the many fraction
surface-based model)
12
Test sand effect in a sediment feed flumeFeed gravel (2-32 mm) at same rate in each run;Increase sand feed rate from much less to much more than gravel
ResultsAs sand feed increases, bed gets sandier & slope decreases:less stress required to carry same gravel load &increased sand load
0
200
400
600
800
0 200 400 600 800
Gravel Feed RateSand Feed Rate
0.02
0.025
0.03
0 200 400 600 800
Bed Slope
Total Feed Rate (g/ms)
00.20.40.60.8
1
0 200 400 600 800
FeedBed Surface
13
Pay attention to this slide
The point?
Adding sand can have a huge effect on gravel transport ratesmost of this is captured in a changed critical Shields Number
There are a number of ways to increase sand supply to a gravel-bed riverfire, urbanization, reservoir flushing, dam removal
A two fraction approach captures this effect in a tractable framework
0
0.01
0.02
0.03
0.04
0.05
0 0.1 0.2 0.3 0.4 0.5 0.6
rg*
Sand Content of Bed 14
Step 1 Determine design bed‐material gradation/channel boundary.
Step 2 Determine preliminary width.
Step 3 Estimate critical shear stress/velocity.
Step 4 Determine flow resistance (Manning’s n).
Step 5 Calculate depth and slope.
Step 6 Determine planform.
Step 7 Assess for failure and sediment impact.
*0 c 50 84
*50
1/6lim
2/523/5
1
2
Given , , , and ,find , , , and from
( -1)
0.1129
1.16 2.03log84
2 1
2 1
c
c c
o nn
o n
o
o
c
Q B D Dn R U S
s gD
RnR
D
B h mnQhB mhS
h B mhARP B h m
QUA
Sgh
5/3
2/32
2 2
Finding Normal Depth - Trapezoidal Channel
( )Manning's eqn:
2 1
where
2 , , 2 1Finding , , or is easy; to find requires iteration
Try Mann
o
o
o o o o
h B mhSQn
B h m
B B mh A B h mh h B mh P B h mn Q S h
2/523/5
1
2 1ing arranged as
where and 1 subscripts indicate successive approximations
o nn
o n
B h mnQh
B mhSn n
h
Bomh
m
1
mh
*Given discharge , grain size ,
critical Shields Number ,Limerinos roughness &trapezoidal channel shape,find slope producing incipient motion.
c
Q D
S
18
0
0.002
0.004
0.006
0.008
0.01
0.012
0.014
0
0.2
0.4
0.6
0.8
1
1.2
1.4
0 5 10 15 20 25
SlopeDep
th (m
)
Bottom Width (m)
Depth Slope
*
Given discharge , grain size , Limerinos roughness & trapezoidal channel shape,find slope producing incipient motion.
Specify 12.5 m and 0.047,solution is 0.0064 with depth 0.54 m
c
Q DS
BS h
Sv
* 0.047c
19
0
0.002
0.004
0.006
0.008
0.01
0.012
0.014
0
0.2
0.4
0.6
0.8
1
1.2
1.4
0 5 10 15 20 25
SlopeDe
pth (m
)
Bottom Width (m)
DepthD = 32 mm, t* = 0.03SlopeD = 32 mm, t* = 0.03
*
*
Other values of , , and could be chosen
Changing 0.047 0.030 and 45 mm 32 mmc
c
n D
D
6( 1)
1 10/77 *( 1)
bb
cc
aQS s Dn
Sv
Calculated slope 3x bigger! = RISK
20
StrategyWhat is probability of failure? What probability are you willing to accept?
( ) ( ) ( )Choose width, slope combination to match acceptable risk.For example, for a 25yr and a cha
D D c
D
P failure P Q P Q Q
Q
nnel design with 10% failure probability,( ) ( ) ( ) (0.04)(0.1) 0.004
giving a 0.4% chance of failure in any year.D D cP failure P Q P Q Q
Qc
Streambed Armoring
0
5
10
15
20
25
30
35
40
45
50
0-1 1-2 2-3 3-4 4-5 5-6 6-7 7-8 8-9 9-10
10-11
11-12
12-13
13-14
14-15
15-16
Armor Ratio
Freq
uenc
y
Mean: 2.80Std. Deviation: 2.06
Median: 2.16
Stream‐bed armoring is pervasive in gravel‐bed steams
Bed surface • grains available for transportcomposition • hydraulic roughnessdetermines: • bed permeability
• living conditions for bugs & fish
Armor Ratio =
D50 (surface) D50 (subsurface)
The armor problem
• We can measure the bed surface size at low flow, but not at flows moving sediment
• We don’t know what the bed surface looks like at the flows that create it
• Does the armor layer stay or goduring floods?
