Soil Classification 1

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    Standard Practice for Classification of

    Soils for Engineering Purposes.

    (Unified Soil Classification System)[ASTM:D 248700]

    Prepared by: Sitti Aminah

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    CONTENT

    Scope

    Terminology

    Significance

    Apparatus

    Sampling

    Examples

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    SCOPE

    describes a system for classifying mineral and organo-mineral soils

    for engineering purposes based on laboratory determination of

    particle-size characteristics, liquid limit, and plasticity index and shall

    be used when precise classification is required.

    The group symbol portion of this system is based on laboratory tests

    performed on the portion of a soil sample passing the 3-in. (75-mm)

    sieve

    This standard is the ASTM version of the Unified Soil Classification

    System.

    2

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    TERMINOLOGY

    Clay

    soil passing a No. 200 (75-m) U.S. standard sieve that can be made to exhibit

    plasticity (putty-like properties) within a range of water contents and that exhibits

    considerable strength when air dry.

    Gravel

    Particles of rock that will pass a 3-in. (75-mm) sieve and be retained on a No.4

    (4.75mm) U.S. standard sieve.

    Two types:

    > Coarse: passes 3-in. (75-mm) sieve and retained on 34-in. (19-mm)

    sieve;

    > Fine: passes 34-in. (19-mm) sieve and retained on No. 4 (4.75-mm)

    sieve.

    Organic

    clay

    A soil that would be classified as a clay except that its liquid limit value after oven

    drying is less than 75 % of its liquid limit value before oven drying.

    Organic siltan organic silt is a soil that would be classified as a silt except that its liquid limit value

    after oven drying is less than 75 % of its liquid limit value before oven drying.

    Peat

    a soil composed of vegetable tissue in various stages of decomposition usually with an

    organic odor, a dark-brown to black color, a spongy consistency, and a texture ranging

    from fibrous to amorphous.

    3

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    Sand

    Particles of rock that will pass a No.4 (75-mm) sieve and be retained on a

    No.200 (75-m) U.S. standard sieve.

    Three types:

    Coarsepasses No. 4 (4.75-mm) sieve and retained on No.10 (2.00-mm)

    sieve,

    Mediumpasses No. 10 (2.00-mm) sieve and retained on No. 40 (425-m)

    sieve, and

    Finepasses No. 40 (425-m) sieve and retained on No. 200 (75-m) sieve.

    Silt

    a silt is a fine-grained soil, or the fine-grained portion of a soil, with a

    plasticity index less than 4 or if the plot of plasticity index versus liquid limit falls

    below the A line.

    4

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    Soil classification chart5

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    SIGNIFICANCE AND USE

    classifies soils from any geographic location into categories representing the

    results of prescribed laboratory tests to determine the particle-size

    characteristics, the liquid limit, and the plasticity index.

    The assigning of a group name and symbol(s) can be used to describe a soil

    to aid in the evaluation of its significant properties for engineering use. provides a useful first step in any field or laboratory investigation for

    geotechnical engineering purposes.

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    APPARATUSPlasticity Chart cumulative particle-size distribution

    curve

    7

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    SAMPLING AND SPECIMEN

    Where only the particle-size analysis of the sample is required, specimens

    having the following minimum dry weights are required:

    *Whenever possible, the field samples should

    have weights two to four times larger than

    shown.

    When the liquid and plastic limit tests must also be performed, additional material

    will be required sufficient to provide 150 g to 200 g of soil finer than the No. 40 (425-

    m) sieve.8

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    Examples

    Preliminary classification

    Procedure

    1)FINE GRAINED:

    >= 50% passNo.200 sieve

    2) COARSE GRAINED:

    > 50% retainedNo. 200 sieve

    * In this case, (100-15.2=84.8%),hence >50%retained at No. 200 sieve, COARSE GRAINED

    Example 1

    9

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    If Coarse- grainedsoil

    Retained No 4 (Gravel) = 100 - 76.5= 23.5% of the total

    soilor (23.5/84.8)(100) = 27.7%of the coarse-grained soil

    Therefore, Sand = 100 - 27.7= 72.3%of the coarse-

    grained soil.

