Stat Mech Overview Sci2

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  • 8/10/2019 Stat Mech Overview Sci2

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    N

    f

    p

    q

    q

    p

    Rf

    f

    p

    q

    Rf

    i

    pi

    H(q, p)

    pidpidt

    =H

    qi;

    qi

    dqidt

    = H

    pi,

    i [1, f]

    (q, p)

    M,

    (q, p)

    fi=1dqidpi (q, p) (q, p)

    fi=1dqidpi

    (q, p)

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    (q,p,t)

    ddt

    = 0.

    t

    +f

    i=1

    qi

    qi+ pi

    pi

    = 0

    )=

    t+

    fi=1

    qi

    Hpi

    + pi

    Hqi

    = 0.

    (p,q,t)t

    = 0

    s.s =(H(q, p))

    N V E

    N

    V

    T

    V

    T

    N V E

    (N , V , E )

    N V E = constant N V E(q, p) 1

    ,

    (N , V , E )

    1/(N , V , E )

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    N V T

    T

    E

    NV T(q, p)

    exp(H(q, p))

    = (kBT)1

    T

    kB

    N

    V

    T

    ZN(V, T) =

    dq

    dp exp(H(q, p))

    N V T(q, p) = exp (H(q, p)) /Z

    V T

    E H

    V T(q,p,N) exp((HN(q, p) N))

    V T =

    N

    dq

    dp exp((HN(q, p) N)) =

    N=0eNZN(V, T)

    |(ra, rb)|

    2 = |(rb, ra)|2

    (ra, rb) = (rb, ra)

    (ra, rb) = (rb, ra)

    (r1, r2 = r1) = 0

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    r

    nr r r

    r

    r

    nr =N;

    r

    nrr =E.

    {n1, n2, n3, }

    nr = 0 1 nr = 0, 1, 2, 3, 4,

    P({n1, n2, }) exp

    r

    nrr

    r

    nr

    =

    r

    exp[nr(r )] .

    P({n1, n2, }) =

    r

    pr(nr); pr(nr) exp[nr(r )]

    nr pr(nr) = 1,

    pr(nr) =exp[nr(r )]

    S ,

    S=

    nr

    exp[nr(r )] ,

    nr = {0, 1} S

    SFD, r = 1 + exp [(r )] = 1 +xr xr = exp [(r )]

    nr = {0, 1, 2, 3, } S

    SBE, r = 1 + xr+ x2r+ x3r+ = 11xr .

    SFDBE , r = (1 xr)1

    F D

    r

    pFDBE

    , r = xnrr

    (1 xr)1 , xr = exp [(r )] .

    nr =

    nrnrpr =

    0x0r+1x

    1r

    (1+xr)

    , nr = {0, 1}

    0x0r+1x1r +mx

    mr +

    (1xr)1 , nr = {0, 1, 2, 3, 4

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