CSIR NET TEST-1Prepared by BioTecNika.Org6/29/2012Opt for India’s Best CSIR NET Classroom Coaching atBioTecNika

TEST-1 (29th June 2012)

1. Which of the following represents themost reduced form of carbon?1

a) R-CH3b) R-COOHc) R-CHOd) R-CH2OHe) CO2

2. The nucleoside adenosine exists in aprotonated form with a pKa of 3.8.The percentage of the protonated format pH 4.8 is closest to 35

a. 1b. 9c. 50d. 91e. 99

3. Acetyl CoA, the cytoplasmic substratefor fatty acid synthesis, is formed inmitochondria. The innermitochondrial membrane isimpermeable to acetyl CoA. Which ofthe following compounds is the formin which the carbon of acetyl CoA istransported to the cytoplasm?

a) Malateb) Acetatec) Citrated) Pyruvatee) Glucose

4. The ion product for liquid water, Kw,varies with temperature (T), asindicated by the change in pKwshown in the table above. Thedefinition of neutrality is [H+] =[OH−]. Which of the following is thepH of water at neutrality at 50C ?

a. 6.35

b. 6.64c. 7.00d. 7.40e. 13.28

5. Which of the following groups ofenzymes are unique to the Calvincycle?

a. Ribulose bisphosphatecarboxylase,phosphoribulokinase, andsedoheptulose 1,7-bisphosphatase

b. Ribose 5-phosphate isomerase,epimerase, and aldolase

c. Glyceraldehyde 3-phosphatedehydrogenase,phosphofructokinase, andphosphoenolpyruvatecarboxylase

d. Phosphoglycolate phosphatase,glycerol kinase, and serinesynthetase

e. Sucrose synthase, hexokinase,and glucose 6-phosphatedehydrogenase

6. Which of the following is NOT aconsequence of increased cellularlevels of cAMP?

(A) Activation of a kinase cascade(B) Activation of the transducin Gprotein(C) Increased phosphorylation of

glycogen phosphorylase(D) Inhibition of glycogen

synthesis(E) Dissociation of the cAMP-dependent protein kinase tetramer.

7. The urea cycle occurs in the(A) mitochondrion and cytoplasm

(B) mitochondrion and lysosome(C) endoplasmic reticulum(D) Golgi complex(E) peroxisome

8. How many grams of MgCl2 arerequired to prepare one liter of a 10-millimolar MgCl2 solution? (Atomicweight of Mg = 24.3 g; atomic weightof Cl = 35.5 g.)

a. 0.59 gb. 0.95 gc. 59 gd. 95 ge. 950 g

9. The zymogen chymotrypsinogen isconverted to active chymotrypsin by

a) binding of a necessary metalion

b) reduction of a disulfide bondc) proteolytic cleavaged) phosphorylation of an amino

acid sidechaine) the action of a signal peptide

peptidase10.Glycophorin, an integral membrane

protein, has a single transmembranealpha helix. Which of the followingidealized hydropathy plots most likelyrepresents the transmembrane natureofglycophorin?

a)

b)

c)

d)

11.Which of the following statementsabout repetitive DNA is NOT true?a. Repetitive DNA is associated with

the centromeres and telomeres inhigher eukaryotes.

b. Repetitive DNA is restricted tonontranscribed regions of thegenome.

c. Repetitive DNA sequences areoften found in tandem clustersthroughout the genome.

d. Repetitive DNA was first detectedbecause of its rapid reassociationkinetics.

e. Transposable elements cancontribute to the repetitive DNAfraction.

12.A stranded DNA plasmid has apropensity to undergo a B form to Zform transition. Which one of thefollowing conditions will facilitatethis transition?a) Intercalation of ethidium bromide

into a covalently closed circularplasmid

b) Introduction of negativesupercoiling in the plasmid bytopoisomerases

c) Introduction of positive supercoilsin the plasmid by reverse gyrase

d) Introduction of nick in the plasmid13.The committed step in the de novo

synthesis of purine nucleotides is theformation of

a) Ribose 5 phosphate from ribose1 phosphate

b) 5 PRPP from ribose 5phosphate

c) 5 phosphoribosylamine fromPRPP

d) 5 phosphoribosylglycinamidefrom 5 phosphoribosylamine

14.The following are the DNA moleculeswith base composition. Which one ofthem requires high meltingtemperature for denaturation?

