SEQUENCES AND SERIESsciannamath.weebly.com/uploads/1/6/9/2/16922340/chapter_11_-_se… · sequences. Use summation notation to write series and find sums of series, as applied in

� � � � � � � �SEQUENCES ANDSERIESSEQUENCES ANDSERIES

c How is a fractal formed?

648

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649

APPLICATION: Fractals

Have you ever noticed how a

fern leaf looks like a miniature

version of the fern? When the

parts of an object are similar to

the whole object, the object is

called self-similar. A fractal is a

complex shape that basically

looks the same at different levels

of magnification and is generally

self-similar.

Think & Discuss

The diagram shows the first three stages in the growth

of a fractal plant.

1. Draw the next stage in the growth process.

2. Describe in words how the fractal plant changesfrom one stage to the next.

3. What could you do to make the fractal plant lookeven more realistic?

Learn More About It

You will find the number of branches in a fractal tree

in Exercise 45 on p. 685.

APPLICATION LINK Visit www.mcdougallittell.com

for more information about fractals.

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Stage 1 Stage 2 Stage 3

c

C H A P T E R

11

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650 Chapter 11

What’s the chapter about?

Chapter 11 is about sequences and series. In Chapter 11 you’ll learn

• how to find terms of sequences and write algebraic rules to define sequences.

• how to use summation notation and find sums of arithmetic and geometric series.

CHAPTER

11Study Guide

PREVIEW

Are you ready for the chapter?

SKILL REVIEW Do these exercises to review key skills that you’ll apply in thischapter. See the given reference page if there is something you don’t understand.

Write the given phrase as an algebraic expression. (Skills Review, p. 929)

1. 4 more than a number 2. 3 times a number 3. half of a number

Evaluate the expression. (Review Example 3, p. 12)

4. 3x º 7 when x = 3 5. }

x +x

1} when x = 8 6. 3(2)n º 1 when n = 4

Show that the nth-order finite differences for the function of degree n are

nonzero and constant. (Review Example 2, p. 380)

7. ƒ(x) = º3x2 + 3 8. ƒ(x) = x3 + 2x

2 9. ƒ(x) = x4 º 5x + 1

Solve the equation. (Review Example 3, p. 502; Example 4, p. 569)

10. 4x = 16,384 11. 2x º 1 = 32 12. 10 = }1 º

5x

} 13. 24 = }1 +

2x

}

PREPARE

Here’s a study strategy!

STUDY

STRATEGY

c Review

• integers, p. 3

• finite differences, p. 380

c New

• terms of a sequence, p. 651

• sequence, p. 651

• finite sequence, p. 651

• infinite sequence, p. 651

• series, p. 653

• summation notation, p. 653

• arithmetic sequence, p. 659

• common difference, p. 659

• arithmetic series, p. 661

• geometric sequence, p. 666

• common ratio, p. 666

• geometric series, p. 668

• explicit rule, p. 681

• recursive rule, p. 681

KEY VOCABULARY

STUDENT HELP

Study Tip“Student Help” boxesthroughout the chaptergive you study tips andtell you where to look forextra help in this bookand on the Internet.

Learn by Teaching

Explain to a teacher, friend, or family member how todo an important skill in this chapter. Show an exampleand use words to describe your steps.You can use a variation of this strategy when you arealone, too. Talk to yourself and explain your reasoningas you work toward an answer.

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11.1 An Introduction to Sequences and Series 651

An Introduction to Sequencesand Series

USING AND WRITING SEQUENCES

Saying that a collection of objects is listed “in sequence” means that the collection isordered so that it has a first member, a second member, a third member, and so on.Below are two examples of sequences of numbers. The numbers in the sequences arecalled

SEQUENCE 1: SEQUENCE 2:

3, 6, 9, 12, 15 3, 6, 9, 12, 15, . . .

You can think of a as a function whose domain is a set of consecutiveintegers. If a domain is not specified, it is understood that the domain starts with 1.

DOMAIN: 1 2 3 4 5 The domain gives the relative position of

each term: 1st, 2nd, 3rd, and so on.

RANGE: 3 6 9 12 15 The range gives the terms of the sequence.

Sequence 1 above is a because it has a last term. Sequence 2 is anbecause it continues without stopping. Both sequences have the

general rule an = 3n where an represents the nth term of the sequence. The generalrule can also be written using function notation: ƒ(n) = 3n.

Writing Terms of Sequences

Write the first six terms of the sequence.

a. an = 2n + 3 b. ƒ(n) = (º2)n º 1

SOLUTION

a. a1 = 2(1) + 3 = 5 1st term

a2 = 2(2) + 3 = 7 2nd term

a3 = 2(3) + 3 = 9 3rd term

a4 = 2(4) + 3 = 11 4th term

a5 = 2(5) + 3 = 13 5th term

a6 = 2(6) + 3 = 15 6th term

b. ƒ(1) = (º2)1 º 1 = 1 1st term

ƒ(2) = (º2)2 º 1 = º2 2nd term

ƒ(3) = (º2)3 º 1 = 4 3rd term

ƒ(4) = (º2)4 º 1 = º8 4th term

ƒ(5) = (º2)5 º 1 = 16 5th term

ƒ(6) = (º2)6 º 1 = º32 6th term

E X A M P L E 1

infinite sequence

finite sequence

sequence

terms.

GOAL 1

Use and write

sequences.

Use summation

notation to write series and

find sums of series, as

applied in Example 6.

. To model real-lifesituations, such as

building a roof frame in

Exs. 65 and 66.

Why you should learn it

GOAL 2

GOAL 1

What you should learn

11.1R

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Look Back For help with evaluatingexpressions, see p. 12.

STUDENT HELP

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652 Chapter 11 Sequences and Series

If the terms of a sequence have a recognizable pattern, then you may be able to writea rule for the nth term of the sequence.

Writing Rules for Sequences

For each sequence, describe the pattern, write the next term, and write a rule for the nth term.

a. º}13

}, }19

}, º}217}, }

811}, . . . b. 2, 6, 12, 20, . . .

SOLUTION

a. You can write the terms as Sº}13

}D1, Sº}

13

}D2, Sº}

13

}D3, Sº}

13

}D4, . . . .

The next term is a5 = Sº}13

}D5= º}

2143}. A rule for the nth term is an = Sº}

13

}Dn.

b. You can write the terms as 1(2), 2(3), 3(4), 4(5), . . . .

The next term is ƒ(5) = 5(6) = 30. A rule for the nth term is ƒ(n) = n(n + 1).

. . . . . . . . . .

You can graph a sequence by letting the horizontal axis represent the positionnumbers (the domain) and the vertical axis represent the terms (the range).

Graphing a Sequence

You work in the produce department of agrocery store and are stacking oranges in theshape of a square pyramid with 10 layers.

a. Write a rule for the number of oranges in each layer.

b. Graph the sequence.

SOLUTION

a. The diagram below shows the first three layers of the stack. Let anrepresent the number of oranges in layer n.

From the diagram, you can see that an = n2.

b. Plot the points (1, 1), (2, 4), (3, 9), . . . , (10, 100). The graph is shown at the right.

E X A M P L E 3

E X A M P L E 2

STUDENT HELP

Study TipIf you are given only thefirst several terms of asequence, there is nosingle rule for the n thterm. For instance, thesequence 2, 4, 8, . . . canbe given by an = 2n or an = n2 º n + 2.

STUDENT HELP

Study TipAlthough the plottedpoints in part (b) ofExample 3 follow acurve, do not draw thecurve because thesequence is defined onlyfor integer values of n.

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Retail Displays

� ��

Layer number

Nu

mb

er

in l

aye

r � �� n 1 2 3

an 1 = 12 4 = 22 9 = 32

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USING SERIES

When the terms of a sequence are added, the resulting expression is a A series can be infinite or finite.

FINITE SEQUENCE INFINITE SEQUENCE

3, 6, 9, 12, 15 3, 6, 9, 12, 15, . . .

FINITE SERIES INFINITE SERIES

3 + 6 + 9 + 12 + 15 3 + 6 + 9 + 12 + 15 + . . .

You can use to write a series. For example, for the finite seriesshown above, you can write

3 + 6 + 9 + 12 + 15 = ∑5

i = 13i

where i is the index of summation, 1 is the lower limit of summation, and 5 is theupper limit of summation. In this case the summation notation is read as “the sumfrom i equals 1 to 5 of 3i.” Summation notation is also called because it uses the uppercase Greek letter sigma, written S.

Summation notation for an infinite series is similar to that for a finite series. Forexample, for the infinite series shown above, you can write:

3 + 6 + 9 + 12 + 15 + . . . = ∑‡

i = 13i

The infinity symbol, ‡, indicates that the series continues without end.

Writing Series with Summation Notation

Write each series with summation notation.

a. 5 + 10 + 15 + . . . + 100 b. }12

} + }23

} + }34

} + }45

} + . . .

SOLUTION

a. Notice that the first term is 5(1), the second is 5(2), the third is 5(3), and the lastis 5(20). So, the terms of the series can be written as:

ai = 5i where i = 1, 2, 3, . . . , 20

c The summation notation for the series is ∑20

i = 15i.

b. Notice that for each term the denominator of the fraction is 1 more than thenumerator. So, the terms of the series can be written as:

ai = }i +

i1

} where i = 1, 2, 3, 4, . . .

c The summation notation for the series is ∑‡

i = 1}i +

i1

}.

. . . . . . . . . .

The index of summation does not have to be i — any letter can be used. Also, theindex does not have to begin at 1. For instance, in part (b) of Example 5 on the nextpage, the index begins at 3.

E X A M P L E 4

sigma notation

summation notation

series.

GOAL 2

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Using Summation Notation

Find the sum of the series.

a. ∑6

i = 12i = 2(1) + 2(2) + 2(3) + 2(4) + 2(5) + 2(6)

= 2(1 + 2 + 3 + 4 + 5 + 6)

= 2(21)

= 42

b. ∑6

k = 3(2 + k2) = (2 + 32) + (2 + 42) + (2 + 52) + (2 + 62)

= 11 + 18 + 27 + 38

= 94

. . . . . . . . . .

The sum of the terms of a finite sequence can be found by simply adding the terms.For sequences with many terms, however, adding the terms can be tedious. Formulasfor finding the sum of the terms of three special types of sequences are given below.

Using a Formula for a Sum

RETAIL DISPLAYS How many oranges are in the stack in Example 3?

SOLUTION

From Example 3 you know that the ith term of the series is given by ai = i2, where i = 1, 2, 3, . . . , 10. Using summation notation and the third formula listed above,you can find the total number of oranges as follows.

∑10

i = 1i2 = 12 + 22 + . . . + 102

=

= }10(11

6

)(21)}

= 385

c There are 385 oranges in the stack. Check this by actually adding the number of

oranges in each of the ten layers.

10(10 + 1)(2 • 10 + 1)}}}

6

E X A M P L E 6

E X A M P L E 5

THOMAS HALES,a mathematician at

the University of Michigan,proved in 1998 that thearrangement of identicalspheres illustrated inExamples 3 and 6 (usingoranges) wastes less spacethan any other arrangement.

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FOCUS ON

PEOPLE

1. ∑n

i = 1

1 = n 2. ∑n

i = 1

i = }n(n

2

+ 1)} 3. ∑

n

i = 1

i2 = }

n(n + 1)

6

(2n + 1)}

In words, the first formula gives the sum of n 1’s. The second formula gives

the sum of the positive integers from 1 to n. The third formula gives the sum

of the squares of the positive integers from 1 to n.

FORMULAS FOR SPECIAL SERIESCONCEPT

SUMMARY

STUDENT HELP

Study TipNotice that the first termin Example 5b occurswhen k = 3 (not when k = 1) and that there areonly 4 terms (not 6) in theseries.

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Vocabulary Check ✓

Concept Check ✓

Skill Check ✓

Extra Practiceto help you masterskills is on p. 955.

STUDENT HELP

STUDENT HELP

HOMEWORK HELP

Example 1: Exs. 9–20Example 2: Exs. 21–29Example 3: Exs. 30–35,

64–68Example 4: Exs. 36–43Example 5: Exs. 44–55Example 6: Exs. 56–68

GUIDED PRACTICE

1. Explain the difference between a sequence and a series.

2. Answer the following questions about the series ∑10

k = 3(k + 2).

a. In words, how do you read the summation notation?

b. What is the index of summation?

c. What is the lower limit of summation?

d. What is the upper limit of summation?


3. an = 2n 4. an = 6 º n 5. an = 3n + 1 6. ƒ(n) = 2n + 3

7. Find the sum of the series in Exercise 2.

8. STACKING Find the total number of oranges in the stack in Example 3 ifthere are 12 layers.

WRITING TERMS Write the first six terms of the sequence.

9. an = n + 1 10. an = n2 11. an = 3 º n 12. an = n3 º 1

13. an = (n + 1)2 14. an = (ºn)3 15. an = n2 + 3 16. an = (n º 1)2

17. ƒ(n) = }n +

n1

} 18. ƒ(n) = }2nn

2

} 19. ƒ(n) = }n

2+n

2} 20. ƒ(n) = }

º3n}

WRITING RULES Write the next term in the sequence. Then write a rule for

the nth term.

21. 1, 3, 5, 7, . . . 22. 1, 10, 100, 1000, . . . 23. 2, º4, 8, º10, 14, . . .

24. º5, 10, º15, 20, . . . 25. º}12

}, º}14

}, º}16

}, º}18

}, . . . 26. }14

}, }25

}, }36

}, }47

}, }58

}, . . .

27. }13

}, }23

}, }33

}, }43

}, }53

}, . . . 28. }210}, }

320}, }

430}, }

540}, . . . 29. 1.9, 2.7, 3.5, 4.3, 5.1, . . .

GRAPHING SEQUENCES Graph the sequence.

30. 1, 4, 7, 10, . . . , 28 31. 3, 6, 12, 21, 33, 48 32. º1, º6, º11, º16, º21

33. 1, 4, 9, 16, 25, 36 34. }19

}, }28

}, }37

}, }46

}, . . . , }91

} 35. 3, º6, 9, º12, . . . , º36

WRITING SUMMATION NOTATION Write the series with summation notation.

