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Statistics in Hydrology Mean, median and mode (central tendency) Dispersion: the spread of the items in a data set around its central value

Statistics in Hydrology

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Statistics in Hydrology. Mean, median and mode (central tendency) Dispersion: the spread of the items in a data set around its central value. Statistics in Hydrology. Measure of central tendency Measure of dispersion ModeRange MedianQuartile deviation MeanStandard dev. - PowerPoint PPT Presentation

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Page 1: Statistics in Hydrology

Statistics in Hydrology

• Mean, median and mode (central tendency)

• Dispersion: the spread of the items in a data set around its central value  

Page 2: Statistics in Hydrology

Statistics in Hydrology

Measure of central tendency Measure of dispersion

Mode RangeMedian Quartile deviationMean Standard dev.

Page 3: Statistics in Hydrology

Statistics in Hydrology

Page 4: Statistics in Hydrology

Statistics in Hydrology

Why do we need to include variance/SD?

Page 5: Statistics in Hydrology

Probability

• We need to know its probability of occurrence (the level of peak Q likely to occur/100 years (moving to inferential stats) 

Page 6: Statistics in Hydrology

Probability

Page 7: Statistics in Hydrology

Probability

Page 8: Statistics in Hydrology

Probability

Example 1

What is the probability that an individual value will be more than 1.5 S.D. below the mean in normally distributed data? 

a. Draw a diagram  

Page 9: Statistics in Hydrology

Probability

b. If the area under the curve = 100%, then the area below 1.5 S.D. below the mean represents the probability we require

Page 10: Statistics in Hydrology

Probability

Page 11: Statistics in Hydrology

Probability

c. With z = 1.5 then p = 0.9932%. Look at the table again! It lists p values > 50% (not always required value); be careful!

Page 12: Statistics in Hydrology

Probability

d. the probability we require is 1 - 0.9332 = 0.0668 e. The probability that an individual value will be more than 1.5 S.D. below the mean in the data set is 6.68% At home: What is the probabilityof getting less than 500 mm of rainfall in any one year inEdinburgh, Scotland given a mean annual rainfall of 664 mm and a S.D. of 120 mm?

Page 13: Statistics in Hydrology

Risk

Risk = probability * consequence

Page 14: Statistics in Hydrology

Probability

Fi = m/(n + 1) * 100

where Fi = cum. % frequency  

Page 15: Statistics in Hydrology

Hypothesis Testing

• Sampling from a larger population  

Null hypothesis: no significant difference between the figures (H0)

 Alternative hypothesis: is a significant difference between the figures (H1)

  • Level of significance (0.05 and 0.01)  

Page 16: Statistics in Hydrology

Hypothesis Testing

Daily Q: Mean = 200 l/day S.D. = 30 l/day

  Sample = 128 litres

SD = 30 * 1.96 = 58.8 L

95% of obs. should lie between 141.2and 258.8 L  

Page 17: Statistics in Hydrology

Correlation and Regression

Observation Oil consumption (gallons)

Temperature (oC)

1 11.5 11.5

2 13.5 11.0

3 13.8 10.5

4 15.0 7.5

5 16.2 8.0

6 17.0 7.0

7 18.5 7.5

8 22.0 3.5

9 22.3 3

Page 18: Statistics in Hydrology

Correlation and Regression

25

0 2 4 6 8 10 12

Temperature (C)

Oil

consu

mp

tion

(g

)

20

15

10

5

0

Page 19: Statistics in Hydrology

Correlation and Regression

Correlation coefficient(r)

Coefficient of determination(r2) Lies between 0 and 1 Proportion of variation of Y associated with variations in X r = 0.96; r2 = 0.92  

Page 20: Statistics in Hydrology

Correlation and Regression

y = a + bx (y = mx + c) 

y = 1 + 0.5x  

0

0.5

1

1.5

2

2.5

3

0 0.5 1 1.5 2 2.5 3 3.5 4

Page 21: Statistics in Hydrology

Correlation and Regression

• Least squares

Page 22: Statistics in Hydrology

Non-linear Regression

0

2

4

6

8

10

0 50 100 150Discharge (m^3/s)

SS

C (

t/d

ay)

Page 23: Statistics in Hydrology

Non-linear Regression

logy = a + b logx (y = 0.8393x - 1.2253)r^2 = 0.8534

-2.0-1.5-1.0-0.50.00.51.01.5

0.0 1.0 2.0 3.0log Discharge (m^3/s)

log

SS

C (

t/d

ay)

Page 24: Statistics in Hydrology

Non-linear Regression

y = 0.0595x0.8393

R2 = 0.8534

0.1

1.0

10.0

1 10 100 1000Discharge (m^3/s)

SS

C (

t/d

ay)