19
BELT CONVEYOR CALCULUS ( ACCORDING CEMA ) BELT CONVEYOR # 1 A) BELT WIDTH AND BELT SPEED 1 Determine initial data a) Client information and site restrictions MTPD = 14,000 MTPD = Metric tonnage per day HPD = 20.00 HPD = Hours of operation per day Use factor = 75% Load factor = 75% 34.00 168.60 Process data = Heavy, hard, sharp-edged ore, coarse-crushed stone ump size ( in ) = 20.00 Lump proportion = 10% L = 27.90 m = 91.54 ft Length of conveyor between center o H = 8.60 m = 28.22 ft Height of conveyor between center o 17.95 MTPH = MTPD MTPH = Metric tonnage per hour HPD x Use factor MTPH = 933 b) See: Table 3-1: Flowability - angle of surcharge - angle repose Table 3-2: Material class description Table 3-3: Material characteristics and weight per cubic foot Material Name = Ore Code = P-2357 34.00 19.00 to 29.00 f ( °sex ) = f ( °sex ) = Repose angle dm ( lb / ft 3 ) = dm ( lb / ft 3 ) = Apparent density g ( °sex ) = g ( °sex ) = Inclination. Site rest f ( °sex ) = f ( °sex ) = Repose angle a ( °sex ) = f ( °sex ) - [ 5 to 15 ]( °sex ) a ( °sex ) = Surcharge angle a ( °sex ) = 1

TRAYECTORIAS fajas

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Page 1: TRAYECTORIAS fajas

BELT CONVEYOR CALCULUS ( ACCORDING CEMA )

BELT CONVEYOR # 1

A) BELT WIDTH AND BELT SPEED

1 Determine initial data

a) Client information and site restrictions

MTPD = 14,000 MTPD = Metric tonnage per day

HPD = 20.00 HPD = Hours of operation per day

Use factor = 75%

Load factor = 75%

34.00

168.60

Process data = Heavy, hard, sharp-edged ore, coarse-crushed stone

Lump size ( in ) = 20.00

Lump proportion = 10%

L = 27.90 m = 91.54 ft Length of conveyor between center of terminal pulleys

H = 8.60 m = 28.22 ft Height of conveyor between center of terminal pulleys

17.95

MTPH = MTPD MTPH = Metric tonnage per hour

HPD x Use factor

MTPH = 933

b)

See: Table 3-1: Flowability - angle of surcharge - angle repose

Table 3-2: Material class description

Table 3-3: Material characteristics and weight per cubic foot

Material Name = Ore

Code = P-2357

34.00

19.00 to 29.00

f ( °sex ) = f ( °sex ) = Repose angle

dm ( lb / ft3 ) = dm ( lb / ft3 ) = Apparent density

g ( °sex ) = g ( °sex ) = Inclination. Site restrictions

f ( °sex ) = f ( °sex ) = Repose angle

a ( °sex ) = f ( °sex ) - [ 5 to 15 ]( °sex ) a ( °sex ) = Surcharge angle

a ( °sex ) =

1

Page 2: TRAYECTORIAS fajas

20.00

168.60

18.00 to 20.00

Final values:

34.00

17.95

2 Choose the idler shape.

See: Chapter 5: Belt Conveyor Idlers

35.00

3

(For Metric Tonnage)

12,206

4 Select a suitable conveyor belt speed

See: Table 4-1: Recommended maximum belt speeds

Table 4-2: 20 degree troughed belt - three equal rolls standard edge distance = 0.055b + 0.9 inch

Table 4-3: 35 degree troughed belt - three equal rolls standard edge distance = 0.055b + 0.9 inch

Table 4-4: 45 degree troughed belt - three equal rolls standard edge distance = 0.055b + 0.9 inch

Table 4-5: Flat belt capacity standard edge distance = 0.055b + 0.9 inch

Belt Speed Belt Speed Belt Equivalent Equivalent

actual reduced Width Capacity Capacity

(fpm) (inches) Step 5 Table 4-3

350 262.50 18 4,650 1,274 NO

500 375.00 24 3,255 2,438 NO

400 300.00 30 4,069 3,976 NO

280 210.00 36 5,813 5,886 OK

600 450.00 42 2,713 8,169 OK

600 450.00 48 2,713 10,826 OK

600 450.00 54 2,713 13,855 OK

600 450.00 Over 60 2,713

fpm (actual) * Load factor Belt Speed reduced in fpm

fpm (actual) = 280.00 fpm (actual) = Belt Speed actual in fpm

5

a ( °sex ) = To < a: < load, so for = Q, > V or > b. It is site safe.