Q
Q
Qs
Q
Q Qs
Qs
Bed S f
Transport
Bed
Transport
D50
0
0.5
1
D50
Transport D50Surface D50
Flow, Transport Rate Flow, Transport RateFlow, Transport Rate
Sediment FeedSediment
Recirculation Both Cases
Mobility – driven armoring
Zero divergenceKinematic sorting
Flume studies do notresolve the issue
%
Grain Size
Q
To address the armor problem, we first tackle the transport problem
• Transport rates depend on transport of grains available for transport on bed surface
• But nearly all transport data provide composition of the bed subsurface, not surface!
• This means that the resulting transport models must somehow implicitly account for surface sorting (armoring)
Transport Modeling Basics ‐ 1
)sed , , , ,( miibi DDffnq
sed),/,(
),(
2
1
mimri
rii
bi
DDDfn
fnf
q
Given fully rough flow with boundary stress ,sediment of mean size Dm, with individual fractions of size Di and proportion fi. Transport rate qbi depends on
where sed = other sediment properties. We search a transport model of form
But, what size distribution should we use for fi ?
ans: surface
where ri is a reference value of near the onset of sediment motion
There were essentially no surface‐based transport observations, so we made some
• 5 sediments, add sand to gravel
• Sand: 0.5 – 2.0 mm• Gravel: 2.0 – 64 mm• Sand Content:
6, 14, 21, 27, & 34%• 9 or 10 runs with each
sediment, wide range of transport rates
• Depth & width held constant, primary variables are sand content & flow strength
0
5
10
15
0
5
10
15
y
0
5
10
15
y
0
5
10
15
J06
J14
J21
J27
BOMC
0
5
10
15
64.0
32.0
16.08.0
4.0
2.0
0.7
0.4
0.2
BOMC
0.25 0.5 421 8 16 32
Grain Size (mm)
SandGravel%
%
%
%
%
Transport Modeling Basics ‐ 2
),(1 rii
bi fnFq
To develop a general transport model, we nondimensionalize
in the form of a similarity collapse
rii fnW
3*
where 2/3
*
/)1(i
bii
FgqsW
gr. spec. sed density; water
gravity; ;proportion surface
s
gFi
The Point:The transport function does not contain grain size!
Building a surface‐based transport model
0.0001
0.001
0.01
0.1
1
10
1 10 100
0.711.191.682.383.364.766.739.5113.519.026.938.153.8treftr fn
(Pa)
*iW
0.0001
0.001
0.01
0.1
1
10
0.1 1 10 ri
*iW
*rW
Sediment = J14 Sediment = J14
*rW
Surface‐Based Transport Model
All sizes,All runs,
All sediments
0.00001
0.0001
0.001
0.01
0.1
1
10
0.1 1 10 100
*iW
ri /
Values of ri for all sizes and all sediments
0.1
1
10
100
0.1 1 10 100
J06 J14J21 J27BOMC ShieldsSurface Dm
Grain Size (mm) Di
r i
Values of ri collapse nicely when divided by values at the mean size Dsm
0.1
1
10
0.01 0.1 1 10 100
J06J14J21J27BOMCA 'hiding' function
r i rsm
D i D sm
Relative size effect weaker for larger sizes(absolute size effect makes ri increase with Di)
Wilcock, P.R. & Crowe, J.C., J. Hydr. Eng., 2003
It remains to explain rm …
Sand Interaction Function
The sand interaction function completes the surface‐based transport model
Surface‐based transport model can be used in both forward & inverse forms
• Forward: predict transport rate & grain sizeas function of and bed surface grain size
• Inverse: predict and bed surface grain sizeas function of transport rate & grain size
The inversemodel provides a useful tool for considering armor persistence – because we do have good transport data from the field
Don’t try this with a subsurface –based model!
To the field!
Transport grain size increases with flow!
iSBTM not only predicts a persistent armor layer, it also predicts the surface grain size observed in the field!
0
1020
30
4050
60
70
8090
100
0.1 1 10 100 1000
0.00025 0.000250.0013 0.00130.0042 0.00420.0072 0.00720.033 0.0330.11 0.11Surface
Grain Size (mm)
Perc
ent F
iner
Oak Ck, ORGrain size of transport (measured) and bed surface (calculated)
Transport Rate (kg/ms)(a)
1
10
100
0.0001 0.001 0.01 0.1 1
Surface D50Transport D50
(b)
Transport Rate (kg/ms)
Med
ian
Gra
in S
ize
(mm
)
Solid symbols: predicted surface grain size
Again, transport grain size increases with flow!
