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Calculator TechniquesPrepared By: Engr. Jamille G. Quindara
Lesson 4. Mode 5. (EQN)
Press (5: EQN)Mode 5
Press (5: EQN)
1:
2:
3:
4:
Mode 5
AnX + BnY = Cn
AnX + BnY + CnZ = Dn
aX2 + bX + c = 0
aX3 + bX2 + cX + d = 0
Press (5: EQN)
1: 2EQs 2Unknowns
2: 3EQs 3Unknowns
3: Quadratic Eqn.
4: Cubic Eqn.
Mode 5
AnX + BnY = Cn
AnX + BnY + CnZ = Dn
aX2 + bX + c = 0
aX3 + bX2 + cX + d = 0
Problem 1. Find the value of x and n2x + 3y = 1053x + 5y = 160
a. 45 , 5b. 5 , 50c. 50 , 45d. 45, 50
Solution: Press Mode 5
Solution: Press Mode 5 1
Solution: Press
a b c1 [ 0 0 0]2 [ 0 0 0]
Mode 5 1
0
Solution: Press
a b c1 [ 0 0 0]2 [ 0 0 0]
Input
Mode 5 1
0
2 = 3 = 105 =
Solution: Press
a b c1 [ 0 0 0]2 [ 0 0 0]
Input
Mode 5 1
0
2 = 3 = 105 =
3 = 5 = 160 =
Problem 2. Find the value of x and y4x + 2y = 513x - 3y = 2
a. Y=1/2 , X=3/2b. Y=3/2 , X=1/2c. Y=2 , X=1d. Y=3, X=1
Problem 2. Find the value of x and y4x + 2y = 513x - 3y = 2
a. Y=1/2 , X=3/2b. Y=3/2 , X=1/2c. Y=2 , X=1d. Y=3, X=1
Problem 3. Find the value of x and yx - 4y + 2 = 02x + y -4 = 0
a. 11/7 , -5/7b. 11/9 , 8/9c. 14/9 , 8/9d. 3/2 , 5/3
Problem 3. Find the value of x and yx - 4y + 2 = 02x + y -4 = 0
a. 11/7 , -5/7b. 11/9 , 8/9c. 14/9 , 8/9d. 3/2 , 5/3
Problem 4. Find the value of x2x – y + z = 6x – 3y – 2z = 132x – 3y – 3z = 16
a. 4b. 3c. 2d. -1
Solution: Press Mode 5 2
Solution: Press
a b c d1 [ 0 0 0 0]2 [ 0 0 0 0]3 [ 0 0 0 0]
Mode 5 2
0
Solution: Press
a b c d1 [ 0 0 0 0]2 [ 0 0 0 0]3 [ 0 0 0 0]
Input coefficient of 1st, 2nd, and 3rd equation
Mode 5 2
0
Solution: Press
a b c d1 [ 0 0 0 0]2 [ 0 0 0 0]3 [ 0 0 0 0]
Input coefficient of 1st, 2nd, and 3rd equationAns.X= 2 Y=-3 Z=-1
Mode 5 2
0
Problem 5. Find the value of x y and z.x + y = -4x + z – 1 = 0y + z + 1 = 0
a. -1 , -5 , 3b. 1 , 2 , -3c. -1 , -3 , 2d. -2 , -3 , -1
Problem 5. Find the value of x y and z.x + y = -4x + z – 1 = 0y + z + 1 = 0
a. -1 , -5 , 3b. 1 , 2 , -3c. -1 , -3 , 2d. -2 , -3 , -1
Lesson 5. Mode 2. (Cmplx)
Press (2: Cmplx)Mode 2
Press (2: Cmplx)Mode 2
M cmplx D Math
Problem 6. Given the Technical Description of a triangular lot, Find the missing line.
Line Bearing Distance(m)AB N 45d E 30.72BC S 10d E 22.06CA - -
Problem 6. Given the Technical Description of a triangular lot, Find the missing line.
Line Bearing Distance(m)AB N 45d E 30.72BC S 10d E 22.06CA - -
Ans. 25.55 / Due West
Problem 7. Given the Technical Description of a triangular lot, Find the missing line.
Line Bearing Distance(m)AB S 8d 51m W 126.90BC N 18d 51m W 90.20CD N 32d 27m E 110.80DA - -
Problem 7. Given the Technical Description of a triangular lot, Find the missing line.
Line Bearing Distance(m)AB S 8d 51m W 126.90BC N 18d 51m W 90.20CD N 32d 27m E 110.80DA - -
Ans. 54.55 / S 11d 24 E
