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Test - 09 (Code E) (Answers) All India Aakash Test Series for Medical-2018
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1. (1)
2. (2)
3. (3)
4. (4)
5. (2)
6. (3)
7. (1)
8. (4)
9. (3)
10. (2)
11. (4)
12. (2)
13. (1)
14. (1)
15. (1)
16. (2)
17. (3)
18. (4)
19. (1)
20. (4)
21. (2)
22. (3)
23. (4)
24. (3)
25. (1)
26. (3)
27. (2)
28. (2)
29. (4)
30. (3)
31. (1)
32. (3)
33. (3)
34. (3)
35. (1)
36. (2)
Test Date : 08/04/2018
TEST - 09 (Code E)
All India Aakash Test Series for Medical - 2018
ANSWERS
37. (2)
38. (4)
39. (4)
40. (4)
41. (1)
42. (2)
43. (3)
44. (1)
45. (4)
46. (1)
47. (2)
48. (2)
49. (3)
50. (1)
51. (1)
52. (4)
53. (1)
54. (2)
55. (4)
56. (1)
57. (2)
58. (3)
59. (1)
60. (4)
61. (3)
62. (2)
63. (3)
64. (1)
65. (4)
66. (2)
67. (3)
68. (2)
69. (1)
70. (2)
71. (3)
72. (1)
73. (2)
74. (3)
75. (2)
76. (1)
77. (1)
78. (2)
79. (4)
80. (2)
81. (3)
82. (3)
83. (2)
84. (3)
85. (1)
86. (2)
87. (4)
88. (3)
89. (2)
90. (4)
91. (3)
92. (3)
93. (2)
94. (1)
95. (3)
96. (2)
97. (2)
98. (1)
99. (3)
100. (2)
101. (4)
102. (4)
103. (4)
104. (3)
105. (4)
106. (3)
107. (2)
108. (3)
109. (2)
110. (4)
111. (1)
112. (1)
113. (2)
114. (2)
115. (4)
116. (1)
117. (2)
118. (3)
119. (1)
120. (4)
121. (4)
122. (3)
123. (2)
124. (1)
125. (1)
126. (4)
127. (1)
128. (2)
129. (4)
130. (1)
131. (4)
132. (1)
133. (3)
134. (4)
135. (2)
136. (3)
137. (3)
138. (3)
139. (3)
140. (3)
141. (4)
142. (4)
143. (3)
144. (3)
145. (3)
146. (4)
147. (4)
148. (4)
149. (3)
150. (2)
151. (3)
152. (3)
153. (4)
154. (3)
155. (3)
156. (3)
157. (2)
158. (4)
159. (3)
160. (2)
161. (2)
162. (3)
163. (3)
164. (4)
165. (2)
166. (1)
167. (3)
168. (4)
169. (3)
170. (3)
171. (2)
172. (3)
173. (3)
174. (4)
175. (1)
176. (3)
177. (3)
178. (2)
179. (1)
180. (3)
All India Aakash Test Series for Medical-2018 Test - 09 (Code E) (Hints)
2/9
PHYSICS
1. According to principle of homogeneity,
6 2 2 6 8 2
6
AE A Er ML T L ML T
r
⇒
12 2 2 12 14 2
12
BE B Er ML T L ML T
r
⇒
2.1 2
1 2
t tt
t t
t1 = 90 s
t = 36 s
t2 = ?
2
2
9036
90
t
t
36 × 90 + 36t2 = 90t
2
36 × 90 = 54t2
2
36 9060 s
54t
3.1 2
cot cot 602 3
u u u u
tg g g
4.
mgcosmg
mgsin
f
h
r-h
RO
f = N
mgsin = mgcos = tanBut, h = r(1 – cos)
2
11
1
⎛ ⎞ ⎜ ⎟⎜ ⎟ ⎝ ⎠
h r
5. m1u
1 + m
2u
2 = m
1v
1 + m
2v
2From, u
1 – u
2 = v
2 – v
1
3 3 3
1 2 2 20r u r u r v 2u = v
2 – 0
3 3 3
1 2 2(2 )r u r u r u v
2 = 2u
3 3
1 23r u r u
HINTS
3
3 1
23
rr
1
2 1/3 1/33 3
r rr
6.
L
4
C1
C2
C
O
/2x
From OCC1,
cos2
4
x
L
cos4 2
Lx
7.21(1 )
2mgh mv
2
(1 )2
vgh
5 11
2 2
gRgh
⎛ ⎞ ⎜ ⎟⎝ ⎠
5 3 15
2 2 4
R Rh
8. u = uf – u
i
2 21 1( )
2 2k a b ka
2 2 21[( 2 )]
2k a b ab a
21[ 2 ]
2k b ab
1( 2 )