Again, iSBTM predicts a persistent armor layer. This time it overpredicts the surface grain size observed in the field!
Reason: dunes!
0102030405060708090
100
0.1 1 10 100
0.002 0.0020.011 0.0110.056 0.0560.185 0.1850.706 0.706SURF
Grain Size (mm)Pe
rcen
t Fin
er
Goodwin Ck MSGrain size of transport
(measured) and bed surface (calculated)
(a) Transport Rate (kg/ms)
0.1
1
10
100
0.001 0.01 0.1 1
Surface D50Transport D50
(b)
Transport Rate (kg/ms)
Med
ian
Gra
in S
ize
(mm
)
Solid symbols: predicted surface grain size
At “reach” and “storm” scales of space and time
• Armor layer grain size appears to be persistent – a real advantage for predicting roughness & transport during floods: a low flow measurement of bed composition may suffice (unless dunes develop)
Increasing transport grain size balances change in grain mobility to produce a constant bed surfaceA SBTM needed to model transients
(III) Sediment Transport in Alluvial Channel Design – reconnaissance,
planning, and design phases
41
Connecting sediment supply to the design problem1. Reconnaissance phase: What is the trajectory of the stream? How has it
responded to changes in water and sediment supply over the years? {Henderson relation mixed‐size seds}
2. Develop flood series, specify flood frequency Qbf.{Select Qbf for flood frequency specified to maintain riparian ecosystem & prevent vegetation encroachment}
3. Estimate sediment supply
4. Planning phase: What slope S is needed to carry the sediment supply with the available flow? {How does S vary with Qs and width b?}
5. Develop flow duration curve
6. Design phase: Evaluate trial designs. Will the sediment supply be routed through the reach over the flow duration curve?{Build 1‐d hydraulic model for trial design. Calculate cumulative transport over flow duration curve at each section; evaluate sediment continuity.}
Lane/Borland “Stable Channel” Balance (USBR 1955‐1960)
Sediment Supply Transport Capacity
This defines the controls for an alluvial channel
Reconnaissance
3
33/ 2
3/ 2
3 23
3/ 2
2 2
3/ 2
3/ 4
3/ 422 2 1
1 1 1 2
Einstein-Brown depth-slope continuity Chezy
* ( *)
( )
or
or for two cases
b
b
b
b
b
b
q RS q UR U RS
q q R SDRS qq R
SDq SqDq D
Sq
qS D qS q D q
The Lane Balance, quantified almost 40 yrs agoby Henderson (1966, Open Channel Flow)
What if qb increases and D decreases? Lane’s balance is indeterminate.
Reconnaissance
Pay attention to this slide
Surface‐based transport model can be used in both forward & inverse forms
• Forward: predict transport rate & grain sizeas function of and bed surface grain size
• Inverse: predict and bed surface grain sizeas function of transport rate & grain size
Don’t try this with a subsurface –based model!
We can use an inverse transport model to forecast, or design, a steady state channel that will transport a specified sediment supply rate and grain size with the available flow (!)
1. State Diagram I –transport v. discharge, lines of constant slope
2. State Diagram II –transport v. slope, lines of constant discharge
3. Channel Stability Diagram
Presenting ….
iSURF
• Inverse Model: predict and bed surface grain size as fn(transport rate & grain size)
• Specify discharge and basic channel geometry and solve for slope (& depth)
• Conservation RelationsWater Mass Momentum
• Constitutive RelationsRoughness relationSediment transport Flow resistance 2 / 3SU h
n
q UhghS
"Given": , , , , ,"Find": , , , , ,
t i s
i
q q p gU h S F n
gives , iiSBTM F
Stream State Diagrams
( )in f F
*3/ 2( 1)
tt
s
qqs gD
*3/ 2( 1)
ww
s
qqs gD
: Surface grain size: Transport grain size
i
i
Fp
We are working per unit width …The iSBTM routine calculates bed shear stress and bed surface grain size for a specified transport rate and transport grain size. Each transport rate and grain size and, therefore, shear stress and bed surface grain size, can be produced by different combinations of unit discharge q and slope S. The state diagrams present families of curves giving either transport rate and water discharge for specified values of S, or transport rate and S for specified values of water discharge.