a) %A-28, %T-28, %G-22, %C-22

b) %A-15, %T-15, %G-35, %C-35

c) %A-35, %T-35, %G-15, %C-15

d) %A-30, %T-30, %G-20, %C-215.A 42 amino acids peptide related to

the extracellular Alzheimer amyloiddeposits has the last few residuesimmersed in the membrane bilayer,which of the following sequencesmost probably identifies the last fiveamino acids in this 42 residuepeptide?

a) Ala-Glu-Phe-Argb) Val-Val-Ile-Alac) Asp-Ser-Gly-Tyrd) Lys-Val-His-His-Gln

16.Match items in grp1 with those in grp2P. Mixture of gly and albuminQ. Mixture of 20 and 60KDa proteinR. Histone from nuclear extractsS. Lectinsa. Gas chromatographyb. Dialysisc. Affinity chromatography

d. Size exclusion chromatographye. Thin Layer chromatographyf. Cation exchange chromatography

a) P-a, Q-d, R-c, S-bb) P-b, Q-d, R-f, S-cc) P-e, Q-c, R-f, S-ad) P-f, Q-e, R-b, S-d

17.What is the approximate pI for thispolyprptide?Asp-Met-Pro-Lys-His

a. 5b. 8c. 10d. 11

18.A mixture of 4 proteins with pIs 11, 7,5and 3 are loaded on DEAE anionexchange column equilibrated withlow ionic strength buffer of pH-8.Which of the 4 proteins would beexpected to be retained in thecolumn?

a) Protein with pI but not othersb) Protein with pI 11, 7, but not 5

and 3c) Proteins with pI 7,5,3d) Protein with pI 7 but not others

19.Silk does not stretch becausea. Due to the presence of

extensive disulphide linkageb. Due to extensive hydrogen

bond formation in between thebeta sheets

c. Optimisation of vanderwaalsinteraction

d. Because the beta conformationis already highly extended

20.An unknown, containing somecombination of alanine, lysine oraspartic acid, is subjected to paperelectrophoresis at pH=7. Ninhydrintreatment (to stain them) shows some

amino acid at the negative electrodeand some amino acids have notmoved from the center. No aminoacid is found at the positive electrode.Which amino acid (s) is (are) in theunknown?

a) Alanine and lysine but notaspartic acid

b) Alanine and aspartic acid butnot lysine

c) Only alanined) All the three amino acids

Topic:- Inheritance biologyPart – B

1. Assuming the comparablechromosome in different individualsare genetically dissimilar because ofdifferent alleles. How many uniquecombinations are possible followingfertilization in an organism where n=3(assuming that no crossing over)?

a. 8b. 16c. 64d. 216

2. Two genes are located on the samechromosome and are known to be 12map unit apart. An AABB individualis crossed to an aabb individual tproduce AaBb offspring. The AaBboffspring are then crossed to aabbindividuals. If this cross produces1000 offsprings. What are thepredicted no. of offsprings with eachof the 4 genotypes: AaBb, aaBb andaabb?

a. 60 Aabb, 440 aaBb, 440 AaBb and60 aabb

b. 0 Aabb, 0 aabb, 440 AaBb and 440aabb

c. 440 Aabb, 440 aaBb, 60 AaBb and60 aabb

d. 60 Aabb, 60 aaBb, 440 AaBb and440 aabb

3. In a haploid organism, the C and Dloci 8 map unit apart. From a crossCd/cD, give the proportion of each ofthe following progeny classes . P-CD;Q-cd; R-Cd, S-all recombinant.a. P-4%, Q-4%, R-46%, S-8%b. P-46%, Q-46%, R-4%, S-4%c. P-46%, Q-4%, R-46%, S-4%d. P-4%, Q-4%, R-8%, S-8%

4. Match the followingColumn A Column BP. Acridine orange a. base analogQ. 5-BU b.IntercalationR. EMS c.DeaminationS. HNO2 d. Alkylation

a. P-b, Q-d, R-a, S-cb. P-b, Q-a, R-d, S-cc. P-a, Q-d, R-d, S-cd. P-a, Q-b, R-c, S-d5. Using site-directed mutagenesis four

mutation of a protein have beengenerated. Which of the followingmissense mutation has the largestdifference in terms of number of

atoms between the wild type and themutant?a. Ser cysb. Tyr Phec. Lys Alad. Arg Lys

6. Probable cause of low fertility inplants is –a. Chromosomal irregularityb. improper spindle formationc. chemical pesticidesd. All of the above.

