Transcript

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Factoring

Trinomials

Guided Notes

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Algebra 1 – Notes Packet Name: Pd:

Factoring Trinomials Clear Targets:

I can factor trinomials with and without a leading coefficient. Concept:

When factoring polynomials, we are doing reverse multiplication or β€œun-distributing.”

Remember: Factoring is the process of finding the factors that would multiply together to make a certain polynomial. Example A.

Multiply: 6𝑏(3𝑏2 βˆ’ 7𝑏 βˆ’ 4)

Factor by GCF: 18𝑏3 βˆ’ 42𝑏2 βˆ’ 24𝑏

Example B. Multiply: (3π‘₯2 βˆ’ 1)(7π‘₯ + 6)

Factor by Grouping: 21π‘₯3 + 18π‘₯2 βˆ’ 7π‘₯ βˆ’ 6

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Strategy:

Strategy for Factoring Trinomials: Step 1: Multiply the first and third coefficients to make the β€œmagic number”. Make sure your trinomial is in descending order. Step 2: Write out the factor table for the magic number. Step 3: Play the β€œX” Game: Circle the pair of factors that adds up to equal the second coefficient. If there is no possible pair that will work, the polynomial cannot be factored using this method. Step 4: Rewrite the middle term (the term with only an β€œx”) of the trinomial using the pair of factors you circled. Step 5: You should now have four terms in your polynomial, so use factor by grouping to complete the problem.

Directions: Factor each polynomial.

1. 2π‘₯2 + 17π‘₯ + 21

2. 2𝑛2 + 15𝑛 + 7

3. π‘š2 + 6π‘š βˆ’ 27

4. 𝑑2 + 7𝑑 + 10

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5. 9π‘˜2 βˆ’ 11π‘˜ + 2

6. 𝑦2 βˆ’ 13𝑦 + 36

7. π‘š2 βˆ’ 36

8. 8𝑦2 βˆ’ 10𝑦 βˆ’ 3

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Practice Work: Directions: Factor each polynomial. Show all of your work! 1. 𝑛2 βˆ’ 2𝑛 βˆ’ 63

2. 𝑛2 + 𝑛 βˆ’ 90

3. π‘₯2 + 8π‘₯ βˆ’ 9

4. π‘˜2 βˆ’ 7π‘˜ + 12

5. π‘₯2 βˆ’ 4π‘₯ βˆ’ 45

6. π‘Ÿ2 βˆ’ 10π‘Ÿ + 16

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Multi-Step Factoring Sometimes, you will have to use more than one factoring strategy to complete a problem. Most commonly, you will need to pull out a GCF first, then factor the trinomial.

Practice:

7. 5𝑛2 + 30𝑛 + 40

8. 6𝑝2 βˆ’ 60𝑝 + 150

9. βˆ’2𝑛2 βˆ’ 6𝑛 βˆ’ 4

10. 4π‘Ÿ2 + 52π‘Ÿ + 160

11. 5𝑏3 βˆ’ 30𝑏2 + 45𝑏

12. 4𝑣3 + 48𝑛2 + 108𝑛

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Due Date: Name: Pd: .

Factoring Trinomials Homework 1. π‘˜2 + 18π‘˜ + 81

2. 𝑣2 βˆ’ 13𝑣 + 30

3. 𝑣2 + 12𝑣 + 32

4. π‘₯2 βˆ’ π‘₯ βˆ’ 6

5. 𝑣2 + 14𝑣 + 48

6. 5π‘Ÿ2 βˆ’ 11π‘Ÿ βˆ’ 12

7. 2𝑝2 βˆ’ 11𝑣 βˆ’ 63

8. 3𝑣2 βˆ’ 5𝑣 βˆ’ 28

9. 7π‘₯2 + 52π‘₯ + 60

10. βˆ’3π‘₯2 + 31π‘₯ βˆ’ 70

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Factoring Trinomials Homework Page 2 This second parge is all multi-step factoring problems. Be sure to check for GCF first, then factor the remaining trinomial! 11. 20𝑣2 βˆ’ 104𝑣 + 20

