Evaluation and Optimization of AC Losses in a Fully Superconducting Machine for Offshore Wind
TurbinesB. Thanatheepan, Noah Salk, Dongsu Lee
Supervisor: Prof. Kiruba.S.Haran
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Electrical and Computer Engineering
University of Illinois, Urbana-Champaign
Global Wind Turbines Market Trends
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π = π»πππ
π = βππ πππ«ππ³
π
π΅ππππππ
π΅ππππ π«
ππ
π = πΎ β π£πππ’ππ β ππππππ‘ππ πππππππβ πΈππππ‘πππππ πππππππ β ππ
Constraints - Transportation- Tower- Thermal β hysteresis loss - eddy current
loss - Cost - Resistive loss- Mechanical constraints - loss
1. Capture more energy2. Increase capacity factor: Partial loads 3. Reduced levelized cost of energy
Bigger is better !!Why?
Solution..Superconducting technologies!! Resistance is almost 0 at cryogenic temperature.
Air-gap flux density 0.5 T to10π Partially superconducting
Current density 5A/mm2 to 200π΄/ππ2 Fully superconducting
Superconducting Machines
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β’ GE (+ Alstom, Converteam)
β’ Siemens
β’ AMSC
β’ AML superconductivity
Superconducting machines
Partial Superconducting
Fully Superconducting
Conventional design with iron core/ iron shield
Actively shielded machines
Conventional design with iron core/ iron shield
Actively shielded machines
β’ UIUC
β’ Previously explored for electric aircraft propulsion under NASA learn program.
GE high temperature partial SC motor Proposed machine model
Challenges
β’ Cost
β’ Minimize the SC usage
β’ AC loss in armature
β’ Mitigate ac losses
β’ Cryocooler design
β’ Critical temperature
β’ Mechanical design
β’ Torque transmission
β’ Nacelle integration
β’ Employing in a wind turbine
Advantage of Superconducting Turbines
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β’ Direct drive and larger capacity 10MW to 20MW
β’ Increased efficiency up to 99%.
β’ Weight 30 -50% less than a permanent magnet machine.
β’ 10-20 % reduction in capital cost.
β’ Reduction in maintenance cost
β’ Efficient energy capturing capability at partial loads.
Reduced levelized
cost of energy
(LCOE)
Proposed Machine Specification β Active Shield
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Specification Value
Power 10MW
Pole number 10 / 20 /30 / 40/ 50/ 60
Speed 10 rpm
Superconductor MgB2
Operating temperature 20 K
Armature Current density Max 200 Arms/mm2
Field current density 200 A/mm2
Shield current density 200 A/mm2
β’Active magnetic shield to eliminate field outside
β’No core loss or core saturation - explore peak fields up to 10T ??
β’Further weight reduction
β’Estimated low ac loss ??
Fully Superconducting Machines
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Low ac loss MgB2
superconductors (HyperTech)
Symbol ParameterConductor I0.32/10/5
π½π
Critical current density at 0.4 self-field at 20K [A/m2]
6.6e9
π«πΆ SC diameter [mm] 0.32ππ Filament diameter [πm] 10π Number of filaments 114π The area fraction of the wire that is SC 0.15
ππππ Effective fill factor 0.49
ππππ Effective transverse resistivity [Ξ©-m] 12.5e-8
πΏ The twist pitch (mm) 5
Actively-Shield Fully Superconducting Motor for Wind Turbine Conceptual Design
Flux density Vs Critical Current Density
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Measured B Vs Jc for MgB2 conductors at 20 K
π½πΈ = π β π βπ·2
4β π½πΆ
At 20K and 2T field density π½πΈ = 200π΄/ππ2 at 20K and 3T π½πΈ = 113π΄/ππ2
Operating current β Safety margin πΌπ΄ = .5 β πΌπ , πΌπΉ = .75 β πΌπ
Partial and fully: Self magnetic field at field coils cannot go beyond allowable field valueEg: π½πΈ = 200π΄/ππ2 field current designs limited to 2T self field
Fully: Armature current cannot exceed 50% of the airgap field critical current value
AC Losses