7. Mr. John cannot differentiate Red andgreen colour. He married a girl whocan differentiate all known coloursaccurately. They have a colour blinddaughter. Now if you have draw areciprocal cross of this family, whatwould you predict about thephenotype of the children.a. All girls normal and tallb. All boys colourblind and girls

normalc. All girls colour blind and all boys

normal.d. ¾ of the girls normal and ¼ of

boys colour blind.

8. In a Neurospora 8 asci are formedfrom the two mating type a+ and a.How do you expect to obtain 8 ascispores from the mating of 2 gametes?a. Mitosis followed by one meiosisb. Mitosis followed by 2 cycles of

meiosis

c. 2 cycles of meiosis followed bymitosis

d. Binary fission giving 8 asci frominitial 2 gametes.

9. If E.coli are grown on lactose freemedium for 20 generation underpressence of constant mutagen whichproduces the lac- mutants as well aslac+ revertants in equal amount. Atthe end it will be observed thata) Equal no.of Lac- and lac

revertants.b) More no.of Lac revertants at the

endc) More no.of Lac- at the end of

experiment.d) Cannot be predicted.

10. Genes a, b, and c are widelyspaced in the bacterial genome.Transducing phage from an a+ b+

c+ bacterium were used to infect a

culture of a− b− c− cells, and b+

transductants were selected. Which ofthe following best describes thepredicted genotypes of thesetransductants?

(A) Mostly a− b+ c−

(B) Mostly a− b+ c+

(C) Mostly a+ b+ c+

(D) Mostly a+ b+ c−

(E) a+ b+ c+ and a− b+ c− inequal frequencies

PART –C1. A homozygous male fruit fly with

black body colour and curved wing iscrossed with a virgin homozygousfemale fruit fly with yellow bodycolour and flat wings. All the

offspring of this cross display yellowbody colour and flat wings. If a virginfemale selected from these offspringis mated to a homozygous male fruitfly with black body colour and curvedwings, 4 types of offspring will occur.Which of the following conclusioncan be drawn about the nature ofinheritance on the basis of these data?a. Black body colour and curved

wings are dominant over yellowbody colour and flat wings

b. The results do not fit the typical9:3:3:1 ratio, making this anexample of multiple allelicinheritance rather than a normaldihybrid cross

c. Recombinant types of offspring, asin this case, appear morefrequently than do parental types.

d. These genes for body colour andwings shape are not linked

2. In Drosophila melanogaster, cherubwings(ch) black cody (b) and cinnabareye(cn) are recessive to theircorresponding allels (represented asch+, b+ and cn+, respectively) and areall located on chromosome 2 .homozygous wild type flies wasmated with cherub, black andcinnabar flies and the resulting F1female were test crossed with cherub,black and cinnabar males. Thefollowing progeny were producedfrom the test cross:Ch b+ cn 110Ch+ b+ cn+ 780Ch+ b cn 70Ch+ b+ cn 6Ch b cn 769Ch b+ cn+ 60

Ch+ b cn+ 111Ch b cn+ 9Total 1915

Of these three genes, which one is inthe middle?a. The locus that determines cherub

wingsb. The locus that determines cinnabar

eyesc. The locus that determine black

bodyd. Cannot be determined from the

given data.3. Two different triats affecting pod

characteristics in garden pea plantsare encoded by genes found onchromosome 5. Narrow pod isrecessive to normal pod; yellow podis recesiive to green pod. A truebreeding plant with narrow, greenpods was crossed to a true-breedingplant with normal, yellow pods. TheF1 offsprings were then crossed toplant with narrow, yellow pods. Thefollowing results were obtained 144normal green pods, 150 normalyellow pods, 11 narrow yellow pods,9 normal green pods. How far apartthese two genes?a. 1 mub. 12muc. 6.4 mud. 32.4 mu

