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The lecture shall begin
shortlyhellip
Mathematics
Review
Umpisa
na
5M sa math lecture
1MAKINIG
2MAG-BEHAVE
3MAGTANONG
4MAGSAGOT
5MAG-ENJOY
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Mathematics
Review
Umpisa
na
5M sa math lecture
1MAKINIG
2MAG-BEHAVE
3MAGTANONG
4MAGSAGOT
5MAG-ENJOY
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Umpisa
na
5M sa math lecture
1MAKINIG
2MAG-BEHAVE
3MAGTANONG
4MAGSAGOT
5MAG-ENJOY
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
5M sa math lecture
1MAKINIG
2MAG-BEHAVE
3MAGTANONG
4MAGSAGOT
5MAG-ENJOY
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Bago ang lahat
(a) 0
(b) 1
(c) 5
(d) 7
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Determine the domain and range of
(a)
(b)
(c)
(d)
QUESTION 1
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 1 Solution
The domain of y excludes values of x that will make the
denominator zero Thus the domain is
To solve for the range we first solve for x in terms of y
5
7
xyx
1 5y x x
7 5xy y x
7 5xy x y
1 7 5x y y
7 5
1
yx
y
Therefore the
range is
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
If and
find
(a)
(b)
(c)
(d)
QUESTION 2
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Recall for functions F and G
and
QUESTION 2 Solution
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 2 Alternative Solution
SUBSTITUTE a value of x and test which choice will give
the same value
Para madali let x = 0
QUESTION 2 Solution
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION
Which will give a value of 3 at x = 0
(a)
(b)
(c)
(d)
Astig lsquodi ba
QUESTION 2 Solution
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Which of the following is a linear function
(a)
(b)
(c)
(d)
QUESTION 3
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Recall that a linear function is a polynomial function
wherein the highest power of the independent
variable is 1
QUESTION 3 Solution
(a)
(b)
(c)
(d) cannot be a linear function since x and are
in the denominator
Is QUADRATIC because of
the terms 3x2
Is LINEAR so the answer is (a)
WAIT This is also linear
The answers are BOTH (a) amp (c) Weh lsquodi nga
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
What is the equation of the linear function ywhose graph passes through the point (2 4) and
has the given slope m = 57
(a)
(b)
(c)
(d)
QUESTION 4
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
We use the slope-intercept form
QUESTION 4 Solution
STRATEGY Substitute x = 2 y = 4 and m = 57 then
solve for bHence the equation of the line is
or
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 4 Alternative Solution
Check the choices Which among the choiceshellip
1 Has slope 57
2 Has a value y = 4 when x = 2
QUESTION 4 Solution
CLUE 5 angnasa unahan
ng x at 7 ang nasa
denominator
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Determine the distance from the point ( 2 9) to
the line 3x + 4y = 2
QUESTION 5
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
No choice Solution We have NO CHOICE but use the
following formula for the distance D of a point (x0 y0)
from a line with equation Ax + By + C = 0
QUESTION 5 Solution
Before doing anything rewrite 3x + 4y = 2 as
3x + 4y 2 = 0
Then substitute the values
A = 3 B = 4 C = 2 x0 = 2 and y0 = 9
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 5 Solution
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 6
If ax2 + bx + c = 0 where a b and c are real
numbers and a ne 0 which of the following
statements is true about the discriminant D
(a) If D lt 0 the two roots are real and equal
(b) If D lt 0 the two roots are imaginary and unequal
(c) If D gt 0 the two roots are real and unequal
(d) If D lt 0 the two roots are imaginary and equal
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 6 Solution
Recall the solutions or ROOTS of the quadratic equation
ax2 + bx + c = 0 where a b and c are real numbers and
a ne 0 can be solved using the QUADRATIC FORMULA
The DISCRIMINANT D of ax2 + bx + c = 0 is the value
INSIDE THE SQUARE ROOT ie
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 6 Solution
The DISCRIMINANT D determines the type or
NATURE of solutions or roots a quadratic equation
with real coefficients has
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
As an ASIDEhellipSome UPCAT-level problems that can be solved
using the discriminant
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 7
Determine the radius of the circle whose
equation is
(a) 2
(b) 3
(c) 4
(d) 5
r
y
x
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 7 Solution
The CENTER-RADIUS FORM of the equation of a
circle with radius r and center at (h k) is
To write x2 + y2 1048576 8x + 6y = 0 in center-radius
form complete the squareThe radius is
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 8
Find the quotient of
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 8 Solution
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 9
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 10