2kb b a
9. Acceleration of block is 6 2
3 3= = =
Fa
m m m
For block 2m, N 2m
N = 2ma
22 4 N= ⇒N m
m
Test - 09 (Code E) (Hints) All India Aakash Test Series for Medical-2018
3/9
10.Δ ρ
= =⎛ ⎞Δ Δ ⎟⎜ ⎟⎜ ⎟⎜⎝ ⎠
P ghB
V V
V V
11. F1 = Force due to complete sphere
24
GMm
R
F2 = Force due to removed portion of sphere
2 2
8
9 18
4
⎛ ⎞⎜ ⎟⎝ ⎠
MG m
GMm
R R
Fnet
= Force due to remaining part of sphere
1 2 2
1 1
4 18
GMmF F
R
⎛ ⎞ ⎜ ⎟⎝ ⎠
2 2
9 2 7 7
36 9 94
GMm GMm F
R R
⎛ ⎞ ⎛ ⎞ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠
12. Compare with equation, x = acost
In 3 s, its distance is 3a
2
24 s
2
⇒ TT
13. Conceptual
14. Let h be the height will the ball jump out of water.
Using work energy theorem,
WB + W
gravity = KE
FBh
– W(h + h) = 0
1⎛ ⎞⎟⎜′ = − ⎟⎜ ⎟⎟⎜⎝ ⎠
BF
h hW
water
body
1
⎛ ⎞ρ ⎟⎜ ⎟⎜′ = − ⎟⎜ ⎟⎜ ρ ⎟⎜⎝ ⎠h h
900
1000
⎛ ⎞⎟⎜′ = −⎟⎜ ⎟⎟⎜⎝ ⎠h h
2 cm9
′ = ⇒h
h
15. 2= πE
E
LT
g, 2= π
M
m
LT
g
2
2
E
m E
M
Tg g
T
⎛ ⎞⎟⎜ ⎟⎜= ⎟⎜ ⎟⎜ ⎟⎝ ⎠
16. 1
2
T
T 1 15
2 30
t
t
15 ( 15)
2t 30 – t = 2t – 30
110 (30 )
2t 60 = 3t t = 20°C
17.1
1dw
dQ r
75 3 11
4 4dQ dQ = 300 J
18.
2 2half half
2complete complete
(Area) 2 3
(Area) 44
E R R
E R
19. xLice
= msx × 80 = 40 × 1 × 60
x = 30 g
Mass of ice = 50 – 30 = 20 g
Mass of water = 40 + 30 = 70 g
20.90°
( )TA
BCT
C = ?
L
2 L
2 )T(
L
Using, KA
HL
HBC
= HCA
2 ( )
2
c C
KA T T KA T T
L L
2 2C C
T T T T
33 2 1
2 1C C
TT T T ⇒
21. n w
2 2
1 1
n w
n w
1 2
1 1
2n w
n w
w2 = 4w
1= 4 × 4
w2 = 16 kg wt.
All India Aakash Test Series for Medical-2018 Test - 09 (Code E) (Hints)
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22. Temp.n
1
2
n T
n T
10000 1 10016.67 Hz
2 2 300 6
n Tn
T
23. Conceptual
24. kr2 = constant
25.a a
–q –qQ
u12
+ u23
+ u13
= 0
2
02
Qq Qq q
a a a
22
1 : 42
⇒ Qq q Q
a a q
26. ts = t
1 + t
2 = 45 min
tp =
1 2
1 2
15 3010 min
45
t t
t t
45 9
10 2
s
p
t
t
27.
2
volume
L LR
A
2 3 3
RVL
3
L
28.1
2
lx
R l
1
2
20 11
80 4
lx R
l
2 21 2
4 4 1 2
l r r
A
⇒
6
64 102 10 ohm-m.
2
29. = BA 0
MH A
V
⎛ ⎞ ⎜ ⎟⎝ ⎠ 0
pm
H AA
⎛ ⎞ ⎜ ⎟⎝ ⎠
= 0(AH + m
p)
30. F = Bqv
2VqF Bq
m
as, 21
2mv Vq
F V
2 2
1 1
F V
F V
2
2
22
F VF F
F V ⇒
31. A
B
C
D
E
F
Mnet
= 2 M 2 i A
10 102 3
100 100 23
1.4 0.042 Am100
32.1
wC
2 1
1 1
w C
w KC
100 1
125 K
51.25
4K K = 1.56
33. Conceptual
34. Momentum, 2 2E IAt
pC C
4
8
2 24 3.5 3.5 10 60 60
3 10
= 2.2×10–6
35.2
n
nhJ mvr
2n
nhp
r
...(i)
Again, de Broglie’s wavelength
2
2
n n
h h r
nhp n
r
⇒ ⎛ ⎞⎜ ⎟⎝ ⎠
...(ii)
Test - 09 (Code E) (Hints) All India Aakash Test Series for Medical-2018
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2 2
2
2 2 2
(i)( )
(ii) 2 2 4 4⇒
n
n
J nh n h n h nr n
r r n
constant
n
n n
n
JJ ⇒
36. U r2, dU
Fdr
F r,
2mv
r
r
v r ...(i)
From angular momentum,
2
nhmvr
nr
v
...(ii)
From (i) & (ii), r n37. A = A
0e–t
90
03
II e
9 1
3e
Later, 18
0A I e
29
0I e
2
0
1
3I⎛ ⎞ ⎜ ⎟⎝ ⎠
0
9
IA
38. dNN
dt
AmNdN
dt M
39.5 216
K.E220
d
d
Qm
m m = 4.9 MeV.
40.1 2
1 1 1
F f f
1 1 1 5 8 3
40 25 200 200
F
200 cm
3F
Power = 100 100 3
1.5 Din cm 200
F
41.
u = 20 cm
O
Power of system, P = 2PL + P
m
1 2 2
15
L
F f
F = –7.5 cm
From mirror formula,
1 1 1 1 1 1
75 20F v u v
⇒
1 1 1012 cm
20 75v
v
⇒
42.1 11
tan cot cot ⎛ ⎞ ⎛ ⎞ ⇒ ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠
v
c
43. ⇒ d
d
i iv n
neA v
7 4 4.
5 7 5 e e n
h h e
n i v
n i v
44. Apply the truth table, verify with .A B A
45.
98
10049
2
100
C
B
I
I
CHEMISTRY
46.2 3 2 2
X O 3H 2X 3H O
1 mol 3 mol
(2a 48)g 6 g
∵ 0.006 g H2 is required by 0.3192 g oxide
6 g H2 will be required by 319.2 g oxide.
2a + 48 = 319.2
a = 135.6 amu
47. Magnetic quantum number (m) represents the
orientation to atomic orbitals in three-dimensional
space.
48. Cr (Z = 24) = 1s22s22p6 3s23p63d54s1
n + l = 4 is for orbitals 4s and 3p
Hence the number of electrons in orbitals having
n + l = 4 is equal to 7.
All India Aakash Test Series for Medical-2018 Test - 09 (Code E) (Hints)
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49. On Pauling scale,
Electronegativity of an atom = I.P E.A
2 2.8
,
where I.P. and E.A are in eV.