4. The DNA from the bacteriophageX174 has a base composition of

25% A, 33% T, 24% G, and 18% C.Which of the following best explainsthis observation?a. In viral genomes, the base pairing

does not follow the standardWatson-Crick rules, and allowsG-A and C-T base pairs

b. In viral genomes, the base pairingdoes not follow the standardWatson-Crick rules, and allows G-T and C-A base pairs.

c. Viral genomes are linear andtolerate base- pair mismatches

d. Nucleic acids from viruses aretightly complexed with nucleicacid-binding proteins and socannot base-pair with oneanother.

e. The genome of bacteriophageX174 is single-stranded

5. If A/A B/B is crossed with the a/a b/band the F1 is test crossed. What % ofthe test cross progeny will be a/a b/bif the two genes areP. linkedQ. completely linked (no crossingover at all)R. 10 map unit apartS. 24 map unit aparta. P-0%; Q-0% ; R-38% ; S-45%b. P-25%; Q-0%, R-45%, S-38%c. P-0%, Q-25%, R-45%, S-38%d. P-25%, Q-0%, R- 38%, S-45%

6. In rabbit, spotted pattern is dominantover solid colour and short hair overangora. A F1 between true breedingspotted short hair strain and solidcolour angora was back crossed tosolid coloured angora. The crossproduced 26 spotted angora, 144 solidcoloured angora, 157 spotted shorthaired and 23 solid coloured shorthaired. What is the recombinantpercentage between the genes?a. 12%

b. 24%c. 14%d. 28%

7. A Neurospora cross involving twopairs of genes A-a and T-t producedthe following types of asci in thegiven frequency-

i. AT AT AT AT at at at at = 41ii. at at at at AT AT AT AT= 38

iii. At At At At aT aT aT aT = 42iv. aT aT aT aT At At At At = 43

what can you say about thelocation of the two genes on thechromosome.

a. The genes are 23.5 mu apart.b. The recombination frequency is 0.5c. The genes are on chromosome no 3d. The genes do not follow Mendelism.8. The CFTR is chloride channel present

in all over the body elementary canaland genital tract. It can have up to 80different types of mutations in CFTRcoding gene, causing improper iontransport. Mutation can be mild ononly one copy of gene per cell orsevere affecting both the copies. Whatdo expect about a genitalia of malewho is having a certain mutation inhis both copies of CFTR allele onchromosome 7,a. He will become sterile due to

improper chloride channel intesticles, resulting in hydrocele.

b. He will produce sterile off springsc. He becomes infertile due to block

of Vas deference

d. He becomes infertile due to nonproduction of sperm.

9. Choose the incorrect statement(s)Intercalating agents cause primaryframe shift.

I. Luria-Delbruck fluctuation testprovided the first experimentalevidence supporting the hypothesisthat mutation occur spontaneously

II. Tautomer is an alternativeisomeric form of a base due to themovement of one hydrogen atomfrom one position to other.

III. Mis sense type of mutation resultswhen a base substitution in acodon leads to the formation ofanother codon calling for theinsertion of different amino acids.

IV. Suppressor mutation cause thereversion of a mutant phenotype tothe wild type even thought they arenot back mutationa. 1 and 2b. Only 4c. 4 and 5d. None

10.Mendel crossed tall pea plants withdwarf ones. The F1 plants were alltall. When these F1 plants were selfedto produce F2 generation, he got a 3:1 tall to dwarf ratio in the offspring.What is the probability that out ofthree plants (of F2 generation) pickedup at random at least 2 would be tall?a. 9/64b. 9/16c. 27/64d. 1/16

Molecular Biology1. The overall length of the cell cycle

can be measured from the doublingtime of a population ofexponentially proliferating cells.The doubling time of a populationof mouse L cells was determined bycounting the number of cells insamples of culture at various times.What is the overall length of the cellcycle in mouse L cells?

