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1
The Generation of Ultrashort Laser Pulses II
The phase condition
Trains of pulses – the Shah function
Laser modes and mode locking
2
There are 3 conditions for steady-state laser operation.
Amplitude condition
threshold
slope efficiency
Phase condition
axial modes
homogeneous vs. inhomogeneous gain media
Transverse modes
Hermite Gaussians
the “donut” mode
x y
|E(x,y)|2
3
( ) 1/exp)(
)(=ω−= cLi
Eangle
Eanglert
before
afterq
L
c
rt
q ⋅π
=ω2
(q = an integer)
An integer number of wavelengths must fit in the cavity.
Steady-state condition #2:
Phase is invariant after each round trip
length Lm
collection of 4-level systems
Round-trip length Lrt
Phase condition
4
“axial” or “longitudinal” cavity modes
Mode
spacing:
∆ν = c/Lrt
ω0
laser gain
profile
qL
c
rt
q ⋅π
=ω2
(q = an integer)
Longitudinal modes
fits
does not fit
But how does this translate to the case of short pulses?
5
Femtosecond lasers emit trains of
identical pulses.
where I(t) represents a single pulse intensity vs. time and T is the time
between pulses.
Every time the laser pulse hits the output mirror, some of it emerges.
The output of a
typical ultrafast laser
is a train of identical
very short pulses:
R = 100% R < 100%
Output
mirror
Back
mirror
Laser medium
t-3T -2T 0 T 2T 3T-T
Intensity
vs. time
I(t) I(t-2T)
6
The Shah Function
The Shah function, III(t), is an infinitely long train
of equally spaced delta-functions.
The symbol III is pronounced shah after the Cyrillic character III, which is
said to have been modeled on the Hebrew letter (shin) which, in turn,
may derive from the Egyptian , a hieroglyph depicting papyrus plants
along the Nile.
III( ) ( )
m
t t mδ∞
=−∞
≡ −∑
t-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
� �
7
If ω = 2nπ, where n is an integer, the sum diverges; otherwise, cancellation occurs.
{III( )} III(t ω π∝ / 2 )Y
) exp( )m
t m i t dtδ ω∞ ∞
=−∞−∞
= ( − −∑∫
III(t)
So:
exp( )m
i mω∞
=−∞
= −∑
) exp( )m
t m i t dtδ ω∞∞
=−∞ −∞
= ( − −∑ ∫
t-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
… …
F{III(t)}
2
ωπ-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
… …
{III( )}t =Y
The Fourier Transform of the Shah Function
8
The Shah Function
and a Pulse Traint
-3T -2T 0 T 2T 3T-T
E(t)
t-3T -2T 0 T 2T 3T-T
E(t)
t-3T -2T 0 T 2T 3T-T
E(t)f(t) f(t-2T)f(t) f(t-2T)
where f(t) is the shape of each pulse and T is the time between pulses.
III( /( () ))t TE t f t= ∗But E(t) can also can be written:
(( ))m
f t mE t T∞
=−∞
−= ∑An infinite train of
identical pulses can
be written:
( )m
f t mT∞
=−∞
−= ∑To do the integral, set:
t’/T = m or t’ = mT
( ) (III( / ) ( / ) )m
t T t T mf t f t t dtδ∞∞
=−∞ −∞
′−′ ′∗ = −∑ ∫Proof:
convolution
9
An infinite train of
identical pulses can
be written:
The Fourier Transform of an Infinite Train of Pulses
E(t) = III(t/T) * f(t)t
-3T -2T 0 T 2T 3T-T
E(t)
t-3T -2T 0 T 2T 3T-T
E(t)
t-3T -2T 0 T 2T 3T-T
E(t)f(t) f(t-2T)f(t) f(t-2T)
II ) () / 2( I(E T Fω πω ω)∝%
The spacing between frequencies (modes) is then δω = 2π/T or δνδνδνδν = 1= 1= 1= 1////T.
The Convolution Theorem says that the Fourier Transform of a
convolution is the product of
the Fourier Transforms. So:
ωΤ / 2π-4 -2 0 2 4
F(ωωωω) ( )E ω%
10
The Fourier Transform of a Finite Pulse Train
A finite train of identical pulses can be written:
[III(( ) ( () )/ ) ]t T g tE t f t= ∗
where g(t) is a finite-width envelope over the pulse train.
g(t)
t-3T -2T 0 T 2T 3T-T
E(t)
f(t)
[III( / 2 ) ( )( ) ]( )TE FG ωωω ω π∝ ∗%
F(ωωωω)
-6π/T -4π/Tω
0 2π/T 4π/T 6π/T-2π/T
( )E ω%
Use the fact
that the Fourier
transform of a
product is a
convolution<
G(ωωωω)
11
A laser’s frequencies are often called longitudinal modes.
They’re separated by 1/T = c/2L, where L is the length of the laser.
Which modes lase depends on the gain and loss profiles.
Frequency
Inte
nsity
Here,
additional
narrowband
filtering has
yielded a
single
mode.