50. H– = 208 pm, I– = 216 pm.
51. H – O – BO – H
O – H,2Na
+
HO – BO
O
B
B
B – OH 8H O2
O
O
OH
1 2
4
3
OH
1 & 2 3 = sp2
3 & 4 4 = sp3
3 = sp2
O
2–
52. Solubility of salts depend on hydration enthalpy and
lattice ethalpy. If hydration enthalpy decreases and
lattice enthalpy increases, the solubility of salt will
decrease.
53.
A
3 NK.E R 150 x
2 N ...(i)
A
3 yK.E R 300 2x
2 N ...(ii)
Dividing 1 by 2, y = N molecules.
54. The fraction of molecules with most probable speed
decreases on increasing temperature.
55. For the process, H2O(�) H
2O(g)
ng = 1 – 0 = 1
We know, H = U + ngRT
40.66 × 1000 = U + 1 × 8.314 × 373
U = 37559 J mol–1
U = 8.98 kcal mol–1 (∵ 1 kcal = 4.18 kJ)
56. 3 2Ag Fe Ag Fe
3 2cell Fe /Fe Ag /AgE E E
= 0.77 – 0.80 V = –0.03 V
cell
oE 0
Hence not fesible.
57.i
2 4 4H SO H HSO
Cathode : 2
2H 2e H
Anode : 4 2 2 8
2HSO H S O 2e
58. pKa = –log
1010–6
= 6
a
[Salt]pH pK log
[Acid]
(1/ 3)6 log
(2 / 3)
6 log2
5.7
59.
2 2H I 2HI
Initial mole 15 5.2 0
eq. mole 15 5 5.2 5 10
+
− −
���⇀↽���
2
c p2 2
[HI] 100K or K 50
[H ][I ] 10 0.2
G = G° + RT lnQ
At eq., G = 0
G°= –8.314 × 800 × 2.303 log10
50
= –26040 J
= –26 kJ
60. *1s, *2pz and 2p
x have one nodal plane each
whereas *2py has two nodal plane.
61.
CH3
CH3
CH3
Reductive3
Ozonolysis3CH C CHO
||O
62. p = pA + p
B
2 3120 80
5 5 = 96 torr.
mole fraction of B in the vapour phase,
YB = B
total
380
p 15
p 96 2
63. As A Ahas higher activation energy hence it will
be slowest and rate determining step.
64. Order of reaction may by fractional.
65. % Packing = Area of one circle
100Area of square
2
2
r100 25
(2r)
66. C.N. of Fe in ferrocene is = 10
C.N. of Pt in zeise’s salt is = 4
Fe
Pt
(CN) 10 5
(CN) 4 2
67. en forms chelate.
Test - 09 (Code E) (Hints) All India Aakash Test Series for Medical-2018
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68.
base
Acid acid
V1.4 M n V
n%N
W
⎛ ⎞ ⎜ ⎟⎝ ⎠
W = Weight of organic compound
n = n factor of acid used
3
1.4 0.2 1(30 20)
200 10 g
31.4 2 10
14%200
69. Cell reaction, Ni(s) + 2H+(aq) Ni2+(aq) + H2(g)
22
o o ocell H |H Ni |Ni
E E E 0.236
2
2
Ho
cell cell 10 2
[p ][Ni ]0.0591E E log
n [H ]
10 2
0.0591 1 10 0.236 log
2 [H ]
0.05910.236 2 pH
2 10
1log pH
[H ]
⎛ ⎞⎜ ⎟⎜ ⎟
⎝ ⎠∵
0.236
pH 40.0591
70. Geometrical isomers = 22 = 4
71. U.I. = (H N)
(C 1)2
(91 3)(50 1) 51 44 7
2
72. [Fe(ox)3]3– is optically active.
E.A.N. in both = 26 – 3 + 6 × 2 = 35, hence do
not follow EAN rule.
Fe3+ 3d 5, due to one unpaired electron both
are paramagnetic.
73. NO2 is EWG and when present at para position
increases acidic strength of phenols.
74. Species b, c, d are antiaromatic compounds.
75. H
3 2 3CH CH CH CH CH
3 2 2 3CH CH CH CH CH
or 3 2 2 3
CH CH CH CH CH
both are secondary carbocation.
76. O
CH MgBr3 CH
3
OMgBr
HOH CH3
OH
+ MgBrOH
77.+ HC – C H
6 5
O
OH/
O
CH – C H6 5
O
78. Since reaction intermediate is a carbanion, therefore
E.W.G stabilize the carbanion.
79.H /
6 5 2Glucose 3C H NH NH
Osazone of glucose + C6H
5NH
2 + NH
3
80.
CH = CH2
H+
CH – CH3
CH – CH – CH2
CH3
Intramolecular Friedel
craft reaction.
CH3
CH = CH2
+ H+
82. PbS is black colour.
83. Emulsification of micelles takes place.
84. KF + AlF3 3K+ + [AlF
6]3–
85. Number of unpaired electrons, Mn2+ = 5, Cr2+ = 4,
V2+ = 3.
Magnetic moment is proportional to the number of
unpaired electrons.
86.2 4 2
ZnS 4NaCN Na [Zn(CN) ] Na S.
87.
OO
O O
O
P
P
P = OO = P O
O
O
All P atoms are sp3 hybridised.
1% s-character 100 25%
4
88. Lattice energy depends on charge and size of the
ions.
89. As2S
3 is a negatively charged sol therefore according
to Hardy schulze rule higher the valency of cation
good is flocculating agent.
90. All these species have acidic hydrogen.
All India Aakash Test Series for Medical-2018 Test - 09 (Code E) (Hints)
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BIOLOGY
91. Zoospore are flagellated motile spores.
Conidia are non motile asexual spore found in
fungi (Penicillium).
Rhizome is underground stem modification
found in ginger, turmeric, banana.
Bulbils are large fleshy bud present in Agave.
92. Epidermis, endothecium and middle layer perform
function of protection.