(1) 30 h (2) 20h(3) 10 h (4) 40

2. Budding yeast cells that aredeficient for Mad2, a component ofthe spindle-attachment-check point,are killed by treatment withbenomyl, which causes microtublesto depolymerise. In the absence ofbenomyl, however, the cells areperfectly viable. Which explanationout of the following is able to justifythis observation?(1) In the absence of benomy I, themajority of spindles forms normally

and the spindle-attachment checkpoint(Mad2) plays no role.(2) In the presence of benomy I, themajority of spindles form normallyand Mad2 plays critical role in cellsurvival.(3) Other than the role in cell survival,microtubule depolymerization affectsoxidative phosphorylation in theabsence of Mad2.(4) Benomyl also affects proteinsynthesis in the absence of Mad2.

3. A researcher has isolated arestriction endonuclease thatcleaves at only one specific 10 basepair site.A) Would this enzyme be useful inprotecting cells from viralinfections, given that a typical viralgenome is 5 x 104 base pairs long?B) Restriction endonucleases areslow enzymes with turnovernumber of 1 s-1. Suppose theisolated endonuclease was fasterwith turnover numbers similar tothose for carbonic anhydrase (106s-1), would this increased rate bebeneficial to host cells, assumingthat the fast enzymes have similarlevels of specificity?

The correct combination ofanswer is

(1) (A) : No (B) : Yes(2) (A) : No (B) : No(3) (A) : Yes (B) : No(4) (A) : Yes (B) : Yes

4. It has been observed that in 5-10%of the eukaryotic mRNAs withmultiple AUGs, the first AUG is notthe initiation site. In such cases, theribosome skips over one or more

AUGs before encountering thefavorable one and initiatingtranslation. This is postulated to bedue to the presence of the followingconsensus sequence (s):A) CCA CC AUG GB) CCG CC AUG GC) CCG CC AUG CD) AAC GG AUG AWhich of the following sequencesets related to the abovepostulations is correct?

(1) A and B(2) A and C

(3) C and D(4) B and D

5. Presence of circular mRNAs for aspecific protein in an eukaryotic cellreflects a rapid rate of synthesis ofthat protein. Following mechanismsare suggested:A) eIF-4G and PABP promote thisprocess through 5'-3' interaction ofmRNA.B) Ribosome are less active inrecognizing circular mRNA.C) PABP and eIF-4A promote thisprocess.D) Ribosome can reinitiatetranslation without beingDisassembled.Which of the following is correct?(1) A and D(2) B and D(3) A and C(4) B and C

6. siRNAs and miRNAs are used forachieving gene silencing. Although,major steps are similar there aredistinct differences in the keyplayers of the two processing

pathways. Following statementsrelate to some characteristicfeatures of gene silencing.A) Both siRNAs and miRNAs areprocessed by Cytoplasmicendonuclease Dicer.B) 'Drosha' is needed for processingmiRNAs and precursor siRNAs.C) Both siRNAs and miRNAs showassociation with Argonaute protein.D) Both the processing pathwaysinvolve RISe complex.Which of the followingcombinations is NOT correct?(1) A and C(2) C and D(3) A and B(4) D and A

7. In eukaryotic chromatin, 30 nmfiber (solenoid) can open up to giverise to two kinds of chromatin. Inone type (A), the promoter of a genewithin the open chromatin isoccupied by a nucleosome whereasin the other (B), the promoter isoccupied by histone H1. Thefollowing possibilities are suggested.A) The gene in (A) is repressed.B) The gene in (B) is repressed.C) The gene in (A) is active.D) The gene in (B) is active.Which of the following sets iscorrect?(1)A and D(2) A and B(3) Band D(4) C and D

8. Genetic studies demonstrated thatTBP mutant cell extracts aredeficient in transcription of genesfrom all three promoters viz. class

I, II and III. Following statementsdescribe characteristic features ofTBP.A) TBP is considered as anuniversal basal transcription factor.B) TBP is not required fortranscription of archaeal genes.C) TBP is involved in recognizingTATA box.D) TBP operates at all promotersregardless of .their TATA content.Which of the followingcombinations is NOT correct?(1) A and D(2) C and D(3) B and D(4) A and C

9. Eukaryotic genomes are organizedinto chromosomes and can bevisualized at mitosis by stainingwith specific dyes. Heatdenaturation followed by stainingwith Giemsa produced alternatedark and light bands. The darkbands obtained by this process aremainly(1) AT -rich and gene rich regions.(2) AT -rich and gene desert regions.(3) GC-rich and gene rich regions.(4) GC-rich and gene desert region

10.Cancer causing genes can befunctionally classified into mainlythree types: (i) genes that inducecellular proliferation,(ii) tumorsuppressor genes, (iii) genes thatregulate apoptotic pathway.Epstein-Barr virus that causes cancerby modulatingapoptotic pathway, contains a genehaving sequence homology withwhich of the following genes?

