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The Empirical Gas Laws

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The Empirical Gas Laws. The Empirical Gas Laws: Pressure. Kinetic Molecular Theory states that all substances are made of tiny particles that are in constant motion. - PowerPoint PPT Presentation

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Page 1: The Empirical Gas Laws
Page 2: The Empirical Gas Laws

Kinetic Molecular Theory states that all substances are made of tiny particles that are in constant motion.

Gases have the most amount of movement in the three states of matter. The movement of the particles is independent of each other as each particle travels in a straight line until it bumps into another particle or wall of its container.

Page 3: The Empirical Gas Laws

The movement of the particle is referred to as kinetic energy. As the energy increases so does the movement of the particles.

Page 4: The Empirical Gas Laws

Quantitative measurements on gases were first made by the English chemist Robert Boyle (1627 - 1691). Boyle used two instruments to measure pressure: the manometer, which measures differences in pressure, and the barometer, which measures the total pressure of the atmosphere

Page 5: The Empirical Gas Laws

Units of pressure were originally all based on the length of the column of liquid, usually mercury, supported in a manometer or barometer.

By far the most common of these units was the mm Hg.

Page 6: The Empirical Gas Laws

However, the modern SI unit of pressure is derived from the fundamental units of the SI.

Pressure is force per unit area, and force is the product of mass times acceleration, so the SI unit of pressure is the kg m s2/m2 or newton/m2,

which is called the pascal (Pa).

Page 7: The Empirical Gas Laws

The standard temperature and pressure that gas experiments are done at is referred to as SATP.

Standard Ambient Temperature and Pressure is 25° C and 100kPa.

Page 8: The Empirical Gas Laws

All of the older units of pressure have now been redefined in terms of the pascal.

One standard atmosphere, the pressure of the atmosphere at sea level, is by definition exactly 101,325 Pa.

The torr, named in honour of Torricelli, is defined as 1/760 of a standard atmosphere or as 101,325/760 Pa.

The mmHg can be considered identical to the torr. The term bar is used for 100,000 Pa, which is slightly below one standard atmosphere. 

Page 9: The Empirical Gas Laws
Page 10: The Empirical Gas Laws

Boyle used the manometer and barometer to study the pressures and volumes of different samples of different gases. The results of his studies can be summarized in a simple statement which has come to be known as Boyle's law:

At any constant temperature, the product of the pressure and the volume of any size sample of any gas is a constant.  

Page 11: The Empirical Gas Laws

For a particular sample of any gas, Boyle's law can be shown graphically as done in the Figure below. It is more common to express it mathematically as 

P1V1 =P2V2

Page 12: The Empirical Gas Laws

This means that the pressure and the volume vary inversely; as the pressure increases the volume of the sample gas must decrease and vice versa.

Page 13: The Empirical Gas Laws

A sample of gas occupies a volume of 47.3 cm3 at 25°C with a pressure of 30 mm of mercury. If the pressure is increased to 75 mm of mercury, what will the volume be at the new pressure?

Page 14: The Empirical Gas Laws

G P1 = 30 mm Hg

V1 = 47.3 cm3

P2 = 75 mm Hg

S V2 = (30 cm x 47.3 cm3)

75 cm Hg

V2 = 18.9 cm3

R V2 = ? P Therefore, When the pressure increased from 47.3 mm Hg to 75 mm Hg the volume decreased from 47.5 cm3 to 18.9 cm3

A P1V1 = P2V2

V2 = P1V1 / P2

Page 15: The Empirical Gas Laws

A student is trying to compress the gas in a cylinder that has an initial volume of 1000 cm3 and a pressure of 100 kPa. The student decreases the volume by 500 cm3. What is the pressure of the gas in the cylinder?

Page 16: The Empirical Gas Laws

G P1 = 100 kPa

V1 = 1000 cm3

V2 = 500 cm3

S P2

= (100 kPa x1,000 cm3)

500 cm3

P2 = 200 kPa

R P2 = ? P Therefore, When the student compressed the cylinder to half of its original volume the pressure doubled to 200 kPa.

A P1V1 = P2V2

P2= P1V1 / V2

Page 17: The Empirical Gas Laws

Questions: page 425 # 1 – 4, page 428# 5-9.