Tapetum is the innermost layer of anther wall.
Each lobe of anther has two microsporangia.
93. Family and genus are taxonomic category.
94. Only recessive trait can be expressed in
homozygous state.
(i) Yellow pod colour
(ii) Constricted pod shape
(iii) Wrinkled seed shape
(iv) Terminal flower position
95. Meiocyte is 2n(diploid) = 20 chromosome
Tube nucleus – (n) – 10 chromosome
PEC – (3n) – 30 chromosome
Nucellus – (2n) – 20 chromosome
Synergid – (n) – 10 chromosome
96. Zostera is marine plant which show hydrophily.
97. Hybrid produced in garden pea are fertile.
98. G = 14%
Guanine = cytosine C = 14%
Thymine = adenine where remaining 72% are A & T
So A = 36%, T = 36%
99. Three biodiversity hot spots present in India are
Western Ghats and Sri Lanka
Indo – Burma
Himalaya
100. Immunosuppressive agent Cyclosporin-A is obtained
from Trichoderma polysporum.
103. Clown fish and sea anemone show
commensalism.
Barnacles Balanus and Chathamalus show
competition.
Tiger and deer show predation.
Fig (Ficus) and Fig wastes show mutualism.
104. Eltonian pyramids are ecological pyramid.
These pyramids assume simple food chain and can
not accommodate food web.
107. Life cycle of Drosophila is two weeks.
Male and female are easily distinguishable.
108. UTRs are present at both end at 5 end before start
codon and at 3 end after stop codon.
111. Klinefelter’s syndrome have
(a) 44 + XXY Trisomy
(b) Sterile males with overall musculine development
(e) Testicular atrophy (small testes)
112. (Sigma) is initiation factor
(Rho) is termination factor
115. a. About 13%
b. Homofermentaive lactic acid bacteria,
(Lactobacillus lacti)
116. Allen’s rule
119. Cymose inflorescence.
120. A – Mammals
B – Reptiles
C – Fishes
123. Lema, Peru – CoP 20
125. N2O – 6%
CO2 – 60%
CFC – 14%
CH4 – 20%
127. Phloem parenchyma is present in dicot stem, but
absent in monocot stem.
128. Dichogamy
129. Inversion of C and D segment.
130. Frequency of PPQqRrSSTt is
1 1 1 1 1 1
2 2 2 2 2 32
133.uses
31 NH 4e ;4H ;8ATP
135. Coding strand is non template strand of double
stranded DNA.
mRNA
5 AUCGGCUACGA 3
Sequence on template strand
3 TAGCCGATGCT 3
Test - 09 (Code E) (Hints) All India Aakash Test Series for Medical-2018
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Sequence on non template or coding strand
5 ATCGGCTACGA 3
This can be written as
3 AGCATCGGCTA 5
136. Dope test is done to estimate alcohol and other
drugs level in blood by blood sampling not through
breath analysis.
137. Cellular oncogenes are growth promoter genes
that upon undergoing mutations lead to overgrowth.
139. Coxal is hip bone formed by fusion of ilium, ischium
and pubis. At the point of fusion of all these three
bones, a cavity called acetabulum is present.
140. Adrenaline increases heart rate.
141. Glossopharyngeal is a mixed nerve.
142. The activity of enzymes increases with increase in
substrate conc. till they achieve steady state.
143. Cysteine is a sulphur containing amino acid.
144. Sma I produces blunt ends.
All others e.g., Bam HI, Sal I and Pst I produce
sticky ends.
145. Fact.
147. hPL is maternal growth hormone of pregnancy.
148. Ascending limb of loop of Henle being permeable to
electrolytes and impermeable to water makes the
filtrate hypo-osmotic to plasma.
149. Inhibin hormone further brings down the level of FSH.
150. The combined pills are taken for 21 days, starting
preferably within the first five days of menstrual
cycle.
151. Fact.
152. Exoskeleton is made up of four plates called
sclerites in each segment.
(i) Structures of mastication are mandibles.
(ii) Excretory product of cockroach is uric acid.
153. Flatworms are also bilaterally symmetrical and
triploblastic and show cephalisation.
154. Typhoid, pertussis, diphtheria and cholera are caused
by bacteria.
155. In ectinoderms, mouth is on ventral side and anus is
on dorsal side, e.g. Asterias.
In molluscs, organ of Bojanus is the excretory organ
and teeth of sharks are modified placoid scales.
156. They are all non-chordates having double ventral solid
nerve cord.
157. Neutrophils and monocytes perform the function of
phagocytosis.
158. Adrenaline – Emergency hormone.
159. Deposition of uric acid in joints is gout.
Autoimmune disorder of muscles is myasthenia
gravis.
Disorder of joints associated with inflammation of
joints is rheumatoid arthritis.
160. Fact.
161. A decrease in body fluid volume stimulates ADH
release.
164. Mutations are sources of variations hence bring
changes in gene frequencies.
165. Fact
166. One thick filament is composed of many meromyosin
molecules.
167. The corticoids which are involved in carbohydrate
metabolism are glucocorticoids, mainly cortisol.
168. In test tube baby programme, ova from the wife/
donor female and sperms from husband/donor male
are collected and are induced to form zygote under
simulated conditions in the laboratory.
169. Mendel established purelines by inbreeding.
170. Parasympathetic nervous system stimulates salivary
secretion and peristaltic contractions.
171. Asthma is difficulty in breathing causing wheezing
due to inflammation of bronchi and bronchioles.
172. At low pO2 carbamino haemoglobin is stable and at
high pO2 carbamino haemoglobin is unstable.
173. Fact
174. Morphine is obtained from Papaver somniferum.
175. All our blood cells develop in bone marrow.
176. ‘C’ being circular will move fastest towards anode.
177. Fact
178. Fact
179. Sponges are pore bearing animals. They have water
transport or canal system. Echinoderms have water
vascular system.
