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Tehnička mehanika-statika, rešeni zadaci

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Chapter 1Januar 20071.1 Uslovni zadatak1ˇ TEHNICKA MEHANIKA 1 26.01.2007.1.2Prvi zadatakˇ Cvor F: X = 0 : SEF = 10 Y = 0 : SF G = 10 Deo E-G-C:ME Y X= = =0 : 10 · 5 − YC · 3 = 0 0 : YE + 16.67 − 10 = 0 0 : XE = 10⇒ YC = 16.67 ⇒ YE = −6.67Deo A-D-B:Beograd, januar 2006Page 2 of 10ˇ TEHNICKA MEHANIKA 1 26.01.2007.MA=0: −15 · 1.5 + 20 · 2 − 10 − 6.67 · 10 −10 · 6 + 15 − YB · 8 = 0⇒ YB = −13.025 MD = 0: −10 − 6.67 · 6 + 15 + 13.025 · 4 − XB · 6 = 0 ⇒ XB = 2.85

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Chapter 1

Januar 20071.1 Uslovni zadatak

1

TEHNICKA MEHANIKA 1 26.01.2007.

1.2

Prvi zadatak

Cvor F: X = 0 : SEF = 10 Y = 0 : SF G = 10 Deo E-G-C:

ME Y X

= = =

0 : 10 5 YC 3 = 0 0 : YE + 16.67 10 = 0 0 : XE = 10

YC = 16.67 YE = 6.67

Deo A-D-B:

Beograd, januar 2006

Page 2 of 10

TEHNICKA MEHANIKA 1 26.01.2007.

MA

=

0: 15 1.5 + 20 2 10 6.67 10 10 6 + 15 YB 8 = 0

YB = 13.025 MD = 0: 10 6.67 6 + 15 + 13.025 4 XB 6 = 0 XB = 2.85 Y = 0: YA 20 + 6.67 13.025 = 0 YA = 26.355 X = 0: XA 10 + 2.85 15 = 0 Deo A-B: MA XA = 22.15 = 0: 20 2 13.025 8 + YB 8 = 0 YB = 18.025 Y = 0: YA 26.355 + 20 + 13.025 18.025 = 0 YA = 11.355 X = 0: 22.15 2.85 + XA = 0 XA = 25 (1.2) (1.1)

Beograd, januar 2006

Page 3 of 10

TEHNICKA MEHANIKA 1 26.01.2007.

Stvarni smerovi sila i optereenja na krajevima: c

Beograd, januar 2006

Page 4 of 10

TEHNICKA MEHANIKA 1 26.01.2007.

N

T

M

Beograd, januar 2006

Page 5 of 10

TEHNICKA MEHANIKA 1 26.01.2007.

1.3

Drugi zadatak

Deo E-C: ME = 0: 28 3.5 20 2 15 2.5 YC 5 = 0 YC = 4.1 Y = 0: YE 28 + 15 + 4.1 = 0 YE = 8.9 X=0: Deo D-G-H: MH = XE = 20 0: 20 3.5 + SGD 5.5 15 = 0 SGD = 15.45 Y = 0: YH 20 + 15.45 = 0 YH = 4.55 X Deo A-D-B: = 0: XH = 0

Beograd, januar 2006

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TEHNICKA MEHANIKA 1 26.01.2007.

MA

=

0: 56 7 + 20 + 15.45 7 + 8.9 14 20 4 + 4.55 12.5 YB 14 = 0

YB = 44.4levo MD

(1.3)

=

0: 40.5 7 + 20 28 3.5 XA 4 = 0

XA = 51.375 Y = 0: YA + 44.4 56 15.45 4.55 8.9 = 0 YA = 40.5 X = 0: XB + 51.375 20 = 0 XB = 31.375

Stvarni smerovi sila i optereenja na krajevima: c

Beograd, januar 2006

Page 7 of 10

TEHNICKA MEHANIKA 1 26.01.2007.

N

T

M

Beograd, januar 2006

Page 8 of 10

TEHNICKA MEHANIKA 1 26.01.2007.

1.4

Trei zadatak c

N

Ty

Tz

Mt

Mz

My

Beograd, januar 2006

Page 9 of 10

Contents1 Januar 2007 1.1 Uslovni zadatak 1.2 Prvi zadatak . 1.3 Drugi zadatak . 1.4 Trei zadatak . c 1 1 2 6 9

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