36. 1 + 5 + 9 + 13 + 17 37. 4 + 8 + 12 + 16 + 20

38. º3 + 3 + 9 + 15 + 21 + . . . 39. 1 º 2 + 3 º 4 + 5 º . . .

40. º7 º 8 º 9 º 10 º 11 41. }56

} + }67

} + }78

} + }89

} + . . .

42. 1 + 0.1 + 0.01 + 0.001 43. 1 + 4 + 9 + 16 + 25 + 36

PRACTICE AND APPLICATIONS

! " # $ % & ' (


USING SUMMATION NOTATION Find the sum of the series.

44. ∑6

i = 13i 45. ∑

5

i = 012i 46. ∑

4

n = 0n2 47. ∑

3

n = 14n3

48. ∑5

k = 1(k2 º 1) 49. ∑

4

n = 0(2n2 + 1) 50. ∑

4

k = 1k(k + 2) 51. ∑

10

n = 2}2n

}

52. ∑12

n = 2}n º

11

} 53. ∑5

n = 1}n +

n1

} 54. ∑6

i = 2}i º

i1

} 55. ∑‡

n = 1S}

n

n2} º }

1n

}D

USING FORMULAS Use one of the formulas for special series to find the sum

of the series.

56. ∑42

i = 11 57. ∑

5

n = 1n 58. ∑

18

i = 1i 59. ∑

20

k = 1k

60. ∑6

n = 1n2 61. ∑

10

i = 1i2 62. ∑

12

i = 1i2 63. ∑

35

k = 1k2

64. The degree measurement dn in each angle at the tips of the six n-pointed stars shown at the right is given by:

dn =}180(n

n

º 4)}, n ≥ 5


CARPENTRY In Exercises 65 and 66, use the following information.

The diagram shows part of a roof frame. The

length (in feet) of each vertical support is given

below the support. These lengths form an

arithmetic sequence from each end to the middle.

65. Find the total length of the vertical supports from one end to the middle.

66. Use your result from Exercise 65 to find the total length of the vertical supports from end to end.

67. TOWER OF HANOI In the puzzle called the Tower of Hanoi, the object is to use a series of moves to take the rings from one peg and stack them in orderon another peg. A move consists of moving exactly one ring, and no ring may be placed on top of a smaller ring. The minimum number of moves required tomove n rings is 1 for 1 ring, 3 for 2 rings, 7 for 3 rings, 15 for 4 rings, and 31 for5 rings. Find a formula for the sequence. What is the minimum number of movesrequired to move 6 rings?

68. PYRAMID STACK Suppose you are stacking tennis balls in a pyramid as adisplay at a sports store. If the base is an equilateral triangle, then the number an

of balls per layer would be an = }12

}n2 + }12

}n where n = 1 represents the top layer.

How many balls are in the fifth layer? How many balls are in a stack with 5layers?

GEOMETRY CONNECTION

TOWER OF HANOI

The puzzle was firstdescribed in print by theFrench mathematicianEdouard Lucas in 1883 in his four volume book onrecreational mathematics.

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FOCUS ON

APPLICATIONS

5 6 7

8 9 10

HOMEWORK HELP

Visit our Web sitewww.mcdougallittell.comfor help with Exs. 56–63.

INT

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STUDENT HELP

11 2 23 34 45

) * + , - . / 0


QUANTITATIVE COMPARISON In Exercises 69 and 70, choose the statement

that is true about the given quantities.

¡A The quantity in column A is greater.

¡B The quantity in column B is greater.

¡C The two quantities are equal.

¡D The relationship cannot be determined from the given information.

69.

70.

71. LOGICAL REASONING Tell whether the statement about summation notation is true or false. If the statement is true, prove it. If the statement is false, give acounterexample.

a. ∑n

i = 1kai = k ∑

n

i = 1ai b. ∑

n

i = 1(ai + bi) = ∑

n

i = 1ai + ∑

n

i = 1bi

c. ∑n

i = 1aibi = S ∑

n

i = 1aiDS ∑

n

i = 1biD d. ∑

n

i = 1(ai)

k = S ∑n

i = 1aiDk

72. Using the true statements from Exercise 71 and the special formulas from page 654,find a formula for the number of balls in n layers of the pyramid in Exercise 68.

SOLVING EQUATIONS Solve the equation. Check your solution.

(Review 1.3 for 11.2)

73. 17 = 3x + 5 74. 18 = º7 + x 75. 15 = º1 + 8x

76. 9 = 4 º 5x 77. 5 = 6 º 2x 78. 24 = 10 + 7x

FINDING EXPONENTIAL MODELS Use the table of values to draw a scatter

plot of ln y versus x. Then find an exponential model for the data. (Review 8.7)

79.

80.

FINDING THE DISTANCE Find the distance between the points. (Review 10.1)

81. (0, 0), (º4, º6) 82. (1, 4), (º3, º9) 83. (5, 2), (º1, 8)

84. (9, º1), (2, 9) 85. (3, º3), (11, º4) 86. (10, 30), (40, º20)

MIXED REVIEW

TestPreparation

★★Challenge

x 1 2 3 4 5 6 7 8 9

y 5 10 20 40 80 160 320 640 1280

x 1 2 3 4 5 6 7 8

y 3.2 9.6 28.8 86.4 259.2 777.6 2332.8 6998.4

Column A Column B

The fifth term of the sequence an = n2 + 1 ∑5

n = 1(n2 + 1)

The first term of the sequence an = 5 º n ∑8

n = 4(5 º n)

EXTRA CHALLENGE

www.mcdougallittell.com

) * + , - . / 0Working with Sequences

You can use a graphing calculator to find the terms of a sequence, graph a

sequence, and find the sum of a series.

c EXAMPLE

Use a graphing calculator to perform the following.

• Find the first eight terms of the sequence an = 3n º 1.

• Graph the sequence.

• Find the sum of the first eight terms of the sequence.

c SOLUTION

Put the graphing calculator in Use the Table feature to view the Sequence mode and Dot mode. Enter terms of the sequence. The first eight the sequence. Note that the calculator terms are 2, 5, 8, 11, 14, 17, 20, and 23.uses u(n) rather than an.

Set the viewing window so that Use the Summation feature to find1 ≤ n ≤ 8, 1 ≤ x ≤ 8, and the sum of the first eight terms0 ≤ y ≤ 25. Graph the sequence. of the sequence. The screen showsUse the Trace feature to view the that the sum is 100.terms of the sequence.

c EXERCISES

Use a graphing calculator to (a) find the first ten terms of the sequence, (b) graph

the sequence, and (c) find the sum of the first ten terms of the sequence.

1. an = 2n + 3 2. an = 4(n + 1) 3. an = 50 º 2n

4. an = 2n º 1 5. an = S}

12

}Dn6. an = 2 + n2

7. an = 3 • 4n º 2 8. an = 10n + 2 9. an = }

13

} + n3

sum(seq(3 -1, ,1,8,1))

100

=4X=4 Y=11

u=3 -1

43

u( )1 22 53 84 115 14 =1

Min=1u( )=3 -1u( Min)=v( )=v( Min)=w( )=w( Min)=

21


Using Technology

Graphing Calculator Activity for use with Lesson 11.1ACTIVITY 11.1

STUDENT HELP

KEYSTROKE

HELP

See keystrokes for several models ofcalculators atwww.mcdougallittell.com

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1 2 3 4 5 6 7 8

11.2 Arithmetic Sequences and Series 659

Arithmetic Sequences and Series

USING ARITHMETIC SEQUENCES AND SERIES

In an the difference between consecutive terms is constant.The constant difference is called the and is denoted by d.

Identifying Arithmetic Sequences

Decide whether each sequence is arithmetic.

a. º3, 1, 5, 9, 13, . . . b. 2, 5, 10, 17, 26, . . .

SOLUTION

To decide whether a sequence is arithmetic, find the differences of consecutive terms.

a. a2 º a1 = 1 º (º3) = 4 b. a2 º a1 = 5 º 2 = 3

a3 º a2 = 5 º 1 = 4 a3 º a2 = 10 º 5 = 5

a4 º a3 = 9 º 5 = 4 a4 º a3 = 17 º 10 = 7

a5 º a4 = 13 º 9 = 4 a5 º a4 = 26 º 17 = 9

Each difference is 4, so the The differences are not constant,sequence is arithmetic. so the sequence is not arithmetic.

Writing a Rule for the nth Term

Write a rule for the nth term of the sequence 50, 44, 38, 32, . . . . Then find a20.

SOLUTION

The sequence is arithmetic with first term a1 = 50 and common difference d = 44 º 50 = º6. So, a rule for the nth term is:

an = a1 + (n º 1)d Write general rule.

= 50 + (n º 1)(º6) Substitute for a1 and d.

= 56 º 6n Simplify.

The 20th term is a20 = 56 º 6(20) = º64.

E X A M P L E 2

E X A M P L E 1

common difference

arithmetic sequence,

GOAL 1

Write rules for

arithmetic sequences and

find sums of arithmetic

series.

Use arithmetic

sequences and series in real-life problems, such as finding

the number of cells in a

honeycomb in Ex. 57.

. To solve real-lifeproblems, such as finding the

number of seats in a concert

hall in Example 7.


GOAL 2

GOAL 1


11.2R

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REA

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The nth term of an arithmetic sequence with first term a1 and common

difference d is given by:

an = a1 + (n º 1)d

RULE FOR AN ARITHMETIC SEQUENCE

1 2 3 4 5 6 7 8


Finding the nth Term Given a Term and the Common Difference

One term of an arithmetic sequence is a13 = 30. The common difference is d = }

32

}.

a. Write a rule for the nth term. b. Graph the sequence.

SOLUTION

a. Begin by finding the first term as follows.

an = a1 + (n º 1)d Write rule for n th term.

a13 = a1 + (13 º 1)d Substitute 13 for n .

30 = a1 + 12S}

32

}D Substitute for a13 and d.

12 = a1 Solve for a1.

So, a rule for the nth term is:

an = a1 + (n º 1)d Write general rule.

= 12 + (n º 1)}

32

} Substitute for a1 and d.

= }

221} + }

32

}n Simplify.

b. The graph is shown at the right. Notice that the pointslie on a line. This is true for any arithmetic sequence.

Finding the nth Term Given Two Terms

Two terms of an arithmetic sequence are a6 = 10 and a21 = 55.

a. Find a rule for the nth term. b. Find the value of n for which an = 40.

SOLUTION

a. Write a system of equations using an = a1 + (n º 1)d and substituting 21 for n(Equation 1) and then 6 for n (Equation 2).

a21 = a1 + (21 º 1)d 55 = a1 + 20d Equation 1

a6 = a1 + (6 º 1)d 10 = a1 + 5d Equation 2

Solve the system. 45 = 15d Subtract equations.

3 = d Solve for d.

55 = a1 + 20(3) Substitute for d.

º5 = a1 Solve for a1.

Find a rule for an. an = a1 + (n º 1)d Write general rule.

an = º5 + (n º 1)3 Substitute for a1 and d.

an = º8 + 3n Simplify.

b. an = º8 + 3n Use the rule for an from part (a).

40 = º8 + 3n Substitute 40 for an .

16 = n Solve for n.

E X A M P L E 4

E X A M P L E 3

9 :;< =

> ? @ A B C D E


The expression formed by adding the terms of an arithmetic sequence is called anThe sum of the first n terms of an arithmetic series is denoted by

Sn . To find a rule for Sn, you can write Sn in two different ways and add the results.

Sn = a1 + (a1 + d) + (a1 + 2d) + . . . + an

Sn = an + (an º d) + (an º 2d) + . . . + a1

2Sn = (a1 + an) + (a1 + an) + (a1 + an) + . . . + (a1 + an)

You can conclude that 2Sn = n(a1 + an), which leads to the following result.

Finding a Sum

Consider the arithmetic series 4 + 7 + 10 + 13 + 16 + 19 + . . . .

a. Find the sum of the first 30 terms. b. Find n such that Sn = 175.

SOLUTION

a. To begin, notice that a1 = 4 and d = 3. So, a formula for the nth term is:

an = a1 + (n º 1)d Write rule for the n th term.

= 4 + (n º 1)3 Substitute for a1 and d.

= 1 + 3n Simplify.

The 30th term is a30 = 1 + 3(30) = 91. So, the sum of the first 30 terms is:

S30 = 30S D Write rule for S30.

= 30S D Substitute for a1 and a30.

= 1425 Simplify.

c The sum of the first 30 terms is 1425.

b. nS D = 175 Use rule for Sn .

5n + 3n2 = 350 Multiply each side by 2.

3n2 + 5n º 350 = 0 Write in standard form.

(3n + 35)(n º 10) = 0 Factor.

n = 10 Choose positive solution.

c So, Sn = 175 when n = 10.

4 + (1 + 3n)}}

2

4 + 91}

2

a1 + a30}

2

E X A M P L E 5

arithmetic series.

The sum of the first n terms of an arithmetic series is:

Sn = nS}a1 +

2

an}D

In words, Sn is the mean of the first and nth terms, multiplied by the number

of terms.

THE SUM OF A FINITE ARITHMETIC SERIES

KARL FRIEDRICH

GAUSS, a famousnineteenth century mathe-matician, was a childprodigy. It is said that whenGauss was ten his teacherasked his class to add thenumbers from 1 to 100.Almost immediately Gaussfound the answer by mentallyfiguring the summation.

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ARITHMETIC SEQUENCES AND SERIES IN REAL LIFE

Writing an Arithmetic Sequence

SEATING CAPACITY The first row of a concert hall has 25 seats, and each rowafter the first has one more seat than the row before it. There are 32 rows of seats.

a. Write a rule for the number of seats in the nth row.

b. Thirty-five students from a class want to sit in the same row. How close to the front can they sit?

SOLUTION

a. Use a1 = 25 and d = 1 to write a rule for an.

an = a1 + (n º 1)d = 25 + (n º 1)(1) = 24 + n

b. Using the rule an = 24 + n, let an = 35 and solve for n.

35 = 24 + n Substitute for an .

11 = n Solve for n.

c The class can sit in the 11th row.

Finding the Sum of an Arithmetic Series

Use the information about the concert hall in Example 6.

a. What is the total number of seats in the concert hall?

b. Suppose 12 more rows of seats are built (where each row has one more seat thanthe row before it). How many additional seats will the concert hall have?