What is x in the equation
(a) 5
(b) 3
(c) 3
(d) 2
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 11
Evaluate
(a) 32
(b) 23
(c) 3
(d) 6
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 11 Solution
By definition the LOGARITHM of a positive number x to
the base b denoted by logb x is the POWER y of b
equal to x ie
Example log3 9 = 2 since 32 = 9 Simple lsquodi ba
CHALLENGE What is the value of
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 12
Solve for all possible values of x in the equation
(a) 3 and 2
(b) 2 and 3
(c) 6 and 9
(d) 9 and 6
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 12 Solution
A property of logarithm is that
Shortest solutionSUBSTITUTE the choices to the
original equation
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 13
Solve for q in the equation
(a)
(b)
(c)
(d)
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 13 Solution
NOSEBLEEEED
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Naku m
atagal
pa lsquotohellip
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 14
(a) 41
(b) 38
(c) 39
(d) 37
Faye is 5 greater than twice the age of Luigi 5
years from now Faye will be twice as old as
Luigi How old is Faye 3 years ago
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 14 Solution
Let x = Luigirsquos age
2x+5 = Fayersquos age
Age nowAge 5 years from now
Luigi x x + 5
Faye 2x + 5(2x + 5) + 5 =
2x + 10
AGE PROBLEM
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 15
(a) 10
(b) 25
(c) 20
(d) 33
Paolo can finish compiling the books in library in 25
minutes Kevin can finish it in 25 minutes while
Carmela took her 50 minutes How many minutes
will it take them if they were to compile the books
altogether
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 15 Solution
Let x = no of min they can finish the job together
No of minutes
Rate per minute
Paolo 25 125
Kevin 25 125
Carmela 50 150
Together x 1x
WORK PROBLEM
EQUATION
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 16
(a) 300
(b) 370
(c) 380
(d) 390
There are 570 students in a school If the ratio of
female to male is 712 how many male students
are there
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 16 Solution
570 students in the ratio 712
MALES FEMALES
One block =
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
As an ASIDEhellip
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 17
(a) 18
(b) 19
(c) 20
(d) 21
When each side of a square lot was decreased by
3m the area of the lot was decreased by 105 sq
m What was the length of each side of the original
lot
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 17 Solution
Let x = length of the side of the square
Lengthof a side
Area
Original x x2
New x 3 (x 3)2
EQUATION
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 18
(a) 26
(b) 27
(c) 36
(d) 37
The difference of 23 of an even integer and one-
half of the next consecutive even integers is equal
to 5 What is the odd integer between these two
even integers
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 18 Solution
Let x = 1st even integer
x + 2 = 1st even integer
EQUATION The ODD
integer in
between is
the one
AFTER 36
which is 37
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 19
(a) 53
(b) 52
(c) 51
(d) 45
Find the average of all numbers from 1 to 100 that
end in 8
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 19 Solution
The average looks like this
The numerator is actually a sum of an ARITHMETIC
PROGRESSION with first term a1 = 8 and tenth term
a10 = 98 given by The average is
then 53010 = 53
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
As an ASIDEhellip
FACT The average of the first n terms of an
arithmetic progression is just actually the
AVERAGE of the FIRST AND LAST TERM
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 20
(a) 200
(b) 220
(c) 240
(d) 260
A tank is 78 filled with oil After 75 liters of oil are
drawn out the tank is still half-full How many
liters can the tank hold
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 20 Solution
78 full 12 full
75 L
drawn out
25 L
25 L
25 L
CAPACITY
= 25(8) = 200 L
25 L
25 L
25 L
25 L
25 L
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 21
(a) After 7 min
(b) After 8 min
(c) After 9 min
(d) After 10 min
Two new aquariums are being set up Each one
starts with 150 quarts of water The first fills at the
rate of 15 quarts per minute The second one fills
at the rate of 20 quarts per minute When would
the first tank contain 67 as much as the second
tank
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 21 Solution
Let x = no of minutes
EQUATION
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 22
(a) 49
(b) 64
(c) 81
(d) 100
In a classroom chairs are arranged so that each
row has the same number If Ana sits 4th from the
front and 6th from the back 7th from the left and
3rd from the right How many chairs are there
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 22 Solution
anna
FRONT
BACK
LEFT RIGHT
NO OF CHAIRS
9 X 9 = 81