Reconnaissance
0.01
0.1
1
10
100
0.01 0.1 1 10 100
Sedi
men
t Tra
nspo
rt R
ate
per u
nit w
idth
qT
(kg/
m/s
)
Water Discharge per unit width qW (m2/s)
S=0.001
S=0.002
S=0.005
S=0.01
S=0.02
S=0.05
G1=25.07,G2=25.07
G1=16.85,G2=16.85
G1=2.79,G2=2.79
Lines of constant slope
0.001
0.01
0.1
0.01 0.1 1 10 100
qw=0.10 m^2/s
qw=0.32
qw=1.0
qw=3.2
qw=10.0
G1=25.07,G2=25.07
G1=16.85,G2=16.85
G1=2.79,G2=2.79
Lines of constant unit water discharge
Slop
e
Sediment transport Rate per unit width qT (kg/m/s)
High slope
Low slope
Less armored
More armored
Less armoredMore armored
High flow
Low flow
Reconnaissance
GivenWater discharge and sediment supply
Findchannel
slope, depth & width(& velocity & shear)
We have enough general relations to solve for all but one of these unknown variables
If we specify channel width, we can solve for the rest of the variables
What slope is needed to transport the supplied sediment with the available water?
How big the channel?Planning
Hydraulic Design of Stream Restoration Projects September 2001RR Copeland, DN McComas, CR Thorne, PJ Soar, MM Jonas, JB Fripp
For a specified supply of water and sediment, what is the slope needed to transport the supplied sediment
with the available flow?Planning
Sometimes, sediment supply does not matter
Sometimes, it does
1
10
100
1000
1 10 100 1000 10000
AlbertaBritain IIdahoColorado RBritain IIMarylandTuscany
Bankfull Discharge (cms)
Ban
kful
l with
(m)
So, there must be a boundary between cases where sediment supply matters or not
Threshold AlluvialBed & banks immobile Active transport
Easier to model & designBed & banks must only be
strong enough
Harder to designRequires a balance
between transport capacity & sediment supply
Extend Threshold definition to include small sediment supply rates requiring a
slope negligibly larger than the zero supply case
Focus on cases in which slope is sensitive to supply
Nothing new under the sun … see SCS in the ’30s
Why we can ‘neglect’ small sediment supply rates
1. Small sediment supply rates many storms (and many decades) req’d to produce significant aggradation and degradation.
2. Small sediment supply rates channel morphology and slope required to transport the supplied sediment can be negligibly larger than that of a threshold channel.
So, what is a SMALL sediment supply rate?That sounds dangerously like a real question, so first, lets deal with real sediments, which contain a mixture of sizes
But for mixed‐size sediment, there are complications … • Grain size of bed grain size of transport • Bed is sorted spatially and vertically• Transport is a function of the changing population of grains on
the bed surface
iSURF Channel Stability Diagramwhat slope is needed to transport a specified sediment supply of specified size distribution with a specified discharge?
Find velocity, boundary stress, depth, slope, and bed surface grain size fromcontinuity, momentum, flow resistance, and the Wilcock‐Crowe Surface‐Based Mixed‐Size Sediment Transport Model
hm
1
b
Channel Stability Diagram
As a bonus, you find out how armored the bed becomes !
0
0.001
0.002
0.003
0.004
0.005
0.006
0.007
5 10 15 20 2500.20.40.60.811.21.41.61.8
Slope Case 1 Slope Case 2Depth Case 1 Depth Case 2
Channel Width (m)
Slo
pe
Depth (m
)
Discharge 1 = 17.0 Discharge 2 = 17.0
Sed Supply 1 = 954 kg/hr
Sed Supply 2 = 95 kg/hr
0
0.005
0.01
0.015
0.02
0.025
0.03
1 10 100 1,000 10,000 100,000 1,000,000
Case 1Case 2Your sediment supply
Sediment Supply Rate (kg/hr)
Slo
pe
Discharge 1 = 17.0 cms
Discharge 2 = 17.0 cms
b = 14.0 m
0
20
40
60
80
100
0.1 1 10 100 1000Grain Size (mm)
Case 1 TransportCase 2 TransportCase 1 Bed SurfaceCase 2 Bed Surface
% F
iner
b = 14.0 m
And get a measure of where you are relative to the threshold/alluvial channel boundary !
Planning
0
0.001
0.002
0.003
0.004
0.005
0.006
0.007
1 10 100 1,000 10,000 100,000 1,000,000
Q = 70.8 cms
Your sediment supply
Sediment Supply Rate (kg/hr)
Slo
peb = 19.0 m
If your sediment supply is safely below the boundary between “low” slope and “high” slope, channel slope is relatively insensitive to sediment supply – you are less likely to accumulate sediment given an error in estimating sediment supply
threshold
Is an accurate sediment supply estimate needed?
