Pd 5 Chemistry March 18, 2010
Balance the equation
Write the equation
Start the ratio
Go to the Next part of the Question!!!
Hint: What do we need to figure out the moles part of the stoichiometry problem…
Go Back to 1st Q
2Hg + O2 2HgO
Hg + O2 HgOHg Hg + O2
Go to the Next part of the Question!!!
Hint: Is the equation balanced.
Go Back to 2st Q
What’s FIRST?
gHg
molHggHg
59.200
21
gHg
molHggHg
59.200
20.15
gHg
molHggHg
59.200
10.15
Go to the Next part of the Question!!!
Hint: Are all the numbers correct in the ratio equation?
Go Back to 3st Q
gHg
molHggHg
59.200
10.15
molHgO
gHgO
molHg
molHgO
1
59.216
2
2
gHgO
molHgO
molHg
molHgO
59.216
1
2
2
molHgO
gHgO
molHgO
molHg
2
59.216
2
2
HgOHg 22 2
Go to the Next part of the Question!!!
Hint: Look at the element, amount, and where they are placed on the ratio equation.
Go Back to 4st Q
NEXT
molHgO
gHgO
molHg
molHgO
gHg
molHggHg
1
59.216
2
2
59.200
115
And then…And then…And then… And then… And then…
Have to start Stoichiometry
for O2
We are done
Hg is limiting
Go to the Next part of the Question!!!
Hint: What do we need to decide if something is limiting
Go Back to 6st Q
Next?
molHgO
gHgO
molO
molHgO
gO
molOgO
1
59.216
1
2
32
120
22
22
gHgO
molHgO
molHgO
molO
gO
molOgO
95.216
1
2
1
32
11 2
2
22
gHgO
molHgO
molO
molHgO
gO
molOgO
59.216
1
1
2
32
120
22
22
HgOOHg 22 2
Go to the Next part of the Question!!!
Hint: Look at the element, amount, and where they are placed on the ratio equation.
Go Back to 7st Q
270.7 g HgO
NEXT
molHgO
gHgO
molO
molHgO
gO
molOgO
1
59.216
1
2
32
120
22
22
O2 =270.7 g HgO
Hg= 16.2 g HgO
Hint: The smaller number is limiting because there less of that element to use.
Go Back
YAY!!!! We’re done