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IntroductionPreliminaries
Fractional LaplacianReference
The Fractional Laplacian
Fabian Seoanes Correa
University of Puerto Rico, Rıo Piedras Campus
February 28, 2017
F. Seoanes Wave Equation 1/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Motivation
During the last ten years it has been an increasing interest inthe study of fractional powers operators. This renewedattention on fractional operators started with the works by L.Caffarelli and L. Silvestre and collaborators [4, 1, 2, 3] onproblems involving the fractional Laplacian.
F. Seoanes Wave Equation 2/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Schwarts space
S (Rn) :=
{f ∈ C∞(Rn) : ∀m, j ∈ N0 sup
x∈Rn(1 + |x |2)m/2
∣∣∣f (j)(x)∣∣∣ <∞}
An important fact is that S (Rn) = Lp(Rn) for ≤ p <∞
Fourier transform
For any ϕ ∈ S (Rn),
Fϕ(ξ) =1
(2π)n/2
∫Rn
exp(−ix · ξ)ϕ(x)dx
F. Seoanes Wave Equation 3/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
We have that F : S → S , is an isomorphism andcontinuous map.
By the Riemann- Lebesgue Theorem F : L1(Rn)→ C0(Rn) isa continuous, injective but not suprajective
The inversion Fourier transform is:
F−1ϕ(x) =1
(2π)n/2
∫Rn
exp(−ix · ξ)ϕ(ξ)dx
F−1(F (ϕ))(x) = ϕ(x)
F. Seoanes Wave Equation 4/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Theorem
Let f , g ∈ S (Rn),
a.) F (f ′)(ξ) = iξF (f )(ξ)
b.) F (f ∗ g)(ξ) = F (f )(ξ)F (g)(ξ), where(f ∗ g)(x) = 1
(2π)n/2
∫Rn f (x − y)g(y) dy .
c.) F (exp(−α |x |2)) = 1(2α)n/2 exp(− |ξ|2 /4α)
Clearly the Fourier transform is a linear operator over S .
F. Seoanes Wave Equation 5/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Theorem
Let f , g ∈ S (Rn),
a.) F (f ′)(ξ) = iξF (f )(ξ)
b.) F (f ∗ g)(ξ) = F (f )(ξ)F (g)(ξ), where(f ∗ g)(x) = 1
(2π)n/2
∫Rn f (x − y)g(y) dy .
c.) F (exp(−α |x |2)) = 1(2α)n/2 exp(− |ξ|2 /4α)
Clearly the Fourier transform is a linear operator over S .
F. Seoanes Wave Equation 5/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Heat equation
We will solve for u(t, x), t > 0, x ∈ Rn.∂tu(t, x) = ∆u , si t > 0
u(0, x) = f (x)(1)
Where ∆u =∑n
j=1∂2u∂x2
jrepresent the Laplace operator. We want
solutions in S (Rn). (u(t, ·) ∈ S (Rn), t > 0 fixed). Therefore,
dFu(t,ξ)
dt = − |ξ|2 Fu(t, ξ)
Fu(0, ξ) = F f (ξ)
(2)
the solution for the ODE is Fu(t, ξ) = exp(−t |ξ|2)F f (ξ).
F. Seoanes Wave Equation 6/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Heat equation
We will solve for u(t, x), t > 0, x ∈ Rn.∂tu(t, x) = ∆u , si t > 0
u(0, x) = f (x)(1)
Where ∆u =∑n
j=1∂2u∂x2
jrepresent the Laplace operator. We want
solutions in S (Rn). (u(t, ·) ∈ S (Rn), t > 0 fixed). Therefore,
dFu(t,ξ)
dt = − |ξ|2 Fu(t, ξ)
Fu(0, ξ) = F f (ξ)
(2)
the solution for the ODE is Fu(t, ξ) = exp(−t |ξ|2)F f (ξ).
F. Seoanes Wave Equation 6/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Heat equation
We will solve for u(t, x), t > 0, x ∈ Rn.∂tu(t, x) = ∆u , si t > 0
u(0, x) = f (x)(1)
Where ∆u =∑n
j=1∂2u∂x2
jrepresent the Laplace operator. We want
solutions in S (Rn). (u(t, ·) ∈ S (Rn), t > 0 fixed). Therefore,
dFu(t,ξ)
dt = − |ξ|2 Fu(t, ξ)
Fu(0, ξ) = F f (ξ)
(2)
the solution for the ODE is Fu(t, ξ) = exp(−t |ξ|2)F f (ξ).
F. Seoanes Wave Equation 6/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Consider n = 1, for the previous theorem part(c), we have
exp(−t |ξ|2) = F
(√1
2texp(− |x |2 /4t)
)
So that,
Fu(t, ξ) = F
(√1
2texp(− |x |2 /4t) ∗ f
)(ξ)
= F
(1√4πt
∫R
exp(− |x − y |2 /4t)f (y)dy
)(ξ)
Hence, u(t, x) = 1√4πt
∫R exp(− |x − y |2 /4t)f (y)dy
F. Seoanes Wave Equation 7/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Consider n = 1, for the previous theorem part(c), we have
exp(−t |ξ|2) = F
(√1
2texp(− |x |2 /4t)
)
So that,
Fu(t, ξ) = F
(√1
2texp(− |x |2 /4t) ∗ f
)(ξ)
= F
(1√4πt
∫R
exp(− |x − y |2 /4t)f (y)dy
)(ξ)
Hence, u(t, x) = 1√4πt
∫R exp(− |x − y |2 /4t)f (y)dy
F. Seoanes Wave Equation 7/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Fourier Transform
Consider n = 1, for the previous theorem part(c), we have
exp(−t |ξ|2) = F
(√1
2texp(− |x |2 /4t)
)
So that,
Fu(t, ξ) = F
(√1
2texp(− |x |2 /4t) ∗ f
)(ξ)
= F
(1√4πt
∫R
exp(− |x − y |2 /4t)f (y)dy
)(ξ)
Hence, u(t, x) = 1√4πt
∫R exp(− |x − y |2 /4t)f (y)dy
F. Seoanes Wave Equation 7/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Equivalent definitionsExample
Remember that for f ∈ S the fourier transform gives
F ((−∆)f )(ξ) = |ξ|2 F (ξ), ξ ∈ Rn
Then it is clear how to define the powers of the Laplacian.