d ( lb / ft3 ) = d ( lb / ft3 ) = Average weight

g ( °sex ) = g ( °sex ) = Inclination. Maximum recommended

f ( °sex ) =

g ( °sex ) =

b ( °sex ) = b ( °sex ) = Degree troughed belt

Convert the desired tonnage (MTPH) to ( ft 3 / h )

f t 3 / h = MTPH x 2205 / dm

f t 3 / h =

(fpm)

fpmo = fpmo =

Convert the desired capacity ( ft 3 / h ) to the equivalent capacity at a belt speed of 100 fpm

2

3

4

5

Page 3: TRAYECTORIAS fajas

Equivalent Capacity = x 100 / fpm (actual)

Equivalent Capacity = 5,813

6 Using the equivalent capacity, find the appropriate belt width

36.00

7 Check the belt width with the material lump size

See: Item a) to Item c)

a) In USA: b (in) = 18, 24, 30, 36, 42, 48, 54, 60, 72, 84 and 96

b) f ( lump size )

For: i) 20.00 For: i) 20.00

ii) 10 % lumps and 90% fines ii) 1.00 lumps

b min = 3 x ( maximum lump size ) b min = 5 x ( maximum lump size )

b min = 60.00 in b min = in

For: i) 30.00 For: i) 30.00

ii) 10 % lumps and 90% fines ii) 1.00 lumps

b min = 6 x ( maximum lump size ) b min = 10 x ( maximum lump size )

b min = in b min = in

c) See: Figure 4-1 Belt width necessary for a given lump size

58.00

d) For belt conveyor existing

The belt will be new

Conclusion:

58.00

8 Revise the belt speed for final belt width.

Final Equivalent Capacity = check

x 100 / Final Equivalent Capacity

#VALUE!

#VALUE!

f t 3 / h

bo ( in ) =

b1 ( in ) =

a (°sex) = a (°sex) =

a (°sex) = a (°sex) =

b1 ( in ) =

b2 ( in ) =

b ( in ) =

fpm1 = f t 3 / h

fpm1 =

fpm2 = fpm1 / Load factor

fpm2 =

5

7

8

6

Page 4: TRAYECTORIAS fajas

V = 280.00 fpm Elected speed

B) POWER

hp = Te x V

33,000

Te = L .Kt (Kx + Ky.Wb + 0,015.Wb) + Wm ( L . Ky +/- H ) + Tp + Tam+ Tac

Frictional resistance of the carrying and return idlers (lbs)

Tx = L . Kx . Kt

Kx = 6.80 1.00E-04 ( Wb + Wm ) + Ai / Si

58.00 168.60

See: Table 6-1: Estimated average belt weight ( lb/ft )

Wb = 0.00 lb / ft

Wm = ( Q x 2205 ) / ( 60 x V )

Wm = ( MTPH x 2205 ) / ( 60 x V )

Wm = 122.50 lb / ft

See: Table 5-1: Idler classification

Description = Medium Duty

Classification = D5

See: Table 5-2: Suggested normal spacing of belt idlers ( Si )

Si = 4.00 ft

Ai = 1.80 lb

Wb + Wm = 122.50 lbs / ft

Kx = 0.53

Tmin = -15.00 °C = 5.00 °F

Kt = 1.20

Tx = 58.58 lb

Resistance of the belt to flexure as it moves over the idlers (lbs)

b ( in ) = dm ( lb / ft3 ) =

1

2

Page 5: TRAYECTORIAS fajas

Tyb = L x Wb x Kt x (Ky + 0,015)

See: Table 6-4: A and B for equation Ky = …

Ky =

Average belt tension = 1,000 lb

A = 2.20

B = 2.25

Ky = 0.05

Tyb = 0.00 lb

Resistance of the material to flexure as it rides the belt over the idlers (lbs)

Tym = L x Ky x Wm

Tym = 554.49 lb

Force needed to life or lower the load (material) (lbs)

Tm = +/- H x Wm

Load upwards: 1.00

Load downwards: -1.00

sign: 1.00

Tm = 3,456.36 lb

Tp = 950.00 lb

See: Table 6-5: Belt tension to rotate pulleys

# Pulleys: Tight side = 2.00

# Pulleys: Slack side = 3.00

# Pulleys: All others = 1.00

Pulleys: Tight side = 200.00 lbs/pulley

Pulleys: Slack side = 150.00 lbs/pulley

Pulleys: All others = 100.00 lbs/pulley

Force to accelerate the material continuously as it is fed onto the belt (lbs)

( Wb + Wm ) x A x 10(-4) + B x 10(-2)