SOLUTION

a. Find the sum of an arithmetic series with a1 = 25 and a32 = 24 + 32 = 56.


= 32S}25 +2

56}D = 1296 Substitute for a1 and a32.

c There are 1296 seats in the concert hall.

b. The expanded concert hall has 32 + 12 = 44 rows of seats. Becausea44 = 24 + 44 = 68, the total number of seats in the expanded hall is:


= 44S}25 +2

68}D = 2046 Substitute for a1 and a44.

c The number of additional seats is S44 º S32 = 2046 º 1296 = 750.

a1 + a44}

2

a1 + a32}

2

E X A M P L E 7

E X A M P L E 6

GOAL 2

PHILHARMONIE

HALL in Berlin has2335 seats. This hall was thefirst to use an architecturalconcept called “vineyard”design to reflect sound tothe audience using severalaudience tiers at differentheights.

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N O P Q R S T U


1. Complete this statement: The expression formed by adding the terms of anarithmetic sequence is called a(n)

ooo

? .

2. What is the difference between an arithmetic sequence and an arithmetic series?

3. Explain how to find the sum of the first n terms of an arithmetic series.

Write a rule for the nth term of the arithmetic sequence.

4. d = 2, a1 = 5 5. d = º3, a2 = 18 6. d = }

12

}, a5 = 20

7. a8 = 12, a15 = 61 8. a5 = 10, a12 = 24 9. a10 = 8, a16 = 32

Find the sum of the first 10 terms of the arithmetic series.

10. 2 + 6 + 10 + 14 + 18 + . . . 11. 3 + }

72

} + 4 + }

92

} + 5 + . . .

12. 6 + 3 + 0 + (º3) + (º6) + . . . 13. 0.7 + 1.9 + 3.1 + 4.3 + 5.5 + . . .

14. MOVIE THEATER Suppose a movie theater has 42 rows of seats and thereare 29 seats in the first row. Each row after the first has two more seats than therow before it. How many seats are in the theater?

IDENTIFYING ARITHMETIC SEQUENCES Decide whether the sequence is

arithmetic. Explain why or why not.

15. 14, 11, 8, 5, 2, . . . 16. 1, 3, 9, 27, 81, . . . 17. º5, º7, º11, º13, º15, . . .

18. 0.5, 1, 1.5, 2, 2.5, . . . 19. }

15

}, }

25

}, }

45

}, }

85

}, }

156}, . . . 20. º}

53

}, º1, º}

13

}, }

13

}, 1, . . .

WRITING TERMS Write a rule for the nth term of the arithmetic sequence. Then

find a25.

21. 1, 3, 5, 7, 9, . . . 22. 6, 14, 22, 30, 38, . . . 23. 9, 23, 37, 51, 65, . . .

24. º1, 0, 1, 2, 3, . . . 25. 4, 1, º2, º5, º8, . . . 26. }

12

}, 3, }

121}, 8, }

221}, . . .

27. }

121}, }

265}, }

167}, }

32

}, }

16

}, . . . 28. }

52

}, }

161}, }

76

}, }

12

}, º}

16

}, . . . 29. 1.6, 4, 6.4, 8.8, 11.2, . . .

WRITING RULES Write a rule for the nth term of the arithmetic sequence.

30. d = 4, a14 = 46 31. d = º12, a1 = 80 32. d = }

53

}, a8 = 24

33. a5 = 17, a15 = 77 34. d = º6, a12 = º4 35. a2 = º28, a20 = 52

36. a1 = º2, a9 = º}

16

} 37. a7 = 34, a18 = 122 38. d = º4.1, a16 = 48.2

GRAPHING SEQUENCES Graph the arithmetic sequence.

39. an = 7 + 2n 40. an = º3 + 5n 41. an = 5 º 2n

42. an = 2 º }

13

}n 43. an = 4 º }

12

}n 44. an = º0.25 + 0.45n


GUIDED PRACTICE


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HOMEWORK HELP

Example 1: Exs. 15–20Example 2: Exs. 21–29Example 3: Exs. 30–32, 34,

38–44Example 4: Exs. 33, 35–37Example 5: Exs. 45–56Examples 6, 7: Exs. 57–60

N O P Q R S T U


FINDING SUMS For part (a), find the sum of the first n terms of the arithmetic

series. For part (b), find n for the given sum Sn.

45. 3 + 8 + 13 + 18 + 23 + . . . 46. 50 + 42 + 34 + 26 + 18 + . . .

a. n = 20 b. Sn = 366 a. n = 40 b. Sn = 182

47. º10 + (º5) + 0 + 5 + 10 + . . . 48. 34 + 31 + 28 + 25 + 22 + . . .

a. n = 19 b. Sn = 375 a. n = 32 b. Sn = º12

49. 2 + 9 + 16 + 23 + 30 + . . . 50. 2 + 16 + 30 + 44 + 58 + . . .

a. n = 68 b. Sn = 1661 a. n = 24 b. Sn = 2178


51. ∑20

i = 1(3 + 5i) 52. ∑

34

i = 1(1 + 8i) 53. ∑

15

i = 1(º10 º 3i)

54. ∑22

i = 1S6 º }

34

}iD 55. ∑45

i = 1(11 + 4i) 56. ∑

18

i = 1(8.1 + 4.4i)

57. HONEYCOMBS Domestic bees maketheir honeycomb by starting with a singlehexagonal cell, then forming ring after ring ofhexagonal cells around the initial cell, asshown. The numbers of cells in successiverings form an arithmetic sequence.

c Source: USDA’s Carl Hayden Bee Research Lab

a. Write a rule for the number of cells in the nth ring.

b. What is the total number of cells in the honeycomb after the 9th ring is formed? (Hint: Do not forget to count the initial cell.)

58. STACKING LOGS Logs are stacked in apile, as shown at the right. The bottom rowhas 21 logs and the top row has 15 logs. Eachrow has one less log than the row below it.How many logs are in the pile?

59. QUILTING A quilt is made up of strips ofcloth, starting with an inner square surroundedby rectangles to form successively largersquares. The inner square and all rectangleshave a width of 1 foot. Write an expressionusing summation notation that gives the sum ofthe areas of all the strips of cloth used to makethe quilt shown. Then evaluate the expression.

60. SEATING REVENUE Suppose each seat in rows 1 through 11 of the concerthall in Example 6 costs $24, each seat in rows 12 through 22 costs $18, and eachseat in rows 23 through 32 costs $12. How much money does the concert halltake in for a sold-out event?

61. Writing Compare the graphs of an = 2n + 1 where n is a positive integer andƒ(x) = 2x + 1 where x is a real number. Discuss how the graph of an arithmeticsequence is similar to and different from the graph of a linear function.

ENTOMOLOGIST

Entomology is thescientific study of insects.Some entomologists studybee population dynamicsand pollination of plants.

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62. MULTI-STEP PROBLEM A paper manufacturer sells paper rolled onto cardboard dowels. The thickness of the paper is 0.004 inch. The diameter of a dowel is 3 inches, and the total diameter of a roll is 7 inches.

a. Let n be the number of times the paper is wrapped around the dowel, let dn be the diameter of the roll just before the nth wrap, and let ln be the length ofpaper added in the nth wrap. Copy and complete the table.

b. What can you say about the sequence l1, l2, l3, l4, . . . ? Write a formula for thenth term of the sequence.

c. Find the number of times the paper must be wrapped around the dowel tocreate a roll with a 7 inch diameter. Use your answer and the formula frompart (b) to find the length of paper in a roll with a 7 inch diameter.

d. LOGICAL REASONING Suppose a roll with a 7 inch diameter costs $15.How much would you expect to pay for a roll with an 11 inch diameter whosedowel also has a diameter of 3 inches? Explain your reasoning and anyassumptions you make.

63. AHMES PAPYRUS One of the major sources of our knowledge of Egyptianmathematics is the Ahmes papyrus (also known as the Rhind papyrus), which is ascroll copied in 1650 B.C. by an Egyptian scribe. The following problem is fromthe Ahmes papyrus.

Divide 10 hekats of barley among 10 men so that the common difference

is }

18

} of a hekat of barley.

Use what you know about arithmetic sequences and series to solve the problem.

SOLVING RATIONAL EXPONENT EQUATIONS Solve the equation.


64. x1/2 = 5 65. 2x3/4 = 54 66. x2/3 + 10 = 19

67. (8x)1/2 + 6 = 0 68. x1/3 º 11 = 0 69. (2x)1/2 = x º 4

SOLVING EXPONENTIAL EQUATIONS Solve the exponential equation.


70. 2x = 4.5 71. 4x º 3 = 5 72. 103x + 7 = 15

73. 6x º 5 = 1 74. 25x º 28 = 97 75. 5(2)2x º 4 = 13

GRAPHING EQUATIONS Graph the equation. (Review 10.3)

76. x2 + y2 = 9 77. x2 + y2 = 24 78. x2 + y2 = 64

79. 6x2 + 6y2 = 150 80. }

12

}x2 + }

12

}y2 = 4 81. 20x2 + 20y2 = 400

MIXED REVIEW

TestPreparation

★★Challenge

EXTRA CHALLENGE


n dn (in.) ln (in.)

1 3 3π

2 ? ?

3 ? ?

4 ? ?7 in.

2 in. 3 in. 2 in.

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Geometric Sequencesand Series

USING GEOMETRIC SEQUENCES AND SERIES

In a the ratio of any term to the previous term is constant. This constant ratio is called the and is denoted by r.

Identifying Geometric Sequences

Decide whether each sequence is geometric.

a. 1, 2, 6, 24, 120, . . . b. 81, 27, 9, 3, 1, . . .

SOLUTION

To decide whether a sequence is geometric, find the ratios of consecutive terms.

a. }

a

a2

1} = }

21

} = 2 }

a

a3

2} = }

62

} = 3 }

a

a4

3} = }

264} = 4 }

a

a5

4} = }

12240

} = 5

c The ratios are different, so the sequence is not geometric.

b. }

a

a2

1} = }

28

71} = }

13

} }

a

a3

2} = }

297} = }

13

} }

a

a4

3} = }

93

} = }

13

} }

a

a5

4} = }

13

}

c The ratios are the same, so the sequence is geometric.

Writing a Rule for the nth Term

Write a rule for the nth term of the sequence º8, º12, º18, º27, . . . . Then find a8.

SOLUTION

The sequence is geometric with first term a1 = º8 and common ratio r = }ºº

182

} = }

32

}.So, a rule for the nth term is:

an = a1rn º 1 Write general rule.

= º8S}

32}Dn º 1

Substitute for a1 and r.

The 8th term is a8 = º8S}

32

}D8 º 1= º}

211687}.

E X A M P L E 2

E X A M P L E 1

common ratio

geometric sequence,

GOAL 1

Write rules for

geometric sequences and

find sums of geometric

series.

Use geometric

sequences and series to

model real-life quantities,

such as monthly bills for

cellular telephone service

in Example 6.

. To solve real-lifeproblems, such as finding

the number of tennis

matches played in

Exs. 70 and 71.


GOAL 2

GOAL 1


11.3

The nth term of a geometric sequence with first term a1 and common ratio r is

given by:

an = a1rn º 1

RULE FOR A GEOMETRIC SEQUENCE

REA

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L LIFE

^ _ ` a b c d e

11.3 Geometric Sequences and Series 667

Finding the nth Term Given a Term and the Common Ratio

One term of a geometric sequence is a3 = 5. The common ratio is r = 2.

a. Write a rule for the nth term. b. Graph the sequence.

SOLUTION

a. Begin by finding the first term as follows.


a3 = a1r3 º 1 Substitute 3 for n.

5 = a1(2)2 Substitute for a3 and r.

1.25 = a1 Solve for a1.

So, a rule for the nth term is:


= 1.25(2)n º 1 Substitute for a1 and r.

b. The graph is shown at the right. Notice that thepoints lie on an exponential curve. This is true forany geometric sequence with r > 0.

Finding the nth Term Given Two Terms

Two terms of a geometric sequence are a2 = 45 and a5 = º1215. Find a rule for the nth term.

SOLUTION

Write a system of equations using an = a1r n º 1 and substituting 2 for n(Equation 1) and then 5 for n (Equation 2).

a2 = a1r2 º 1 45 = a1r Equation 1

a5 = a1r5 º 1 º1215 = a1r4 Equation 2

Solve the system. }

4r5} = a1 Solve Equation 1 for a1.

º1215 = }

4r5}(r4) Substitute for a1 in Equation 2.

º1215 = 45r3 Simplify.

º27 = r3 Divide each side by 45.

º3 = r Take the cube root of each side.

45 = a1(º3) Substitute for r in Equation 1.

º15 = a1 Solve for a1.

Find a rule for an. an = a1rn º 1 Write general rule.

an = º15(º3)n º 1 Substitute for a1 and r.

c A rule for the nth term is an = º15(º3)n º 1.

E X A M P L E 4

E X A M P L E 3

fg h ij i

k l mn hf h hf o h

p q r s t u v w


The expression formed by adding the terms of a geometric sequence is called aAs with an arithmetic series, the sum of the first n terms of a

geometric series is denoted by Sn. You can develop a rule for Sn as follows.

Sn = a1 + a1r + a1r2 + a1r3 + . . . + a1rn º 1

ºrSn =0 º a1r º a1r2 º a1r3 º . . . º a1rn º 1 º a1rn

Sn(1 º r) = a1 ºo0o º o0o0 º o0o0 º ... º o0o0 º 0 º a1rn

Therefore, Sn(1 º r) = a1(1 º rn). If r ≠ 1, you can divide both sides of thisequation by 1 º r to obtain the following rule for Sn.

Finding a Sum

Consider the geometric series 1 + 5 + 25 + 125 + 625 + . . . .

a. Find the sum of the first 10 terms. b. Find n such that Sn = 3906.

SOLUTION

a. To begin, notice that a1 = 1 and r = 5. Therefore:

S10 = a1S}11ºº

rr

10

}D Write rule for S10.

= 1S}11ºº

55

10

}D Substitute for a1 and r.

= 2,441,406 Simplify.

c The sum of the first 10 terms is 2,441,406.

b. a1S D = Sn Write general rule.