180. Units of compound eyes are ommatidia.
� � �
Test - 09 (Code F) (Answers) All India Aakash Test Series for Medical-2018
1/9
1. (4)
2. (1)
3. (3)
4. (2)
5. (1)
6. (4)
7. (4)
8. (4)
9. (2)
10. (2)
11. (1)
12. (3)
13. (3)
14. (3)
15. (1)
16. (3)
17. (4)
18. (2)
19. (2)
20. (3)
21. (1)
22. (3)
23. (4)
24. (3)
25. (2)
26. (4)
27. (1)
28. (4)
29. (3)
30. (2)
31. (1)
32. (1)
33. (1)
34. (2)
35. (4)
36. (2)
Test Date : 08/04/2018
TEST - 09 (Code F)
All India Aakash Test Series for Medical - 2018
ANSWERS
37. (3)
38. (4)
39. (1)
40. (3)
41. (2)
42. (4)
43. (3)
44. (2)
45. (1)
46. (4)
47. (2)
48. (3)
49. (4)
50. (2)
51. (1)
52. (3)
53. (2)
54. (3)
55. (3)
56. (2)
57. (4)
58. (2)
59. (1)
60. (1)
61. (2)
62. (3)
63. (2)
64. (1)
65. (3)
66. (2)
67. (1)
68. (2)
69. (3)
70. (2)
71. (4)
72. (1)
73. (3)
74. (2)
75. (3)
76. (4)
77. (1)
78. (3)
79. (2)
80. (1)
81. (4)
82. (2)
83. (1)
84. (4)
85. (1)
86. (1)
87. (3)
88. (2)
89. (2)
90. (1)
91. (2)
92. (4)
93. (3)
94. (1)
95. (4)
96. (1)
97. (4)
98. (2)
99. (1)
100. (4)
101. (1)
102. (1)
103. (2)
104. (3)
105. (4)
106. (4)
107. (1)
108. (3)
109. (2)
110. (1)
111. (4)
112. (2)
113. (2)
114. (1)
115. (1)
116. (4)
117. (2)
118. (3)
119. (2)
120. (3)
121. (4)
122. (3)
123. (4)
124. (4)
125. (4)
126. (2)
127. (3)
128. (1)
129. (2)
130. (2)
131. (3)
132. (1)
133. (2)
134. (3)
135. (3)
136. (3)
137. (1)
138. (2)
139. (3)
140. (3)
141. (1)
142. (4)
143. (3)
144. (3)
145. (2)
146. (3)
147. (3)
148. (4)
149. (3)
150. (1)
151. (2)
152. (4)
153. (3)
154. (3)
155. (2)
156. (2)
157. (3)
158. (4)
159. (2)
160. (3)
161. (3)
162. (3)
163. (4)
164. (3)
165. (3)
166. (2)
167. (3)
168. (4)
169. (4)
170. (4)
171. (3)
172. (3)
173. (3)
174. (4)
175. (4)
176. (3)
177. (3)
178. (3)
179. (3)
180. (3)
All India Aakash Test Series for Medical-2018 Test - 09 (Code F) (Hints)
2/9
PHYSICS
1.
98
10049
2
100
C
B
I
I
2. Apply the truth table, verify with .A B A
3. ⇒ d
d
i iv n
neA v
7 4 4.
5 7 5 e e n
h h e
n i v
n i v
4.1 11
tan cot cot ⎛ ⎞ ⎛ ⎞ ⇒ ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠
v
c
5.
u = 20 cm
O
Power of system, P = 2PL + P
m
1 2 2
15
L
F f
F = –7.5 cm
From mirror formula,
1 1 1 1 1 1
75 20F v u v
⇒
1 1 1012 cm
20 75v
v
⇒
6.1 2
1 1 1
F f f
1 1 1 5 8 3
40 25 200 200
F
200 cm
3F
Power = 100 100 3
1.5 Din cm 200
F
7.5 216
K.E220
d
d
Qm
m m = 4.9 MeV.
HINTS
8. dNN
dt
AmNdN
dt M
9. A = A0e–t
90
03
II e
9 1
3e
Later, 18
0A I e
29
0I e
2
0
1
3I⎛ ⎞ ⎜ ⎟⎝ ⎠
0
9
IA
10. U r2, dU
Fdr
F r,
2mv
r
r
v r ...(i)
From angular momentum,
2
nhmvr
nr
v
...(ii)
From (i) & (ii), r n
11.2
n
nhJ mvr
2n
nhp
r
...(i)
Again, de Broglie’s wavelength
2
2
n n
h h r
nhp n
r
⇒ ⎛ ⎞⎜ ⎟⎝ ⎠
...(ii)
2 2
2
2 2 2
(i)( )
(ii) 2 2 4 4⇒
n
n
J nh n h n h nr n
r r n
constant
n
n n
n
JJ ⇒
Test - 09 (Code F) (Hints) All India Aakash Test Series for Medical-2018
3/9
12. Momentum, 2 2E IAt
pC C
4
8
2 24 3.5 3.5 10 60 60
3 10
= 2.2×10–6
13. Conceptual
14.1
wC
2 1
1 1
w C
w KC
100 1
125 K
51.25
4K K = 1.56
15. A
B
C
D
E
F
Mnet
= 2 M 2 i A
10 102 3
100 100 23
1.4 0.042 Am100
16. F = Bqv
2VqF Bq
m
as, 21
2mv Vq
F V
2 2
1 1
F V
F V
2
2
22
F VF F
F V ⇒
17. = BA 0
MH A
V
⎛ ⎞ ⎜ ⎟⎝ ⎠ 0
pm
H AA
⎛ ⎞ ⎜ ⎟⎝ ⎠
= 0(AH + m
p)
18.1
2
lx
R l
1
2
20 11
80 4
lx R
l
2 21 2
4 4 1 2
l r r
A
⇒
6
64 102 10 ohm-m.
2
19.
