Name Date

Mystery Cube Density LabMaterials: Density cube, graduated cylinder, ruler, beaker, balance

lypothests: If themass and volume of a cube is found, then the density of the cube can be calculated and used to determine thematerial of the cube.

Procedures:1. Determine themass of your table's cube using a balance and record results in the data table.2. Determine the volume of your table's cube using the ruler (Length x Width x Height) and record results in the data table.3. Calculate the density by dividing mass by volume (d = m/v). Record results in the data table.4. Identify themystery cubes based on their densities from the chart below.6. Repeat this procedure for 2 more trials!Known values for cube densities (g/cm3or g/mL)

_ Material (Substance) Density Luster Color

Copper 8.9 Shiny Shiny orange (copper)

Brass 8.0 Shiny Gold

Steel 7.6 Shiny Dark Grey/Dark SilverAluminum 2.7 Shiny Silver

Acrylic 1.15 Clear /No Luster Clear

Oak 0.7 Dull /No Luster Light Brown/Grainy

Hypothesis:What do you predict the identity of your cube to be?

Results:

Table Number

Trial Mass (g) Volume (cms) Density (g/cm?)

Average

Conclusions:

1. What is the identity of your cube using the densities that you calculated and the physical properties youobserved?

2. What determines whether cube will float or sink in water?

3. What is the density of water?

4. Did your cube float in water?

5. Which cube(s), from the list, would float in water based on their density?

6. Explain another way to determine the volume of the cube.

7. Explain how you found the density of the cube.

8. What other properties did you observe about your cube?

9. Was the hypothesis supported or refuted?

a. Why?

10. Was the method a valid way to test the hypothesis? Explain.

How could the method be improved or extended?

o#over the procedure8

use the chart above

D= mT

←use the chart above!

density⇒ is it higher or lower than I" 91MIEnsity > I = sink Density< I = float

oak

volume by displacement (using water)measured length ,width ,

t height using a rulercolor, odor , luster

yes. we used multiple properties to determinethe identityconduct more tests by looking at morephysical or chemical properties.

( = 2.5cm IN .

- 2.5cm HI 2.5cm

Lx W x H = Volume (V)(2.5cm)3 = (2.5cm) (2.5cm) (2.5cm)

V = 15.6250mL

dam Average-

Add the numbers togetherV t divide by the # of numbers .

Water density is lglcm 3 = Ig 1mLObject density is less than water ⇒ floatsobject density is more than water ⇒ sinks