Tuesday, Oct 30

Tuesday, Feb 25Chapter 10

Review

Chapter 10 ReviewFind the area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 ReviewWhat is the area of the Base? Round to the nearest tenth, if necessary.

B = 9.1 x 8 = 72.8in

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

V = lwh

V = 9.1x 8 x 8 = 582.4in orV = Bh = 72.8 8 = 582.4in

Chapter 10 ReviewFind the area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the area of the Base. Round to the nearest tenth, if necessary.

B = 18 x 9 = 162mm

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

V = lwh

V = 18 x 9 x 36 = 5832mm orV = Bh = 162 36 = 5832mm

Chapter 10 ReviewFind the area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the area of the Base. Round to the nearest tenth, if necessary.

B = 10 x 6 2 = 30cm

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

V = lwh 2

V = 10 x 6 x 4 2 = 120cm or

V = Bh = 30 4 = 120cm

Chapter 10 ReviewFind the Area of the Base. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the Area of the Base. Round to the nearest tenth, if necessary.

B = 3 x 4 2 = 6cm

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the volume. Round to the nearest tenth, if necessary.

V = lwh 2

V = 4 x 3 x 8 2 = 48cm or

V = Bh = 6 8 = 48cm

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary.

A = 7 x 4 = 28A = 4 x 10 = 40 A = 10 x 7 = 70

28 + 28 + 40 + 40 + 70 + 70 = 276in

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary. SA = 2B + hpB = 72.8h = 8p = 34.2

SA = 2 x 72.8 + 8 x 34.2 = = 145.6 + 273.6 = 419.2in

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary. SA = 2B + hpB = 162h= 36p = 54

SA = 2 x 162 + 36 x 54 = = 324 + 1944 = 2268mm

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary. SA = 2B + hpB = 3 x 4 2 = 6h= 8p = 12SA = 2 x 6 + 8 x 12 = = 12 + 96 = 108cm

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary.

Chapter 10 ReviewFind the surface area. Round to the nearest tenth, if necessary. SA = 2B + hpB = 10 x 6 2 = 30h= 4p = 25.6

SA = 2 x 30 + 4 x 25.6 = = 60 + 102.4 = 162.4cm

Chapter 10 ReviewA special box designed to hold an antique artifact is shaped like a triangular prism. The height of the box is 6.9 inches, the length is 8 inches and the width is 7.1 inches. What is the volume of box?

Chapter 10 ReviewA special box designed to hold an antique artifact is shaped like a triangular prism. The height of the box is 6.9 inches, the length is 8 inches and the width is 7.1 inches. What is the volume of box?

V = lwh 2

V = 8 x 7.1 x 6.9 2 = 195.96in

Chapter 10 ReviewThere is a sale at the candy store. They have two containers that can be filled with candy and they are the same price. One container is 5in by 6in by 9in. The other container is 4in by 8in by 8in. Which container would hold more candy?

Chapter 10 ReviewThere is a sale at the candy store. They have two containers that can be filled with candy and they are the same price. One container is 5in by 6in by 9in. The other container is 4in by 8in by 8in. Which container would hold more candy?

V = lwh V = 5 x 6 x 9 = 270inV = 4 x 8 x 8 = 256in

Chapter 10 ReviewYou are painting a room that is a rectangular prism and is 20ft by 35ft and 10ft high. You are painting the walls, floor and ceiling. A gallon of paint will cover 1250ft. How many gallons will you need?

Chapter 10 ReviewYou are painting a room that is a rectangular prism and is 20ft by 35ft and 10ft high. You are painting the walls, floor and ceiling. A gallon of paint will cover 1250ft. How many gallons will you need?SA = 2B + hp B = 20 35 = 700 h = 10 p = 20+35+20+35=110SA = 2 x 700 + 110 x 10 = 2500ft2500 1250 = 2 gallons

Chapter 10 ReviewFormulas you will need to have memorized for tomorrow:Volume of a rectangular prismV = lwh and V = BhVolume of a triangular prismV = lwh 2 and V = BhSurface Area of a prismSA = 2B + hp

Chapter 10 ReviewAgenda Notes

Homework Chapter 10 Review Homework-(extra credit for 4th period)Due Wednesday, Feb 26

Chapter 10 Test - Wednesday, Feb 26