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 23
A circle with radius of 5 m and a square of 10 m are
arranged so that a vertex of the square is at the
center of the circle What is the area common to
the figures
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 23 Solution
The area common to the figures is
equal to frac14 the area of the circle 10 m
10 m
5 m
5 m
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 24
How many liters of 20 chemical solution must be
mixed with 30 liters of 60 solution to get a 50
mixture
(a) 5 L
(b) 10 L
(c) 15 L
(d) 20 L
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 24 Solution
Let x = no of L of 20 chemical solrsquon
Vol (L)
concen-tration
Amount of chemical
Sol 1 x 20 02x
Sol 2 30 60 30(06) = 18
mixture (x + 30) 50 05(x + 30)
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 24 Solution
EQUATION
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
ANG TSALAP-TSALAP
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 25
A URent-A-Car rents an intermediate-size car at a
daily rate of 34950 Php plus 100 Php per km a
business person is not to exceed a daily rental
budget of 80000 Php What mileage will allow the
business person to stay within the budget
(a) 300
(b) 350
(c) 400
(d) 450
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 25 Solution
Let x = mileage
EQUATION
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Rules of Counting
The Fundamental Principle of Counting
If an operation can be performed in n1 ways and for each of these a second operation can be performed in n2 waysthen the two operations can be performed in n1n2 ways
Extension The Multiplication Rule
If an operation can be performed in n1 ways and
for each of these a second operation can be
performed in n2 ways a third operation in n3
wayshellip and a kth operation in nk ways then the k
operations can be performed in n1n2n3hellipnk ways
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
PERMUTATION ndash based on arrangement of
objects with order being considered
Permutation of n objects
n(n ndash 1)(n ndash 2)hellip (3)(2)(1) = n (n factorial)
Permutations
Permutation of n objects taken r at a time
rn
nPrn
Permutation of n objects with repetition
1 2
k
n
n n n
Rules of Counting
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Combination ndash based on arrangement of objects
without considering order
Combination of n objects taken r at a time
rnr
n
r
nCrn
Combinations Rules of Counting
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
13983816possible combinations
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 26
How many 3-digit numbers can be formed from the
digits 1 2 3 4 5 and 6 if each digit can be used
only once
(a) 100
(b) 110
(c) 120
(d) 130
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 26 Solution
1st digit
6 choices
62nd digit
5 choices
53rd digit
4 choices
4
By the Multiplication Rule
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 27
The basketball girls are having competition for
inter-colleges There are 15 players but the coaches
can choose only five How many ways can five
players be chosen from the 15 that are present
(a) 3103
(b) 2503
(c) 3000
(d) 3003
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 27 Solution
Since order is NOT important in choosing the
five players out of 15 we use the
Combination rule with n = 15 and r = 5
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 28
A coach must choose first five players from a team
of 12 players How many different ways can the
coach choose the first five
(a) 790
(b) 792
(c) 800
(d) 752
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 28 Solution
Same as no 27
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 30
What is the perimeter of the triangle defined by
the points (2 1) (4 5) and (2 5)
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 30 Solution
We can use the DISTANCE FORMULA to compute the
perimeter of a triangle in the Cartesian plane
(ie the sum of the lengths of the sides of the
triangle)
Kaya lang lsquodi ko na realize na easy lang ang case
sa problem kasi RIGHT TRIANGLE na (See the board
for the solution) p
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 32
If arcs AB and CD measure 4s - 9o and s + 3o
respectively and angle X is 24o find the value of s
See figure below
(a) 6
(b) 12
(c) 18
(d) 20
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 32 Solution
GEOMETRY FACT
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 33
How many possible chords can you form given 20
points lying on a circle
(a) 380
(b) 190
(c) 382
(d) 191
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 33 Solution
The number of chords can be obtained using
the Combination Rule with n = 20 r = 2
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 34
Which of the following sets of numbers cannot be
the measurements of the sides of a triangle
(a) 1 2 2
(b)
(c) 3 4 5
(d) 1 2 3
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 34 Solution
Use the TRIANGLE INEQUALITY
