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Surface Area Slideshow 49, Mathematics Mr Richard Sasaki Room 307

Surface Area

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Surface Area. Slideshow 49, Mathematics Mr Richard Sasaki Room 307. Objectives. Review how to find the area of various polygons Learn how to calculate the surface area of cuboids, triangular prisms and square-based pyramids Learn how to calculate the surface area of a cylinder. Answers. - PowerPoint PPT Presentation

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Page 1: Surface Area

Surface Area

Slideshow 49, MathematicsMr Richard Sasaki

Room 307

Page 2: Surface Area

Objectivesβ€’ Review how to find the area of

various polygonsβ€’ Learn how to calculate the

surface area of cuboids, triangular prisms and square-based pyramids

β€’ Learn how to calculate the surface area of a cylinder

Page 3: Surface Area

Answers15π‘π‘š2 49π‘π‘š2 8π‘π‘š2

108π‘π‘š2 91π‘π‘š2 70π‘π‘š2

26π‘π‘š2 135π‘π‘š2 204 π‘π‘š2

Page 4: Surface Area

Surface AreaWhat is surface area?The total area of faces & surfaces on a 3D shape.Calculating surface area for cuboids and triangular prisms is easy as long as we know the dimensions of each face.

5π‘π‘š 2π‘π‘š3π‘π‘š

5π‘π‘š 2π‘π‘š3π‘π‘š2π‘π‘š3π‘π‘š

Page 5: Surface Area

Surface Area - Cuboid

5π‘π‘š 2π‘π‘š3π‘π‘š

5π‘π‘š 2π‘π‘š3π‘π‘š2π‘π‘š

3π‘π‘š

All we do is add the total area of each face.

10π‘π‘š215π‘π‘š210π‘π‘š26π‘π‘š2 6π‘π‘š215π‘π‘š2

We just simply add the numbers together.10+15+10+15+6+6ΒΏ20+30+12

ΒΏ62π‘π‘š2

Page 6: Surface Area

Triangular PrismVisualising a net is always good!

4π‘π‘š10π‘π‘š

5π‘π‘š

3π‘π‘š

10π‘π‘š4π‘π‘š3π‘π‘š5π‘π‘š3π‘π‘š

4π‘π‘š

Surface Area: (10 βˆ™4 )+ΒΏ(10 βˆ™3 )+ΒΏ(10 βˆ™5 )+ΒΏ(0.5 βˆ™ 4 βˆ™3 ) βˆ™2ΒΏ 40+ΒΏ30+ΒΏ50+ΒΏ12ΒΏ132π‘π‘š2

Page 7: Surface Area

2 (1βˆ™1 )+4 (3 βˆ™1 )=14 π‘π‘š2

(5 βˆ™10 )+(5 βˆ™8 )+ (5 βˆ™6 )+2 (0.5 βˆ™6Γ—8 )ΒΏ168π‘π‘š2

6 (6 βˆ™6)=216π‘π‘š2

(12 βˆ™5 )+(12βˆ™ 4 )+ (12 βˆ™3 )+2 (0.5 βˆ™3Γ—4 )ΒΏ156π‘π‘š2

2 (2 βˆ™8 )+2 (11 βˆ™8 )+2 (2 βˆ™11 )=252π‘π‘š2

(7 βˆ™13 )+(7 βˆ™12 )+(7 βˆ™5 )+2 (0.5 βˆ™5Γ—12 )ΒΏ270π‘π‘š2

Page 8: Surface Area

Square-Based PyramidsLet’s have a look at the square based pyramid.

π‘Žπ‘Žπ‘™

π‘Žπ‘Žπ‘™

This should be easy to calculate the surface area with too!

Page 9: Surface Area

Example

4π‘π‘š7π‘π‘š

4π‘π‘š7π‘π‘š

Surface Area:

42+ΒΏ(4 βˆ™7 βˆ™ 12 )βˆ™ 4ΒΏ16+56ΒΏ72π‘π‘š2

Square-Based Pyramids

Page 10: Surface Area

40π‘π‘š2 45π‘š2 161π‘šπ‘š2

56π‘π‘š2 105π‘˜π‘š2 1035π‘˜π‘š2

Page 11: Surface Area

Let’s calculate the surface area of a cylinder with its radius and length.Example

π‘Ÿπ‘™

ΒΏ2π‘šΒΏ10π‘š

We know the cylinder is made of two and, if flattened a

.

circlesrectangl

e

2π‘š10π‘š

𝐢=2πœ‹ π‘Ÿ4πœ‹π‘š

Cylinders

Page 12: Surface Area

2π‘š10π‘š

𝐢=2πœ‹ π‘Ÿ4πœ‹π‘š

S.A =

ΒΏ8πœ‹+40πœ‹ΒΏ 48πœ‹π‘š2

Note: Formulae for surface area will not be provided on the test as calculations are simply sums of areas of polygons and circles. Some formulae for polygons and circles will be provided.

Cylinders

Page 13: Surface Area

48πœ‹π‘π‘š2 152πœ‹π‘π‘š2 84 πœ‹π‘š2

3.5πœ‹π‘š2 480πœ‹π‘šπ‘š2 16πœ‹ π‘˜π‘š2

Answers