    Since sand is more than 50% > go to Sands (Primary

    letter S)

    Sand or gravel?

    Check % of fines

    (passing No 200)

    If % fines < 5% Clean sands

    If % fines between 5-12% Dually-

    named

    If % fines > 12% Sands with fines

    *in this case, % fines (passing No 200) = 15.2%, Sands with fines,

    10

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    Check Plasticity chart

    (type of fines)

    * soil is classified as SC(Clayey Sand)

    PI = LL- PL = 18, LL = 30

    Check plasticity chart CL (clay with low

    LL)

    Thus, fines are predominantly CLAY

    Hence the Secondary letter is C

    11

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    Example 2

    Given: Sieve Opening (mm) Mass of soil retained on each sieve (kg)4.75 3

    2 1

    0.425 0.5

    0.075 0.3

    pan 0.2

    Sieve No

    Sieve Opening

    (mm)

    Mass of soil retained on each

    sieve (g)

    Percent mass

    retained

    (%)

    Cumulative percent

    retained % passing

    4 4.75 3 60 60 40

    9 2 1 20 80 20

    35 0.425 0.5 10 90 10

    200 0.075 0.3 6 96 4

    Pan 0.2 4 100 0

    Solution:

    12

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    Preliminary classification

    Procedure

    1)FINE GRAINED:

    >= 50% passNo.200 sieve

    2) COARSE GRAINED:

    > 50% retainedNo. 200 sieve

    Fineor coarse?

    * In this case, (100-4=96%),hence >50% retained at No. 200 sieve, COARSE GRAINED

    Sand or gravel?

    Retained No 4 (Gravel) = 60% of the total soilor

    (60/96)(100) = 63%of the coarse-grained soil

    Therefore, Sand = 100 - 63= 37%of the coarse-grained

    soil.

    Since gravelis more than 50% > go to Gravel (Primary

    letter G)

    Check % of fines

    (passing No 200)

    If % fines < 5% Clean gravel

    If % fines between 5-12% Dually-

    named

    If % fines > 12% Gravel with fines

    *in this case, % fines (passing No 200) = 4%, Clean g ravel

    13

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    Well Graded (W) or

    Poorly Graded (P)?Plot the distribution curve, determine

    Cuand Cc

    Grained-size distribution curve

    0

    5

    10

    15

    20

    25

    30

    35

    40

    45

    0.010.1110

    Grain Diameter (mm)

    (Log Scale)

    %P

    assing

    Find D60, D30, D10,then determine the Cuand Cc

    14

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    *D10, D30, and D60= the particle-size diameters corresponding

    to 10, 30, and 60 %, respectively, passing on the cumulative

    particle-size distribution curve.

    Well-graded gravelmust conforming to following conditions:

    *For this case, Cu = 2.3, Cc =1.3, Poorly graded gravel GP

    15

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    Example 3

    Sieve No Mass of soil retained on each sieve

    4 2

    9 2

    35 3

    200 2

    Pan 1

    Given:

    Solution:

    Sieve No Sieve Opening

    Mass of soil retained on

    each sieve

    Percent mass

    retained

    Cumulative percent

    retained

    %

    passing

    4 4.75 2 20 20 80

    9 2 2 20 40 60

    35 0.425 3 30 70 30

    200 0.075 2 20 90 10

    Pan 1 10 100 0

    PL =21, LL = 35

    16

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    Preliminary classification

    Procedure

    1)FINE GRAINED:

    >= 50% passNo.200 sieve

    2) COARSE GRAINED:

    > 50% retainedNo. 200 sieve

    Fineor coarse?

    * In this case, (100-10=90%),hence >50% retained at No. 200 sieve, COARSE GRAINED

    Sand or gravel?

    Retained No 4 (Gravel) = 20% of the total soilor

    (20/90)(100) = 22%of the coarse-grained soil

    Therefore, Sand = 100 - 22= 78%of the coarse-grained

    soil.

