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Solving Systems of Linear Equations by Elimination. Session 6 Practice Test – Sept. 13 LT # 2 – Sept. 15. Objective. Solve a system of linear equations in two variables by the elimination method. 3x – y = 12 (1) 2x + y = 13 (2). +. 5x = 25. x = 5. - PowerPoint PPT Presentation
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Solving Systems of Linear Equations by Elimination
Session 6
Practice Test – Sept. 13
LT # 2 – Sept. 15
ObjectiveSolve a system of linear
equations in two variables by the elimination method.
3x – y = 12 (1)2x + y = 13 (2)
By what operation can we eliminate a variable in the given system?
+
5x = 25
x = 5
3x – y = 12 (1)2x + y = 13 (2)
How do we find the value of y?
+
5x = 25
x = 5
3(5) – y = 12
y = 3
(5, 3)
3x – y = 12 (1)2x + y = 13 (2)
How do we know if the values of x and y are correct?
+
5x = 25
x = 5
3(5) – y = 12
y = 3
(5, 3)
3x – y = 12 (1)2x + y = 13 (2)
How do we know if the values of x and y are correct?
(5, 3)
3(5) – 3 = 12
15 – 3 = 12
12 = 12
2(5) + 3 = 13
10 + 3 = 13
13 = 13
(5, 3)
3x + 7y = 173x - 6y = 4
Example 1 page 154
4x - 5y = 17x - 5y = 8
Example 2 page 155
SYSTEMS THAT HAVE ONLY ONE SOLUTION(Consistent, Independent)
x – 2y = -6 4x + 3y = 20
SYSTEMS THAT HAVE NO SOLUTION(Inconsistent)
y = -1/2x + 2y = -1/2x + 3
SYSTEMS THAT HAVE NO SOLUTION(Inconsistent)
2x – 3y = 66x – 9y = 36
y = -3x + 1y = -3x + 1
SYSTEMS THAT HAVE MORE THAN ONE SOLUTION(Consistent, Dependent)
4x + 6y = 46x + 9y = 6
SYSTEMS THAT HAVE MORE THAN ONE SOLUTION(Consistent, Dependent)
For further understanding http://www.purplemath.com/modules/sy
stlin5.htm
http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut19_systwo.htm#elimination
http://www.regentsprep.org/Regents/math/ALGEBRA/AE3/AlgSysAdd.htm
http://www.youtube.com/watch?v=6c7OPYQLVG0&feature=relmfu
HomeworkExercise 5c # 2
NSM Book 2 page 163
3x + 2y = 84x - y = 7
More Examples on Elimination
13x - 6y = 207x + 4y = 18
More Examples on Elimination
More Examples on Elimination