(1) bax (2)bcl-2

(3) p53 (4)caspase-3

11.In an experiment approach trpoperon and lac operon were fused.Under what condition there wouldbe expression of b-galactosidase?(1)Low lactose and glucose(2)High lactose and glucose(3)Low tryptophan(4)High tryptophan

12.According to Holiday model ifmarkers are present outside ofcrossover point, then recombinantmolecules would be generated when(1)There is no resolution(2)Always recombinant would be

produced(3)Nick is on outer during resolution(4)Nick is on inner strand during

resolution13.“Zinc finger” are important in

cellular regulation because they are(1)At the catalytic site of many

kinases(2)A structural motif in many DNA-

binding proteins(3)Restricted to the Cytoplasmic

domain of growth-factor receptor(4)Structure with high redox potential

14.A study is done on a mammaliancell line that has a doubling time of24 hours. These cells aresynchronized in G1 and thenlabeled for 2 days with BrdU( ananalog of thymidine that increasesthe density of DNA into which it isincorporated). At the end of thelabeling period, chromosomal DNAis isolated from the cells and its

density analyzed by equilibrium incesium chloride gradient. Which ofthe following patterns would beexpected to be seen?( H= heavy, L=light)(1)100% H/H(2)100%H/L(3)50% H/H, 50% H/L(4)50% H/H, 50% L/L(5)25% H/H, 50% H/L , 25% L/L

15.Rho-dependent and rho-independent transcriptiontermination mechanisms operate inprokaryotes. Rho-independenttermination mechanism involves(1)Binding of rho protein upstream of

the termination element(2)No protein factor and only RNA

secondary structure and run of Us(3)Presence of UGA or UAA stop

sodon(4)Binding of accessory factors at

termination signal.16.Wild type E.coli was plated on a

Rifampicin containing medium andincubated at 37 degree Celsius.Majority of the cells died: Howeversome colonies appeared after fewdays. What is the most likelyexplanation for the observation?(1)Degradation of Rifampicin(2)Mutation in DNA polymerase III(3)Efflux of Rifampicin(4)Mutation in the beta subunit of

RNA polymerase17.There are 3 kinds of RNA

polymerase ( I,II,III) in eukaryotescells, each specific for one class ofRNA molecule. Which of thefollowing is a correct match?

(1)RNA pol-I-rRNA; RNA polyII –tRNA

(2)RNA poly II-mRNA; RNA polIII–rRNA

(3)RNA pol I-rRNA; RNA polII-mRNA

(4)RNA polI-tRNA ; RNA polIII-rRNA

18.Which of the following is true aboutinteraction between TBP andTATA sequence?(1)TBP interacts with minor groove

an bends DNA by about 80°(2)TBP interacts with major groove

an bends DNA by about 80°(3)TBP interacts with minor groove

with no significant bending(4)TBP interacts with major groove

with no significant bending19.Broker, Cow, Roberts and P.Sharp

hybridized mRNA from adenovirusto denatured adenovirus DNA andexamined the resultant duplexmolecules by electro microscopy.Which of the following did theyobserve?(1)mRNA and DNA formed a

continuous duplex throughout thelength of the RNA

(2)mRNA and DNA formed acontinuous duplex throughout thelength of the DNA

(3)on one strand there were loopedout regions of ingle-stranded RNA

(4)on one strand there were loopedout regions of single-strandedRNA

20.During the processing of introns, asingle snRNP complex catalyzesboth the cleavage of the RNA andthe joining of the ends. What would

be the consequence if these twoprocesses were catalyzed byseparate enzymes not associated ina single complex?(1)The rate of RNA processing would

be much faster(2)The cell would be unable to

identify the correct cleavage sites(3)The exons might not be joined in

the correct sequence(4)Exons instead of introns would be

cleaved from RNA molecule.

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