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βͺ Penetration field
π©π = π.π β ππ β π±π β π π
βͺ Hysteresis loss
π·π =π
πβ π©π β π±π β π π β π
βͺ Eddy current loss
π·π =π π
π β ππππβ π©π β π«π β π
π
βͺ Coupling loss
π·π =π
π β ππππβ π β π³π β π©π
π
βͺ Transport current loss
π·π° = ππ βπ
π β π°ππ β
π βπ°ππ°π
β πππ π βπ°ππ°π
+π°ππ°π
β. π βπ°ππ°π
π
π βπ«ππ
π
βͺ K=4, n=2 constants
π±π
Critical current density [A/m2]
π«πΆ SC diameter [mm]
π π Filament diameter [πm]
π Number of filaments
π The area fraction of the wire that is SCππππ Effective fill factor
ππππ Effective transverse resistivity [Ξ©-m]
π³ The twist pitch (mm)
Possible operating frequency: 1Hz-400HzPossible Field density: 0.4 T to 10 T
Need more experiment data at operating conditions to reduce uncertainty in loss prediction
Comparison of ac losses β Design Space
βͺ AC losses estimated in π/ππ3 while changing Field density and electrical frequency
βͺ Assuming armature current density is 50% of the π½π at applied field density 0-10T
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10MW Wind Generator Project - NSF 2.5 MW Motor CHEETA Project - NASA
10 rpm machine with 4 8 16 24 32 and 40 pole designs β’ Low ac losses per ππ3
β’ Large armature conductor length β order of 100 kmMinimize conductor usage
4500 rpm machine with 2 4 6 8 10 and 12 pole designs β’ High ac losses per ππ3
β’ Small armature conductor length β order of 1 kmMinimize flux density and pole count
Comparison of ac losses β Design Space
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10 rpm machine with 16 pole designs 1.33Hzβ’ Hysteresis losses are dominant β’ Rate of change is increasing with
decreasing flux densityβ’ There is a possibility of getting very low
flux density designs with larger weight and minimal ac losses
4500 rpm machine with 8 pole design 300 Hzβ’ Coupling losses are dominant β’ Rate of change is decreasing with
decreasing flux densityβ’ There is no possibility of getting very low
flux density designs with larger weight and minimal ac losses
Flux Density (T)
Comparison of ac losses β Design Space
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Assuming armature current density is 50% of the π½π at applied field density 0-2T
10 rpm machine with 10 20 30 40 and 60 pole designs with 0T to 3T airgap flux densityArmature SC machine conductors experience varying flux density across a slotOptimal design space for wind: 0.8 T to 1 TOptimal design space for electric propulsion: 0.4 to 0.6T
Feasible design space
Optimization
Parameter min max Armature slot inner radius [X1](mm) 1500 2000Armature slot radial height [X2](mm) 1 100Radial distance between field coils and shield coils [X3] (mm) 1 100Field slot radial height [X4] (mm) 1 100Field slot circumferential width [X5] (Angle Degree) 0.2 π(ππππ)Shield slot radial height [X6](mm) 1 100Shield slot circumferential width [X7](mm) 1 π(ππππ)Radial distance between shield coil and iron shield [X9] (mm) 1 100Radial iron shield height [X8] (mm) 1 100Armature current density [X10] (A/mm2) 50 200
Results - Pareto fronts
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- As pole count increases weight decreases and ac losses increases
- Between optimized pole counts low pole counts looks desirable due to their low ac loss performance.
β’ AC loss is estimated in the armature axial length as well as in the end windings.
β’ Only active mass is considered for the weight.
β’ Optimal-pareto front for 10,20,30 and 40 pole count designs.
β’ Weight and ac loss has the tradeoff
20 Pole machine designs
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β’ Active shield designs reduce weight significantlyβ’ Air-gap field density and stack length of the motor has significant tradeoffβ’ Different stack length designs can be chosen with corresponding change in ac loss.