1S D = 3906 Substitute for a1, r, and Sn.

= 3906 Simplify.

1 º 5n = º15,624 Multiply each side by º4.

º5n = º15,625 Subtract 1 from each side.

5n = 15,625 Divide each side by º1.

n = }

log

lo

1

g

5,

5

625} = 6 Solve for n.

c So, Sn = 3906 when n = 6.

1 º 5n

}

º4

1 º 5n

}

1 º 5

1 º rn

}

1 º r

E X A M P L E 5

geometric series.

The sum Sn of the first n terms of a geometric series with common ratio r ≠ 1 is:

Sn = a1S}11ºº

r

r

n

}D

THE SUM OF A FINITE GEOMETRIC SERIES

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GEOMETRIC SEQUENCES AND SERIES IN REAL LIFE

Writing a Geometric Sequence

CELLULAR TELEPHONES In 1990 the average monthly bill for cellular telephoneservice in the United States was $80.90. From 1990 through 1997, the averagemonthly bill decreased by about 8.6% per year. c Source: Statistical Abstract of the United States

a. Write a rule for the average monthly cellular telephone bill an (in dollars) interms of the year. Let n = 1 represent 1990.

b. What was the average monthly cellular telephone bill in 1993?

c. When did the average monthly cellular telephone bill fall to $50?

SOLUTION

a. Because the average monthly bill decreased by the same percent each year, the average monthly bills from year to year form a geometric sequence. Use a1 = 80.9 and r = 1 º 0.086 = 0.914. A rule for the average monthly bill is:

an = 80.9(0.914)n º 1

b. In 1993, n = 4. So, the average monthly bill was a4 = 80.9(0.914)3 ≈ $61.77.

c. You want to find n such that an = 50.

80.9(0.914)n º 1 = 50 Write equation using rule for an.

(0.914)n º 1 ≈ 0.618 Divide each side by 80.9.

n º 1 ≈ }

l

l

o

o

g

g

0

0

.

.

6

9

1

1

8

4} ≈ 5.35 Solve for n º 1.

n ≈ 6 Solve for n.

The average monthly cellular telephone bill reached $50 in 1995 (when n = 6).

Finding the Sum of a Geometric Series

Use the model for the average monthly cellular telephone bill in Example 6. Onaverage, what did a person pay for cellular telephone service during 1990–1997?

SOLUTION

Because the model an = 80.9(0.914)n º 1 gives the average monthly bill, the model bn = 12(80.9)(0.914)n º 1 = 970.8(0.914)n º 1 gives the average annual bill. Using a1 = 970.8 and r = 0.914, you can estimate a person’s total cost for cellulartelephone service during the 8 year period 1990–1997 to be:

S8 = a1S}

11

ºº

rr

8

}D Write rule for S8.

= 970.8S}11

º

º

(0

0

.

.

9

9

1

1

4

4

)8

}D Substitute for a1 and r.

≈ 5790 Simplify.

c A person paid about $5790 for cellular telephone service during 1990–1997.

E X A M P L E 7

E X A M P L E 6

GOAL 2

CELLULAR

TELEPHONES

In 1990 there were about 5 million cellular phonesubscribers. By 1997 thenumber had grown to over55 million.

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1. Complete this statement: The constant ratio in a geometric sequence is called the

ooo

? ratio and is denoted by ooo

? .

2. What makes a sequence geometric?

3. State the rule for the sum of the first n terms of a geometric series.

Find the common ratio of the geometric sequence.

4. 4, 12, 36, 108, 324, . . . 5. 1, 6, 36, 216, 1296, . . . 6. 2, º6, 18, º54, 162, . . .

7. 7, 14, 28, 56, 128, . . . 8. 64, º32, 16, º8, 4, . . . 9. 10, 5, }

52

}, }

54

}, }

58

}, . . .

Write the next term and find a rule for the nth term of the geometric sequence.

10. 1, 3, 9, 27, . . . 11. 2, 8, 32, 128, . . . 12. 1, º6, 36, º216, . . .

13. 375, º75, 15, º3, . . . 14. }

12

}, }

14

}, }

18

}, }

116}, . . . 15. º28, 14, º7, }

72

}, º}

74

}, . . .

Write a rule for the nth term of the geometric sequence.

16. r = 3, a1 = 2 17. r = º2, a1 = 6 18. r = º3, a1 = 12

19. a1 = }

14

}, a3 = 6 20. a2 = 5, a4 = }

15

} 21. a2 = 28, a5 = º1792

22. Find the sum of the first 8 terms of the geometric series 1 + 8 + 64 + 512 + . . . .

23. CELLULAR PHONES Use the model from Example 6 to find the averagemonthly bill for cellular telephone service in 1997.

CLASSIFYING SEQUENCES Decide whether the sequence is arithmetic,

geometric, or neither. Explain your answer.

24. 6, 24, 96, 384, . . . 25. 1, 3, 7, 13, . . . 26. 4, 13, 22, 31, . . .

27. 3, º1, º5, º9, . . . 28. º11, º7, º3, 1, . . . 29. }

12

}, }

32

}, }

92

}, }

227}, . . .

30. }

13

}, }

23

}, 1, }

43

}, . . . 31. º}

34

}, }

18

}, º}

116}, }

332}, . . . 32. º}

35

}, }

245}, }

1525}, }

6625}, . . .

FINDING COMMON RATIOS Find the common ratio of the geometric sequence.

33. 1, 4, 16, 64, . . . 34. 3, 6, 12, 24, . . . 35. º3, 6, º12, 24, . . .

36. 5, 40, 320, 2560, . . . 37. 136, 68, 34, 17, . . . 38. º}

14

}, }

18

}, º}

116}, }

312}, . . .

WRITING TERMS Write a rule for the nth term of the geometric sequence.

Then find a6.

39. 1, º4, 16, º64, . . . 40. 5, 10, 20, 40, . . . 41. 2, 14, 98, 686, . . .

42. 6, º30, 150, º750, . . . 43. 5, º}

53

}, }

59

}, º}

257}, . . . 44. 2, }

43

}, }

89

}, }

12

67}, . . .


GUIDED PRACTICE


Concept Check ✓

Skill Check ✓

STUDENT HELP

HOMEWORK HELP

Example 1: Exs. 24–32Example 2: Exs. 33–44Example 3: Exs. 45–49,

54–59 Example 4: Exs. 50–53Example 5: Exs. 60–69Examples 6, 7: Exs. 70–79


STUDENT HELP

x y z { | } ~ �


WRITING RULES Write a rule for the nth term of the geometric sequence.

45. r = 3, a1 = 4 46. r = }

13

}, a1 = 45 47. r = 6, a3 = 72

48. r = }

18

}, a1 = 4 49. r = 8, a1 = º2 50. a1 = º}

12

}, a4 = º16

51. a3 = 10, a6 = 300 52. a2 = º20, a4 = º5 53. a2 = º30, a5 = 3750

GRAPHING SEQUENCES Graph the geometric sequence.

54. an = 4(2)n º 1 55. an = 3(5)n º 1 56. an = 2(3)n º 1

57. an = 8(3)n º 1 58. an = 5S}

12

}Dn º 159. an = 4S}

32

}Dn º 1

FINDING SUMS For part (a), find the sum of the first n terms of the geometric

series. For part (b), find n for the given sum Sn.

60. 1 + 4 + 16 + 64 + . . . 61. 1 + 9 + 81 + 729 + . . .

a. n = 14 b. Sn = 341 a. n = 10 b. Sn = 820

62. 7 + (º21) + 63 + (º189) + . . . 63. º90 + 30 + (º10) + }

130} + . . .

a. n = 18 b. Sn = 3829 a. n = 16 b. Sn = º66.67


64. ∑10

i = 16(2)i º 1 65. ∑

8

i = 15(4)i º 1 66. ∑

9

i = 012Sº}

12

}Di

67. ∑10

i = 18S}

34

}Di º 168. ∑

6

i = 04S}

32

}Di69. ∑

12

i = 1(º2)i º 1

TENNIS In Exercises 70 and 71, use the following information.

The men’s U.S. Open tennis tournament is held annually in Flushing Meadow inNew York City. In the first round of the tournament, 64 matches are played. In eachsuccessive round, the number of matches played decreases by one half.

c Source: United States Tennis Association

70. Find a rule for the number of matches played in the nth round. For what valuesof n does your rule make sense?

71. Find the total number of matches played in the men’s U.S. Open tennistournament.

COMPUTER SCIENCE In Exercises 72 and 73, use the following information.

When a computer must find an item in an ordered list of data (such as an alphabeticallist of names), it may be programmed to perform a binary search. This searchtechnique involves jumping to the middle of the list and deciding whether the item isthere. If not, the computer decides whether the item comes before or after the middle.Half of the list is then ignored on the next pass through the list, and the computerjumps to the middle of the remaining list. This is repeated until the item is found.

72. An ordered list contains 1024 items. Find a rule for the number of itemsremaining after the nth pass through the list.

73. In the worst case, the item to be found is the only one left in the list after n passes through the list. What is the worst-case value of n for a binary search of a list with 1024 items?

COMPUTER

PROGRAMMER

Programmers write, test, and maintain computerprograms. Programs aredetailed lists of instructionsthat a computer must followto perform its functions.

CAREER LINK


INT

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FOCUS ON

CAREERS

� � � � � � � �


PAGER SALES In Exercises 74–77, use the following information.

In 1990 factory sales of pagers in the United States totaled $118 million. From 1990through 1996, the sales increased by about 20% per year.

DATA UPDATE of Statistical Abstract of the United States data at www.mcdougallittel.com.

74. Write a rule for pager sales an (in millions of dollars) in terms of the year. Let n = 1 represent 1990.

75. What did factory sales of pagers total in 1992?

76. When did factory sales of pagers reach $300 million?

77. What was the total of factory sales of pagers for the period 1990–1996?

SIERPINSKI TRIANGLE In Exercises 78 and 79, use the following information.

The Sierpinski triangle is a design using equilateral triangles. The process involvesremoving smaller triangles from larger triangles by joining the midpoints of the sidesof the larger triangles as shown below. Assume that the initial triangle is equilateralwith sides 1 unit long.

78. Let an be the number of triangles removed at the nth stage. Find a rule for an.Then find the total number of triangles removed through the 10th stage.

79. Let bn be the remaining area of the original triangle at the nth stage. Find a rulefor bn. Then find the remaining area of the original triangle at the 15th stage.

80. Writing Compare the graphs of an = 4(2)n º 1 where n is a positive integerand ƒ(x) = 4(2)x º 1 where x is a real number. Discuss how the graph of ageometric sequence with r > 0 is similar to and different from the graph of anexponential function.

81. MULTI-STEP PROBLEM Suppose two computer companies, Company Aand Company B, opened in 1991. The revenues of Company A increased

arithmetically through 2000, while the revenues of Company B increasedgeometrically through 2000. In 1996 the revenue of Company A was $523.7 million. In 1996 the revenue of Company B was $65.6 million.

a. The revenues of Company A have a common difference of 55.5. The revenuesof Company B have a common ratio of 2. Find a rule for the revenues in thenth year of each company. Let a1 represent 1991.

b. Graph each sequence from part (a).

c. Find the sum of the revenues from 1991 through 2000 for each company.

d. Writing Use a graphing calculator or spreadsheet to find when the revenueof Company B is greater than the revenue of Company A. Write a briefparagraph explaining which company you would rather own. Be sure to referto your graphs from part (b).

82. WORKING WITH FRACTIONS Using the rule for the sum of the first n terms ofa geometric series, write the polynomial as a rational expression.

a. 1 + x + x2 + x3 + x4 b. 3x + 6x3 + 12x5 + 24x7

Stage 1 Stage 2 Stage 3

INT

ERNET

TestPreparation

★★Challenge

� � � � � � � �


ORDERING NUMBERS Plot the numbers on a number line. Write the numbers

in increasing order. (Review 1.1 for 11.4)

83. }

32

}, }

25

}, }

76

}, 1, }

67

} 84. Ï5w, 2, º}

15

}, 0, 3 85. º}

52

}, º1, 1.5, º3.2, º2

SOLVING ALGEBRAICALLY Solve the inequality algebraically. (Review 5.7)

86. x2 + x º 2 ≥ 0 87. x2 º 6x º 7 ≤ 0 88. x2 < 36

89. ºx2 º 8x < 20 90. 3x2 º 9x + 6 > 0 91. }

12

}x2 + 5x ≤ º12

SOLVING EQUATIONS Solve using any method. Check each solution.


92. }

1 +3

x} = 8 93. }

1 º4

x} = 10 94. }

xº+12

4} = ºx

95. º}

2x4} º x = 11 96. }

x ºx

8} = }

2x4} 97. x + 10 = }

x ºx2

5}

Write the next term in the sequence. Then write a rule for the nth term.

(Lesson 11.1)

1. 0, 2, 4, 6, . . . 2. 3, 9, 27, 81, . . . 3. }

15

}, º}

110}, }

210}, º}

410}, . . .

Find the sum of the series. (Lesson 11.1)

4. ∑4

k = 0k4 5. ∑

6

m = 1(m2 + 5) 6. ∑

5

n = 1(n3 º 1)

Write a rule for the nth term of the arithmetic sequence. Then find a12.

(Lesson 11.2)

7. 1, 5, 9, 13, . . . 8. 34, 25, 16, 7, º2, . . . 9. }

12

}, 1, }

32

}, 2, . . .

10. Find the sum of the first 30 terms of the arithmetic series1.4 + 2.9 + 4.4 + 5.9 + 7.4 + . . . . (Lesson 11.2)

Write a rule for the nth term of the geometric sequence. Then find a15.

(Lesson 11.3)

11. 2, 10, 50, 250, . . . 12. º3, 12, º48, 192, . . . 13. 12, 4, }

43

}, }

49

}, . . .

14. FAMILY TREE A portionof John’s parental family treeis shown at the right. Find arule for the number of peoplein the nth generation. If 10generations of his family have lived in this country,how many people is this? (Lesson 11.3)

QUIZ 1 Self-Test for Lessons 11.1–11.3

MIXED REVIEW

Maternal Grandmother

Maternal Grandfather

Paternal Grandmother

Paternal Grandfather

Mother

Father

John

Generation 1 Generation 2 Generation 3

� � � � � � � �Developing Concepts

ACTIVITY 11.4Group Activity for use with Lesson 11.4

GROUP ACTIVITY

Work in a small group.

