Two Rational Roots

Solve x2 – 8x = 33 by using the Quadratic Formula.

First, write the equation in the form ax2 + bx + c = 0 and identify a, b, and c.

x2 – 8x = 33 1x2 – 8x – 33 = 0

ax2 + bx + c = 0

Then, substitute these values into the Quadratic Formula.

Quadratic Formula

Two Rational Roots

Replace a with 1, b with –8, and c with –33.

Simplify.

Simplify.

Two Rational Roots

x = 11 x = –3Simplify.

Answer: The solutions are 11 and –3.

or Write as two equations.

A. 15, –2

B. 2, –15

C. 5, –6

D. –5, 6

Solve x2 + 13x = 30 by using the Quadratic Formula.

One Rational Root

Solve x2 – 34x + 289 = 0 by using the Quadratic Formula.

Identify a, b, and c. Then, substitute these values into the Quadratic Formula.

Quadratic Formula

Replace a with 1, b with –34, and c with 289.

Simplify.

One Rational Root

Check A graph of the related function shows that there is one solution at x = 17.

Answer: The solution is 17.

[–5, 25] scl: 1 by [–5, 15] scl: 1

A. 11

B. –11, 11

C. –11

D. 22

Solve x2 – 22x + 121 = 0 by using the Quadratic Formula.

Irrational Roots

Solve x2 – 6x + 2 = 0 by using the Quadratic Formula.

Quadratic Formula

Replace a with 1, b with –6, and c with 2.

Simplify.

or or

Irrational Roots

Check Check these results by graphing the related quadratic function, y = x2 – 6x + 2. Using the ZERO function of a graphing calculator, the approximate zeros of the related function are 0.4 and 5.6.

Answer:

[–10, 10] scl: 1 by [–10, 10] scl: 1

A.

B.

C.

D.

Solve x2 – 5x + 3 = 0 by using the Quadratic Formula.

Complex Roots

Solve x2 + 13 = 6x by using the Quadratic Formula. Quadratic Formula

Replace a with 1, b with –6, and c with 13.

Simplify.

Simplify.

Complex Roots

A graph of the related function shows that the solutions are complex, but it cannot help you find them.

Answer: The solutions are the complex numbers 3 + 2i and 3 – 2i.

[–5, 15] scl: 1 by [–5, 15] scl: 1

Complex Roots

x2 + 13 = 6x

Original equation

Check To check complex solutions, you must substitute them into the original equation. The check for 3 + 2i is shown below.

(3 + 2i)2 + 13 = 6(3 + 2i) x = (3 + 2i)

?

9 + 12i + 4i2 + 13 = 18 + 12iSquare of a sum; Distributive Property

?

22 + 12i – 4 = 18 + 12iSimplify.

?

18 + 12i = 18 + 12i

A. 2 ± i

B. –2 ± i

C. 2 + 2i

D. –2 ± 2i

Solve x2 + 5 = 4x by using the Quadratic Formula.

Describe Roots

A. Find the value of the discriminant for x2 + 3x + 5 = 0. Then describe the number and type of roots for the equation.

a = 1, b = 3, c = 5

b2 – 4ac = (3)2 – 4(1)(5)Substitution

= 9 – 20 Simplify.

= –11 Subtract.Answer: The discriminant is negative, so there are two complex roots.

Describe Roots

B. Find the value of the discriminant for x2 – 11x + 10 = 0. Then describe the number and type of roots for the equation.

a = 1, b = –11, c = 10

b2 – 4ac = (–11)2 – 4(1)(10)Substitution

= 121 – 40 Simplify.

= 81 Subtract.Answer: The discriminant is 81, so there are two rational roots.

A. 0; 1 rational root

B. 16; 2 rational roots

C. 32; 2 irrational roots

D. –64; 2 complex roots

A. Find the value of the discriminant for x2 + 8x + 16 = 0. Describe the number and type of roots for the equation.

A. 0; 1 rational root

B. 36; 2 rational roots

C. 32; 2 irrational roots

D. –24; 2 complex roots

B. Find the value of the discriminant for x2 + 2x + 7 = 0. Describe the number and type of roots for the equation.

• Section 6 (pg 270):

• 15 – 45 odd, 34, 46 (23 problems)