Unit 3 Review Scavenger Hunt

The function y = 187900 (1.025)x represents the value of a home x years after purchase.

What is the rate of appreciation of the home?

• 1.025% (Go to Station A)• 25% (Go to Station B)• 2.5% (Go to Station F)• 187900% (Go to Station C)

Station A

Station F

The function y = 290,000 (0.92)x represents the value of an old home that has been abandoned by its owners x years ago.

Find the decay rate of the old home.

• 92% (Go to Station V)• 8% (Go to Station H)• .92% (Go to Station C)• .8% (Go to Station R)

Station H

Solve the following:3(10)x + 4 + 3 = 15

• x= -3.4 (Go to Station R)• x = 4 (Go to Station E)• X = -5 (Go to station F)• x = 3.4 (Go to Station Y)

Station R

Find the inverse of the following set of points:

f(x) = {(4, -7), (9, 8), (1, 7), (6, 2)}

• f-1(x) = { (-7,4), (8, 9), (7, 1), (2, 6)} (Go to Station O)

• f-1(x) = { (-4, 7), (-9, -8), (-1, -7), (-6, -2)} (Go to Station T)

• f-1(x) = { (7,4), (-8, -9), (7, 1), (2, 6)} (Go to Station X)

• f-1(x) = { (-4,7), (8, 9), (7, 1), (2, 6)} (Go to Station E)

Station OEvaluate the following logarithm:

log 102.9 = ?

• 2 (Go to Station A)• -2.9 (Go to Station H)• Not Possible (Go to Station J)• 2.9 (Go to Station W)

Station W

Find the inverse of the following function

f(x) =

• f-1 (x) = -1/3x – 6 (Go to Station O)• f-1 (x) = 3x-18 (Go to Station T)• f-1 (x) = 3x – 6 (Go to Station H)• f-1 (x) = -3x + 6 (Go to Station A)

Station T

Simplify the following expression:

• 8s2 (Go to Station R)• 8s4 (Go to Station U)• 64s29 (Go to Station S)• 8s (Go to Station B)

Station U

Use the exponent rules to solve for x in the following:

• x = 3 (Go to Station W)• x = 2/3 (Go to Station T)• x = 16 (Go to Station B)• x = 4 (Go to Station O)

(32x)(316) = 348

Station BA popular antique is gaining value because it is so hard to

find. In 1985 its value was $125, and in 2000 its value was $1925.90.

Write the exponential function to model the value of this antique.

• y = 125 (1.2)x (Go to Station M)• y = 1925.90 (1.2)x (Go to Station F)• y = 125 (.8)x (Go to Station U)• y = 125 (10)x (Go to Station V)

Station M

For the function f(x) = (0.75)x – 1, evaluate f(2)

• f(2) = .4375 (Go to Station T)• f(2) = - .4375 (Go to Station A)• f(2) = .5625 (Go to Station F)• f(2) = - .5625 (Go to Station R)