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Warm-Up 4/29 simplify1.
2.
3.
4.
¿12
¿13
¿2
¿1
Rigor:You will learn how to find the number of
possible outcomes using the Fundamental Counting Principle, permutations and
combinations.
Relevance:You will be able to solve probability
problems using the Fundamental Counting Principle, permutations and combinations.
0-4 Counting Techniques
Probability is a measure of the chance that a given event will occur.
Outcome is the result of a probability experiment or an event.
Sample Space is the set of all possible outcomes of an experiment
A tree diagram can be used to list all outcomes in a sample space.
EX: Blood type R H factor
A
B
AB
O
+– +– +–
+–
Fundamental Counting Principle
Words – The number of possible outcomes in a sample space can be determined by multiplying the number of possible outcomes for each event.
Symbols – If event M can occur in m ways and is followed by event N that can occur in n ways, then the event M followed by N can occur in m•n ways.
This rule can be extended for 3 or more events.
4 possible blood types and 2 possible RH factors then there are 42 or 8 possible ways to label blood.
Example 1: A bicycle manufacturer makes five- and ten-speed bikes in seven different colors and four different sizes. How many different bikes do they make?
& 4 frame choices7 color choices, 2 gear choices,
2 ∙7 ∙ 4=56
56 different bicycles can be made.
When there are m ways to do one thing, and n ways to do another, then there are m•n ways of doing both.
Your Turn:You are picking out an outfit.
There are 3 pants and 2 shirts.
How many possible outfits? (draw a tree diagram)
3•2 = 6 outfits1 2
3
ab
ab
ab
Permutation is an arrangement of a group of distinct objects in a certain ORDER.
There are 6 permutations of the letters A, B and C.
ABC, ACB, BAC, BCA, CAB, CBA
_______ _________ ________ = choices for first letter
choices for second letter
choices for third letter
total number of permutations
3•2•1 = 6 permutations
3•2•1 = 3!
Factorial
The number of permutations of distinct objects is !.0 !=1
Two types of permutation:
No Repetition: for example the first three people in a running race. You can't be first and second.
The number of available choices reduces each time.
n × (n – 1) × (n – 2) × …
Repetition is Allowed: such as the combination of a lock. It could be "333". These are the easiest to calculate!n × n × ... × n, (r times) = nr
Example 2a: There are 8 finalists in a band competition. How many different ways can the bands be ranked if they cannot receive the same ranking?
8 !
The bands can be ranked in 40,320 different ways.
8 ∙7 ∙ 6 ∙5 ∙ 4 ∙ 3 ∙2 ∙ 1=40,320
Example 2b: How many different ways are their to order 16 pool balls?
16 !
different ways.
16 ∙ 15 ∙14 ∙ …∙ 3 ∙ 2∙ 1=20,922,789,888,000
What if we don't want to choose them all, just 3 of them?
16 ∙ 15 ∙14=3360
different ways.
Example 2c: How many different ways are their to unlock the lock?
In the lock, there are 10 numbers to choose from (0,1,...9)
There are 1000 permutations to unlock the lock.
10 ∙ 10 ∙10=103=1000
So, we should really call this a "Permutation Lock"!
There are 3 numbers.
Your Turn:1. You have 5 books to arrange on a shelf. How many
different ways can this be done?
2. To create an entry code for a push-button lock, you need to first choose a letter and then, three single-digit numbers. How many different entry code can you create?
3. In how many ways can 25 runners finish first, second and third?
5 !5 ∙4 ∙ 3 ∙ 2 ∙1=120
26 ∙ 10 ∙10 ∙ 10=26000
25 ∙ 24 ∙ 23=13800
Key Concept: PERMUTATIONS of n Objects Taken r at a Time:
The number of permutations of r objects taken from a group of n distinct objects is given by
Going back to the pool ball question. When we only want 3 out of the 16 pool balls.
Example 3: How many ways can two students be assigned to five tutors if only one student is assigned to each tutor?
5 different tutors taken 2 at a time.
The students can be assigned in 20 different ways.
𝑛𝑃𝑟=𝑛 !
(𝑛−𝑟 ) !
n = 5
r = 2 5𝑃2=5 !
(5−2 )!
¿5 ∙4 ∙ 3 ∙ 2∙ 1
3 ∙ 2∙ 1
¿2 0
Your Turn:A photographer has matted and framed 15 photographs and needs to select 10 for a show. How many ways can the photographs be arranged?
𝑛𝑃𝑟=𝑛 !
(𝑛−𝑟 ) !¿15 ∙ 14 ∙ 13 ∙12 ∙11 ∙ 10 ∙ 9 ∙ 8 ∙7 ∙6
¿10,897,286,400
In English we use the word "combination" loosely
• My fruit salad is a combination of apples, grapes and bananas
• The combination to the safe was 472
– We don't care what order the fruits are in, they could also be "bananas, grapes and apples" or "grapes, apples and bananas", its the same fruit salad.
– Now we do care about the order. "724" would not work, nor would "247". It has to be exactly 4-7-2
Star This
If the order doesn't matter, it is a Combination.
If the order does matter it is a Permutation.
To help you to remember, think “Combination”… Committee “Permutation” ... Position
A combinations is a selection of distinct objects in which the order of the objects selected is not important.
Key Concept: COMBINATIONS of n Objects Taken r at a Time:
The number of combinations of r objects taken from a group of n distinct objects is given by
Example 4: How many ways are there to chose 5 cards from a standard deck of 52 playing cards?
52 cards taken 5 at a time and order doesn’t matter.
There are 2,598,960 ways to choose 5 cards from a standard deck of playing cards.
𝑛𝐶𝑟=𝑛 !
(𝑛−𝑟 ) !𝑟 !
n = 52
r = 5 52𝐶5=52!
(52 −5 ) !5 !
¿52∙ 51 ∙50 ∙ 49 ∙ 48 ∙ 47 !
47 ! ∙5 ∙ 4 ∙3 ∙2 ∙1¿2 ,598,960
¿52 !
4 7 !5 ! 210
Example 5: Twenty-five students write their name on paper. Then three names were picked at random to receive prizes. (permutation or combination)
a. Selecting 3 people to each receive a “no homework” pass.
b. Selecting 3 students to receive one of the following prizes: 1st prize – a new graphing calculator; 2nd prize- a “no homework” pass; 3rd prize – a new pencil.
Order doesn’t matter so this is a combination.
Order does matter so this is a permutation.
Your Turn:A restaurant offers a total of 8 side dishes. How many different ways can a customer choose 3 side dishes?
¿56𝑛𝐶𝑟=𝑛 !
(𝑛−𝑟 ) !𝑟 !
AssignmentProb/Stats #1 WS, 1-19 All Conics Project Due Dates:Sections 3 & 4 + 1 & 2 due tomorrowYOU MUST HIGHLIGH CORRECTIONS USING A BLUE HIGHLIGHTER.
Warm-Up 4/29
1. A folders come in 8 different colors. How many different ways can I choose 4 colors?
2. A push-button lock, has a code that you need to first choose a letter and then, 4 single-digit numbers. How many different entry code can you create?
¿708𝐶4=8 !
(8 − 4 ) !4 ! ¿8 ∙7 ∙6 ∙5 ∙ 4 !4 ! ∙ 4 ∙3 ∙ 2∙ 1
2
26 ∙ 10 ∙10 ∙ 10 ∙ 10¿260 ,0 00
Conics Project Due Dates:Sections 3 & 4 + 1 & 2 due tomorrowYOU MUST HIGHLIGH CORRECTIONS USING A BLUE HIGHLIGHTER.