Actual Laser Modes
12
Mode-locked vs. non-mode-locked light
Mode-locked pulse train:
A train of
short pulses
( ) ( 2 / )m
F m Tω δ ω π∞
=−∞
= −∑
Non-mode-locked pulse train:
exp( )( ) ( ) ( 2 / )m
m
iE F m Tω ω ϕ δ ω π∞
=−∞
= −∑%
Random phase for each mode
A mess<( ) () /exp( 2 )m
m
F m Tiω δ ω πϕ∞
=−∞
= −∑
( ) ( III( / 2 )E F Tω ω ω π= )%
13
Generating short pulses = Mode-locking
Locking vs. not locking the phases of the laser modes (frequencies)
Random
phases
Light bulb
Intensity vs. time
Ultrashort
pulse!
Locked
phases
Time
Time
Intensity vs. time
14
Q: How many different modes can oscillate simultaneously in
a 1.5 meter Ti:sapphire laser?
A: Gain bandwidth ∆λ = 200 nm ⇒ ∆ν = (c/λ2) ∆λ ~ 1014 Hz
∆νbandwidth/∆νmode = 106 modes
That seems like a lot. Can this really happen?
Therefore ∆ν = c/Lrt ≈ 100 MHz
200 nm
bandwidth!
Wavelength (nm)
Ti:sapphire: how many modes lock?
Ti: sapphire crystal
pump
Typical cavity layout:
length of path from
M1 to M4 = 1.5 m
15
independent of ω
We have seen that the gain is given by:
2
00
1/12
1)(
ζ+σ
⋅+∆
⋅=ωsatII
Ng
( )γ
ω−ω=ζ 02
where
ωq
laser
gain
profileωq+1
ωq−1
losses Q: Suppose the gain is increased
further. Can it be increased so that the
mode at ωq+1 oscillates in steady state?
A: In an ideal laser, NO!
Homogeneous gain media
Suppose the gain is increased to a point where it
equals the loss at a particular frequency, ωq
which is one of the cavity mode frequencies.
16
Suppose that the collection of 4-level systems do not all share the same ω0
Consider a collection of sites, with fractional number between ω0 and ω0 + dω0:
000 )()( ωω=ω dNgdN
( ) ( ) )(; 000 ωωωχω=ωχ ∫ gd h
The modified susceptibility is:
homogeneous “packet”
inhomogeneous
line
“packets” are mutually independent -
they can saturate independently!
Inhomogeneous gain media
17
Lorentian
homogeneous
line shape
Gaussian
inhomogeneous
distribution of
width ∆ω( ) ( )2
00)2ln(4
00 ;
ω∆ω−ω
−
⋅ωωχω=ωχ ∫ ed h
No closed-form solution
For strong inhomogeneous broadening (∆ω >> γ):
χ"(ω) = Gaussian, with width = ∆ω (NOT γ)χ'(ω): no simple form, but it resembles χh'(ω)
Examples:
Nd:YAG - weak inhomogeneity
Nd:glass - strong inhomogeneity
Ti:sapphire - absurdly strong inhomogeneity
R6G - intermediate case (?)
Inhomogeneous broadening
18
Q: Suppose the gain is increased above threshold
in an inhomogeneously broadened laser. Can it be
increased so that the mode at ωq+1 oscillates cw?
A: Yes! Each homogeneous packet saturates independently
“spectral hole burning”
multiple oscillating cavity modes
a priori, these modes
need not have any
particular phase
relationship to one
another
ωq
laser gain
profile
ωq+1ωq−1
losses
ωq−2 ωq+2 ωq+3
Hole burning
19
There are 3 conditions for steady-state laser operation.
Amplitude condition
threshold
slope efficiency
Phase condition
axial modes
homogeneous vs. inhomogeneous gain media
Transverse modes
Hermite Gaussians
the “donut” mode
x y
|E(x,y)|2
20propagation kernel
Steady-state condition #3:
Transverse profile reproduces on each round trip
How would we determine these modes?
"transverse modes": those which reproduce themselves on
each round trip, except for overall amplitude and phase factors
An eigenvalue problem:
( ) ( ) ( )nm nm 0 0 nm 0 0 0 0E x, y K x, y;x , y E x , y dx dyβ ⋅ = ⋅∫∫
Condition on the transverse profile
21
( ) ( ) ( ), = ⋅nm n mE x y u x u y
Solutions are the product of two functions, one for each transverse dimension:
"TEM" = transverse electric and magnetic
"nm" = number of nodes along two principal axes
Notation:
( )2
2
2exp
= ⋅ −
n n
x xu x H
w w
where the un’s are Hermite Gaussians:
w = beam waist
parameter
Transverse modes
22
TEM00 TEM01 TEM02 TEM13
http://www.physics.adelaide.edu.au/optics/
x y
|E(x,y)|2
12 mode
x y
|E(x,y)|2
A superposition of the 10 and
01 modes: the “donut mode”
Transverse modes - examples