Threshold Design Approach Just make the channel strong enough to stand up to high flows
1. Reconnaissance phase: What is the trajectory of the stream? How has it responded to changes in water and sediment supply over the years?
2. Develop flood series, specify flood frequency Design Q.{Select Qbf for flood frequency specified to maintain riparian ecosystem & prevent vegetation encroachment}
3. Estimate sediment supply
4. Planning phase: What slope S will transportthe sediment supply with the available Qbf? Calculate (b, S) combination {S and valley slope determine sinuosity}
Check if alluvial v. threshold channel
5. Develop flow duration curve
6. Design phase: Evaluate trial designs. Will the sediment supply be routed through the reach over the flow duration curve?{Build 1‐d hydraulic model for trial design. Calculate cumulative transport over flow duration curve at each section; evaluate sediment continuity.}
7. Bottlenecks or blowouts? Adjust for sediment continuity
3/ 422 2 1
1 1 1 2bb
qS D qS q D q
0
0.002
0.004
0.006
0.008
0.01
0.012
0 5 10 15 200
0.5
1
1.5
2
2.5
3
3.5
Slope Case 1 Slope Case 2Depth Case 1 Depth Case 2
Channel Width (m)
Slop
e Depth (m
)
Discharge 1 = 15.0
Discharge 2 = 25.0
Sed Supply 1 = 954 kg/hr
Sed Supply 2 = 2862 kg/hr
0
0.005
0.01
0.015
0.02
0.025
1 10 100 1,000 10,000 100,000 1,000,000
Case 1Case 2Your sediment supply
Sediment Supply Rate (kg/hr)
Slo
pe
Discharge 1 = 15.0 cms
Discharge 2 = 25.0 cms
b = 11.0 m
Design steps incorporating sediment supply
iSURF State Diagrams
Some Design DetailStep-backwater model gives S(Q), U(Q) at each section
Grain stress:
Calculate transport over the flow dur. curve at each section
Adjust x/s transport for lateral variation in
Query potential bottlenecks, blowoutstransport < capacity?flow model reliable?erosion/deposition desirable?
Adjust channel dimensions & shapeto match supply, within tolerance level & design objectives.
1/ 4 3/ 265' 17 SD U
Use transport modeling to:i. Evaluate design, esp. Qs from section to sectionii. Determine if more accurate transport modeling is needed
0.0010.010.1
110
1001000
10000100000
1000000
24 26 28 30 32 34 36 38 40 42 44
Cum Qb * lateral correction (skn)
Section
Tran
spor
t (M
tons
)
Q = 1600 cfs
3/ 2' D
onn
Design
(70.8 m3/s)
(6.7 m)
1. Supply reachEstimate sediment transport rate
2. Design reachGiven discharge and sediment supply rate and grain size, calculate slope needed to transport supplied sediment at a specified channel width
Design
NEH-654 Chapter 9 Example 2, p. 39Given geometry of a trapezoid channel w/specified bed material and side roughness,find boundary and grain stresses
Q 70.79 cmsS 0.0025
D50 3.7 mmD84 22 mmm 1.6nD 0.022ns 0.07
Bo nc h B A R U o ' u*'m composite n m m m^2 m m/s Pa Pa m/s
6.71 0.0369 2.97 16.2 34.0 1.90 2.08 46.6 21.1 0.145total Grain Grain
Bo nc h B A R U boundary stress stressft ft ft ft^2 ft ft/s stress as a shear
22.0 0.0369 9.74 53.2 366.3 6.23 6.83 velocity
Enter information only in green cells!!No cutting and pasting!
No inserting or deleting rows!