12. 25π‘₯2 βˆ’ 145π‘₯ + 180

13. 18π‘₯2 βˆ’ 120π‘₯ βˆ’ 42

14. 9π‘Ÿ2 + 87π‘Ÿ + 54

15. βˆ’20𝑏2 + 136𝑏 + 192

16. βˆ’25π‘Ž2 + 185π‘Ž βˆ’ 70

17. 3𝑣2 + 11𝑣 + 8

18. 9𝑝2 βˆ’ 39𝑝 βˆ’ 30

19. 2π‘₯2 + 25π‘₯ + 63

20. βˆ’5π‘˜2 + 48π‘˜ + 20

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Algebra 1 – Notes Packet - KEY Name: KEY

Pd:

Factoring Trinomials - KEY Clear Targets:

I can factor trinomials with and without a leading coefficient. Concept:

When factoring polynomials, we are doing reverse multiplication or β€œun-distributing.”

Remember: Factoring is the process of finding the factors that would multiply together to make a certain polynomial. Example A.

Multiply: 6𝑏(3𝑏2 βˆ’ 7𝑏 βˆ’ 4)

18𝑏3 βˆ’ 42𝑏2 βˆ’ 24𝑏

Factor by GCF: 18𝑏3 βˆ’ 42𝑏2 βˆ’ 24𝑏

6𝑏(3𝑏2 βˆ’ 7𝑏 βˆ’ 4)

Example B. Multiply: (3π‘₯2 βˆ’ 1)(7π‘₯ + 6)

: 21π‘₯3 + 18π‘₯2 βˆ’ 7π‘₯ βˆ’ 6

Factor by Grouping: 21π‘₯3 + 18π‘₯2 βˆ’ 7π‘₯ βˆ’ 6

(3π‘₯2 βˆ’ 1)(7π‘₯ + 6)

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Strategy:

Strategy for Factoring Trinomials: Step 1: Multiply the first and third coefficients to make the β€œmagic number”. Make sure your trinomial is in descending order. Step 2: Write out the factor table for the magic number. Step 3: Play the β€œX” Game: Circle the pair of factors that adds up to equal the second coefficient. If there is no possible pair that will work, the polynomial cannot be factored using this method. Step 4: Rewrite the middle term (the term with only an β€œx”) of the trinomial using the pair of factors you circled. Step 5: You should now have four terms in your polynomial, so use factor by grouping to complete the problem.

Directions: Factor each polynomial.

1. 2π‘₯2 + 17π‘₯ + 21

(2π‘₯ + 3)(π‘₯ + 7)

2. 2𝑛2 + 15𝑛 + 7

(2𝑛 + 1)(𝑛 + 7)

3. π‘š2 + 6π‘š βˆ’ 27

(π‘š βˆ’ 3)(π‘š + 9)

4. 𝑑2 + 7𝑑 + 10

(𝑑 + 5)(𝑑 + 2)

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5. 9π‘˜2 βˆ’ 11π‘˜ + 2

(π‘₯ βˆ’ 1)(9π‘₯ βˆ’ 2)

6. 𝑦2 βˆ’ 13𝑦 + 36

(𝑦 βˆ’ 9)(𝑦 βˆ’ 4)

7. π‘š2 βˆ’ 36

(π‘š + 6)(π‘š βˆ’ 6)

8. 8𝑦2 βˆ’ 10𝑦 βˆ’ 3

(2𝑦 βˆ’ 3)(4𝑦 + 1)

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Practice Work: Directions: Factor each polynomial. Show all of your work! 1. 𝑛2 βˆ’ 2𝑛 βˆ’ 63

(𝑛 βˆ’ 9)(𝑛 + 7)

2. 𝑛2 + 𝑛 βˆ’ 90

(𝑛 βˆ’ 9)(𝑛 + 10)

3. π‘₯2 + 8π‘₯ βˆ’ 9

(π‘₯ + 9)(π‘₯ βˆ’ 1)

4. π‘˜2 βˆ’ 7π‘˜ + 12 (π‘˜ βˆ’ 3)(π‘˜ βˆ’ 4)

5. π‘₯2 βˆ’ 4π‘₯ βˆ’ 45 (π‘₯ βˆ’ 9)(π‘₯ + 5)

6. π‘Ÿ2 βˆ’ 10π‘Ÿ + 16

(π‘Ÿ βˆ’ 2)(π‘Ÿ βˆ’ 8)

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Multi-Step Factoring Sometimes, you will have to use more than one factoring strategy to complete a problem. Most commonly, you will need to pull out a GCF first, then factor the trinomial.

