Understanding Thermodynamics Properties Tables

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  • 8/13/2019 Understanding Thermodynamics Properties Tables

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    2. If the gi"en specific "olue is less than the specific "olue of the saturated li&uid$ youare in the copressed li&uid state# In this case$ you ay ha"e copressed li&uid ta(lesfor high pressures or else you can estiate the properties as those of the saturated li&uidat the given temperature# )If you are gi"en the pressure$ you ha"e to find the saturationteperature to ake the appro'iation for the copressed li&uid#*

    3# If the gi"en specific "olue is greater than the specific "olue of the saturated "apor$you are in the superheated "apor )gas* state# +ere you use the gi"en teperature )orpressure* and specific "olue in the gas ta(les# This usually re&uires an interpolation tofind the gi"en specific "olue#

    ,# If the gi"en specific "olue is greater than the specific "olue of the saturated li&uid andless than the specific "olue of the saturated "apor$ you are in the i'ed region# +ereyou find the &uality as )" > " f*)"g> "f*# @ou can then use this &uality to find otherproperties$ such as the internal energy$ as u / u fA ')ug> uf*#

    5# -'aple# %or !ater at 200 ka !ith a specific "olue of 0#5 3kg !e find that thespecific "olues of the saturated li&uid and saturated "apor at the gi"en pressure of 200ka are "f/ 0#00101

    3kg and "g/ 0#4457 3kg# Thus !e are in the i'ed regionand !e ha"e to copute the &uality as ' / )" B "f*)"gB "f* / )0#5 B 0#00101* )0#4457 B0#00101* / 0#5,# nce !e kno! the &uality !e can find all other properties# %ore'aple the enthalpy is found as h / h fA ' hfg/ 50,#70 A )0#5,*)2201#* / 17,# k6kg#

    # nother e'aple# %or !ater at 500o% !ith a specific "olue of ft3l($ !e see that thisspecific "olue is greater than the specific "olue of the saturated li&uid at 500o%$ !hichis 0#71 3kg so !e kno! that !e are in the gas )superheat* region# Scanning theta(les for T / 500o%$ !e find a specific "olue of 7#017 ft3l(at 40 psia and a specific"olue of 5#547 ft3l(at 100 psia# Thus our gi"en specific "olue of ft

    3l(ust (e(et!een these pressures# .e ha"e to interpolate using the follo!ing e&uation for ageneral property @ !hich ay e&ual $ u$ s$ or h# %irst !e find the interpolation factor$ f$!hich is a easure of the relati"e distance (et!een the t!o data points# 9ote that f !ill(e negati"e in this case (ecause " is decreasing as is increasing#

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    .e then use this factor to copute any property that is ta(ulated at the t!o pressures# In thee&uation (elo!$ @ represents u$ h$ s$ or #

    ( ))80,500()100,500()80,500(6,500 0003

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    C. If you are given temperature !or pressure" and another specific property !specificinternal energy, specific enthalpy, or specific entropy", follow the same process usedas in part . #his is written below using entropy as a specific e$ample, but you coulduse energy or enthalpy.

    1# se the gi"en pressure or the gi"en teperature to find the specific entropy of thesaturated li&uid )sf* and saturated "apor )sg*#

    -ngineering ;uilding ail: lcaretto?csun#edu 43,4 %a': 414#77#702

    mailto:[email protected]:[email protected]
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    2# If the gi"en specific entropy is less than the specific entropy of the saturated li&uid$ youare in the copressed li&uid state# In this case$ you ay ha"e copressed li&uid ta(lesfor high pressures or else you can estiate the properties as those of the saturated li&uidat the given temperature# )If you are gi"en the pressure$ you ha"e to find the saturationteperature to ake the appro'iation for the copressed li&uid#*

    3# If the gi"en specific entropy is greater than the specific entropy of the saturated "apor$you are in the superheated "apor )gas* state# +ere you use the gi"en teperature )orpressure* and specific entropy in the gas ta(les# This usually re&uires an interpolation tofind the gi"en specific entropy#

    ,# If the gi"en specific entropy is greater than the specific entropy of the saturated li&uid andless than the specific entropy of the saturated "apor$ you are in the i'ed region# +ereyou find the &uality as )s > s f*)sg> sf*# @ou can then use this &uality to find otherproperties$ such as the internal energy$ as u / u fA ')ug> uf*#

    5# The e'aples in this case proceed in e'actly the sae !ay as the e'aples for case ;#nly the other specified property replaces the specific "olue in the e'aples#

    -ngineering ;uilding ail: lcaretto?csun#edu 43,4 %a': 414#77#702

    mailto:[email protected]:[email protected]