Definition:
For s > 0(our interest is in s ∈ (0, 1)) the fractional Laplacian(−∆)s acts as
By Fourier transform:
lims→1−
(−∆)s f = −∆f lims→0+
(−∆)s f = f
F. Seoanes Wave Equation 8/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Equivalent definitionsExample
Remember that for f ∈ S the fourier transform gives
F ((−∆)f )(ξ) = |ξ|2 F (ξ), ξ ∈ Rn
Then it is clear how to define the powers of the Laplacian.
Definition:
For s > 0(our interest is in s ∈ (0, 1)) the fractional Laplacian(−∆)s acts as
By Fourier transform:
lims→1−
(−∆)s f = −∆f lims→0+
(−∆)s f = f
F. Seoanes Wave Equation 8/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Equivalent definitionsExample
Remember that for f ∈ S the fourier transform gives
F ((−∆)f )(ξ) = |ξ|2 F (ξ), ξ ∈ Rn
Then it is clear how to define the powers of the Laplacian.
Definition:
For s > 0(our interest is in s ∈ (0, 1)) the fractional Laplacian(−∆)s acts as
By Fourier transform:
lims→1−
(−∆)s f = −∆f lims→0+
(−∆)s f = f
F. Seoanes Wave Equation 8/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Equivalent definitionsExample
Proposition
Let s ∈ (0, 1) and f ∈ S , then
(−∆)s f (x) = cn,s limε→0
∫Rn−Bε(x)
f (x)− f (y)
|x − y |n+2sdy
where
cn,s = π−n/2 Γf
(n+2s
2
)Γf (−s)
Proposition
Let s ∈ (0, 1) and f ∈ S , then we also have
(−∆)s f (x) =cn,s
2
∫Rn
2f (x)− f (x + y)− f (x − y)
|y |n+2sdy
∀x ∈ Rn
Proof.
See [4].
F. Seoanes Wave Equation 9/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Equivalent definitionsExample
Proposition
Let s ∈ (0, 1) and f ∈ S , then
(−∆)s f (x) = cn,s limε→0
∫Rn−Bε(x)
f (x)− f (y)
|x − y |n+2sdy
where
cn,s = π−n/2 Γf
(n+2s
2
)Γf (−s)
Proposition
Let s ∈ (0, 1) and f ∈ S , then we also have
(−∆)s f (x) =cn,s
2
∫Rn
2f (x)− f (x + y)− f (x − y)
|y |n+2sdy
∀x ∈ Rn
Proof.
See [4].
F. Seoanes Wave Equation 9/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Equivalent definitionsExample
In the theory of stochastic process we are interested in the solutionto the fractional diffusion equation
Example ∂tu(t, x) = −(−∆)su(t, x)
u(0, x) = f (x)
F. Seoanes Wave Equation 10/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Reference
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H. O. Fattorini, Second Order Linear Differential Equations inBanach spaces, North-Holland, Amsterdam, 1985.
F. Seoanes Wave Equation 11/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Reference
J. A. Goldstein, Semigroups of Linear Operators andApplications, Oxford Univ. Press, 1985.
M. Hieber, Integrated semigroups and differential operators onLp(RN)-spaces, Math. Ann.291 (1991), 1-16. MR 92g:47052.
E. Hille and R.S Phillips, Functional analysis and semigroups,Coll. Publ. 31, American Math. Society, 1957.
L. Hormander, Estimates for translation invariant operators inLp spaces, Acta. Math. 104 (1960), pages 93-140. MR22:12389.
F. Seoanes Wave Equation 12/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Reference
A. V. Balakrishnan, Fractional powers of closed operators andthe semigroups generated by them, Pacific J. Math. 10 (1960),419-437
S. Bochner, Diffusion equation and stochastic processes, Proc.Nat. Acad. Sci. U. S. A. 35 (1949), 368-370.
T. Kato, Fractional powers of dissipative operators, J. Math.Soc. Japan 13 (1961), 246-274.
L. A. Caffarelli, S. Salsa and L. Silvestre, Regularity estimatesfor the solution and the free boundary of the obstacle problemfor the fractional Laplacian, Invent. Math.171 (2008), 425-461.
F. Seoanes Wave Equation 13/ 15
IntroductionPreliminaries
Fractional LaplacianReference
Reference
L. A. Caffarelli and L. Silvestre, An extension problem relatedto the fractional Laplacian, Comm. Partial DifferentialEquations 32 (2007), 1245-1260.
L. Silvestre, PhD thesis, The University of Texas at Austin,2005.
L. Silvestre, Regularity of the obstacle problem for a fractionalpower of the Laplace operator, Comm. Pure Appl. Math. 60(2007), 67-112.
Valdinoci E., Palatucci G., and Di Nezza E., Hitchhikers guideto the fractional Sobolev spaces (April 2011), available athttp://arxiv.org/abs/1104.4345.
K. Yosida, Functional analysis, Grund. Math. Wiss. 123,Springer-Verlag 1965.
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Thank You
University of Puerto RicoMathtematics Departmentwww.math.uprrp.edu
F. Seoanes Wave Equation 15/ 15