F
M
w
F
T
B
w
1. Find stress in upstream “supply” channel
SBTM - calculate transport rate and transport grain size fromspecified shear velocity and bed surface grain size
RULES, CONVENTIONS, AND UNITS1. Cells for input data are highlighted in GREEN, cells for output data are ORANGE2. Grain-diameters must be in millimeters (mm)3. Cumulative percentiles, not fractions, are used4. Cumulative grain-size distribution percentiles must span from 0 to 100 %5. Shear velocity must be in meters-per-second (m/s)6. The 0 and 100 % must be EXACTLY 0 and 100INSTRUCTIONS1. In table below, enter grain size and cumulative % in order of decreasing grain size2. Enter your bed shear velocity3. Check input for errors, press Enter , and then click once on the Run SBTM button
Parameter Value Description Unitsu* 1.45E-01 Bed shear velocity m/sqT 8.17E-04 Total transport rate m2/s
D (mm) Surface CDF GSD (% Finer) Transport CDF GSD (% Finer)64.00 100.00 100.0032.00 93.00 98.8616.00 77.00 93.038.00 65.00 84.944.00 53.00 72.392.00 45.00 62.511.00 35.00 49.350.50 20.00 28.820.25 10.00 14.650.13 0.00 0.00
2. Find transport rate in upstream “supply” channel
Parameter Value Description UnitsQ 1 70.8 Case 1 water discharge m3/s
Q T1 0.005478475 Case 1 sediment supply rate m3/s
Q 2 70.8 Case 2 water discharge m3/s
Q T2 0.01095695 Case 2 sediment supply rate m3/s
b min 3.00 Minimum bottom width mb max 35.00 Maximum bottom width m
D (mm) Case 1 Transport Grain Size (% Finer)
Case 2 Transport Grain Size (% Finer)
64.00 100.00 100.0032.00 98.86 98.8616.00 93.03 93.038.00 84.94 84.944.00 72.39 72.392.00 62.51 62.511.00 49.35 49.350.50 28.82 28.820.25 14.65 14.650.13 0.00 0.00
3. Enter transport rate and grain size from upstream “supply” channel as input to the channel stability code
0.001
0.0015
0.002
0.0025
0.003
0.0035
0.004
0 5 10 15 20 25 30 35
Slope Case 1 Slope Case 2 NRCS
Channel Width (m)
Slo
pe
Discharge 1 = 70.8 cms
Discharge 2 = 70.8 cms
Sed Supply 1 = 52265 kg/hr
Sed Supply 2 = 165275 kg/hr
Sv
iSURF (Wilcock&Crowe) solutionincluding case with 3x sediment supply
Potential Degradation
Potential Aggradation
0
0.001
0.002
0.003
0.004
0.005
0.006
0.007
1 10 100 1,000 10,000 100,000 1,000,000
Q = 70.8 cms
Your sediment supply
Sediment Supply Rate (kg/hr)
Slo
peb = 19.0 m
For this design problem, slope is very sensitive to sediment supply rate
(because it is large)
iSURF design module provides this plot of slope vs. sediment supply rate
A simple example of all three channel types
h
Bomh
2
1
mh 3 3
50
100 m /s {160 m /s}20 t/hr {60 t/hr}
Supply 13 mm (0.5 mm - 128 mm)s
D
3
50
84
*
100 m /s64 mm128 mm 10%
0.04 10%
0.03 10%c
QDDn
Pay attention to the next four slides!
0
0.6
1.2
1.8
2.4
3
3.6
0
0.001
0.002
0.003
0.004
0.005
0.006
0.007
10 20 30 40 50
Bottom Width (m)
Slop
e
Channel D
epth (m)
Slope
Depth
h
Bomh
2
1
mh 3
50
84
*
100 m /s64 mm128 mm 10%
0.04 10%
0.03 10%c
QDDn
Failure in a threshold channel = grain entrainment
h
Bomh
2
1
mh 3 3
50
100 m /s {160 m /s}20 t/hr {60 t/hr}
Supply 13 mm (0.5 mm - 128 mm)s
D
Mobile channel design = match transport capacity to sediment supply
0
0.001
0.002
0.003
0.004
0.005
0.006
10 20 30 40 50
Bottom Width (m)
Threshold Slope
Alluvial 100/20
Alluvial 160/60Sl
ope
h
Bomh
2
1
mh 3 3
50
100 m /s {160 m /s}20 t/hr {60 t/hr}
Supply 13 mm (0.5 mm - 128 mm)s
D
3
50
84
*
100 m /s64 mm128 mm 10%
0.04 10%
0.03 10%c
QDDn
Over‐capacity Threshold: combine threshold and alluvial
0
0.001
0.002
0.003
0.004
0.005
10 20 30 40 50
Bottom Width (m)
Threshold Channel
Alluvial Balance
Slop
e
