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4 2 5 1 0011 0010 1010 1101 0001 0100 1011 The Distributive Property Objective: 5.04 Develop fluency in the use of formulas to solve problems.

The Distributive Property Objective: 5.04 Develop fluency in the use of formulas to solve problems

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42510011 0010 1010 1101 0001 0100 1011

The Distributive Property

Objective: 5.04 Develop fluency in the use of formulas to solve

problems.

4251

0011 0010 1010 1101 0001 0100 1011

The Distributive Property

The Distributive Property

1. a(b + c) = ab + ac

2. (b + c)a = ba + ca

Example 2Simplify each expression.c. (8 + x)5 + 2x

4251

0011 0010 1010 1101 0001 0100 1011

The Distributive Property

The Distributive Property

1. a(b + c) = ab + ac

2. (b + c)a = ba + ca

4251

0011 0010 1010 1101 0001 0100 1011

The Distributive Property

The Distributive Property

1. a(b + c) = ab + ac

2. (b + c)a = ba + ca

Example 2Simplify each expression.c. (8 + x)5 + 2x

(8 + x)5 + 2x = 8.5 + x.5 + 2x Distributive Property

4251

0011 0010 1010 1101 0001 0100 1011

The Distributive Property

The Distributive Property

1. a(b + c) = ab + ac

2. (b + c)a = ba + ca

Example 2Simplify each expression.c. (8 + x)5 + 2x

(8 + x)5 + 2x = 8.5 + x.5 + 2x Distributive Property = 40 +5x + 2x Substitution Property

4251

0011 0010 1010 1101 0001 0100 1011

The Distributive Property

The Distributive Property

1. a(b + c) = ab + ac

2. (b + c)a = ba + ca

Example 2Simplify each expression.c. (8 + x)5 + 2x

(8 + x)5 + 2x = 8.5 + x.5 + 2x Distributive Property = 40 +5x + 2x Substitution Property = 40 +(5 + 2)x Distributive Property

4251

0011 0010 1010 1101 0001 0100 1011

The Distributive Property

The Distributive Property

1. a(b + c) = ab + ac

2. (b + c)a = ba + ca

Example 2Simplify each expression.c. (8 + x)5 + 2x

(8 + x)5 + 2x = 8.5 + x.5 + 2x Distributive Property = 40 +5x + 2x Substitution Property = 40 +(5 + 2)x Distributive Property = 40 + 7x Substitution Property

42510011 0010 1010 1101 0001 0100 1011

Using Formulas

Objective: 5.04 Develop fluency in the use of formulas to solve problems.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

A formula shows the relationship between certain quantities.

Variables are used to represent these qualities.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

Write a formula for the diameter of a circle, given it radius r.

It is often helpful to draw a picture.

Let d = diameter.

Let r = radius

The radius is equal to half the diameter of a circle.

r = ½ d

So, d = 2r.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

18m.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

d = 2r Diameter formula.

r = ?

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

d = 2r Diameter formula.18 = 2r Substitute 18 for d.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

d = 2r Diameter formula.

r = ?

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

d = 2r Diameter formula.18 = 2r Substitute 18 for d.18/2 = 2r/2 Divide each side by 2.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

d = 2r Diameter formula.18 = 2r Substitute 18 for d.18/2 = 2r/2 Divide each side by 2.9 = r

r = 9

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

ExampleUse the formula d = 2r to find the radius of a circle that has a diameter of 18 meters.

d = 2r Diameter formula.18 = 2r Substitute 18 for d.18/2 = 2r/2 Divide each side by 2.9 = r

A circle with a diameter of 18 meters has a radius of 9 meters.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

IntegrationAn equilateral triangle is a triangle whose three sides are all equal in length. Give a formula for the perimeter of any equilateral triangle.

s s

s

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

IntegrationAn equilateral triangle is a triangle whose three sides are all equal in length. Give a formula for the perimeter of any equilateral triangle.

Answer: p = 3s where p = perimeter and s = length of each side.

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

The speed limit along a particular highway increased from 55 mph to 65 mph. How much time will be saved on a 100-mile trip?Think! d = rt (distance = rate X time 100 (d) = 65 (rate) t 100d = 65t100 (d) = 55 (rate) t 100 d = 55 t

4251

0011 0010 1010 1101 0001 0100 1011

Using Formulas

The formula F = n/4 + 37 can be used to find the degrees Farenheit when n is the number of cricket chirps per minute.

If a cricket chirps 126 times per minute, determine the temperature.