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VAIBHAV K 2JI11CV054 8 SIMPLE CURVE PROBLEM Determine the ordinates at 5m interval for 180m Radius of the si Long Chord of 60m length. SOLUTION DATA Interval = 5m Radius = R 180 m Length of Long chord= L 60 m FORMULA TABULATION Distnce 'X' from Ordinate mid point of Y (m) Long Chord (m) -30 0.000 -25 0.773 -20 1.403 -15 1.892 -10 2.240 -5 2.448 0 2.518 5 2.448 10 2.240 15 1.892 20 1.403 25 0.773 30 0.000 Y=(R 2 -X 2 ) 1/2 -(R 2 -(L/2) 2 ) 1/2

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Page 1: Simple Curve

VAIBHAV K2JI11CV054

8 SIMPLE CURVE

PROBLEM Determine the ordinates at 5m interval for 180m Radius of the simple circular curve for Long Chord of 60m length.

SOLUTIONDATA

Interval = 5 mRadius = R 180 m

Length of Long chord= L 60 m

FORMULA

TABULATION

Distnce 'X' from Ordinatemid point of Y (m)

Long Chord (m)-30 0.000-25 0.773-20 1.403-15 1.892-10 2.240-5 2.4480 2.5185 2.448

10 2.24015 1.89220 1.40325 0.77330 0.000

Y=(R2-X2)1/2-(R2-(L/2)2)1/2

Page 2: Simple Curve

GRAPH

-30 -25 -20 -15 -10 -5 0 5 10 15 20 25 300.0

0.5

1.0

1.5

2.0

2.5

3.0

CURVE BY OFFSET FROM LONG CHORD

DISTANCE (in m)

OFF

SET

(in m

)