Upload
papa-smurf
View
81
Download
2
Embed Size (px)
Citation preview
Triangles Chapter 2 Triangles2.4 Attitude, Median And Angle Bisector 2.5 Congruence Of Triangles 2.6 Midsegment Theorem
Copyright © 2015 by Papasmurf
seg. CD is _______ of ABC
20
20
B
A
C
D
Angle Bisector
If BE = 8 cm, and CE = 8 cm. then AE is a/an _______ of ABC
B
A
C
E
Copyright © 2015 by Papasmurf
Median
If BF AC, then AF is a/an _______ of ABC
B
A
CF
Copyright © 2015 by Papasmurf
Altitude
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
Every Triangle has secondary parts
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• ANGLE BISECTOR- Is a segment that
DIVIDES (bisects) any angle of a triangle into 2 angles of equal measures.
M N
G SB
A
AG, BN & SM are angle bisector of BAS.
20°20°
40°40°30°
30°
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• ALTITUDE
-The height of a triangle.
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• ALTITUDE- It is a segment
drawn from any vertex of a triangle perpendicular to the opposite side.
S
C
D
H
N
O
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• ALTITUDE
EXAMPLE,
SH, NC, OD are altitudes of
SON.S
C
D
H
N
O
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• MEDIANNOTE:
like markingsindicates
congruent or equal parts.
A B
C NM
O
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• MEDIANTHUS, IN THE
FIGURE
OA = MA, OB = NB, MC = NC.
A B
C NM
O
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
A is the midpoint of MO.
B is the midpoint of NO
C is the midpoint of MN
A B
C NM
O
Copyright © 2000 by Monica Yuskaitis
SECONDARY PARTS OF A TRIANGLE
• MEDIAN- Is a segment drawn
from any vertex of a triangle to the MIDPOINT of the opposite side.
A B
C NM
O
NA, MB & OC are median of MON.
2.5 Congruence of trianglesTwo triangles are said to be congruent, if all the corresponding parts are equal. The symbol used for denoting congruence is and PQR STU implies that
Copyright © 2015 by Papasmurf
i.e. corresponding angles and corresponding sides are equal.
S S S PostulateIf all the sides of one triangle are congruent to the corresponding sides of another triangle then the triangles are congruent (figure 2.15 ).
Copyright © 2015 by Papasmurf
seg. AB = seg. PQ , seg. BC = seg. QR andseg. CA = seg. RP
\ D ABC @ D PQR by S S S.
S A S PostulateIf the two sides and the angle included in one triangle are congruent to the corresponding two sides and the angle included in another triangle then the two triangles are congruent (figure 2.16).
Copyright © 2015 by Papasmurf
seg. AB = seg. PQ , seg. BC = seg. QR and m Ð ABC = m Ð PQR
\ D ABC @ D PQR by S A S postulate.
A S A PostulateIf two angles of one triangle and the side they include are congruent to the corresponding angles and side of another triangle the two triangles are congruent (figure 2.17 ).
Copyright © 2015 by Papasmurf
m Ð B = m Ð R, m Ð C = m Ð P and seg. BC = seg. RP
\D ABC @ D QRP by A S A postulate.
A A S PostulateIf two angles of a triangle and a side not included by them are congruent to the corresponding angles and side of another triangle the two triangles are congruent (figure 2.18)
Copyright © 2015 by Papasmurf
m Ð A = m Ð P m Ð B = m Ð Q and AC = PR
\ D ABC @ D PQR by A A S.
H S PostulateThis postulate is applicable only to right triangles. If the hypotenuse and any one side of a right triangle are congruent to the hypotenuse and the corresponding side of another right triangle then the two triangles are congruent (figure 2.19).
then hypotenuse AC = hypotenuse PR
Side AB = Side PQ
\ D ABC @ D PQR by HS postulate.
Copyright © 2015 by Papasmurf
Midsegment TheoremA midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle
Copyright © 2015 by Papasmurf
T
RX
Z
Y
The segment connecting the midpoints of two sides of a triangle is parallel to the 3rd side and is half as long.
YZRTandRTYZ21
|| T R
X
Z Y
Midsegment Theorem
Copyright © 2015 by Papasmurf
Using Midsegments of a Triangle
10
6
KJ
LA
B
C
Find JK and AB
Copyright © 2015 by Papasmurf
Using Midsegments of a Triangle
Given: DE = x + 2; BC =
Find DE
D E
B C
A
192
1x
Copyright © 2015 by Papasmurf