Bottom Line:specify a width, a channel and its bed material, and a water & sediment supplyCritical Shields Number gives threshold channel slopeTransport Model gives alluvial channel slopeRange of widths gives indication of adjustments with respect to bed material transport
0
0.001
0.002
0.003
0.004
0.005
10 20 30 40 50
Bottom Width (m)
Threshold Channel
Alluvial Balance
Slop
e
0
0.001
0.002
0.003
0.004
0.005
10 20 30 40 50
Bottom Width (m)
Threshold Channel
Alluvial Balance
Slop
e
EvacuateAccumulate
0
0.001
0.002
0.003
0.004
0.005
10 20 30 40 50
Bottom Width (m)
Threshold Channel
Alluvial Balance
Slop
eDischarge
Rate of Sediment Supply
Grain Size of Sediment Supply
But the watershed, and the water and sediment supply may also be changingaka ‘moving the goalposts’
Arrows indicate response to an INCREASE in each driving variable
Strategy(i) Determine if the sediment supply is a big number or a little number
(a) if big, invest in more accurate estimate of sediment supplybe prepared for a dynamic channel reserve riparian corridor and let the stream go
or plan to trap and remove sediment(b) if little, design a threshold channel
(ii) Estimate uncertainty and account for the consequencesesp. potential for aggradation, degradation
0
0.001
0.002
0.003
0.004
0.005
0.006
0.007
1 10 100 1,000 10,000 100,000 1,000,000
Q = 70.8 cms
Your sediment supply
Sediment Supply Rate (kg/hr)
Slo
pe
b = 19.0 m
OR, Make your channel(i) steep enough: transport capacity
exceeds supply and(ii) strong enough: bed material immobile
… an overcapacity threshold channel
Design Basis: Flow Competence
Competence & Capacity
Transport Capacity
Channel Type Threshold Channel
Overcapacity Threshold
Alluvial Channel
Topography & Bed Material
Static Static Dynamic
Pipe‐like channels: an increasingly common & safe design option,may provide acceptable aesthetics.
Does not provide anything like native structure & function
Assess magnitude of sediment supply
“small” “large”
Threshold channel design
Use risk assessment and P(failure) to guide design
Alluvial channel design
Allow for dynamic stream
Invest in improved sediment estimate
Overcapacity channel design
Objectivesediment & nutrients
property & infrastructurebiological recovery
aesthetics, recreationpenance
Whatneeds
fixing?
Stormwater control
Nothing
Channel change
Introduced species Disturbance Internal orexternal?
InternalExternal
Fence out the cows!Remove the concrete!
Template approachcan work
Channel DesignSediment Objectives
Is Sediment Supply Large or Small?
Estimate flood frequency
Design threshold channel
Estimate sediment supply & flow
durationDesign alluvial
channel
Alluvial, Threshold, or Overcapacity Threshold Channel?
…
Sediment Transport in Channel DesignE
nvir
onm
enta
l D
rive
rs
Design Threshold AND
Alluvial Channel
We can go beyond equilibrium channel design by Specifying desired channel behavior and
incorporating sediment transport with uncertainty, Which allows calculation of risk of undesirable behaviorwhile accommodating “typical” channel dimensions
Channel DesignSpecified
equilibrium dimensions
Specified channel behavior
Account for uncertainty & riskAccommodate typical dimensions
0.01
0.1
1
10
100
1000
100 1000 10000
White BridgeRiver RDMidwayCasperville
Discharge (cfs)
Tran
spor
t Rat
e (to
ns/d
ay)
Does not include transport samples <1g for the 2-16mm size class
2-16 mm
1
10
100
1000
100 1000 10000
River RDMidwayCasperville
Discharge (cfs)
Tran
spor
t Rat
e (to
ns/d
ay)
Does not include transport samples <200g for the >16mm size classNo meaasured transport in this size range at White Bridge
> 16 mm
Transport Observations by BioWest Inc.
