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SCHOOL OF ARCHITECTURE, BUILDING & DESIGN
Research Unit for Modern Architecture Studies in Southeast Asia
Bachelor of Science (Honours) (Architecture)
Building Structures (ARC 2522/2523)
Project 2
Structural Analysis of a Bungalow
Tutor: Mr Mohd Adib Ramli
Group Members:
Chong Yu Xuan 0317950
Ng Hong Bin 0319735
Lee Kai Yung 0318314
Table of content
1. Introduction to project2. Architectural plan drawings3. Identification of Type of Slab4. Structural plan drawings5. Slab System analysis6. Individual Components
6.1Ng Hong Bin 03197356.2Lee Kai Yung 03183146.3Chong Yu Xuan 0317950
7. Conclusion8. References
1. Introduction to Project
In this project, we are required to form a group of 3 and design a double storey bangalow from a provided set of plans. Then, we are to identify and analyse the beams and columns in the bangalow. After designing a bangalow with varying beam and column arrangement, we are required to produce a structural plan drawing for each floor for further analysis.
With the information of the structural plan drawings, we have to proceed with calculating and identifying the slab system and load distribution for the beams and columns. Each of us is required to calculate minimum of 6 beams and 3 column from both ground and first floor. Formula used are as follow.
Slab SystemLy/Lx>2(one way slab system)Ly/Lx<2(two way slab system)
Beam CalculationBeam self-weight =beam size x density if reinforced concreteSlab dead load =thickness x density of reinforced concrete x Lx/2(trapezoid)=Thickness x density of reinforced concrete x Lx/2 x 2/3(triangular)Slab live load = live load (UBBL) x Lx/2(trapezoid)=live load (UBBL) x Lx/2 x 2/3(triangular)Brickwall dead load = wall height x thickness x density of bricks
Column calculationBeam self-weight = beam size x density of reinforced concrete x lengthSize of dead load = thickness x density of reinforced concrete x tributary areaSlab live load = live load(UBBL) x tributary areaBrick wall self-weight = thickness x wall height x density of bricks x lengthColumn self-weight = width x length x height x density of reinforced concrete
Specifications
UBBL Density of reinforced concrete = 24kN/m³Density of bricks = 19kN/m³
Room 1. bedroom2. guest room3. washroom4. kitchen5. corridor6. laundry7. game room8. store room9. living room 10.dining room11. office12.Study room 13.Family room 14.Gymnasium 15.Balcony
*According to UBBL, all resident buildings (bungalow) live load factor should be 1.5kN/m³
2. ARCHITECTURAL DRAWINGS
3. IDENTIFICATION OF TYPE OF
SLAB
5.0 Identification of Type of Slab
Identify One Way or Two Way Slab
Ly = Longer side of slab
Lx = Shorter side of slab Ly
Ly/Lx ˃ 2, One way slab
Ly/Lx ˂ 2, Two way slab
Ly/Lx = 2, Two way slab Lx
GROUND FLOOR
Slab A-B/1-2 4/2 = 2 which is = 2, this is two way slab.
Slab B-C/1-2 4/2 = 2 which is = 2, this is two way slab.
Slab C-D/1-4 8.3/3 = 2.77 which is ˃ 2, this is one way slab.
Slab B-C/1-2 4/2 = 2 which is = 2, this is two way slab.
Slab D-F/1-3 5.3/4 = 1.33 which is ˂ 2, this is two way slab.
Slab D-F/3-4 4/3 = 1.33 which is ˂ 2, this is two way slab.
Slab A-B/3-4 6.3/4 = 1.58 which is ˂ 2, this is two way slab.
Slab B-C/3-4 6.3/4 = 1.58 which is ˂ 2, this is two way slab.
Slab A-A1/4-5 5/2.1 = 2.38 which is ˃ 2, this is one way slab.
Slab A1-B/4-5 5/1.9 = 2.63 which is ˃ 2, this is one way slab.
Slab B-C/4-5 5/4 = 1.25 which is ˂ 2, this is two way slab.
Slab C-D/4-5 5/3 = 1.67 which is ˂ 2, this is two way slab.
Slab A-B/5-5a 4/3 = 1.33 which is ˂ 2, this is two way slab.
Slab A-B/5a-6 4/1.7 = 2.35 which is ˃ 2, this is one way slab.
Slab B-C/5-6 4.7/4 = 1.18 which is ˂ 2, this is two way slab.
Slab C-E/5-6 4.7/4 = 1.18 which is ˂ 2, this is two way slab.
Slab E-F/5-6 4.7/3 = 1.57 which is ˂ 2, this is two way slab.
FIRST FLOOR
Slab A-B/1-2 6.3/4 = 1.58 which is ˂ 2, this is two way slab.
Slab B-B1/1-2 3/2 = 1.5 which is ˂ 2, this is two way slab.
Slab B1-C/1-2 3/2 = 1.5 which is ˂ 2, this is two way slab.
Slab B-C/2-3 4/3.3 = 1.21 which is ˂ 2, this is two way slab.
Slab A-B/3-4 4/3 = 1.33 which is ˂ 2, this is two way slab.
Slab B-C/3-4 4/3 = 1.33 which is ˂ 2, this is two way slab.
Slab A1-B/4-5 5/2 = 2.5 which is ˃ 2, this is one way slab.
Slab B-C/4-4a 4/3 = 1.33 which is ˂ 2, this is two way slab.
Slab C-E/4-4a 4/3 = 1.33 which is ˂ 2, this is two way slab.
Slab B-C/4a-5 4/2 = 2 which is = 2, this is two way slab.
Slab C-E/4a-5 4/2 = 2 which is = 2, this is two way slab.
Slab A-B/5-6 4.7/4 = 1.18 which is ˂ 2, this is two way slab.
Slab B-B1/5-6 4.7/2 = 2.35 which is ˂ 2, this is two way slab.
Slab B1-C/5-5a 1.7/1.7 = 1 which is ˂ 2, this is two way slab.
Slab B1-C/5a-6 3/1.7 = 1.76 which is ˂ 2, this is two way slab.
Slab C-E/5-6 4.7/4 = 1.18 which is ˂ 2, this is two way slab.
4. STRUCTURAL DRAWINGS
5. SLAB SYSTEM ANALYSIS
6. INDIVIDUAL COMPONENTS
6.1 NG HONG BIN 0319735
6.2 LEE KAI YUNG 0318314
6.3 CHONG YU XUAN 0317950
7. Conclusion
From this project, we learnt the proper method of calculation and application for the analysis of load distribution to a building structure. The analysis on the structural system has helped us to a better understanding on the design of a basic structure in a building. The calculation exercises also enable us to practice a proper measure of load distribution in a structural system. Upon completion, we are able to gain basic knowledge about the formulas of load distributions.
8. References
Analysis of Beams | Shear Force & Bending Moment Diagram – Learn Engineering. (2016). Learnengineering.org.
Retrieved 24 June 2016, from http://www.learnengineering.org/2013/08/shear-force-bending-moment-diagram.html
Building Construction: Understanding Loads and Loading. (2016). Fireengineering.com. Retrieved 24 June 2016,
from http://www.fireengineering.com/articles/2010/06/building-construction-understanding-loads-and-loading.html
BEAM FORMULAS WITH SHEAR AND MOM. (2016). Linsgroup.com. Retrieved 24 June 2016, from
http://www.linsgroup.com/MECHANICAL_DESIGN/Beam/beam_formula.htm