    Since gravelis more than 50% > go to Sand (Primary

    letter S)

    Check % of fines

    (passing No 200)

    If % fines < 5% Clean sand

    If % fines between 5-12% Dually-

    named

    If % fines > 12% sand with fines

    *in this case, % fines (passing No 200) = 10%, Dual ly n amed

    17

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    Well Graded (W) or

    Poorly Graded (P)?Plot the distribution curve, determine

    Cuand Cc

    Find D60, D30, D10,then determine the Cuand Cc

    Grain size distribution curve

    0

    10

    20

    30

    40

    50

    60

    70

    80

    90

    0.010.1110

    Grain diameter (mm)

    (Log scale)

    %p

    assing

    18

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    *D10, D30, and D60= the particle-size diameters corresponding

    to 10, 30, and 60 %, respectively, passing on the cumulative

    particle-size distribution curve.

    Well-graded gravelmust conforming to following conditions:

    *For this case, Cu = 2.8, Cc =1.3, Poorly- graded sand SP

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    Therefore, the first halfof the dual name is SP-SX

    Check plasticity chart for the x

    LL =35, PI = 35-21 = 14

    From the plasticity chart,

    xlocated at CL. Hence,

    the soil is classified asSP-SC(Poorly Graded

    sand with clay).

    20

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    Example 4

    21

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    Preliminary classification

    Procedure

    1)FINE GRAINED:

    >= 50% passNo.200 sieve

    2) COARSE GRAINED:

    > 50% retainedNo. 200 sieve

    Fineor coarse?

    * In this case, (100-2=98%),hence >50% retained at No. 200 sieve, COARSE GRAINED

    Sand or gravel?

    Retained No 4 (Gravel) = (100-48)=52% of the total soilor(52/98)(100) = 53%of the coarse-grained soil

    Therefore, Sand = 100 - 53= 47%of the coarse-grained

    soil.

    Since gravelis > 50% go to Gravel (Primary letter

    G)

    Check % of fines

    (passing No 200)

    If % fines < 5% Clean gravel

    If % fines between 5-12% Dually-

    named

    If % fines > 12% gravel with fines

    *in this case, % fines (passing No 200) = 2%, Clean gravel

    22

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    Well Graded (W) or

    Poorly Graded (P)?Plot the distribution curve, determine

    Cuand Cc

    Find D60, D30, D10,then determine the Cuand Cc

    Grain size distribution curve

    0

    10

    20

    30

    40

    50

    60

    70

    80

    90

    0.010.1110

    Grain diameter (mm)

    (Log scale)

    %p

    assing

    23

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    *D10, D30, and D60= the particle-size diameters corresponding

    to 10, 30, and 60 %, respectively, passing on the cumulative

    particle-size distribution curve.

    Well-graded gravelmust conforming to following conditions:

    *For this case, Cu = 4.8, Cc =2.2, Well- graded gravel GP

    24

    25

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    Example 5Sieve Opening Mass of soil retained on each sieve

    4.75 3

    2 1

    0.425 0.1

    0.075 0.2

    0.7

    LL = 62, PL= 44

    Sieve No Sieve Opening

    Mass of soil retained on each

    sieve

    Percent mass

    retained

    Cumulative percent

    retained % passing

    4 4.75 3 60 60 40

    10 2 1 20 80 20

    40 0.425 0.1 2 82 18

    200 0.075 0.2 4 86 14

    Pan 0.7 14 100 0

    25

    26

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    % passing No. 200 = 14%

    LL = 62, PI = 62 -44 = 18, MH.

    Hence, GM Silty Gravel

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    Example 6

    PI= 4216 = 36;

    PI plotted above A

    line with LL

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    Example 7

    PI= 6338 = 25;

    PI plotted above A

    line with LL >50,

    MH (Elastic silt)

    28

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    Example 8

    PI= 7025 = 45;

    PI plotted above A

    line with LL >50,

    CH (Fat Clay)

    29

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    Example 9

    PI= 2822 = 6;

    PI plotted below A

    line with LL

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    Example 10

    PI= 4643 = 3

    (less than 4)

    PI plotted below A line

    with LL

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    Thank you