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Stoichiometry Unit 6

Stoichiometry

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Stoichiometry. Unit 6. Topic 1. Intro / mole to mole. Stoichiometry. Quantitative study of chemical reactions The basic question - how much? - is the object of stoichiometry . - PowerPoint PPT Presentation

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Page 1: Stoichiometry

Stoichiometry

Unit 6

Page 2: Stoichiometry

Topic 1

• Intro / mole to mole

Page 3: Stoichiometry

Stoichiometry

• Quantitative study of chemical reactions• The basic question - how much? - is the

object of stoichiometry.• Example: How many grams of silver

chloride are produced when 17.0 grams of silver nitrate react with excess sodium chloride?

Page 4: Stoichiometry

Basic Stoichiometry• Always starts with a balanced equation.

• From the balanced equation we can determine the molar ratios.

• Remember that the coefficients refer to the number of moles of each reactant or product there are in the balanced equation.

• So in this equation 2 moles of aluminum oxide decompose to form 4 moles of aluminum metal and 3 moles of oxygen gas.

Al2O3 Al + O22 4 3

Page 5: Stoichiometry

Basic Stoichiometry

• So for 2 moles of aluminum oxide, three moles of oxygen gas will be produced. Therefore, the molar ratio of aluminum oxide to oxygen gas would be 2:3

• What would the ratio of aluminum metal to oxygen gas be?

Al2O3 Al + O22 4 3

43

Page 6: Stoichiometry

Writing Mole Factors

4 Fe + 3 O2 2 Fe2O3 Fe and O2 4 mole Fe and 3 mole O2

3 mole O2 4 mole Fe

Fe and Fe2O3 4 mole Fe and 2 mole Fe2O3

2 mole Fe2O3 4 mole Fe

O2 and Fe2O3 3 mole O2 and 2 mole Fe2O3

2 mole Fe2O3 3 mole O2

Page 7: Stoichiometry

Learning Check S1

3 H2(g) + N2(g) 2 NH3(g)

A. A mole factor for H2 and N2 is1) 3 mole N2 2) 1 mole N2 3) 1 mole N2

1 mole H2 3 mole H2 2 mole H2

B. A mole factor for NH3 and H2 is1) 1 mole H2 2) 2 mole NH3 3) 3 mole N2

2 mole NH3 3 mole H2 2 mole NH3

Page 8: Stoichiometry

1. Mole-to-Mole conversion

given Mole of A (coeff.)Mole of B (coeff.)Mole of A

Page 9: Stoichiometry

Example4 Fe + 3 O2 2 Fe2O3

Given Unknown

How many moles of Fe2O3 are produced when

6.0 moles O2 react?

6.0 mole O2 2 mole Fe2O3 = 4.0 mole Fe2O3

3 mole O2

Page 10: Stoichiometry

Practice 1

4 Fe + 3 O2 2 Fe2O3

How many moles of Fe are needed to react with 12.0 mole of O2?

Page 11: Stoichiometry

Solution

4 Fe + 3 O2 2 Fe2O3

12.0 mole O2 4 mole Fe = 16.0 mole Fe 3 mole O2

Page 12: Stoichiometry

Practice 2

4 Fe + 3 O2 2 Fe2O3

How many moles of O2 are needed to produce

0.400 mole of Fe2O3?

Page 13: Stoichiometry

Topic 2

• Mass to mole or mole to mass

Page 14: Stoichiometry

2. Mole to Mass/Mass to Mole conversion

mole of A (co) mole of B Molar mass of B (co) mole of A 1 mole of B

Mass(g) of A 1mole A (co)mole of B molar mass of A (co) mole of A

Page 15: Stoichiometry

Example

4 Fe + 3 O2 2 Fe2O3

How many grams of O2 are needed to produce

0.400 mole of Fe2O3?

What’s given? Moles of Fe2O3

What’s unknown? Grams of O2

Plan: Convert moles of Fe2O3 to moles of O2. Then convert moles of O2 to grams of O2.

Page 16: Stoichiometry

Solution

0.400 mole Fe2O3 3 mole O2 32.0 g O2

2 mole Fe2O3 1 mole O2

= 19.2 g O2

Page 17: Stoichiometry

Practice

• 4 Fe + 3 O2 2 Fe2O3

• How many grams of Fe is needed to produce 0.400 mole of Fe2O3?

• How many grams of Fe2O3 is produced from 5 moles of Fe and excess O2?

Page 18: Stoichiometry

Unit 6 Topic 3

• Mass to mass conversion

Page 19: Stoichiometry

3. Mass to mass conversion

Mass(g) of A 1mole A (co)mole of B molar mass(g) of B molar mass(g) of A (co) mole of A 1mole B

Page 20: Stoichiometry

The reaction between H2 and O2 produces 13.1 g of water. How many grams of O2 reacted?Write the equationH2 (g) + O2 (g) H2O (g)

Balance the equation 2 H2 (g) + O2 (g) 2 H2O (g)

Identify what’s given and what’s “unknown”

Example

Page 21: Stoichiometry

2 H2 (g) + O2 (g) 2 H2O (g)

Start w/grams given

1 mole of givenMolar mass ofGiven(g)

Moles of“unknown”(coefficient)

Moles of given (coefficient)

Molar mass of“unknown”

1 mole“unknown”

grams “unknown”

=

given unknown

g H2O mole H2O mole O2 g O2

Page 22: Stoichiometry

13.1 g H2O 1 mole H2O 1 mole O2 32.0 g O2 18.0 g H2O 2 mole H2O 1 mole O2

= 11.6 g O2

Page 23: Stoichiometry

Practice

How many grams of O2 are needed to react w/ 50.0 grams of Na in the reaction

4 Na + O2 2 Na2O

Complete the set up:

50.0 g Na 1 mole Na 23.0 g Na

Page 24: Stoichiometry

Solution

4 Na + O2 2 Na2O

50.0 g Na 1 mole Na 1 mole O2 32.0 g

23.0 g Na 4 mole Na 1 mole O2

= 17.4 g O2

Page 25: Stoichiometry

Practice

Acetylene gas C2H2 burns in the oxyactylene torch for welding. How many grams of C2H2 are burned if the reaction produces 75.0 g of CO2?

2 C2H2 + 5 O2 4 CO2 + 2 H2O

Page 26: Stoichiometry

Solution

2 C2H2 + 5 O2 4 CO2 + 2 H2O

75.0 g CO2 1 mole CO2 2 mole C2H2 26.0 g C2H2

44.0 g CO2 4 mole CO2 1 mole C2H2

= 22.2 g C2H2

Page 27: Stoichiometry

Pathways for Problems Using Equations

Given (A) Unknown (B) grams (A) grams (B)

molar molar mass (A) mass (B) coefficients

moles (A) moles (B) Avogadro's Avogadro’s

number number

particles (A) particles (B)