The sum of the lengths of any two sides of a triangle is
greater than the length of the third side
(d) 1 2 3
1 + 2 = 3 ndash should be GREATER
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 35
The figure shows a square inside a circle that is inside the
bigger square If the diagonal of the bigger square is
units what is the area of the shaded region
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
As an ASIDEhellip
The Pythagorean Theorem and Special Right
Triangles
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 35 Solution
2
Note that
bullThe side of the
larger square is 2
(special right
triangle)
bullThe side of the
square is the
diameter of the
circle so the radius
of the circle is 1
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 35 Solution
Note that
bullThe diagonal of the
smaller square is also 2
bullIf s is the side of the
smaller square then
s
2
bullThe area of the shaded
area is then
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 36
Which of the following statements is NOT true about the
figure Parallel lines a and b are intersected by line x
forming the angles 1 2 3 4 5 and 6
(a) Angles 1 and 6 are congruent
(b) Angles 1 and 5 are
supplementary with each other
(c) Angles 3 and 4 are congruent
(d) Angles 2 and 4 are
supplementary with each other
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 36 Solution
(a) Angles 1 and 6 are
congruent (alt ext)
(b) Angles 1 and 5 are
supplementary with each
other (ext)
(c) Angles 3 and 4 are
congruent (alt int)
(d) Angles 2 and 4 are NOT
supplementary with
each other ndash they are
CONGRUENT
(corresponding angles)
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 38
How many sides does a polygon have if the sum of
the measurements of the interior angles is 1980o
(a) 11
(b) 12
(c) 13
(d) 14
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 38 Solution
The sum of the interior angles of a triangle is given by
httpwwwmathopenrefcompolygoninteriorangleshtml
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 39
An ore sample containing 300 milligrams of radioactive
material was discovered It was known that the material has
a half-life of one day Find the amount of radioactive
material in the sample at the beginning of the 5th day
(a) 9375 mg
(b) 1875 mg
(c) 375 mg
(d) 75
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 39 Solution
This can be solved using a geometric progression with
first term a1 = 300 common ratio r = frac12 and n = 5 days
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 40
A survey of 60 senior students was taken and the following
results were seen 12 students applied for UST and UP only
6 students applied for ADMU only 29 students applied for
UST 2 students applied for UST and ADMU only 10 students
applied for UST ADMU and UP 33 students applied for UP
and only 1 applied for ADMU and UP only How many of the
surveyed students did not apply in any of the three
universities (UP UST ADMU)
(a) 0 (b) 8 (c) 14 (d) 20
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 40 Solution
Using Venn Diagram
UP UST
ADMU
12
6
12 ndash UP amp UST only
6 ndash ADMU only
2
2 ndash UST and ADMU only
10 10 ndash all three
11 ndash UP and ADMU only
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
QUESTION 40 Solution
UP UST
ADMU
12
6
33 (12 + 10 + 1) = 10
210
1
10 5
29 (12 + 10 + 2) = 5
Add all numbers in the
circles 46
Whatrsquos outside
60 46 = 14
14
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
BRIEF TIPS AND TRICKS
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
BRIEF TIPS AND TRICKS
1 READ EACH QUESTION CAREFULLY
2 Take each solution one step at a time Some
seemingly difficult questions are really just a
series of easy questions
3 Remember thy formulas and important facts
(especially in Geometry)
4 Answer the easy items first If you canrsquot solve a
problem right away SKIP it and proceed to the
next
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
BRIEF TIPS AND TRICKS
4 Try the PROCESS OF ELIMINATION A little
guessing might work
5 Employ the EASIEST way as possible (eg
substitution shortcuts tricks etc)
6 Use your scratch paper wiselyhellip
7 If you still have time CHECK your answers
ESPECIALLY your shaded ovals
8 RELAXhellip Donrsquot panic
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
PRACTICE PROBLEMS
1 If x + y = 4 and xy = 2 find the value of x2 + y2
2 If 13 of the liquid contents of a can evaporates
on the first day and 34 of the remaining
contents evaporates on the second day what is
the fractional part of the original contents
remaining at the end of the second day
3 What is the smallest three-digit number that
leaves a remainder of 1 when divided by 2 3 or
5
4 The average of 4 numbers is 12 What is the new
average if 10 is added to the numbers
5
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
For more info
WEBSITEhttpmathgibeyweeblyco
m
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
FACEBOOKMathgibey on FB
For more info
Dakal a Salamat
Dakal a Salamat