Resistance of the belt to flexure around pulleys and the resistance of pulleys to rotate on their bearings (lbs)

2

3

4

5

6

Page 6: TRAYECTORIAS fajas

Tam = (V - Voj )

3600 x 32,2 60.00

0.00 -100.00

794.44 MTPH 138.89 MTPH

Tam = 87.25 lb

Resistance generated by conveyor accessories (lbs)

Tac = Ttr + Tpl + Tbc + Tsb

Ttr = Trippers and stackers

Tpl = Frictional resistance of plows

Tbc = Belt-cleaning devices

Tsb = Skirtboard friction

Ttr = 0.00 In this case

Tpl = 0.00 In this case

Tbc = e x b x # devices

Estimated ( e ) = 8.00 lb / in

# devices = 2.00

Tbc = 928.00 lb

Tsb =

Lb = 49.21 ft Lb = Skirtboard length, two skirtboard

hs = 4.00 in hs = depth of the material touching the skirtboard

Cs = 2 dm x

288.00

Cs = 0.33

Tsb = 555.92 lb

Tac = 1,483.92 lb

Te = 6,590.60 lb

hp = 55.92 HP

S Qj x 2205 x

Vo1 = Vo2 =

Q1 = Q2 =

Lb ( Cs x hs2 + 6 )

( 1 - sinf )

( 1 + sinf )

7

Page 7: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 17.95 ° = 0.31 rad

a1 = 2.50 inches h = 6.10 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 360 fpm

g = 32.20

= 1.29 = l

e = 108.0 ° = 1.88 rad

r0 = 1.04 ft X0 = -0.32 ft Y0 = 0.99 ft

r1 = 1.25 ft X1 = -0.39 ft Y1 = 1.19 ft

r2 = 1.55 ft X2 = -0.48 ft Y2 = 1.47 ft

rpm = 55.00 rpm end of pulley

Vo = 6.00 fps Vxo = 5.71 fps Vyo = 1.85 fps

V1 = 7.20 fps Vx1 = 6.85 fps Vy1 = 2.22 fps

V2 = 8.93 fps Vx2 = 8.49 fps Vy2 = 2.75 fps

Yo / Xo = -3.09

F = 0F > 0 1.88F < 0

= 0.95 =#VALUE! °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

4-0

.88-0

.71-0

.54-0

.37-0

.21-0

.04

0.13

0.29

0.46

0.63

0.79

0.96

1.13

1.29

1.46

1.62

1.79

1.96

2.12

2.29

2.46

2.63

2.79

2.96

3.13

3.29

3.46

3.63

3.79

3.96

4.13

4.29

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 1

X

Y

Page 8: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 7.94 ° = 0.14 rad

a1 = 2.50 inches h = 6.10 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 360 fpm

