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4 minutes. Warm-Up. Evaluate each expression. x – 2, for x = -5 -2x, for x = -1.5 x 2 , for x = -4 -x 2 , for x = -1.2 x 3 , for x = -2 -x 3 , for x = -0.1. 2.3 Intro to Functions. Objectives: State the domain and range of a relation, and tell whether it is a function - PowerPoint PPT Presentation
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Warm-UpEvaluate each expression.
1) x – 2, for x = -5
2) -2x, for x = -1.5
3) x2, for x = -4
4) -x2, for x = -1.2
5) x3, for x = -2
6) -x3, for x = -0.1
4 minutes
2.3 Intro to Functions2.3 Intro to Functions2.3 Intro to Functions2.3 Intro to FunctionsObjectives: •State the domain and range of a relation, and tell whether it is a function•Write a function in function notation and evaluate it
Definition of a Function
Function: each value of the first variable is paired with exactly one value of the second variable
Domain: set of all possible values of the first variable
Range: set of all possible values of the second variable
Example 1
x y
2 2
4 3
6 4
8 5
State whether the data in each table represents y as a function of x. Explain.
x y
3 4
3 5
5 -4
6 3
function not a function
Vertical-Line TestIf every vertical line intersects a given graph at no more than one point, then the graph represents a function.
function not a function
Definition of a RelationRelation: each value of the first variable
is paired with one or more values of the second variable
Domain: set of all possible values of the first variable
Range: set of all possible values of the second variable
Example 2State the domain and range of the relation, and state whether it is a function.{ (–7, 5), (4, 12), (8, 23), (16, 8) }
domain: { –7, 4, 8, 16}range: { 5, 8, 12, 23 }
This is a function because each x-coordinate is paired with only one y-coordinate.
Function NotationIf there is a correspondence between values of the domain, x, and values of the range, y, that is a function, then y = f(x), and (x,y) can be written as (x,f(x)).
The variable x is called the independent variable.The variable y, or f(x) is called the dependent variable.
Example 3
f(–1) = –2.5 (–1) + 11f(–1) = 2.5 + 11
f(–1) = 13.5
Evaluate f(x) = –2.5x + 11, where x = –1.
Example 4A gift shop sells a specialty fruit and nut mix at a cost of $2.99 per pound. During the holiday season, you can buy as much of the mix as you like and have it packaged in a decorative tin that costs $4.95.a) Write a linear function to model the total cost in dollars, c, of the tin containing the fruit and nut mix as a function of the number of pounds of the mix, n.
c(n) =
4.95 + 2.99n b) Find the total cost of a tin that contains 1.5
pounds of the mix.c(n) = 4.95 + 2.99n
c(1.5) = 4.95 + 2.99(1.5)c(1.5) = 9.44
$9.44
Homework
p.107 #17-49 odds