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Unit Revision PQ
Q and A
Q1
Q2
Q3
Q4
Q5
Q6
Q7
Q8
Q9
Q10
Q11
Q12
Q13
Q14
Q15
Q16
Q17
Q18
Q19
Q20• An aircraft is flying due north with a velocity of 200 m s−1. A side wind of velocity
50 m s−1 is blowing due east. What is the aircraft’s resultant velocity (give the magnitude and direction)?
Q21
• A cyclist is travelling at 15 m s−1. She brakes so that she doesn’t collide with the wall. Calculate the magnitude of her deceleration.
Q22• To get a rough value for g, a student dropped a stone from the top of a cliff . A
second student timed the stone’s fall using a stopwatch. Here are their results: estimated height of cliff = 30 m time of fall = 2.6 s Use the results to estimate a value for g.
Or alternatively
Q23• A cyclist of mass 60 kg rides a bicycle of mass 20 kg. When starting off, the cyclist
provides a force of 200 N. Calculate the initial acceleration.
Q24• A car of mass 500 kg is travelling at 20 m s−1. The driver sees a red traffic light
ahead, and slows to a halt in 10 s. Calculate the braking force provided by the car.
• Calculate the acceleration required. The car’s final velocity is 0 m s−1, so its change in velocity Δv = 0 − 20 = −20 m s−1
• Calculate the force, we use: F = ma = 500 × −2 = −1000 N So the brakes must provide a force of 1000 N. (The minus sign shows a force decreasing the velocity of the car.)
Q25• A boy of mass 40 kg is on a waterslide which slopes at 30° to the horizontal. The
frictional force up the slope is 120 N. Calculate the boy’s acceleration down the slope. Take the acceleration of free fall g to be 9.81 m s−2.
Boy’s weight W = 40 × 9.81 = 392
N the frictional force up the slope F = 120 N
Contact force N at 90° to the slope
Component of W down the slope = 392 × cos 60° = 196
N component of F down the slope = −120 N (negative because F is directed up the slope)
Component of N down the slope = 0 (because it is at 90° to the slope)
It is convenient that N has no component down the slope, since we do not know the value of N.
Calculate the resultant force on the boy: resultant force = 196 − 120 = 76 N
Calculate his acceleration:
acceleration = resultant force mass =
76 40 = 1.9 ms−2
Q26• A ship is pulled at a constant speed by two small boats, A and B. The engine of the
ship does not produce any force.
Q27• A block of mass 1.5 kg is at rest on a rough surface which is inclined at 20° to the
horizontal as shown.
Q28• A man pulls a box along horizontal ground using a rope. The force provided by the
rope is 200 N, at an angle of 30° to the horizontal. Calculate the work done if the box moves 5.0 m along the ground.
• horizontal component of force = 200 cos 30° ≈ 173 N
• work done = force × distance moved = 173 × 5.0 = 865 J
Q29• The crane shown lifts its 500 N load to the top of the building from A to B.
Distances are as shown on the diagram. Calculate how much work is done by the crane.
Q30• Diagram shows the forces acting on a box which is being pushed up a slope.
Calculate the work done by each force if the box moves 0.50 m up the slope.
Q31• A 120 kg crate is dragged along the horizontal ground by a 200 N force acting at an
angle of 30° to the horizontal, as shown in Figure 5.20. The crate moves along the surface with a constant velocity of 0.5 m s−1. The 200 N force is applied for a time of 16 s.
Q32
Q33• A sprint cyclist starts from rest and accelerates at 1 m/s2 for 20 seconds. He then
travels at a constant speed for 1 minute and finally decelerates at 2 m/s2 until he stops. Find his maximum speed in km/h and the total distance covered in metres.
Q34• A ball is projected vertically upwards with an initial velocity of 30 m/s. Find a its
maximum height and b the time taken to return to its starting point. Neglect air resistance and take g = 10 m/s2.
Q35• A block of mass 2 kg has a constant velocity when it is pushed along a table by a
force of 5 N. When the push is increased to 9 N what is a the resultant force, b the acceleration?
Q36• Use the direction conventions to determine the perpendicular components of a
235 N force acting on a bike at a direction of 17.0° north of west.
Q37
Q38• A golf ball is dropped onto a concrete floor and strikes the floor at 5.0 m s–1.
It then rebounds at 5.0 m s–1. The contact with the floor lasts for 25 ms.
Q39• A construction worker accidentally knocks a brick from a building so that it falls
vertically a distance of 50 m to the ground. Use g = –9.8 m s–2 and ignore air resistance.
• How long does the brick take to fall halfway, to 25 m?
Q40• A 2 tonne truck travelling at 100 km h–1 slows to 80 km h–1 before turning a
corner.
• Calculate the work done by the brakes to make this change. Give answers to two significant figures.
Q40 continued
• If it takes 50 m for this deceleration to take place, calculate the average force applied by the truck’s brakes.