MATERIALS

• scissors

• piece of paper

Investigating an Infinite Geometric Series

c QUESTION What is the sum of an infinite geometric series?

c EXPLORING THE CONCEPT

You can illustrate an infinite geometric series by cutting a piece of paper into smallerand smaller pieces. Start with a square piece of paper. Define the area of the paper tobe 1 square unit.

Fold the paper in half and cut

along the fold. Place one half

on a desktop and hold the

remaining half.

Repeat Steps 1 and 2 until you find it too difficult to fold and cut the piece of

paper you are holding.

The first piece of paper you placed on the desktop has an area of }

12

} square unit.

The second piece of paper has an area of }

14

} square unit. Write the areas of the

next three pieces of paper. Explain why these areas form a geometric sequence.

Copy and complete the table by recording the number of pieces of paper on the

desktop and the combined area of the pieces at each step.

c DRAWING CONCLUSIONS

1. What number does the combined area of the pieces of paper appear to beapproaching?

2. The formula for the combined area after n cuts is An = }

12

}S D.

What happens to this formula as n ˘ ‡? (Hint: The only term with n in it, S}

12

}Dn

,approaches 0 as n ˘ ‡.)

1 º S}

12

}Dn

}}

1 º }

12

}

5

4

3

1


Number of pieces on desktop 1 2 3 4 5 . . .

Combined area of pieces }

12

} }

12

} + }

14

} = ? ? ? ? . . .

Fold the piece of paper you

are holding in half and cut

along the fold. Place one half

on the desktop and hold the

remaining half.

2

� � � � � � � �

11.4 Infinite Geometric Series 675

Infinite Geometric Series

USING INFINITE GEOMETRIC SERIES

Consider the following infinite geometric series:

}

12

} + }

14

} + }

18

} + }

116} + }

312} + . . .

Even though this series has infinitely many terms, it has a finite sum! To see this,compute and graph the sum of the first n terms for several values of n.

S1 = }

12

} = 0.5

S2 = }

12

} + }

14

} = 0.75

S3 = }

12

} + }

14

} + }

18

} ≈ 0.88

S4 = }

12

} + }

14

} + }

18

} + }

116} ≈ 0.94

S5 = }

12

} + }

14

} + }

18

} + }

116} + }

312} ≈ 0.97

Notice that Sn appears to be approaching 1 as n increases. To see why this makessense, consider the rule for Sn:

Sn = a1S D = }

12

}S D = 1 º S}

12

}Dn

As n increases, S}

12

}Dngets closer and closer to 0, which means that Sn gets closer and

closer to 1. The same is true for rn provided r is between º1 and 1. Therefore, the

formula for the sum of a finite geometric series, Sn = a1S D, approaches theformula below as n increases.

THE SUM OF AN INFINITE GEOMETRIC S

For the series described above, the sum is S = = 1, as expected.}

12

}

}

1 º }

12

}

1 º rn

}

1 º r

1 º S}

12

}Dn

}}

1 º }

12

}

1 º rn

}

1 º r

GOAL 1

Find sums of

infinite geometric series.

Use infinite

geometric series as models

of real-life situations, such

as the distance traveled by a

bouncing ball in Example 4.

. To solve real-lifeproblems, such as finding

the spending generated by

tourists in Malaysia in

Exs. 50 and 51.


GOAL 2

GOAL 1


11.4R

EAL LIFE

REA

L LIFE � � � ��

�� ¡� � ¢£

¤ � �¤ ¥

The sum of an infinite geometric series with first term a1 and common ratio r is given by

S =

provided |r|< 1. If |r|≥ 1, the series has no sum.

a1}1 º r

THE SUM OF AN INFINITE GEOMETRIC SERIES

¦ § ¨ © ª « ¬


Finding Sums of Infinite Geometric Series

Find the sum of the infinite geometric series.

a. ∑‡

i = 13(0.7)i º 1 b. 1 º }

14

} + }

116} º }

614} + . . .

SOLUTION

a. For this series, a1 = 3 and r = 0.7. b. For this series, a1 = 1 and r = º}

14

}.

S = = }1 º

30.7} = 10 S = = = }

54

}

Finding the Common Ratio

An infinite geometric series with first term a1 = 4 has a sum of 10. What is thecommon ratio of the series?

SOLUTION

S = Write rule for sum.

10 = }1 º

4r

} Substitute for S and a1.

10(1 º r) = 4 Multiply each side by 1 º r.

1 º r = }

25

} Divide each side by 10.

r = }

35

} Solve for r.

c The common ratio is r = }

35

}.

Writing a Repeating Decimal as a Fraction

Write 0.181818 . . . as a fraction.

SOLUTION

0.181818 . . . = 18(0.01) + 18(0.01)2 + 18(0.01)3 + . . .

= Write rule for sum.

= Substitute for a1 and r.

= Write as a quotient of integers.

= Simplify.

c The repeating decimal 0.181818 . . . is }

121} as a fraction.

2}

11

18}

99

18(0.01)}

1 º 0.01

a1}

1 º r

E X A M P L E 3

a1}

1 º r

E X A M P L E 2

1}}

1 º Sº}

14

}Da1

}

1 º r

a1}

1 º r

E X A M P L E 1

STUDENT HELP

Study TipYou can check the result

in Example 3 by dividing

2 by 11 on a calculator.

HOMEWORK HELP

Visit our Web site


for extra examples.

INT

ERNET

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® ¯ ° ± ² ³ ´ µ


INFINITE GEOMETRIC SERIES IN REAL LIFE

Using an Infinite Series as a Model

BALL BOUNCE A ball is dropped from a height of 10 feet. Each time it hits the ground, it bounces to 80% of its previous height.

a. Find the total distance traveled by the ball.

b. On which bounce will the ball have traveled 85% of its total distance?

SOLUTION

a. The total distance traveled by the ball is:

d = 10 + 10(0.8) + 10(0.8) + 10(0.8)2 + 10(0.8)2 + 10(0.8)3 + . . .

down up down up down up

= 10 + 2[10(0.8)] + 2[10(0.8)2] + 2[10(0.8)3] + . . .

= 10 + 20(0.8) + 20(0.8)2 + 20(0.8)3 + . . .

= 10 + }1

20

º

(0

0

.8

.8

)} Excluding first term, find sum of series.

= 10 + 80 Simplify fraction.

= 90 Simplify.

c The ball travels a total distance of 90 feet.

b. Let n be the number of up-and-down bounces. The distance dn the ball travels is:

dn = 10 + 20(0.8)S D Write rule for dn.

down-only sum of n

distance up-and-down

bounces

0.85(90) = 10 + 20(0.8)S D Substitute for dn.

76.5 = 10 + 16S D Simplify.

4.156 ≈ }1 º

0

(

.

0

2

.8)n

} Isolate fraction.

0.831 ≈ 1 º (0.8)nMultiply each side by 0.2.

(0.8)n ≈ 0.169 Isolate exponential expression.

n ≈ ≈ 7.97 Solve for n.

c The ball travels 85% of its total distance after about 8 up-and-down bounces,or after 9 bounces including the first down-only bounce.

log 0.169}}

log 0.8

1 º (0.8)n

}}

1 º 0.8

1 º (0.8)n

}}

1 º 0.8

1 º (0.8)n

}}

1 º 0.8

E X A M P L E 4

GOAL 2

BALL BOUNCE

This photo of a ball

bouncing was taken with

time-lapse photography. The

images of the ball get closer

together as you move up,

which means the ball’s

speed is decreasing.

RE

AL LIFE

RE

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FOCUS ON

APPLICATIONS

10 ft8 ft

8 ft 6.4 ft

6.4 ft5.12 ft

5.12 ft4.096 ft

4.096 ft

1 2 3 4 5 Bounce number

1

1

1

1

® ¯ ° ± ² ³ ´ µ


1. Complete this statement: A(n) ooo

? geometric series has infinitely many terms.

2. Under what conditions will ∑‡

i = 1a1ri º 1 have a sum?

3. What two things do you need to know to find the sum of an infinite geometricseries?


4. ∑‡

n = 15S}

14

}Dn º 15. º2 + }

12

} º }

18

} + }

312} º . . .

Find the common ratio of the infinite geometric series with the given sum and

first term.

6. S = 6, a1 = 1 7. S = 12, a1 = 2 8. S = 10}

12

}, a1 = }

12

}

Write the repeating decimal as a fraction.

9. 0.555 . . . 10. 0.1212 . . . 11. 245.245245 . . .

12. BALL BOUNCE A ball is dropped from a height of 5 feet. Each time it hitsthe ground, it bounces one half of its previous height.

a. Find the total distance traveled by the ball.

b. On which bounce will the ball have traveled 75% of its total distance?

IDENTIFYING A SUM Decide whether the infinite geometric series has a sum.

Explain why or why not.

13. ∑‡

n = 13S}

32

}Dn º 114. ∑

‡

n = 0º5S}

15

}Dn

15. ∑‡

n = 1}

32

}S}

13

}Dn º 116. ∑

‡

n = 0}

14

}S}

43

}Dn

FINDING SUMS Find the sum of the infinite geometric series if it has one.

17. ∑‡

n = 0S}

12

}Dn

18. ∑‡

n = 03S}

23

}Dn

19. ∑‡

n = 1Sº}

12

}Dn º 120. ∑

‡

n = 0}

27

}(2)n

21. ∑‡

n = 04S}

14

}Dn

22. ∑‡

n = 1S}

110}Dn º 1

23. ∑‡

n = 02S}

65

}Dn

24. ∑‡

n = 04S}

37

}Dn

25. ∑‡

n = 0º}

18

}Sº}

12

}Dn

26. ∑‡

n = 1}

12

}Sº}

25

}Dn º 127. ∑

‡

n = 0}

112}Sº}

235}Dn

28. ∑‡

n = 1ºSº}

121}Dn º 1

FINDING COMMON RATIOS Find the common ratio of the infinite geometric

series with the given sum and first term.

29. S = 4, a1 = 1 30. S = 10, a1 = 1 31. S = 12, a1 = 3

32. S = 8, a1 = 2 33. S = 6, a1 = 2 34. S = 50, a1 = 4

35. S = º}

19

}, a1 = º}

16

} 36. S = º}

11

13}, a1 = º1 37. S = 2}

29

}, a1 = 4


GUIDED PRACTICE


Concept Check ✓

Skill Check ✓

STUDENT HELP

HOMEWORK HELP

Example 1: Exs. 13–28




Extra Practiceto help you master

skills is on p. 956.

STUDENT HELP

¶ · ¸ ¹ º » ¼ ½WRITING REPEATING DECIMALS Write the repeating decimal as a fraction.

38. 0.444 . . . 39. 0.777 . . . 40. 0.999 . . .

41. 0.5151 . . . 42. 0.2323 . . . 43. 0.1616 . . .

44. 63.6363 . . . 45. 120.120120 . . . 46. 297.297297 . . .

47. PENDULUM A pendulum is released toswing freely. On the first swing, the pendulumtravels a distance of 18 inches. On eachsuccessive swing, the pendulum travels 90% ofthe distance of the previous swing. What is thetotal distance the pendulum swings? After howmany swings has the pendulum traveled 80%of its total distance?

48. WINDOWS Some types of windows are constructed with twoparallel panes of glass, each of whichreflects half of the sunlight that hits it from either side. The other half of the sunlight passes through the pane. How much of the sunlight will pass through both panes?

49. ZENO’S PARADOX Can the Greek hero Achilles, running at 20 feet persecond, ever catch a tortoise, starting 20 feet away and running at 10 feet persecond? The Greek mathematician Zeno said no. He reasoned as follows:

• When Achilles runs 20 feet the tortoise will be in a new spot, 10 feet away.

• Then, when Achilles gets to that spot, the tortoise will be 5 feet away.

• Achilles will keep cutting the distance in half but will never catch the tortoise.

In actuality, looking at the race as Zeno did, you can see that both the distancesand the times required to achieve them form infinite geometric series. Using thetable, show that both series have finite sums. What do these sums represent?

TOURISM In Exercises 50 and 51, use the following information.

In 1974 the Malaysian Tourist Development Corporation studied the economicimpact of distributing tourist brochures. It was estimated that M$4.72 (“M$” meansMalaysian dollars) in additional money was spent by tourists for every brochuredistributed in the capital city of Kuala Lumpur. It was also estimated that for eachM$1 spent on goods or services, 80.5% of that would be re-spent, creating a“multiplier” effect. (That is, each Malaysian dollar spent would lead to total spendingof M$1 + (0.805)M$1 + (0.805)(0.805)M$1 + (0.805)(0.805)(0.805)M$1 + . . . .)

50. What total spending was generated by a tourist spending M$1 in 1974?

51. How much total spending would be generated by the average tourist whoreceived a brochure?

52. LOGICAL REASONING Find two different infinite geometric series whose sum is 3.


ECONOMIST

Economists study the

ways a society distributes

resources to produce goods

and services. They conduct

research, monitor economic

trends, and make

projections.

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swing 1

swing 2

swing 318(0.9)2

18(0.9)

18

incomingsunlight¾ ¿

2¿2

¿4

¿4¿

8¿8

¿64

¿32

¿16¿

64

¿32

¿16 ÀÀÀ

Distance (ft) 20 10 5 2.5 1.25 0.625 . . .

Time (sec) 1 0.5 0.25 0.125 0.0625 0.03125 . . .

¶ · ¸ ¹ º » ¼ ½

Figure Figure Figure Figure . . . Figure1 2 3 4 n

Number of new triangles 1 3 ? ? . . . ?

Area of each new triangle ? ? . . . ?

Total new area ? ? . . . ?Ï3w}

12Ï3w}

4

Ï3w}

36Ï3w}

4


53. MULTIPLE CHOICE An infinite geometric series with first term a1 = 24 has asum of 48. What is the common ratio of the series?

¡A r = 1 ¡B r = }

12

} ¡C r = 2 ¡D r = }

214} ¡E r = }

38

}

54. MULTIPLE CHOICE The repeating decimal 18.181818 . . . is equivalent to whatfraction?

¡A }

85901

} ¡B }

121} ¡C }

189

1} ¡D }

21010

} ¡E }

197983}

55.

