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The 5 Kinematic Equations

The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

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Page 1: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

The 5 Kinematic Equations

Page 2: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

The average speed is equal to the total distance traveled divided by the total time of travel

d v = ----t

During an acceleration the average speed is equal to midpoint between the initial and final velocity

vf + vi

2 v =

Find the average speed in the first 4 seconds Find the average speed in the

first 2 seconds

V(2) = ?

V(1) = ?

Page 3: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

We can rearrange these equations to create other useful equations..

Goal: Let’s derive an equation for the distance traveled by an accelerating object

v = ----t

d vf + vi

2 =

Now solve the right side for d: d = v t

Substitute v = (vf + vi ) / 2 d = (vf + vi ) t

2Now lets introduce

a = v/t = (Vf – Vi)/t

So t = (Vf – Vi)/a

which we can substitute above…..

Now we can expand out the parenthesis and derive equation #5 from this………..

d = (vf + vi ) (Vf – Vi)/a

2

Page 4: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

d = (vf + vi ) (Vf – Vi)

2 a

Page 5: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

Vf2 = Vi

2 + 2 a d This is a handy equation used to solve

problems like this:

A car accelerates from a speed of 20 m/s to 30 m/s at an acceleration of 2.0 m/s2.

How far will the car travel during this acceleration?

Page 6: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

How fast will an object dropped from rest be moving after 4 seconds?

How far will an object dropped from rest have fallen after 4 seconds?

Page 7: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

The rearrangement of equation #2………

a = v/t Solve this for v : v = at = Vf -Vi

Solve this for Vf:

vf = vi + at which is equation #3

Ex: A rocket moving at 1000 m/s accelerates at 20 m/s2 for 10 seconds to achieve a higher orbit. What will its new speed be after it reaches its new orbit?

Page 8: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration
Page 9: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

D

And that’s equation #4: d = vi t + ½ at2

Example: A car traveling at 10 m/s accelerates for 5.0 s at a rate of 2.5 m/s2. How far will it travel during those 5.0 seconds?

Page 10: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

Many of his experimental apparatus can be found at the Museo di Storia della Scienza in Florence, Italy

There we have the 5 Kinematic Equations. Galileo didn’t exactly write them algebraically like this, but he set up the ideas for measuring v, a, d and t and showed through reasoning, measurement proportions how v, d , a and t related to one another. Note there is no concept of force yet in Physics…that will come later with Isaac Newton.

Page 11: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration
Page 12: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration
Page 13: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

d = vi t + ½ at20

d t ½ a t2

Page 14: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

Distance vs Displacement5 meters east in 2 seconds

3 meters south in 1 second

The total distance d traveled is

The total displacement d is

Speed = d / t = v

Velocity= d / t = v

Page 15: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

Vector mathematics is different than scalar mathematics

Vectors have direction and must be drawn to scale and connected head-to-tail. They add up to a resultant.

Scalars are just numbers and can be added with regular math. They add up to a sum.

HEADTail

Start

Finish

Page 16: The 5 Kinematic Equations. The average speed is equal to the total distance traveled divided by the total time of travel d v =---- t During an acceleration

2 miles

4 miles 3 miles

Road runner travels 5 miles before Marvin sends him back. Road runner takes a shortcut back that saves him a mile. If the whole round trip took 1 hour, what is roadrunner’s

a) speed? b) displacement ?