Designs with significant iron shield
Designs without significant iron shield designs
Designs without significant iron shield designs
Optimization Results β20 pole
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20 pole Machine designs β Comparison
ParameterLowest weight
Lowest Ac loss
Optimal design
Outer Diameter [m] 3.91 4.39 4.36
Axial length [m] 1.66 4.31 2.49
Air-gap flux density [T] 1.2 0.93 0.96
Outside flux density [T] 0.039 0.037 0.047
Armature SC length 2430 898.6 1091
Field SC length [km] 1230 5253 2916
Shield SC length [km] 135 1765 1090
Total SC length [km] 3796 7917 5097
Iron shield weight [Ton] 0.29 24 4.33
Total loss [W] 2280 764 943
Weight (Iron and SC) [Ton] 2.8 29.3 7.7
Cost (Iron and SC) [million $] 7.2 15.88 10.2
High Loss = 2280 W, Low weight = 2.8 Ton
Low ac loss = 764 W, High Weight = 29.3 Ton
Optimal loss = 943 W, Weight = 10.2 ton
β’ Iron shield significantly affect the weightβ’ Air-gap flux density and active length affect ac losses
Optimization Results β10 pole
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10 pole Machine designs β Comparison
ParameterLowest weight
Lowest Ac loss
Optimal design
Outer Diameter [m] 4.18 4.34 4.29
Axial length [m] 3.34 4.72 2.45
Air-gap flux density [T] 0.88 0.86 0.91
Outside flux density [T] 0.049 0.048 0.044
Armature SC length 2852 1190 1494
Field SC length [km] 3316 4850 2610
Shield SC length [km] 1656 2683 1544
Total SC length [km] 8125 7917 5648
Iron shield weight [Ton] 4.27 19.51 7.57
Total loss [W] 1135 477 618
Weight (Iron and SC) [Ton] 9.7 25.3 11.4
Cost (Iron and SC) [million $] 16.2 17.5 11.3
High Loss = 2280 W, Low weight = 2.8 Ton
Low ac loss = 764 W, High Weight = 29.3 Ton
β’ All the designs converge towards active shield designs β’ Air-gap flux density and active length affect ac losses
AC Loss summary
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Machine designs with ac losses 477W and weight 25.3 Ton could be achieved with 10-poles
Best design ac loss 618 W, weight 11.3 Ton, axial length is 2.45 m and diameter is 4.29 m.
Total system weight and efficiency considering cryogenic system
π πππ’ππππ πππ¦πππππππ πππ€ππ β90
1.5β 618 = 37.08πΎπ
πππππππππ¦ β1ππ β 37.698ππ
1ππβ 100 = 99.6%
ππ¦π π‘ππ π€πππβπ‘ β 11.3 β 200% +10
1.5β 618 = 38 πππ
Discussion
βͺ Fully superconducting machines attractive for 10 MW scale wind turbines
βͺ Armature winding ac losses and associated added cryogen system weight are significant challenges.
βͺ Relatively low field, low pole-count designs preferred. AC loss data close to operating conditions needed for more rigorous analysis.
βͺ Iron yoke weight dominates in passively shielded designs. Actively shielded designs give lowest weight.
βͺ Mechanical design needs to be refined to estimate total weight including non-active components.
βͺ TRL increase will be sought within ac loss measurement with race track winding build and test.
βͺ Minimize ac loss and cost in the optimization 19
βͺ LH2 energy storage with fuel cell system
β’ Guaranteed energy availability
β’ Doubled use as cryogen for superconducting electrical system
βͺ Fully-electric propulsion system
β’ Superconducting machines and cryogenic power electronics
β’ Lightweight, low-voltage transmission system
β’ Distributed, aero-integrated propulsion system
Cryogenic High-Efficiency Electric Technologies for Aircraft (CHEETA)
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Cryocooler Design β Why πππ΅2
Cryocooler input power to achieve 1.5W cooling Cryocooler weight to achieve 1.5W cooling
π πππ’ππππ πΆππ¦πππππππ πππ€ππ:90
1.5Γ 1.5ππ = 90ππ
πΈππππππππ¦ =9910
10000β 100 = 99.1%
ππππβπ‘ =10
1.5β 1.5ππ = 10ππππππ
1.5ππ πππ π ππ π πππβπππ ππππππ‘πππ ππ‘ 4πΎ (ππ΅3ππ)
π πππ’ππππ πΆππ¦πππππππ πππ€ππ:2 β 103
1.5Γ 1.5ππ = 2ππ
πΈππππππππ¦ =8
10β 100 = 80%
ππππβπ‘ =100
1.5β 1.5ππ = 100ππππππ
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1.5ππ πππ π ππ π πππβπππ ππππππ‘πππ ππ‘ 20πΎ (πππ΅2)