11
Slide 1 of 54 Worked Examples Follow:

Slide 1 of 54 Worked Examples Follow:. Slide 2 of 54

  • View
    217

  • Download
    0

Embed Size (px)

Citation preview

Slide 1 of 54

Worked Examples Follow:

Slide 2 of 54

Slide 3 of 54

Slide 4 of 54

Slide 5 of 54

CRS Questions Follow:

Slide 6 of 54

What is the oxidation state of Cr in ?2-

2 7Cr O

1. +8

2. +7

3. +6

4. -1

5. -2

Slide 7 of 54

What is the oxidation state of Cr in ?2-

2 7Cr O

1. +8

2. +7

3. +6

4. -1

5. -2

Slide 8 of 54

When a piece of copper metal is put into a solution of silver nitrate (AgNO3), silver metal is produced along with Cu2+, the latter of which is responsible for the blue color of the solution. Which of the following statements is false?

1. G for the reaction is negative (the reaction is exergonic).

3. Cu is oxidized.

2. For every mole of Cu reacted, two moles of Ag is produced.

4. Ag is an oxidizing agent.

5. A solution of CuSO4 will be blue.

Slide 9 of 54

When a piece of copper metal is put into a solution of silver nitrate (AgNO3), silver metal is produced along with Cu2+, the latter of which is responsible for the blue color of the solution. Which of the following statements is false?

1. G for the reaction is negative (the reaction is exergonic).

3. Cu is oxidized.

2. For every mole of Cu reacted, two moles of Ag is produced.

4. Ag is an oxidizing agent.

5. A solution of CuSO4 will be blue.

Slide 10 of 54

1.8 x 10-4 MPb(NO3)2

0.25 M KI

Pb(s), PbI2(s)Pb(s)

For the electrochemical cell depicted to the right, which of the following is correct the shorthand notation?

+ 41. Pb(s) Pb (1.8 10 M) I (0.25 M) Pb(s)

2+ 424. Pb(s) Pb (1.8 10 M) I (0.25 M) PbI (s)

+ 423. Pb(s) Pb (1.8 10 M) I (0.25 M) Pb(s),PbI (s)

2+ 422. Pb(s) Pb (1.8 10 M) I (0.25 M) Pb(s),PbI (s)

Slide 11 of 54

1.8 x 10-4 MPb(NO3)2

0.25 M KI

Pb(s), PbI2(s)Pb(s)

For the electrochemical cell depicted to the right, which of the following is correct the shorthand notation?

+ 41. Pb(s) Pb (1.8 10 M) I (0.25 M) Pb(s)

2+ 424. Pb(s) Pb (1.8 10 M) I (0.25 M) PbI (s)

+ 423. Pb(s) Pb (1.8 10 M) I (0.25 M) Pb(s),PbI (s)

2+ 422. Pb(s) Pb (1.8 10 M) I (0.25 M) Pb(s),PbI (s)