A Koch snowflake is createdby starting with an equilateraltriangle with sides 1 unit long.Then, on the middle third ofeach side of the triangle, anew equilateral triangle is constructed. This process is repeated as shown.

a. Recall that the area of an equilateral triangle with side length s can be found

using the formula A = . Use this formula to complete the table below.

b. What is the total area of the Koch snowflake? (Hint: Add up the entries in thelast row of the table.)

IDENTIFYING ASYMPTOTES Identify the horizontal and vertical asymptotes.

State the domain and range of the function. (Review 9.2)

56. ƒ(x) = }

5x

} 57. ƒ(x) = º}

5x

} 58. ƒ(x) = }

7x

} º 3

59. ƒ(x) = }xx

º+

57

} 60. ƒ(x) = }º

42xx

++

317

} 61. ƒ(x) = }2.

x2x

º+0.

37.1

}

GRAPHING Graph the equation. (Review 10.4)

62. }

x4

2

} + }

1

y

6

2

} = 1 63. }

254x2

} + }25

9

y2

} = 1 64. }

1x6

2

} + y2 = 1

WRITING RULES Write a rule for the n th term of the sequence. Recall that d is

the common difference of an arithmetic sequence and r is the common ratio of

a geometric sequence. (Review 11.2, 11.3 for 11.5)

65. d = 4, a1 = 1 66. d = 8, a1 = º2 67. d = º2, a2 = 9

68. r = 2, a3 = º20 69. r = 0.5, a1 = 4 70. r = 0.875, a1 = º10

MIXED REVIEW

s2 Ï3w}

4

GEOMETRY CONNECTION

TestPreparation

★★Challenge

Figure 1 Figure 2 Figure 3

EXTRA CHALLENGE


Á Â Ã Ä Å Æ Ç È

Investigating Recursive Rules

Find the first five terms of each sequence.

a. a1 = 3 b. a1 = 3

an = an º 1 + 5 an = 2an º 1

Based on the lists of terms you found in Step 1, what type of sequence is

the sequence in part (a)? in part (b)?

2

1

DevelopingConcepts

ACTIVITY

11.5 Recursive Rules for Sequences 681

Recursive Rules for Sequences

USING RECURSIVE RULES FOR SEQUENCES

So far in this chapter you have worked with explicit rules for the nth term of asequence, such as an = 3n º 2 and an = 3(2)n. An gives an as afunction of the term’s position number n in the sequence.

In this lesson you will learn another way to define a sequence—by a recursive rule. A gives the beginning term or terms of a sequence and then arecursive equation that tells how an is related to one or more preceding terms.

Evaluating Recursive Rules

Write the first five terms of the sequence.

a. Factorial numbers: a0 = 1, an = n • an º 1

b. Fibonacci sequence: a1 = 1, a2 = 1, an = an º 2 + an º 1

SOLUTION

a. a0 = 1 b. a1 = 1

a1 = 1 • a0 = 1 • 1 = 1 a2 = 1

a2 = 2 • a1 = 2 • 1 = 2 a3 = a1 + a2 = 1 + 1 = 2

a3 = 3 • a2 = 3 • 2 = 6 a4 = a2 + a3 = 1 + 2 = 3

a4 = 4 • a3 = 4 • 6 = 24 a5 = a3 + a4 = 2 + 3 = 5

. . . . . . . . . .

The factorial numbers in part (a) of Example 1 are denoted by a special symbol, !,called a symbol. The expression n! is read “n factorial” and represents theproduct of all integers from 1 to n. Here are several factorial values.

0! = 1 (by definition) 1! = 1 2! = 2 • 1 = 2

3! = 3 • 2 • 1 = 6 4! = 4 • 3 • 2 • 1 = 24 5! = 5 • 4 • 3 • 2 • 1 = 120

factorial

E X A M P L E 1

recursive rule

explicit rule

GOAL 1

Evaluate and

write recursive rules for

sequences.

Use recursive

rules to solve real-lifeproblems, such as finding

the number of fish in a lake

in Example 5.

. To model real-lifequantities, such as the num-

ber of trees on a tree farm

in Exs. 49 and 50.


GOAL 2

GOAL 1


REA

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11.5

E X P L O R I N G D ATA

A N D S TAT I S T I C S



Writing a Recursive Rule for an Arithmetic Sequence

Write the indicated rule for the arithmetic sequence with a1 = 4 and d = 3.

a. an explicit rule b. a recursive rule

SOLUTION

a. From Lesson 11.2 you know that an explicit rule for the nth term of thearithmetic sequence is:

an = a1 + (n º 1)d General explicit rule for an

= 4 + (n º 1)3 Substitute for a1 and d.

= 1 + 3n Simplify.

b. To find the recursive equation, use the fact that you can obtain an by adding thecommon difference d to the previous term.

an = an º 1 + d General recursive rule for an

= an º 1 + 3 Substitute for d.

A recursive rule for the sequence is a1 = 4, an = an º 1 + 3.

Writing a Recursive Rule for a Geometric Sequence

Write the indicated rule for the geometric sequence with a1 = 3 and r = 0.1.

a. an explicit rule b. a recursive rule

SOLUTION

a. From Lesson 11.3 you know that an explicit rule for the nth term of thegeometric sequence is:

an = a1rn º 1 General explicit rule for an

= 3(0.1)n º 1 Substitute for a1 and r.

b. To write a recursive rule, use the fact that you can obtain an by multiplying theprevious term by r.

an = r • an º 1 General recursive rule for an

= (0.1)an º 1 Substitute for r.

A recursive rule for the sequence is a1 = 3, an = (0.1)an º 1.

Writing a Recursive Rule

Write a recursive rule for the sequence 1, 2, 2, 4, 8, 32, . . . .

SOLUTION

Beginning with the third term in the sequence, each term is the product of the twoprevious terms. Therefore, a recursive rule is given by:

a1 = 1, a2 = 2, an = an º 2 • an º 1

E X A M P L E 4

E X A M P L E 3

E X A M P L E 2



USING RECURSIVE RULES IN REAL LIFE

Using a Recursive Rule

FISH A lake initially contains 5200 fish. Each year the population declines 30%

due to fishing and other causes, and the lake is restocked with 400 fish.

a. Write a recursive rule for the number an of fish at the beginning of the nth year.How many fish are in the lake at the beginning of the fifth year?

b. What happens to the population of fish in the lake over time?

SOLUTION

a. Because the population declines 30% each year, 70% of the fish remain in thelake from one year to the next, and new fish are added.

A recursive rule is:

a1 = 5200, an = (0.7)an º 1 + 400

You can use a graphing calculator tofind a5, the number of fish in the lakeat the beginning of the fifth year. Enterthe number of fish at the beginning ofthe first year, which is a1 = 5200. Thenenter the rule 0.7 ª Ans + 400 to finda2. Press three more times tofind a5 ≈ 2262.

c There are about 2262 fish in the lakeat the beginning of the fifth year.

b. To determine what happens to thelake’s fish population over time,continue pressing on thecalculator. The calculator screen at theright shows the fish populations foryears 44–50. Observe that the numbersapproach about 1333.

c Over time, the population of fish inthe lake stabilizes at about 1333 fish.

E X A M P L E 5

GOAL 2

FISHERY

BIOLOGIST

Some fishery biologistsmanage fish hatcheries,conduct fish disease controlprograms, and work withorganizations to restore andenhance fish habitats.

CAREER LINK


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FOCUS ON

CAREERS

= 0.7 +

Fish at start of nth year =

Fish at start of (n º 1)st year =

New fish added = 400

= (0.7) + 400an º 1a

n

an º 1

an

New fishadded

Fish at start of(n º 1)st year

Fish at startof nth year

LABELS

VERBAL

MODEL

ALGEBRAIC

MODEL

5200

5200

.7*Ans+400

4040

3228

2659.6

2261.72

1333.334178

1333.333924

1333.333747

1333.333623

1333.333536

1333.333475

1333.333433

É Ê Ë Ì Í Î Ï Ð


1. Complete this statement: The expression ooo

? represents the product of all integers

from 1 to n.

2. Explain the difference between an explicit rule for a sequence and a recursive

rule for a sequence.

3. Give an example of an explicit rule for a sequence and a recursive rule for asequence.

Write the first five terms of the sequence Ñ4. a1 = 1 5. a1 = 2 6. a0 = 1

an = an º 1 + 1 an = 4an º 1 an = an º 1 º 2

7. a1 = º1 8. a1 = 2 9. a0 = 3an = º3an º 1 an = 2an º 1 º 3 an = (an º 1)2 + 1

Write a recursive rule for the sequence Ñ10. 21, 17, 13, 9, 5, . . . 11. 2, 6, 18, 54, 162, . . . 12. }

12

}, }14

}, }18

}, }116}, }

312}, . . .

13. FISH Suppose each year the lake in Example 5 is restocked with 750 fish.How many fish are in the lake at the beginning of the fifth year?

WRITING TERMS Write the first five terms of the sequence.

14. a0 = 1 15. a1 = 4 16. a0 = 0an = an º 1 + 4 an = n + an º 1 + 6 an = an º 1 º n2

17. a0 = º4 18. a1 = 2 19. a0 = 5an = an º 1 º 8 an = (an º 1)2 + 2 an = n2 º an º 1

20. a1 = 10 21. a0 = 2 22. a0 = 3an = 3an º 1 an = n2 + 2n º an º 1 an = (an º 1)2 º 2

23. a0 = 48 24. a0 = 4, a1 = 2 25. a1 = 1, a2 = 3

an = }12

}an º 1 + 2an = an º 1 º an º 2 an = an º 1 • an º 2

WRITING RULES Write an explicit rule and a recursive rule for the sequence.

(Recall that d is the common difference of an arithmetic sequence and r is the

common ratio of a geometric sequence.)

26. a1 = 2 27. a1 = 3 28. a1 = 10r = 10 d = 10 r = 2

29. a1 = 5 30. a1 = 0 31. a1 = 5d = 3 d = º1 r = 2.5

32. a1 = 14 33. a1 = }12

} 34. a1 = º1

d = }12

} r = 4 d = º}32

}


GUIDED PRACTICE


Concept Check ✓

Skill Check ✓


STUDENT HELP

STUDENT HELP

HOMEWORK HELP

Example 1: Exs. 14–25Examples 2, 3: Exs. 26–34Example 4: Exs. 35–43Example 5: Exs. 44–54

É Ê Ë Ì Í Î Ï Ð


WRITING RULES Write a recursive rule for the sequence. The sequence may be

arithmetic, geometric, or neither.

35. 1, 7, 13, 19, . . . 36. 66, 33, 16.5, 8.25, . . . 37. 41, 32, 23, 14, . . .

38. 3, 8, 63, 3968, . . . 39. 33, 11, }131}, }

191}, . . . 40. 7.2, 3.2, º0.8, º4.8, . . .

41. 2, 5, 10, 50, 500, . . . 42. 6, 6Ï2w, 12, 12Ï2w, . . . 43. 48, 4.8, 0.48, 0.048, . . .

44. ON LAYAWAY Suppose you buy a $500 camcorder on layaway by making adown payment of $150 and then paying $25 per month. Write a recursive rule forthe total amount of money paid on the camcorder at the beginning of the nthmonth. How much will you have left to pay on the camcorder at the beginning ofthe twelfth month?

FRACTAL TREE In Exercises 45 and 46, use the following information.

A fractal tree starts with a singlebranch (the trunk). At each stage the new branches from the previousstage each grow two more branches,as shown.

45. List the number of new branches in each of the first seven stages. What type ofsequence do these numbers form?

46. Write an explicit rule and a recursive rule for the sequence in Exercise 45.

POOL CARE In Exercises 47 and 48, use the following information.

You have just bought a new swimming pool and need to add chlorine to thewater. You add 32 ounces of chlorine the first week and 14 ounces every weekthereafter. Each week 40% of the chlorine in the pool evaporates.

47. Write a recursive rule for the amount of chlorine in the pool each week. Howmuch chlorine is in the pool at the beginning of the sixth week?

48. What happens to the amount of chlorine after an extended period of time?

TREE FARM In Exercises 49 and 50, use the following information.

Suppose a tree farm initially has 9000 trees. Each year 10% of the trees areharvested and 800 seedlings are planted.

49. Write a recursive rule for the number of trees on the tree farm at the beginning ofthe nth year. How many trees remain at the beginning of the fourth year?

50. What happens to the number of trees after an extended period of time?

DOSAGE In Exercises 51–54, use the following information.

A person repeatedly takes 20 milligrams of a prescribed drug every four hours.Suppose that 30% of the drug is removed from the bloodstream every four hours.

51. Write a recursive rule for the amount of the drug in the bloodstream after n doses.

52. What value does the drug level in the person’s body approach after an extendedperiod of time? This value is called the maintenance level.

53. Suppose the first dosage is doubled (to 40 milligrams), but the normal dosage istaken thereafter. Does the maintenance level from Exercise 52 change?

54. Suppose every dosage is doubled. Does the maintenance level double as well?

Stage 1 Stage 2 Stage 3 Stage 4

PHYSICIAN

Physicians diagnoseillnesses and administertreatment such as drugs, the focus of Exs. 51–54. In 1996 there were about738,000 physicians in theUnited States.

CAREER LINK


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CAREERS

HOMEWORK HELP


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STUDENT HELP

Ò Ó Ô Õ Ö × Ø Ù


55. CRITICAL THINKING Give an example of a sequence in which each term afterthe third term is a function of the three terms preceding it. Write a recursive rulefor the sequence and find the first 8 terms.

56. MULTIPLE CHOICE What is the fifth term of the sequence whose first term is a1 = 10 and whose nth term is an = 2an º 1 + 9?

¡A 67 ¡B 143 ¡C 286 ¡D 295 ¡E 599

57. MULTIPLE CHOICE What is a recursive equation for the sequence 4, º6.6, 10.89, º17.9685, . . .?

¡A an = (º2.6)an º 1 ¡B an = (º1.65)an º 1

¡C an = (2.6)an º 1 ¡D an = (1.65)an º 1

58. PIECEWISE-DEFINED SEQUENCE You can define a sequence using apiecewise rule. The following is an example of a piecewise-defined sequence.

a1 = 7, an = }an

2º 1}, if an º 1 is even

3an º 1 + 1, if an º 1 is odd

a. Write the first ten terms of the sequence.

b. LOGICAL REASONING Choose three different values for a1 (other than a1 = 7). For each value of a1, find the first ten terms of the sequence. Whatconclusions can you make about the behavior of this sequence?

