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Molarity Concentration and Parts Per Million 2019.notebook
1
April 05, 2019
Feb 61:39 PM
Molarity Concentration
Aim: To analyze a solution's concentration using Molarity.
Concentration is based on the amount of solute present in a solution.
Feb 61:39 PM
Molarity and MolalityMolarity (M): the concentration of a solution measured in the number of moles of solute per liters of solution.
The larger the number of moles of solute in solution, the higher the molarity concentration.
1.00 L of a 1.0 molar solution VS. 1.00 L of a 0.10 molar solution
Molarity Concentration and Parts Per Million 2019.notebook
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April 05, 2019
Feb 61:39 PM
Molarity and MolalityMolarity (M): the concentration of a solution measured in the number of moles of solute per liters of solution.
The larger the number of moles of solute in solution, the higher the molarity concentration.
1.00 L of a 1.0 molar solution VS. 1.00 L of a 0.10 molar solution moles solute = molarity x liters solutionmoles solute = 1.0 M x 1.00 Lmoles solute = 1 mole
moles solute = molarity x liters solutionmoles solute= 0.10 M x 1.00 Lmoles solute= 0.10 moles
Feb 61:39 PM
1. What is the molarity of a 6.00 L solution containing 0.500 moles of glucose?
2. How many moles of sodium chloride must be dissolved to create 2.00 L of a 2.50 M solution?
Molarity Problems
Molarity Concentration and Parts Per Million 2019.notebook
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April 05, 2019
Feb 61:39 PM
1. What is the molarity of a 6.00 L solution containing 0.500 moles of glucose?
2. How many moles of sodium chloride must be dissolved to create 2.00 L of a 2.50 M solution?
Molarity Problems
Molarity= moles solute ; M = 0.500 moles glucoseliters of solution 6.00 L solution
Molarity= 0.0833 M
Molarity= moles solute ; 2.50 M = moles NaClliters of solution 2.00 L solution
moles NaCl= 2.50 M x 2.00 Lmoles NaCl = 5.00 moles
Feb 61:39 PM
Molarity Problems
3. What is the molarity of a solution containing 196 g of sodium chloride (NaCl) dissolved into 1.85 L of solution?
4. How many liters of a 5.0 molar solution will be produced by dissolving 2.00 moles of sugar in a sufficient amount of water?
Molarity Concentration and Parts Per Million 2019.notebook
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April 05, 2019
Feb 61:39 PM
Molarity Problems
3. What is the molarity of a solution containing 196 g of sodium chloride (NaCl) dissolved into 1.85 L of solution?
4. How many liters of a 5.0 molar solution will be produced by dissolving 2.00 moles of sugar in a sufficient amount of water?
Molarity= moles soluteliters of solution
# moles= given massg.f.m
# moles= 196 g =3.35 mol58.5 g/mol
convert to moles using gfm
Molarity= 3.35 moles NaCl1.85 L solution
Molarity= 1.81 M
Molarity= moles solute ; 5.0 M = 2.00 moles sugarliters of solution liters of solution
liters of solution= 2.00 moles sugar/ 5.0 Mliters of solution= 0.40 L
Feb 61:39 PM
5. How many moles of Ca(NO3)2 are present in 3.8 liters of a 0.45 molar solution?
Molarity Problems
Molarity Concentration and Parts Per Million 2019.notebook
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April 05, 2019
Feb 61:39 PM
5. How many moles of Ca(NO3)2 are present in 3.8 liters of a 0.45 molar solution?
Molarity Problems
Molarity= moles solute; 0.45 M= moles soluteliters of solution 3.8 L solution
moles solute= 0.45 M x 3.8 Lmoles solute= 1.71 mol
Feb 61:39 PM
Making a Solution
3. Add enough solvent to the solute to make the TOTAL LITERS of solution.
1. You always determine the amount of required solute using the appropriate concentration data and formula.
2. Calculate the amount of grams of solute needed from the moles using the GFM. Measure this mass using a balance.
Make 1.0 L of a 0.10 M C12H22O11 solution.
Molarity Concentration and Parts Per Million 2019.notebook
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April 05, 2019
Feb 61:39 PM
Making a Solution
3. Add enough solvent to the solute to make the TOTAL LITERS of solution. (Solution volume = solute volume + solvent volume)– The solute occupies a small fraction of the volume.
1. You always determine the amount of required solute using the appropriate concentration data and formula.
2. Calculate the amount of grams of solute needed from the moles using the GFM. Measure this mass using a balance.
Make 1.0 L of a 0.10 M C12H22O11 solution.
Molarity= moles solute ; 0.10 M = moles soluteliters of solution 1.0 L solutionmoles solute= 0.10 moles
# moles= given mass ; 0.10 moles = given massg.f.m. 342.0 g/mol
given mass= 0.10 moles x 342.0 g= 34.2 grams of C12H22O11 solute
Feb 61:39 PM
Molarity Dilution and Parts Per Million
Concentration
Aim: To determine the concentration of diluting a solution and concentration using parts per million.
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Parts per millionParts per million is typically used when working with extremely small quantities of solute in solution.
FORMULA
parts per million = mass of solute x 1000000mass of solution
Ex 3) A solution contains 330 grams of CaCl2 dissolved in 1000 grams of water.What is the concentration of the solution in parts per million?mass solute= 330 g ppm= 330 g x 1,000,000= 248120.3 mass solution= 330 g + 1000 g H2O 1330 g ppm
Feb 61:39 PM
Ex 4) A 67.0 g sample of a solution contains 4.7 x 10‐3 grams of lead nitrate. What is the concentration in parts per million of the solution?
Parts per million
mass solute= 4.7 x 10‐3 g ppm= .0047 g x 1,000,000= 70.15 mass solution= 67.0 g 67.0 g ppm