g = 32.20

= 1.29 = l

e = 97.9 ° = 1.71 rad

r0 = 1.04 ft X0 = -0.14 ft Y0 = 1.03 ft

r1 = 1.25 ft X1 = -0.17 ft Y1 = 1.24 ft

r2 = 1.55 ft X2 = -0.21 ft Y2 = 1.54 ft

rpm = 55.00 rpm end of pulley

Vo = 6.00 fps Vxo = 5.94 fps Vyo = 0.83 fps

V1 = 7.20 fps Vx1 = 7.13 fps Vy1 = 0.99 fps

V2 = 8.93 fps Vx2 = 8.84 fps Vy2 = 1.23 fps

Yo / Xo = -7.17

F = 0F > 0 1.71F < 0

= 0.99 =#VALUE! °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

4-0

.88-0

.71-0

.54-0

.37-0

.21-0

.04

0.13

0.29

0.46

0.63

0.79

0.96

1.13

1.29

1.46

1.62

1.79

1.96

2.12

2.29

2.46

2.63

2.79

2.96

3.13

3.29

3.46

3.63

3.79

3.96

4.13

4.29

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 2

X

Y

Page 9: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 17.83 ° = 0.31 rad

a1 = 2.50 inches h = 6.10 inches

R = 9.00 inches Pulley e = 0.50 inchesespesor faja

V = 550 fpm

g = 32.20

= 4.16 = l

e = 107.8 ° = 1.88 rad

r0 = 0.79 ft X0 = -0.24 ft Y0 = 0.75 ft

r1 = 1.00 ft X1 = -0.31 ft Y1 = 0.95 ft

r2 = 1.30 ft X2 = -0.40 ft Y2 = 1.24 ft

rpm = ### rpm end of pulley

Vo = 9.17 fps Vxo = 8.73 fps Vyo = 2.81 fps

V1 = 11.58 fps Vx1 = 11.02 fps Vy1 = 3.55 fps

V2 = 15.05 fps Vx2 = 14.33 fps Vy2 = 4.61 fps

Yo / Xo = -3.11

F = 0F > 0 1.88F < 0

= 0.95 =#VALUE! °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-0.7

9-0

.71

-0.6

3-0

.55

-0.4

7-0

.40

-0.3

2-0

.24

-0.1

6-0

.08

0.00

0.08

0.16

0.24

0.32

0.40

0.48

0.55

0.63

0.71

0.79

0.87

0.95

1.03

1.11

1.19

1.27

1.35

1.43

1.50

1.58

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-0.7

9-0

.63-0

.47-0

.32-0

.16

0.00

0.16

0.32

0.48

0.63

0.79

0.95

1.11

1.27

1.43

1.58

1.74

1.90

2.06

2.22

2.37

2.53

2.69

2.85

3.01

3.17

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 3

X

Y

Page 10: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y = 5.405.00

Y = 0.400.12

Y = ( Yo / Xo ) * X

F = 14.39 ° = 0.25 rad

a1 = 2.13 inches h = 5.19 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 550 fpm0.85

g = 32.20

= 2.93 = l

e = 104.4 ° = 1.82 rad

r0 = 1.04 ft X0 = -0.26 ft Y0 = 1.01 ft

r1 = 1.22 ft X1 = -0.30 ft Y1 = 1.18 ft

r2 = 1.47 ft X2 = -0.37 ft Y2 = 1.43 ft

rpm = 84.03 rpm end of pulley

Vo = 9.17 fps Vxo = 8.88 fps Vyo = 2.28 fps

V1 = 10.72 fps Vx1 = 10.39 fps Vy1 = 2.67 fps

V2 = 12.97 fps Vx2 = 12.56 fps Vy2 = 3.22 fps

Yo / Xo = -3.90

F = 0F > 0 1.82F < 0

= 0.97 =#VALUE! °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

2-0

.69

-0.3

5-0

.02

0.31

0.65

0.98

1.31

1.65

1.98

2.31

2.65

2.98

3.31

3.65

3.98

4.31

4.65

4.98

5.31

5.65

5.98

6.31

6.65

6.98

7.31

7.65

7.98

8.31

8.65

8.98

9.31

9.65

9.98

10.3

1

10.6

5

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 4

X

Y

Page 11: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 15.78 ° = 0.28 rad

a1 = 2.50 inches h = 6.10 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 120 fpm

g = 32.20

= 0.14 = l

e = 8.2 ° = 0.14 rad

r0 = 1.04 ft X0 = 1.03 ft Y0 = 0.15 ft

r1 = 1.25 ft X1 = 1.24 ft Y1 = 0.18 ft

r2 = 1.55 ft X2 = 1.53 ft Y2 = 0.22 ft

rpm = 18.33 rpm end of pulley

Vo = 2.00 fps Vxo = 0.29 fps Vyo = -1.98 fps

V1 = 2.40 fps Vx1 = 0.34 fps Vy1 = -2.38 fps

V2 = 2.98 fps Vx2 = 0.43 fps Vy2 = -2.95 fps

Yo / Xo = 0.14

F = 0F > 0 0.14F < 0

= 0.96 = 1.4381.8 °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

4-0

.88-0

.71-0

.54-0

.37-0

.21-0

.04

0.13

0.29

0.46

0.63

0.79

0.96

1.13

1.29

1.46

1.62

1.79

1.96

2.12

2.29

2.46

2.63

2.79

2.96

3.13

3.29

3.46

3.63

3.79

3.96

4.13

4.29

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 5

X

Y

Page 12: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 15.23 ° = 0.27 rad

a1 = 2.50 inches h = 6.10 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 260 fpm

g = 32.20

= 0.67 = l

e = 42.2 ° = 0.74 rad

r0 = 1.04 ft X0 = 0.77 ft Y0 = 0.70 ft

r1 = 1.25 ft X1 = 0.93 ft Y1 = 0.84 ft

r2 = 1.55 ft X2 = 1.15 ft Y2 = 1.04 ft

rpm = 39.73 rpm end of pulley

Vo = 4.33 fps Vxo = 2.91 fps Vyo = -3.21 fps

V1 = 5.20 fps Vx1 = 3.49 fps Vy1 = -3.85 fps

V2 = 6.45 fps Vx2 = 4.33 fps Vy2 = -4.78 fps

Yo / Xo = 0.91

F = 0F > 0 0.74F < 0

= 0.96 = 0.8347.8 °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

4-0

.88-0

.71-0

.54-0

.37-0

.21-0

.04

0.13

0.29

0.46

0.63

0.79

0.96

1.13

1.29

1.46

1.62

1.79

1.96

2.12

2.29

2.46

2.63

2.79

2.96

3.13

3.29

3.46

3.63

3.79

3.96

4.13

4.29

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 5A

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Y

Page 13: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 0.00 ° = 0.00 rad

a1 = 2.50 inches h = 6.10 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 180 fpm