EVALUATING POWERS Evaluate the power. (Review 1.2 for 12.1)

59. 25 60. 64 61. 84 62. 123

63. 263 64. 105 65. 183 66. 37

OPERATIONS WITH RATIONAL EXPRESSIONS Perform the indicated

operation and simplify. (Review 9.5)

67. }53x} + }

73x} 68. }

º7x

2} º }

35x} 69. }

x

x2

+

º

1

9} º }

x º5

3}

70. }3x

2+x2

5} º }

x1+4

7} 71. }

4

x

x2 º

+

4

1} º }

x º3

2} 72. }

xx

2

+º

21

} º }x +

31

}

FINDING POINTS OF INTERSECTION Find the points of intersection, if any, of

the graphs in the system. (Review 10.7)

73. x2 + y2 = 4 74. x2 + y2 = 25 75. x2 + 4y2 = 162x + y = º1 y = x º 1 y = 3x + 1

76. x2 + y2 = 10 77. x2 + y2 = 30 78. 16x2 + y2 = 32

4x + y = 6 y = x + 2 }14

}x º }12

}y = 2

WRITING TERMS Write the first six terms of the sequence. (Review 11.1)

79. an = 8 º n 80. an = n4 81. an = n2 + 9

82. an = (n + 3)2 83. an = }n +

n4

} 84. an = }nn

++ 3

1}

MIXED REVIEW

★★Challenge

TestPreparation

EXTRA CHALLENGE


Ò Ó Ô Õ Ö × Ø Ù


Find the sum of the infinite geometric series if it has one. (Lesson 11.4)

1. ∑`

n = 04S}

19

}Dn2. ∑

‡

n = 15Sº}

67

}Dn º 13. ∑

‡

n = 0º}

38

}S}47

}Dn4. ∑

‡

n = 0}45

}S}54

}Dn

Find the common ratio of the infinite geometric series with the given sum and

first term. (Lesson 11.4)

5. S = 5, a1 = 1 6. S = 12, a1 = 1 7. S = 24, a1 = 3

Write the repeating decimal as a fraction. (Lesson 11.4)

8. 0.888 . . . 9. 0.1515 . . . 10. 126.126126 . . .

Write the first five terms of the sequence. (Lesson 11.5)

11. a1 = 5 12. a0 = 1 13. a1 = 17an = an º 1 + 3 an = 4an º 1 an = an º 1 + n

14. a1 = 1, a2 = 2 15. a1 = 2, a2 = 4 16. a1 = 10, a2 = 10an = an º 1 º an º 2 an = an º 1 • an º 2 an = an º 2 + an º 1

17. BALL BOUNCE You drop a ball from a height of 8 feet. Each time it hits theground, it bounces 40% of its previous height. Find the total distance traveled bythe ball. (Lesson 11.4)

QUIZ 2 Self-Test for Lessons 11.4 and 11.5

The Fibonacci Sequence

THENTHENIN 1202 the mathematician Leonardo Fibonacci wrote Liber Abaci in which he proposed the following rabbit problem.

Begin with a pair of newborn rabbits that never die.

When a pair of rabbits is two months old, it begins

producing a new pair of rabbits each month.

This problem can be represented by a sequence, known as the Fibonaccisequence. The numbers that make up the sequence are called Fibonaccinumbers. The ratio of two Fibonacci numbers approximates the same number,denoted by F. The Greeks called this number the golden ratio.

1. Draw a tree diagram to illustrate the sequence.

2. If the initial pair of rabbits produces their first pair of rabbits in January, how many pairs of rabbits will there be in December of that year? What happens to the rabbit population over time?

TODAY we know that Fibonacci numbers occur in nature, such as in the spiral patterns on the head of a sunflower or the surface of a pineapple.

APPLICATION LINK


INT

ERNET

NOWNOW

Fibonacci

numbers

recognized

in nature.

Month

Pairs at start

of month

1

1 1

2

2 3

4 5

5

6

8

3

Fibonacci develops

sequence.

Golden Section

used in Great

Pyramid.

2500 B .C .

A .D . 1202

1999

Ú Û Ü Ý Þ ß à áEvaluating Recursive Rules

You can use a spreadsheet to evaluate a recursive rule.

c EXAMPLE

You owe $5000 to a credit card company that charges interest at a rate of 1.5% permonth. Each month you make a payment of $100. Write a recursive rule for an, thebalance of the account at the beginning of the nth month. How much will you stillowe at the beginning of the 6th month? How long will it take to pay off the account?

c SOLUTION

A recursive rule for the balance of the account each month is:

a1 = 5000, an = (1.015)an º 1 º 100

You can use a spreadsheet to find how much you owe at the start of each month.

Enter a1 into cell A1. In cell A2, enter the recursive equation.

Use the Fill Down feature to copy the recursive equation into the rest of the column.

c At the beginning of the 6th month you still owe $4871.19, and it will take about

94 months, or 7 years and 10 months, to pay off the account.

c EXERCISES

Use a spreadsheet to find the first twelve terms of the sequence.

1. a1 = 5100, an = (0.9)an º 1 º 125 2. a1 = 6150, an = (0.82)an º 1 º 200

3. a1 = 3500, an = (0.85)an º 1 º 50 4. a1 = 7500, an = (0.775)an º 1 º 175

5. FINANCE You owe $8000 on a credit card with 1% monthly interest. If youpay $125 each month, how long will it take to pay off the account?

A B C

89 488.4879425

90 395.8152616

91 301.7524905

92 206.2787779

93 109.3729595

94 11.01355393

95 –88.8212428

A95 =1.015*A94–100

A B C

1 5000

2 4975

3 4949.625

4 4923.869375

5 4897.727416

6 4871.193327

7 4844.261227

A2 =1.015*A1–100

3

A B C

1 5000

2 4975

3

A2 =1.015*A1–100

A B C

1 5000

2

3

A1 5000

21


Using Technology

Spreadsheet Software Activity for use with Lesson 11.5ACTIVITY 11.5

STUDENT HELP

SOFTWARE

HELP

Visit our Web site


to see instructions for

several software

packages.

INT

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Ú Û Ü Ý Þ ß à á

Chapter 11 Extension 689

Mathematical InductionIn Lesson 11.1 you saw that the rule for the sum of the first n positive integers is:

∑n

i = 1i = 1 + 2 + . . . + n = }

n(n

2

+ 1)}

Statements like the one above about all positive integers can be proven using amethod called mathematical induction.

Mathematical induction works as follows. If you know from the basis step that astatement is true for n = 1, then the inductive step implies that it is true for n = 2,and therefore, for n = 3, and so on for all positive integers n.

Using Mathematical Induction

Use mathematical induction to prove that 1 + 2 + . . . + n = }n(n

2

+ 1)}.

SOLUTION

Basis step: Check to see if the formula works for n = 1.

1 · }

(1)(1

2

+ 1)} 1 = 1 ✓

Inductive step: Assume that 1 + 2 + . . . + k = }k(k

2

+ 1)}.

Show that 1 + 2 + . . . + k + (k + 1) = .

1 + 2 + . . . + k = }k(k

2

+ 1)} Assume true for k.

1 + 2 + . . . + k + (k + 1) = }k(k

2

+ 1)} + (k + 1) Add k + 1 to each side.

= Add.

= }(k + 1)

2

(k + 2)} Factor out k + 1.

= Rewrite k + 2 as (k + 1) + 1.

Therefore, 1 + 2 + . . . + n = }n(n

2

+ 1)} for all positive integers n.

(k + 1)[(k + 1) + 1]}}}

2

k(k + 1) + 2(k + 1)}}}

2

(k + 1)[(k + 1) + 1]}}}

2

E X A M P L E 1

Use mathematical

induction to prove statements

about all positive integers.

GOAL


To show that a statement is true for all positive integers n, perform these steps.

BASIS STEP: Show that the statement is true for n = 1.

INDUCTIVE STEP: Assume that the statement is true for n = k where k is any

positive integer. Show that this implies the statement is true for n = k + 1.

MATHEMATICAL INDUCTION

Extension

C H A P T E R 1 1

Florida Standardsand AssessmentMA.D.1.4.1

â ã ä å æ ç è é


Using Mathematical Induction

Let an = 3an º 1 + 1 with a1 = 1. Use mathematical induction to prove that an

explicit rule for the nth term is an = }3n

2º 1}.

SOLUTION

Basis step: Check to see that the rule works for n = 1.

a1·

}

31

2º 1} 1 = 1✓

Inductive step: Assume that ak = }3k º

21

}. Show that ak + 1 = }3k +

2

1 º 1}.

ak + 1 = 3ak + 1 Definition of an for n = k + 1

= 3S D + 1 Substitute for ak.

= }3k +

2

1 º 3} + 1 Multiply.

= }3k + 1 º

23 + 2} Add.

= }3k +

2

1 º 1} Simplify.

Therefore, an explicit rule for the nth term is an = }3n

2º 1} for all positive integers n.

EXERCISES

Use mathematical induction to prove the statement.

1. ∑n

i = 1i2 = }

n(n + 1)

6

(2n + 1)} 2. ∑

n

i = 1(2i + 1) = n(n + 2)

3. ∑n

i = 1a1ri º 1 = a1S D 4. ∑

n

i = 1(2i)2 =}

2n(n + 1

3

)(2n + 1)}

5. ∑n

i = 15i = }

5n +

4

1 º 5} 6. ∑

n

i = 1S}

12

}Di= 1 º S}

12

}Dn

7. The numbers 1, 5,12, 22, 35, 51, . . . are called pentagonal

numbers because they represent the numbers of dots used to make pentagons, as shown at the right. Prove that the nth pentagonal number Pn is given by:

Pn = }n(3n

2

º 1)}

8. LOGICAL REASONING Let ƒ1, ƒ2, . . . , ƒn, . . .be the Fibonacci sequence. Prove that f1 + ƒ2 + . . . + ƒn = ƒn + 2 º 1.

GEOMETRY CONNECTION

1 º r n

}

1 º r

3k

º 1}

2

E X A M P L E 2

â ã ä å æ ç è é

691

Chapter SummaryCHAPTER

11

WHAT did you learn?

Use summation notation to write a series. (11.1)

Find terms of sequences.• defined by explicit rules (11.1)

• defined by recursive rules (11.5)

Graph and classify sequences. (11.1º11.3)

Write rules for nth terms of sequences.• given some terms (11.1º11.3)

• arithmetic sequences (11.2)

• geometric sequences (11.3)

Find sums of series.• by adding terms or using formulas (11.1)

• finite arithmetic series (11.2)

• finite geometric series (11.3)

• infinite geometric series (11.4)

Write recursive rules for sequences. (11.5)

Use sequences and series to solve real-life problems. (11.1–11.5)

How does Chapter 11 fit into the BIGGER PICTURE of algebra?

Since elementary school you have studied number patterns (sequences). Now you canuse algebra to write and use rules for sequences and series. An arithmetic sequencehas a common difference, so it is similar to a linear function. A geometric sequencehas a common ratio, so it is similar to an exponential function. Recursive rules areused in computer programs and in spreadsheet formulas.

How did you learnby teaching?

Here is an example of anexplanation given by one studentto another, following the Study

Strategy on page 650.

STUDY STRATEGY

Learn by Teaching

Write a rule for the n th term of this sequence: 2, 7, 12, 17, . . .“First look for a common difference or a commonratio. 7 º 2 = 5, 12 º 7 = 5, and 17 º 12 = 5, sothe common difference is 5. So 5n will be part of therule. If n = 1, 5n = 5. But the first term is 2, whichis 3 less than 5, so we need to subtract 3. Let’s try5n º 3 and see if it works. 5(1) º 3 = 2, 5(2) º 3 = 7, 5(3) º 3 = 12, and 5(4) º 3 = 17.Yes, it works. So the rule is an = 5n º 3.”

WHY did you learn it?

Express the number of oranges in a stack. (p. 654)

Find angle measures at the tips of a star. (p. 656)

Find the number of fish in a stocked lake. (p. 683)

Compare the revenues of two companies. (p. 672)

Model the minimum number of moves in the Tower of Hanoi puzzle. (p. 656)

Model the number of seats in a concert hall. (p. 662)

Model the number of matches in a tennis tournament. (p. 671)

Find the number of tennis balls in a stack. (p. 656)

Find the number of cells in a honeycomb. (p. 664)

Find the cost of cellular telephone service. (p. 669)

Find the amount of money spent by tourists who receive a tourist brochure. (p. 679)

Model the number of trees on a tree farm. (p. 685)

Find the total length of the vertical supports used to build a roof. (p. 656)

ê ë ì í î ï ð ñ


Chapter ReviewCHAPTER

11

• terms of a sequence, p. 651

• sequence, p. 651

• finite sequence, p. 651

• infinite sequence, p. 651

• series, p. 653

• summation notation, p. 653

• sigma notation, p. 653

• arithmetic sequence, p. 659

• common difference, p. 659

• arithmetic series, p. 661

• geometric sequence, p. 666

• common ratio, p. 666

• geometric series, p. 668

• explicit rule, p. 681

• recursive rule, p. 681

• factorial, p. 681

VOCABULARY

11.1 AN INTRODUCTION TO SEQUENCES AND SERIES

You can find the first four terms of the sequence an = 3n º 7.

a1 = 3(1) º 7 = º4 first term

a2 = 3(2) º 7 = º1 second term

a3 = 3(3) º 7 = 2 third term

a4 = 3(4) º 7 = 5 fourth term

The sequence defined by an = 3n º 7 is º4, º1, 2, 5, . . . .

The associated series is the sum of the terms of the sequence: (º4) + (º1) + 2 + 5 + . . . .

You can use summation notation to write the series 2 + 4 + 6 + 8 + 10 as ∑5

i = 12i.

You can find the sum of a series by adding the terms or by using formulas for special series.