iSURF Channel Stability Diagram for 1200 cfs and 1800 cfs flowsCHANNEL STABILITY DIAGRAM FOR GRAVEL-BED RIVERS - INPUT WORKSHEET For the input entered below, here are max and min values of RULES, CONVENTIONS, AND UNITS water discharge per unit width1. Cells for input data are highlighted in GREEN Maximum q Minimum q2. Grain-diameters must be in millimeters (mm) 4.25 m 2̂/s 0.68 m 2̂/s Case 13. Cumulative percentiles, not fractions, are used 6.38 m 2̂/s 1.02 m 2̂/s Case 24. Cumulative grain-size distribution percentiles must span from 0 to 100 %5. The 0 and 100 % must be EXACTLY 0 and 100 For the input entered below, here are max and min values of INSTRUCTIONS sediment transport rate per unit width1. In first table below, enter water discharge and sediment supply rate in units of m3/s Maximum qs Minimum qs
and the minimum and maximum channel widths to be evaluated 0.00 kg/m/s 0.00 kg/m/s Case 12. In second table below, enter grain size and cumulative % in order of decreasing grain size 0.48 kg/m/s 0.08 kg/m/s Case 23. In cells to right, enter side slope angle z and side slope roughness ns4. Check input for errors and then click once on the Run STAB button this cell intentionally left blank5. Results appear on Worksheet "STAB OUTPUT"Parameter Value Description Units Parameter Value Description Units
Q 1 34 Case 1 water discharge m3/s z 1 side slope z:1 H:V 0Q T1 0.00000397 Case 1 sediment supply rate m3/s ns 0.08 side slope roughness #&%@$Q 2 51 Case 2 water discharge m3/s
Q T2 0.00145 Case 2 sediment supply rate m3/s
b min 8.00 Minimum bottom width mb max 50.00 Maximum bottom width m
D (mm) Case 1 Transport Grain Size (% Finer)
Case 2 Transport Grain Size (% Finer)
128.00 100.00 100.0090.00 99.50 98.7064.00 97.60 90.0045.00 92.00 74.30 Statistic FIRST Transport GSD SECOND Transport GSD Units32.00 73.10 53.50 Dmin 1.00 1.00 mm22.00 50.40 32.60 Dmax 128.00 128.00 mm16.00 13.30 10.80 D50 21.92 30.05 mm8.00 9.70 7.10 Dg 20.52 26.85 mm4.00 7.50 5.30 g 1.18 1.24 /-units
2.00 4.30 4.20 Fs 4.30 4.20 %1.00 0.00 0.00
0
20
40
60
80
100
0.1 1 10 100Grain Size (mm)
GSD1
GSD2
% F
iner
Input transport size distributions
hz
b
Reset: inserts some harmless data and cleans up output cells
Run STAB
Reset
Channel Stability chart developed using inverse calculation of the Wilcock & Crowe (2003) transport relation. z 1 side slope z:1 H:V ns 0.08 side slope 1. CHANNEL STABILITY DIAGRAM 2. THRESHOLD CHECK - SLOPE AS FN(SEDIMENT SUPPLY RATE) AT MEAN WI
At b=29.0m U=1.6m/s qt=0.000kg/m/s3. GRAIN-SIZE DISTRIBUTIONS At b=29.0m U=2.3m/s qt=0.133kg/m/s
0
0.5
1
1.5
2
2.5
00.0010.0020.0030.0040.0050.0060.0070.0080.0090.01
0 10 20 30 40 50 60
Slope Case 1 Slope Case 2
Depth Case 1 Depth Case 2
Channel Width (m)
Slo
pe
Depth (m
)
Discharge 1 = 34.0 cms
Discharge 2 = 51.0 cms
Sed Supply 1 = 38 kg/hr
Sed Supply 2 = 13833 kg/hr
0
0.005
0.01
0.015
0.02
0.025
0.03
1 10 100 1,000 10,000 100,000 1
Case 1
Case 2
Your sediment supply
Sediment Supply Rate (kg/hr)
Slo
pe Discharge 1 = 34.0 cms
Discharge 2 = 51.0 cms
b = 29.0 m
0
20
40
60
80
100
0.1 1 10 100Grain Size (mm)
Case 1 Transport
Case 2 Transport
Case 1 Bed Surface
Case 2 Bed Surface
% F
iner
b = 29.0 m
0.00.10.20.30.40.50.60.70.80.91.0
0
0.5
1
1.5
2
2.5
0 10 20 30 40 50 60
Armor Case 1 Armor Case 2
Froude # Case 1 Froude # Case 2
Channel Width (m)
Arm
or R
atio
Dsm
/Dtm Froude N
umber
iSURF Channel Stability Diagram for 1200 cfs and 1800 cfs flows
Fortier and Scobey (1926)
Increased Bank Velocity in Bends
1.74 0.52log
: depth-averaged velocity at 20% slope length from toe: X/S average velocity
: bend hydraulic radius: channel top width
ssavg
ss
avg
V RV W
V
V
RW
3/ 21/ 6
0
c
1. Calculate total stress (use RAS if flow non-uniform)
2. Calculate grain stress ' using
' and 0.013
for in mm3. Choose critical Shields Number4. Compare ' and
DD
n n Dn
D
Step 1 Determine design bed‐material gradation/channel boundary.
Step 2 Determine preliminary width.
Step 3 Estimate critical shear stress/velocity.
Step 4 Determine flow resistance (Manning’s n).
Step 5 Calculate depth and slope.
Step 6 Determine planform.
Step 7 Assess for failure and sediment impact.
(70.8 m3/s)
(6.7 m)
1. Supply reachEstimate sediment transport rate
2. Design reachGiven discharge and sediment supply rate and grain size, calculate slope needed to transport supplied sediment at a specified channel width
Design