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Copyright © 2004 Pearson Education, Inc. Slide 4-1
Systems ofSystems ofLinear EquationsLinear Equations
Chapter 4Chapter 4
Copyright © 2004 Pearson Education, Inc. Slide 4-2
Page 224, Figure 4.1
Copyright © 2004 Pearson Education, Inc. Slide 4-3
Page 225, Figure 4.2
Copyright © 2004 Pearson Education, Inc. Slide 4-4
Page 226
Copyright © 2004 Pearson Education, Inc. Slide 4-5
Page 226-227
Copyright © 2004 Pearson Education, Inc. Slide 4-6
Page 229, Figure 4.4
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Page 229, Figure 4.5
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Page 229
Copyright © 2004 Pearson Education, Inc. Slide 4-9
Page 230
Copyright © 2004 Pearson Education, Inc. Slide 4-10
Page 232, Figure 4.6
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Page 239, Figure 4.7
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Page 239-240
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Page 240
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Page 247
Copyright © 2004 Pearson Education, Inc. Slide 4-15
Page 250, Figure 4.9
Mixture Problems
Copyright © 2004 Pearson Education, Inc. Slide 4-16
The illustration above is a bit deceiving if we are adding volume of the same measurement. For example, if the first container has 3 ounces and is mixed
with the second container that has 7 ounces , the resulting container must have 10 ounces. Remember that the volume is added in the result.
The set-up:
For the illustration above, the equation we need to solve becomes:.05x+.20y=.125*10
Since x+y = 10, then y=10-x .05x+.20y=.125*10
.05x+.20(10-x)=.125*10Solving yields: x=5.
Since the total liquid is known to be 10 liters, then y must be 5 ounces in this case.
Slide Edited by Ted Koukounas