2
volume
L LR
A
2 3 3
RVL
3
L
20. ts = t
1 + t
2 = 45 min
tp =
1 2
1 2
15 3010 min
45
t t
t t
45 9
10 2
s
p
t
t
21.a a
–q –qQ
u12
+ u23
+ u13
= 0
2
02
Qq Qq q
a a a
22
1 : 42
⇒ Qq q Q
a a q
22. kr2 = constant
23. Conceptual
24. Temp.n
1
2
n T
n T
10000 1 10016.67 Hz
2 2 300 6
n Tn
T
25. n w
2 2
1 1
n w
n w
1 2
1 1
2n w
n w
w2 = 4w
1= 4 × 4
w2 = 16 kg wt.
All India Aakash Test Series for Medical-2018 Test - 09 (Code F) (Hints)
4/9
26.90°
( )TA
BCT
C = ?
L
2 L
2 )T(
L
Using, KA
HL
HBC
= HCA
2 ( )
2
c C
KA T T KA T T
L L
2 2C C
T T T T
33 2 1
2 1C C
TT T T ⇒
27. xL
ice = ms
x × 80 = 40 × 1 × 60
x = 30 g
Mass of ice = 50 – 30 = 20 g
Mass of water = 40 + 30 = 70 g
28.
2 2half half
2complete complete
(Area) 2 3
(Area) 44
E R R
E R
29.1
1dw
dQ r
75 3 11
4 4dQ dQ = 300 J
30. 1
2
T
T 1 15
2 30
t
t
15 ( 15)
2t 30 – t = 2t – 30
110 (30 )
2t 60 = 3t t = 20°C
31. 2= πE
E
LT
g, 2= π
M
m
LT
g
2
2
E
m E
M
Tg g
T
⎛ ⎞⎟⎜ ⎟⎜= ⎟⎜ ⎟⎜ ⎟⎝ ⎠
32. Let h be the height will the ball jump out of water.
Using work energy theorem,
WB + W
gravity = KE
FBh
– W(h + h) = 0
1⎛ ⎞⎟⎜′ = − ⎟⎜ ⎟⎟⎜⎝ ⎠
BF
h hW
water
body
1
⎛ ⎞ρ ⎟⎜ ⎟⎜′ = − ⎟⎜ ⎟⎜ ρ ⎟⎜⎝ ⎠h h
900
1000
⎛ ⎞⎟⎜′ = −⎟⎜ ⎟⎟⎜⎝ ⎠h h
2 cm9
′ = ⇒h
h
33. Conceptual
34. Compare with equation, x = acost
In 3 s, its distance is 3a
2
24 s
2
⇒ TT
35. F1 = Force due to complete sphere
24
GMm
R
F2 = Force due to removed portion of sphere
2 2
8
9 18
4
⎛ ⎞⎜ ⎟⎝ ⎠
MG m
GMm
R R
Fnet
= Force due to remaining part of sphere
1 2 2
1 1
4 18
GMmF F
R
⎛ ⎞ ⎜ ⎟⎝ ⎠
2 2
9 2 7 7
36 9 94
GMm GMm F
R R
⎛ ⎞ ⎛ ⎞ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠
36.Δ ρ
= =⎛ ⎞Δ Δ ⎟⎜ ⎟⎜ ⎟⎜⎝ ⎠
P ghB
V V
V V
37. Acceleration of block is 6 2
3 3= = =
Fa
m m m
For block 2m, N 2m
N = 2ma
22 4 N= ⇒N m
m
38. u = uf – u
i
Test - 09 (Code F) (Hints) All India Aakash Test Series for Medical-2018
5/9
2 21 1( )
2 2k a b ka
2 2 21[( 2 )]
2k a b ab a
21[ 2 ]
2k b ab
1( 2 )
2kb b a
39.21(1 )
2mgh mv
2
(1 )2
vgh
5 11
2 2
gRgh
⎛ ⎞ ⎜ ⎟⎝ ⎠
5 3 15
2 2 4
R Rh
40.
L
4
C1
C2
C
O
/2x
From OCC1, cos
2
4
x
L
cos4 2
Lx
41. m1u
1 + m
2u
2 = m
1v
1 + m
2v
2From, u
1 – u
2 = v
2 – v
1
3 3 3
1 2 2 20r u r u r v 2u = v
2 – 0
3 3 3
1 2 2(2 )r u r u r u v
2 = 2u
3 3
1 23r u r u3
3 1
23
rr
1
2 1/3 1/33 3
r rr
42.
mgcosmg
mgsin
f
h
r-h
RO
f = N
mgsin = mgcos = tanBut, h = r(1 – cos)
2
11
1
⎛ ⎞ ⎜ ⎟⎜ ⎟ ⎝ ⎠
h r
43.1 2
cot cot 602 3
u u u u
tg g g
44.1 2
1 2
t tt
t t
t1 = 90 s, t = 36 s, t
2 = ?
2
2
9036
90
t
t
36 × 90 + 36t2 = 90t
2
36 × 90 = 54t2
2
36 9060 s
54t
45. According to principle of homogeneity,
6 2 2 6 8 2
6
AE A Er ML T L ML T
r
⇒
12 2 2 12 14 2
12
BE B Er ML T L ML T
r
⇒
CHEMISTRY
46. All these species have acidic hydrogen.
47. As2S
3 is a negatively charged sol therefore according
to Hardy schulze rule higher the valency of cation
good is flocculating agent.
48. Lattice energy depends on charge and size of the
ions.
49.
OO
O O
O
P
P
P = OO = P O
O
O
All P atoms are sp3 hybridised.
1% s-character 100 25%
4
All India Aakash Test Series for Medical-2018 Test - 09 (Code F) (Hints)
6/9
50.2 4 2
ZnS 4NaCN Na [Zn(CN) ] Na S.
51. Number of unpaired electrons, Mn2+ = 5, Cr2+ = 4,
V2+ = 3.
Magnetic moment is proportional to the number of
unpaired electrons.
52. KF + AlF3 3K+ + [AlF
6]3–
53. Emulsification of micelles takes place.
54. PbS is black colour.
56.
