975$9.163/MWh
9.16
9.16
9.16
975 = 450 + 315 + 210
483 MW
305 MW
187 MW
Upper limit violated:→ P1= 450 MW
→ solve the dispatch problem with two generators:P2 + P3 = 525 MW
→ λ = $9.4/MWh→ P2 = 315 MW→ P3 = 210 MW
lossPPPP
PP
PP
PP
=−++
+−
=
+−
=+−
150
),014.8.6)(000358.1
1(
)018.3.6)(000456.1
1()016.7()000436.1
1(
321
33
22
11
Results (obtained numerically):•P1 = 35.1 MW•P2 = 64.1 MW•P3 = 52.5 MW•Ploss = 1.7 MW•Pdemand = 150 MW