Practice:

7. 5𝑛2 + 30𝑛 + 40 5(𝑛 + 2)(𝑛 + 4)

8. 6𝑝2 βˆ’ 60𝑝 + 150 6(𝑝 βˆ’ 5)(𝑝 βˆ’ 5)

9. βˆ’2𝑛2 βˆ’ 6𝑛 βˆ’ 4 βˆ’2(π‘₯ + 2)(π‘₯ + 1)

10. 4π‘Ÿ2 + 52π‘Ÿ + 160 4(π‘Ÿ + 5)(π‘Ÿ + 8)

11. 5𝑏3 βˆ’ 30𝑏2 + 45𝑏 5𝑏(𝑏 βˆ’ 3)(𝑏 βˆ’ 3)

12. 4𝑣3 + 48𝑛2 + 108𝑛 4𝑛(𝑛 + 3)(𝑛 + 9)

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Due Date: Name: Pd: .

Factoring Trinomials Homework 1. π‘˜2 + 18π‘˜ + 81

(π‘˜ + 9)(π‘˜ + 9)

2. 𝑣2 βˆ’ 13𝑣 + 30 (𝑣 βˆ’ 10)(𝑣 βˆ’ 3)

3. 𝑣2 + 12𝑣 + 32 (𝑣 + 4)(𝑣 + 8)

4. π‘₯2 βˆ’ π‘₯ βˆ’ 6 (π‘₯ + 2)(π‘₯ βˆ’ 3)

5. 𝑣2 + 14𝑣 + 48 (𝑣 + 6)(𝑣 + 8)

6. 5π‘Ÿ2 βˆ’ 11π‘Ÿ βˆ’ 12 (5π‘Ÿ + 4)(π‘Ÿ βˆ’ 3)

7. 2𝑝2 βˆ’ 11𝑣 βˆ’ 63 (2𝑣 + 7)(𝑣 βˆ’ 9)

8. 3𝑣2 βˆ’ 5𝑣 βˆ’ 28 (3𝑣 + 7)(𝑣 βˆ’ 4)

9. 7π‘₯2 + 52π‘₯ + 60 (7π‘₯ + 10)(π‘₯ + 6)

10. βˆ’3π‘₯2 + 31π‘₯ βˆ’ 70 βˆ’(3π‘₯ βˆ’ 10)(π‘₯ βˆ’ 7)

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Factoring Trinomials Homework Page 2 This second parge is all multi-step factoring problems. Be sure to check for GCF first, then factor the remaining trinomial! 11. 20𝑣2 βˆ’ 104𝑣 + 20

4(5𝑣 βˆ’ 1)(𝑣 βˆ’ 5)

12. 25π‘₯2 βˆ’ 145π‘₯ + 180 5(5π‘₯ βˆ’ 9)(π‘₯ βˆ’ 4)

13. 18π‘₯2 βˆ’ 120π‘₯ βˆ’ 42 6(3π‘₯ + 1)(π‘₯ βˆ’ 7)

14. 9π‘Ÿ2 + 87π‘Ÿ + 54 3(3π‘Ÿ + 2)(π‘Ÿ + 9)

15. βˆ’20𝑏2 + 136𝑏 + 192 βˆ’4(𝑏 + 6)(𝑏 βˆ’ 8)

16. βˆ’25π‘Ž2 + 185π‘Ž βˆ’ 70 βˆ’5(5π‘Ž βˆ’ 2)(π‘Ž βˆ’ 7)

17. 3𝑣2 + 11𝑣 + 8 (3𝑣 + 8)(𝑣 + 1)

18. 9𝑝2 βˆ’ 39𝑝 βˆ’ 30 3(3𝑝 + 2)(𝑝 βˆ’ 5)

19. 2π‘₯2 + 25π‘₯ + 63 (2π‘₯ + 7)(π‘₯ + 9)

20. βˆ’5π‘˜2 + 48π‘˜ + 20 βˆ’(5π‘˜ + 2)(π‘˜ βˆ’ 10)

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