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Work, Pumping liquid and Fluid Pressure
Lesson 7.7
Work
• Work is the product of force and distance.
2
How much work is done in lifting a mass of 1.2 kg a distance of 12 meters?The weight of the mass is (1.2)(9.8) Newton, so the work is (1.2)(9.8)(12) = 141.12 joules.
3
Work
• DefinitionThe product of❧ The force exerted on an object❧ The distance the object is moved by the force
• When a force of 50 lbs is exerted to move an object 12 ft.❧ 600 ft. lbs. of work is done
50
12 ft
4
Hooke's Law
• Consider the work done to stretch a spring
• Force required is proportional to distance❧ When k is constant of proportionality❧ Force to move dist x = k • x = F(x)
• Force required to move through i th
interval, ❒x❧ ❒W = F(xi) ❒x
a b
❒x
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Hooke's Law
• We sum those values using the definite integral
• The work done by a continuous force F(x)❧ Directed along the x-axis❧ From x = a to x = b
( )b
a
W F x dx= ∫
Find the work required to compress a spring from its natural length of 1 ft to a length of 0.75 ft if the force constant is K=16lb/ft.
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Hooke's Law
• A spring is stretched 15 cm by a force of 4.5 N❧ How much work is needed to stretch the
spring 50 cm?
• What is F(x) the force function?
• Work done?
4.5 0.15
30
( ) 30
F k x
k
k
F x x
= ×= ×
==
0.5
0
30W xdx= ∫
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Winding Cable
• Consider a cable being wound up by a winch❧ Cable is 50 ft long❧ 2 lb/ft❧ How much work to wind in 20 ft?
• Think about winding in ❒y❧ y units from the top → 50 – y ft hanging ❧ dist = ❒y ❧ force required (weight) =2(50 – y)
( )20
0
2 50W y dy= −∫
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Pumping Liquids
• Consider the work needed to pump a liquid into or out of a tank
• Basic concept: Work = weight x dist moved
• For each ❒V of liquid❧ Determine weight❧ Determine dist moved❧ Take summation (integral)
13
• Draw a picture with thecoordinate system
• Determine mass of thinhorizontal slab of liquid
• Find expression for work needed to lift this slab to its destination
• Integrate expression from bottom of liquid to the top
-a
r-y
-b
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Pumping Liquids – Guidelines
• Draw a picture with thecoordinate system
• Determine mass of thinhorizontal slab of liquid
• Find expression for work needed to lift this slab to its destination
• Integrate expression from bottom of liquid to the top
ab
r
2
0
( )a
W r b y dyρ π= × × −∫
y
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Pumping Liquids
• Suppose tank has❧ r = 4❧ height = 8❧ filled with petroleum (54.8 lb/ft3)
• What is work done to pump oil over top❧ Disk weight?❧ Distance moved?❧ Integral?
84
54.8 16Weight yπ= × × ×∆(8 – y)
8
0
54.8 16 (8 )Work y yπ= × × × − ∆∫
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Pumping Liquids
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Pumping Liquids A hemispherical bowl with radius 10 ft is filled with water to a level of 6 ft. Find the work done to the nearest ft.lb to pump all the water to the top of the bowl.Density of water = 62.4 lb/ft3.
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Pumping Liquids
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• A spherical tank of radius 8 feet is half of oil that weight 50 pounds per cubic foot. Find the work required to pump oil out through a hole in the top of the tank.
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Fluid Pressure
• Consider the pressure of fluidagainst the side surface of the container
• Pressure at a point❧ Density x g x depth
• Pressure for a horizontal slice❧ Density x g x depth x Area
• Total force( ) ( )
d
c
F h y L y dyρ= ×∫
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( ) ( )d
c
F h y L y dyρ= ×∫
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25
Fluid Pressure
• The tank has cross sectionof a trapazoid❧ Filled to 2.5 ft with water❧ Water is 62.4 lbs/ft3
• Function of edge• Length of strip• Depth of strip
(-2,0) (2,0)
(-4,2.5) (4,2.5)
2.5 - y
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Fluid Pressure
• The tank has cross sectionof a trapazoid❧ Filled to 2.5 ft with water❧ Water is 62.4 lbs/ft3
• Function of edge• Length of strip• Depth of strip
• Integral
(-2,0) (2,0)
(-4,2.5) (4,2.5)
2.5 - y
y = 1.25x – 2.5x = 0.8y + 22 (0.8y + 2)
2.5 - y