CH = CH2
H+
CH – CH3
CH – CH – CH2
CH3
Intramolecular Friedel
craft reaction.
CH3
CH = CH2
+ H+
57.H /
6 5 2Glucose 3C H NH NH
Osazone of glucose + C6H
5NH
2 + NH
3
58. Since reaction intermediate is a carbanion, therefore
E.W.G stabilize the carbanion.
59.+ HC – C H
6 5
O
OH/
O
CH – C H6 5
O
60. O
CH MgBr3 CH
3
OMgBr
HOH CH3
OH
+ MgBrOH
61. H
3 2 3CH CH CH CH CH
3 2 2 3CH CH CH CH CH
or 3 2 2 3
CH CH CH CH CH
both are secondary carbocation.
62. Species b, c, d are antiaromatic compounds.
63. NO2 is EWG and when present at para position
increases acidic strength of phenols.
64. [Fe(ox)3]3– is optically active.
E.A.N. in both = 26 – 3 + 6 × 2 = 35, hence do
not follow EAN rule.
Fe3+ 3d 5, due to one unpaired electron both
are paramagnetic.
65. U.I. = (H N)
(C 1)2
(91 3)(50 1) 51 44 7
2
66. Geometrical isomers = 22 = 4
67 Cell reaction, Ni(s) + 2H+(aq) Ni2+(aq) + H2(g)
22
o o ocell H |H Ni |Ni
E E E 0.236
2
2
Ho
cell cell 10 2
[p ][Ni ]0.0591E E log
n [H ]
10 2
0.0591 1 10 0.236 log
2 [H ]
0.05910.236 2 pH
2 10
1log pH
[H ]
⎛ ⎞⎜ ⎟⎜ ⎟
⎝ ⎠∵
0.236
pH 40.0591
68.
base
Acid acid
V1.4 M n V
n%N
W
⎛ ⎞ ⎜ ⎟⎝ ⎠
W = Weight of organic compound
n = n factor of acid used
3
1.4 0.2 1(30 20)
200 10 g
31.4 2 10
14%200
69. en forms chelate.
70. C.N. of Fe in ferrocene is = 10
C.N. of Pt in Zeise’s salt is = 4
Fe
Pt
(CN) 10 5
(CN) 4 2
71. % Packing = Area of one circle
100Area of square
2
2
r100 25
(2r)
72. Order of reaction may by fractional.
73. As A Ahas higher activation energy hence it will
be slowest and rate determining step.
Test - 09 (Code F) (Hints) All India Aakash Test Series for Medical-2018
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74. p = pA + p
B
2 3120 80
5 5 = 96 torr.
mole fraction of B in the vapour phase,
YB = B
total
380
p 15
p 96 2
75.
CH3
CH3
CH3
Reductive3
Ozonolysis3CH C CHO
||O
76. *1s, *2pz and 2p
x have one nodal plane each
whereas *2py has two nodal plane.
77.
2 2H I 2HI
Initial mole 15 5.2 0
eq. mole 15 5 5.2 5 10
+
− −
���⇀↽���
2
c p2 2
[HI] 100K or K 50
[H ][I ] 10 0.2
G = G° + RT lnQ
At eq., G = 0
G°= –8.314 × 800 × 2.303 log10
50
= –26040 J
= –26 kJ
78. pKa = –log
1010–6
= 6
a
[Salt]pH pK log
[Acid]
(1/ 3)6 log
(2 / 3)
6 log2
5.7
79.i
2 4 4H SO H HSO
Cathode : 2
2H 2e H
Anode : 4 2 2 8
2HSO H S O 2e
80. 3 2Ag Fe Ag Fe
3 2cell Fe /Fe Ag /AgE E E
= 0.77 – 0.80 V = –0.03 V
cell
oE 0
Hence not fesible.
81. For the process, H2O(�) H
2O(g)
ng = 1 – 0 = 1
We know, H = U + ngRT
40.66 × 1000 = U + 1 × 8.314 × 373
U = 37559 J mol–1
U = 8.98 kcal mol–1 (∵ 1 kcal = 4.18 kJ)
82. The fraction of molecules with most probable speed
decreases on increasing temperature.
83.
A
3 NK.E R 150 x
2 N ...(i)
A
3 yK.E R 300 2x
2 N ...(ii)
Dividing 1 by 2, y = N molecules.
84. Solubility of salts depend on hydration enthalpy and
lattice ethalpy. If hydration enthalpy decreases and
lattice enthalpy increases, the solubility of salt will
decrease.
85. H – O – BO – H
O – H,2Na
+
HO – BO
O
B
B
B – OH 8H O2
O
O
OH
1 2
4
3
OH
1 & 2 3 = sp2
3 & 4 4 = sp3
3 = sp2
O
2–
86. H– = 208 pm, I– = 216 pm.
87. On Pauling scale,
Electronegativity of an atom = I.P E.A
2 2.8
,
where I.P. and E.A are in eV.
88. Cr (Z = 24) = 1s22s22p6 3s23p63d54s1
n + l = 4 is for orbitals 4s and 3p
Hence the number of electrons in orbitals having
n + l = 4 is equal to 7.
89. Magnetic quantum number (m) represents the
orientation to atomic orbitals in three-dimensional
space.
90.2 3 2 2
X O 3H 2X 3H O
1 mol 3 mol
(2a 48)g 6 g
∵ 0.006 g H2 is required by 0.3192 g oxide
6 g H2 will be required by 319.2 g oxide.
2a + 48 = 319.2
a = 135.6 amu
All India Aakash Test Series for Medical-2018 Test - 09 (Code F) (Hints)
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BIOLOGY
91. Coding strand is non template strand of double
stranded DNA.
mRNA
5 AUCGGCUACGA 3
Sequence on template strand
3 TAGCCGATGCT 3
Sequence on non template or coding strand
5 ATCGGCTACGA 3
This can be written as
3 AGCATCGGCTA 5
93.uses
31 NH 4e ;4H ;8ATP
96. Frequency of PPQqRrSSTt is
1 1 1 1 1 1
2 2 2 2 2 32
97. Inversion of C and D segment.
98. Dichogamy
99. Phloem parenchyma is present in dicot stem, but
absent in monocot stem.