The sum of the series ∑22

i = 1i2 is }

n(n + 1)6(2n + 1)} = = 3795.

22(22 + 1)(2(22)+1)}}}6

Examples onpp. 651–654


1. an = n2 + 5 2. an = (n + 1)3 3. an = 6 º 2n 4. an = }n +

n3}

Write the next term in the sequence. Then write a formula for the nth term.

5. 2, 4, 6, 8, . . . 6. º3, 6, º12, 24, . . . 7. }

13}, }

19}, }2

17}, }8

11}, . . .

Write the series with summation notation.

8. 4 + 8 + 12 + 16 9. 1 + 2 + 3 + 4 + . . . 10. 0 + 3 + 6 + 9 + 12


11. ∑25

n = 1n2 12. ∑

10

n = 4n(2n º 1) 13. ∑

12

i = 1i 14. ∑

30

k = 14

EXAMPLES


Chapter Review 693

The sequence 5, 15, 45, 135, 405, . . . is a geometric sequence becausethe ratio of any term to the previous term is constant:

}

155} = 3 }

41

55} = 3 }

14355

} = 3 }

41

03

55} = 3

The common ratio is 3, so r = 3.

A rule for the nth term of this geometric sequence is:

an = a1rn º 1 = 5(3)n º 1

The sum of the first 8 terms of this geometric series is:

S8 = a1S}11ºº

rr

8}D = 5S}11º

º33

8}D = 16,400

11.2 ARITHMETIC SEQUENCES AND SERIES

The sequence 4, 7, 10, 13, 16, . . . is an arithmetic sequence because thedifference between consecutive terms is constant:

7 º 4 = 3 10 º 7 = 3 13 º 10 = 3 16 º 13 = 3

The common difference is 3, so d = 3.

A rule for the nth term of this arithmetic sequence is:

an = a1 + (n º 1)d = 4 + (n º 1)3 = 3n + 1

The sum of the first 20 terms of this arithmetic series is:

S20 = 20S}a1 +2

a20}D = 20S}4 +

261

}D = 650


Write a rule for the nth term of the arithmetic sequence.

15. 1, 7, 13, 19, 25, . . . 16. 4, 6, 8, 10, 12, . . . 17. 3.5, 3, 2.5, 2, 1.5, . . .

18. d = 5, a1 = 13 19. d = º2, a9 = 3 20. a4 = 20, a13 = 65

Find the sum of the first n terms of the arithmetic series.

21. 8 + 20 + 32 + 44 + . . . ; n = 14 22. (º6) + (º2) + 2 + 6 + . . . ; n = 20

23. 0.5 + 0.9 + 1.3 + 1.7 + . . . ; n = 54 24. (º12) + (º8) + (º4) + 0 + . . . ; n = 40

Write a rule for the nth term of the geometric sequence.

25. 64, 32, 16, 8, 4, . . . 26. 6, 12, 24, 48, . . . 27. 200, 20, 2, 0.2, 0.02, . . .

28. r = 3, a1 = 6 29. r = º}

14}, a4 = 1 30. a2 = 50, a6 = 0.005


31. ∑5

i = 116(2)i º 1 32. ∑

10

i = 120(0.2)i º 1 33. ∑

6

i = 010S}

12}Di

34. ∑8

i = 12S}

35}Di º 1

EXAMPLES

11.3 GEOMETRIC SEQUENCES AND SERIESExamples onpp. 666–669

EXAMPLES



11.4 INFINITE GEOMETRIC SERIES

You can find the sum of the infinite geometric series

∑‡

n = 14S}

35}Dn º 1

because |r| = *}

35}* < 1: S = }1

a

º1

r} = = 10.

The infinite geometric series ∑‡

n = 1}

12}(5)n º 1 has no sum because |r| = |5| ≥ 1.

4}

1 º }

35}

EXAMPLES


You can find the first five terms of the sequence defined by the recursiverule a1 = 3, an = an º 1 + n + 6.

a1 = 3 first term

a2 = an º 1 + n + 6 = a1 + 2 + 6 = 3 + 2 + 6 = 11 second term

a3 = an º 1 + n + 6 = a2 + 3 + 6 = 11 + 3 + 6 = 20 third term

a4 = an º 1 + n + 6 = a3 + 4 + 6 = 20 + 4 + 6 = 30 fourth term

a5 = an º 1 + n + 6 = a4 + 5 + 6 = 30 + 5 + 6 = 41 fifth term

The sequence is 3, 11, 20, 30, 41, . . . .

A recursive formula for the sequence 1, 5, 14, 30, . . . is a1 = 1, an = an º 1 + n2.


35. ∑‡

n = 115S}

29}Dn º 1

36. ∑‡

n = 13S}

34}Dn º 1

37. ∑‡

n = 15(0.8)n º 1 38. ∑

‡

n = 14(º0.2)n º 1

Find the common ratio of the infinite geometric series with the given sum and first

term.

39. S = 18, a1 = 12 40. S = 2, a1 = 0.5 41. S = 20, a1 = 4 42. S = º5, a1 = º2

43. S = º10, a1 = º3 44. S = 6, a1 = }

13} 45. S = }

14}, a1 = }1

16} 46. S = 3}

13}, a1 = 6

Write the repeating decimal as a fraction.

47. 0.222 . . . 48. 0.4545 . . . 49. 39.3939 . . . 50. 0.001001 . . .


51. a1 = 10 52. a1 = 1 53. a1 = 2 54. a1 = º1an = 4an º 1 an = n • an º 1 an = an º 1 º n an = (an º 1)2 + 3

Write a recursive rule for the sequence. The sequence may be arithmetic,

geometric, or neither.

55. 7, 14, 28, 56, 112, . . . 56. 4, 8, 13, 19, 26, . . . 57. 1, 6, 11, 16, 21, . . .

58. 200, 100, 50, 25, . . . 59. 1, 2, 5, 26, 677, . . . 60. º2, º6, º12, º20, . . .

11.5 RECURSIVE RULES FOR SEQUENCESExamples onpp. 681–683

EXAMPLES

ò ó ô õ ö ÷ ø ù

Chapter Test 695

Chapter TestCHAPTER

11

Tell whether the sequence is arithmetic, geometric, or neither.

Explain your answer.

1. º5, º3, º1, 1, . . . 2. º4, º2, 2, 4, . . . 3. 12, 6, 3, }

32}, . . . 4. }

13}, 1, 3, 9, . . .


5. an = n2 + 1 6. an = 3n º 5 7. a1 = 4 8. a1 = 1an = n + an º 1 an = 2an º 1

Write the next term of the sequence, and then write a rule for the nth term.

9. 2, 4, 8, 16, . . . 10. 4, 9, 14, 19, . . . 11. 2, 10, 50, 250, . . . 12. º9, º10, º11, º12, . . .

13. 5, º}

52}, }

54}, º}

58}, . . . 14. }

23}, }

34}, }

45}, }

56}, . . . 15. }

32}, }

44}, }

56}, }

68}, . . . 16. 1.1, 2.2, 3.3, 4.4, . . .

Write a recursive rule for the sequence. (Recall that d is the common difference

of an arithmetic sequence and r is the common ratio of a geometric sequence.)

17. r = 0.3, a1 = 4 18. d = 4, a1 = 1 19. 40, 20, 10, 5, . . . 20. 2, 8, 18, 32, 50, . . .


21. ∑100

i = 1i 22. ∑

5

i = 2}

12}i2 23. ∑

6

i = 1(i º 10) 24. ∑

20

i = 1(3i + 2)

25. ∑5

i = 17(º2)i º 1 26. ∑

9

i = 05S}

14}Di

27. ∑‡

i = 164Sº}

12}Di º 1

28. ∑‡

i = 1100S}1

70}D

i º 1

29. Find the sum of the first 30 terms of the arithmetic sequence 3, 7, 11, 15, . . . .

30. Find the sum of the infinite geometric series 2 + 1 + 0.5 + 0.25 + . . . .

31. Write the series 1 + 3 + 5 + 7 + 9 + 11 with summation notation.

32. Write the repeating decimal 0.7575 . . . as a fraction.

33. FALLING OBJECT An object is dropped from an airplane. During thefirst second, the object falls 4.9 meters. During the second second, it falls 14.7 meters. During the third second, it falls 24.5 meters. During the fourth second,it falls 34.3 meters. If this pattern continues, how far will the object fall during thetenth second? Find the total distance the object will fall after 10 seconds.

34. CELL DIVISION In early growth of an embryo, a human cell divides intotwo cells, each of which divides into two cells, and so on. The number an of newcells formed after the nth division is an = 2n º 1. Find the sum of the first 9 termsof the series to find the total number of new cells after the 8th division.

35. SPRING The length of the first loop of a spring is 20 inches. The length of

the second loop is }190} of the length of the first loop. The length of the third loop

is }190} of the length of the second loop, and so on. If the spring could have infinitely

many loops, would its length be finite? If so, find the length.

¬1 = 20

¬2 = }

190}(20)

. .

.

¬3 = S}190}D2(20)



Chapter Standardized TestCHAPTER

11

1. MULTIPLE CHOICE What is the next term in thesequence 1, 4, 9, 16, 25, . . .?

¡A 34 ¡B 35 ¡C 36

¡D 38 ¡E 39

2. MULTIPLE CHOICE Which series is represented by

∑4

i = 1(4i º 2)?

¡A 2 + 6 + 10 + 14

¡B º2 + 2 + 6 + 10

¡C 4 + 8 + 12 + 16

¡D 6 + 10 + 14 + 18

¡E 2 + 6 + 10 + 14 + . . .

3. MULTIPLE CHOICE What type of series is32 + 16 + 8 + 4 + 2 + 1?

¡A Finite arithmetic series

¡B Finite geometric series

¡C Infinite arithmetic series

¡D Infinite geometric series

¡E None of these

4. MULTIPLE CHOICE What is the sum of the series

∑5

n = 0(n3 + 3)?

¡A 128 ¡B 131 ¡C 240

¡D 242 ¡E 243

5. MULTIPLE CHOICE What is a rule for the nth termof the arithmetic sequence with a14 = 9 and commondifference d = 2?

¡A an = 2n + 7 ¡B an = 2n + 11

¡C an = 2n º 9 ¡D an = 2n º 15

¡E an = 2n º 19

6. MULTIPLE CHOICE What is the sum of the first 50terms of the series 2 + 17 + 32 + 47 + . . .?

¡A 1600 ¡B 18,235 ¡C 18,475

¡D 18,800 ¡E 19,125

7. MULTIPLE CHOICE What is a rule for the nth termof the geometric sequence with a3 = º12 andcommon ratio r = 3?

¡A an = º}

43

}(3)n º 1¡B an = º4(3)n º 1

¡C an = º}

34

}(3)n º 1¡D an = º}

13

}(3)n º 1

¡E an = 4(3)n º 1


∑9

i = 020S}

12

}Di

?

¡A ≈ 11.74 ¡B ≈ 13.30 ¡C ≈ 13.32

¡D ≈ 39.96 ¡E ≈ 29.97


∑‡

i = 15(1.2)i º 1?

¡A º30 ¡B º25 ¡C 25

¡D 30 ¡E The series has no sum.

10. MULTIPLE CHOICE Which fraction is equivalent tothe repeating decimal 0.3838 . . .?

¡A }

130} ¡B }

38

} ¡C }

13080

}

¡D }

1308030

} ¡E }

9398}

11. MULTIPLE CHOICE What is a recursive rule for thesequence 2, 6, 18, 54, . . .?

¡A an = 2(3)n º 1

¡B an = 3(2)n º 1

¡C a1 = 2, an = an º 1 + 4

¡D a1 = 2, an = 3an º 1

¡E a1 = 3, an = 2an º 1

12. MULTIPLE CHOICE What is the fourth term of thesequence defined by the recursive rulea1 = 3, an = n + an º 1 º 7?

¡A º1 ¡B º6 ¡C º9

¡D º10 ¡E º11

TEST-TAKING STRATEGY If the answers to a question are formulas, substitute the given

numbers into the formulas to test the possible answers.


Chapter Standardized Test 697

QUANTITATIVE COMPARISON In Exercises 13 and 14, choose the statement

that is true about the given quantities.

¡A The quantity in column A is greater.

¡B The quantity in column B is greater.

¡C The two quantities are equal.

¡D The relationship cannot be determined from the given information.

13.

14.

15. MULTI-STEP PROBLEM Use the pattern of checkerboard quilts at the right.

a. What does n represent in each quilt?

b. What does an represent in each quilt?

c. Draw the next four quilts in the pattern.

d. Complete a table that gives n and an for n = 1, 2, 3, 4, 5, 6, 7, 8.

e. Use the rule an = }

n

2

2

} + }

14

}[1 º (º1)n] to find an for n = 1, 2, 3, 4, 5, 6, 7, 8.

Compare with the results in your table. What can you conclude about thesequence defined by this rule?

16. MULTI-STEP PROBLEM Use the series 4 + 7 + 10 + 13 + 16 + 19 + 22 + 25.

a. Use a formula to find the sum of the series. Show your work.

b. Find the sum of the series without using a formula. Explain your method.

c. Write the series with summation notation. Use 1 as the lower limit ofsummation.

d. Write the series with summation notation. Use 0 as the lower limit ofsummation.

e. Write the series with summation notation. Use 4 as the lower limit ofsummation.

f. Writing Compare your answers to parts (c), (d), and (e). Describe anysimilarities and differences. Which of these ways do you prefer to write theseries? Explain your answer.

17. MULTI-STEP PROBLEM Use the sequence 100, 50, 25, 12.5, . . . .

a. Is this sequence arithmetic, geometric, or neither? Is it finite or infinite?

b. Write the next three terms of the sequence.

c. Graph the sequence. Describe the curve on which the points lie.

d. Write an explicit rule for the nth term of the sequence.

e. Write a recursive rule for the sequence.

f. Find the twelfth term of the sequence. Which rule from parts (d) and (e) didyou use? Explain your choice.

Column A Column B

The tenth term of the sequencedefined by an = 7 º 2n ∑

10

n = 1

(7 º 2n)

n! when n is an integer greater than 1 nn when n is an integer greater than 1

n = 1a1 = 1

n = 3a3 = 5

n = 4a4 = 8

n = 2a2 = 2

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