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Week 10: VaR and G Week 10: VaR and G ARCH model ARCH model

Week 10: VaR and GARCH model

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Week 10: VaR and GARCH model. Estimation of VaR with Pareto tail. Disadvantages (parametric and nonparametric method): For parametric method: the assumption of normal distribution is always not true. - PowerPoint PPT Presentation

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Page 1: Week 10:  VaR and GARCH model

Week 10: VaR and GARWeek 10: VaR and GARCH modelCH model

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Estimation of VaR with Pareto tailEstimation of VaR with Pareto tail

• Disadvantages (parametric and nonparametric method):

a. For parametric method: the assumption of normal distribution is always not true.

b. For nonparametric estimation, it is usually possible only for large α, but not for small α. So, one may expect to resort to

use nonparametric regression for large αto estimate small one.

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Extreme Value Theory (EVT)Extreme Value Theory (EVT)• Assume {rt} i.i.d with distribution F(x), then the C

DF of r(1) , denoted by Fn,1(x) is given by Fn,1(x)=1-[1-F(x)]n. In practice F(x) is unknown and then Fn,1(x) is un

known. The EVT is concerned with finding two sequence {an) and {bn} such that

(r(1) – an)/ bn

converges to a non-degenerated distribution as n goes to infinity. Under the independent assumption, the limit distribution is given by

F*(x)=1-exp[-(1+kx)1/k], when k≠0 and 1-exp[-exp(x)], when k=0.

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Three types for the above EVT distributionThree types for the above EVT distribution

a. Type I: k=0, the Gumbel family with CDF: F*(x)= 1-exp[-exp(x)], x R.∈

b. Type II: k<0, the Frechet family with CDF F*(x)= 1-exp[-(1+kx)1/k], if x<-1/k and =1, otherwise.

c. Type III: k>0, the Weibull family with CDF F*(x)= 1-exp[-(1+kx)1/k], if x>-1/k and =1, otherwise.

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Pareto tailsPareto tails• In risk management, we are mainly interested in

the Frechet family, which includes stable and student-t distribution.

• We know that when {rt} i.i.d with tail distribution P(|r1|>x)=x-βL(x), i.e., rt has Pareto tails, then {Xt} converges to a stable distribution with tail index β. Here the tail index β is always unknown. To evaluate the VaR of small α, we estimate the tail index β first and apply the nonparametric method to draw the value of VaR for largeα0, and then use the VaR(α0) to estimate VaR(α) . (how?) This is the so-called semi-parametric method.

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How to estimate the tail index How to estimate the tail index ββ??• MLE: when the whole distribution of rt is known.• Linear regression: suppose {rt} have a Pareto left tail, for x>0,

P(r1 <-x)= x-βL(x), then log(k/n)=log P(r1 <r(k) )= -βlog (-r(k)) + log L(-r(k)).

• Hill estimator: based on MLE, one can get that n/β= log(r1/c)+ log(r2/c)+….+ log(rn/c), when P(r1 <-x)= 1-(x/c)-β, x>c. When one only uses the data in the t

ail to compute the tail index, then β^ =n(c)/∑ri>c log(ri/c) and let H=1/β, then

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The properties of Hill estimatorThe properties of Hill estimator

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VaR for a derivativeVaR for a derivative

• Suppose that instead of a stock, one owns a derivative whose value depends on the stock. One can estimate a VaR for this derivative by

VaR for derivative =LX VaR for asset, where L=(Delta pt-1

asset/ pt-1option),

and Delta=d C(s, T,t, K, σ,r)/dS.

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Volatility modelingVolatility modeling

• Volatility is important in options trading: for example the price of a European call option, the well known Black-Scholes option pricing formula states that the price is C(S0) = S0(d1) – Ke –rT (d2),

where d1= (T) –1[log (S0/K) + (r+2/2)T], d2= (T) –1[log (S0/K) + (r–2/2)T] = d1 –

T.

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• In VaR, let Rt be the daily asset log-return and St be the daily closing price, then

Rt+1=log(St+1/ St) .

Suppose the return is normal distributed with mean zero, then one can write it as

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• The variance as measure by square return, exhibit strong autocorrelation, so that if the recent period was one of high variance, then tomorrow is tend to have high variance. To capture this phenomenon, the easiest way is to use

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The advantages of RiskmetricsThe advantages of Riskmetrics

• It is reasonable from the observed return that recent returns matter tomorrow’s variance than distance returns.

• It is simple: only one parameter is contained in the model.

• Relative little data need to be stored to calculate tomorrow’s variance.

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Shortcoming of RiskmetricsShortcoming of Riskmetrics

• It ignores the fact that the long-run average variance tends to relative stable over time.

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GARCH modelGARCH model

• ARCH(1) model:

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The unconditional kurtosis of ARCH(1)The unconditional kurtosis of ARCH(1)

• Suppose the innovations are normal, then E(at

4| Ft-1)=3[ E(at2 | Ft-1) ]2

=3(α0+α1at-12 )2,

it follows that Eat

4 = 3α0 2

( 1 +α1 ) / [ ( 1 -α1

) ( 1 -3α1 2 )]

and Eat

4 /(Eat2 )2 =3 ( 1 -α1

2 )/ ( 1 -3α1 2 )>3.

This shows that the tail distribution of at is heavier than that of a normal distribution.

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How to build an ARCH modelHow to build an ARCH model

• Build an econometric model (e.g. an ARMA model) for the return series to remove any linear dependence in data abd use the residual series of the model to test for ARCH effects

• Specify the ARCH order and perform estimation: AIC(p)=log[(σ^)p

2)]+2p/n

• Model checking: Ljung-Box statistics. Q=n(n+2) ∑k=1 h (ρ^)

k2/(n-k).

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GARCH(1, 1) modelGARCH(1, 1) model

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Note that: Note that: σσ22==ωω/(1-/(1-αα--ββ))

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The forecast of variance of k-The forecast of variance of k-day cumulative returnday cumulative return

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If the returns have zero autocorrelation and If the returns have zero autocorrelation and σσt+1t+1<<σσ, then Var forecast of GARCH> RM, then Var forecast of GARCH> RM