g = 32.20

= 0.32 = l

e = 18.8 ° = 0.33 rad

r0 = 1.04 ft X0 = 0.99 ft Y0 = 0.34 ft

r1 = 1.25 ft X1 = 1.18 ft Y1 = 0.40 ft

r2 = 1.55 ft X2 = 1.47 ft Y2 = 0.50 ft

rpm = 27.50 rpm end of pulley

Vo = 3.00 fps Vxo = 0.97 fps Vyo = -2.84 fps

V1 = 3.60 fps Vx1 = 1.16 fps Vy1 = -3.41 fps

V2 = 4.46 fps Vx2 = 1.44 fps Vy2 = -4.23 fps

Yo / Xo = 0.34

F = 0 0.33F > 0F < 0

= 1.00 = 1.2471.2 °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

4-0

.88-0

.71-0

.54-0

.37-0

.21-0

.04

0.13

0.29

0.46

0.63

0.79

0.96

1.13

1.29

1.46

1.62

1.79

1.96

2.12

2.29

2.46

2.63

2.79

2.96

3.13

3.29

3.46

3.63

3.79

3.96

4.13

4.29

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 5B

X

Y

Page 14: TRAYECTORIAS fajas

DISCHARGE TRAJECTORIES

Y =

Y =

Y =

Y =

Y = ( Yo / Xo ) * X

F = 13.36 ° = 0.23 rad

a1 = 2.50 inches h = 6.10 inches

R = 12.00 inches Pulley e = 0.50 inchesespesor faja

V = 420 fpm

g = 32.20

= 1.75 = l

e = 103.4 ° = 1.80 rad

r0 = 1.04 ft X0 = -0.24 ft Y0 = 1.01 ft

r1 = 1.25 ft X1 = -0.29 ft Y1 = 1.22 ft

r2 = 1.55 ft X2 = -0.36 ft Y2 = 1.51 ft

rpm = 64.17 rpm end of pulley

Vo = 7.00 fps Vxo = 6.81 fps Vyo = 1.62 fps

V1 = 8.40 fps Vx1 = 8.17 fps Vy1 = 1.94 fps

V2 = 10.42 fps Vx2 = 10.13 fps Vy2 = 2.41 fps

Yo / Xo = -4.21

F = 0F > 0 1.80F < 0

= 0.97 =#VALUE! °

SQRT ( r02 - X2 )

Yo + ( Vyo / Vxo ) * ( X - Xo ) - ( g / 2 Vxo2 ) * ( X - Xo )2

Y1 + ( Vy1 / Vx1 ) * ( X - X1 ) - ( g / 2 Vx12 ) * ( X - X1 )2

Y2 + ( Vy2 / Vx2 ) * ( X - X2 ) - ( g / 2 Vx22 ) * ( X - X2 )2

ft / s2

V2 / g r

e ( rad )

l > 1 l = 1 l < 1l>=cosF l<cosF

cos F G ( rad )

-1.0

4-0

.94

-0.8

3-0

.73

-0.6

2-0

.52

-0.4

2-0

.31

-0.2

1-0

.10

0.00

0.10

0.21

0.31

0.42

0.52

0.63

0.73

0.83

0.94

1.04

1.15

1.25

1.35

1.46

1.56

1.67

1.77

1.87

1.98

2.08

-0.01

-0.01

-0.01

-0.01

-0.01

-0.01

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.00

0.01

0.01

0.01

0.01

0.01

-1.0

4-0

.88-0

.71-0

.54-0

.37-0

.21-0

.04

0.13

0.29

0.46

0.63

0.79

0.96

1.13

1.29

1.46

1.62

1.79

1.96

2.12

2.29

2.46

2.63

2.79

2.96

3.13

3.29

3.46

3.63

3.79

3.96

4.13

4.29

-1.80

-1.60

-1.40

-1.20

-1.00

-0.80

-0.60

-0.40

-0.20

0.00

0.20

0.40

0.60

0.80

1.00

1.20

1.40

1.60

1.80

DISCHARGE TRAJECTORIES FAJA 6

X

Y