101. N2O – 6%
CO2 – 60%
CFC – 14%
CH4 – 20%
103. Lema, Peru – CoP 20
106. A – Mammals
B – Reptiles
C – Fishes
107. Cymose inflorescence.
110. Allen’s rule
111. a. About 13%
b. Homofermentaive lactic acid bacteria,
(Lactobacillus lacti)
114. (Sigma) is initiation factor
(Rho) is termination factor
115. Klinefelter’s syndrome have
(a) 44 + XXY Trisomy
(b) Sterile males with overall musculine development
(e) Testicular atrophy (small testes)
118. UTRs are present at both end at 5 end before start
codon and at 3 end after stop codon.
119. Life cycle of Drosophila is two weeks.
Male and female are easily distinguishable.
122. Eltonian pyramids are ecological pyramid.
These pyramids assume simple food chain and can
not accommodate food web.
123. Clown fish and sea anemone show
commensalism.
Barnacles Balanus and Chathamalus show
competition.
Tiger and deer show predation.
Fig (Ficus) and Fig wastes show mutualism.
126. Immunosuppressive agent Cyclosporin-A is obtained
from Trichoderma polysporum.
127. Three biodiversity hot spots present in India are
Western Ghats and Sri Lanka
Indo – Burma
Himalaya
128. G = 14%
Guanine = cytosine C = 14%
Thymine = adenine where remaining 72% are A & T
So A = 36%, T = 36%
129. Hybrid produced in garden pea are fertile.
130. Zostera is marine plant which show hydrophily.
131. Meiocyte is 2n(diploid) = 20 chromosome
Tube nucleus – (n) – 10 chromosome
PEC – (3n) – 30 chromosome
Nucellus – (2n) – 20 chromosome
Synergid – (n) – 10 chromosome
132. Only recessive trait can be expressed in
homozygous state.
(i) Yellow pod colour
(ii) Constricted pod shape
(iii) Wrinkled seed shape
(iv) Terminal flower position
133. Family and genus are taxonomic category.
134. Epidermis, endothecium and middle layer perform
function of protection.
Tapetum is the innermost layer of anther wall.
Each lobe of anther has two microsporangia.
135. Zoospore are flagellated motile spores.
Conidia are non motile asexual spore found in
fungi (Penicillium).
Test - 09 (Code F) (Hints) All India Aakash Test Series for Medical-2018
9/9
� � �
Rhizome is underground stem modification
found in ginger, turmeric, banana.
Bulbils are large fleshy bud present in Agave.
136. Units of compound eyes are ommatidia.
137. Sponges are pore bearing animals. They have water
transport or canal system. Echinoderms have water
vascular system.
138. Fact
139. Fact
140. ‘C’ being circular will move fastest towards anode.
141. All our blood cells develop in bone marrow.
142. Morphine is obtained from Papaver somniferum.
143. Fact
144. At low pO2 carbamino haemoglobin is stable and at
high pO2 carbamino haemoglobin is unstable.
145. Asthma is difficulty in breathing causing wheezing
due to inflammation of bronchi and bronchioles.
146. Parasympathetic nervous system stimulates salivary
secretion and peristaltic contractions.
147. Mendel established purelines by inbreeding.
148. In test tube baby programme, ova from the wife/
donor female and sperms from husband/donor male
are collected and are induced to form zygote under
simulated conditions in the laboratory.
149. The corticoids which are involved in carbohydrate
metabolism are glucocorticoids, mainly cortisol.
150. One thick filament is composed of many meromyosin
molecules.
151. Fact
152. Mutations are sources of variations hence bring
changes in gene frequencies.
155. A decrease in body fluid volume stimulates ADH
release.
156. Fact.
157. Deposition of uric acid in joints is gout.
Autoimmune disorder of muscles is myasthenia
gravis.
Disorder of joints associated with inflammation of
joints is rheumatoid arthritis.
158. Adrenaline – Emergency hormone.
159. Neutrophils and monocytes perform the function of
phagocytosis.
160. They are all non-chordates having double ventral
solid nerve cord.
161. In ectinoderms, mouth is on ventral side and
anus is on dorsal side, e.g. Asterias.
In molluscs, organ of Bojanus is the excretory
organ and teeth of sharks are modified placoid
scales.
162. Typhoid, pertussis, diphtheria and cholera are
caused by bacteria.
163. Flatworms are also bilaterally symmetrical and
triploblastic and show cephalisation.
164. Exoskeleton is made up of four plates called
sclerites in each segment.
(i) Structures of mastication are mandibles.
(ii) Excretory product of cockroach is uric acid.
165. Fact.
166. The combined pills are taken for 21 days,
starting preferably within the first five days of
menstrual cycle.
167. Inhibin hormone further brings down the level of
FSH.
168. Ascending limb of loop of Henle being
permeable to electrolytes and impermeable to
water makes the filtrate hypo-osmotic to plasma.
169. hPL is maternal growth hormone of pregnancy.
171. Fact.
172. Sma I produces blunt ends.
All others e.g., Bam HI, Sal I and Pst I produce
sticky ends.
173. Cysteine is a sulphur containing amino acid.
174. The activity of enzymes increases with increase
in substrate conc. till they achieve steady state.
175. Glossopharyngeal is a mixed nerve.
176. Adrenaline increases heart rate.
177. Coxal is hip bone formed by fusion of ilium,
ischium and pubis. At the point of fusion of all
these three bones, a cavity called acetabulum is
present.
179. Cellular oncogenes are growth promoter genes
that upon undergoing mutations lead to
overgrowth.
180. Dope test is done to estimate alcohol and other
drugs level in blood by blood sampling not
through breath analysis.