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A bacteria gets *16 every hour hours bacteria 0 10 1 2 3

Equivalent exponential situations

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A class activity to deepen understanding of the nature of exponential relations.

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Page 1: Equivalent exponential situations

A bacteria gets *16 every hour hours bacteria

0 10

1

2

3

Page 2: Equivalent exponential situations

A bacteria gets *16 every hour hours bacteria

0 10

1 160

2 2560

3 40960

Page 3: Equivalent exponential situations

A bacteria gets *4 every half-hour hours bacteria

0 10

.5

1

1.5

2

2.5

3

Page 4: Equivalent exponential situations

A bacteria gets *4 every half-hour hours bacteria

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

Page 5: Equivalent exponential situations

Coincidence? hours bacteria

0 10

1 160

2 2560

3 40960

hours bacteria

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

Page 6: Equivalent exponential situations

A bacteria gets doubled every ¼ hour hours bacteria

0 10

.25

.5

.75

1

1.25

1.5

1.75

2

2.25

2.5

2.75

3

Page 7: Equivalent exponential situations

A bacteria gets doubled every ¼ hour hours bacteria

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

Page 8: Equivalent exponential situations

Coincidence? hours bacteria

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

hours bacteria

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

Page 9: Equivalent exponential situations

2 coincidences?!?!? hours bacteria

0 10

1 160

2 2560

3 40960

hours bacteria

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

hours bacteria

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

Page 10: Equivalent exponential situations

Are these 3 situations identical? hours bacteria

0 10

1 160

2 2560

3 40960

hours bacteria

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

hours bacteria

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

Page 11: Equivalent exponential situations

Are these 3 situations identical? hours bacteria

0 10

1 160

2 2560

3 40960

hours bacteria

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

hours bacteria

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

According to these tables, yes they are!

Page 12: Equivalent exponential situations

Let’s see what the algebra has to say: x

0 10

1 160

2 2560

3 40960

Page 13: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 160

2 2560

3 40960

*16 every hour

Page 14: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 160

2 2560

3 40960

*16 every hour

Page 15: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 160

2 2560

3 40960

x

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

= 10(4)1

= 10(4)2

= 10(4)3

= 10(4)4

= 10(4)5

= 10(4)6

Page 16: Equivalent exponential situations

= 10(4)1

= 10(4)2

= 10(4)3

= 10(4)4

= 10(4)5

= 10(4)6

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 160

2 2560

3 40960

x y = 10(1.41)2x

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

quadrupled every half hour

After each hour, it’s happened twice

Page 17: Equivalent exponential situations

= 10(4)1

= 10(4)2

= 10(4)3

= 10(4)4

= 10(4)5

= 10(4)6

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 160

2 2560

3 40960

x y = 10(4)2x

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

quadrupled every half hour

After each hour, it’s happened twice

Page 18: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 160

2 2560

3 40960

x y = 10(4)2x

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

x

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

Page 19: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 160

2 2560

3 40960

x y = 10(4)2x

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

x y = 10(1.189)4x

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

doubled every quarter hour After each hour, it’s happened 4

times

Page 20: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(16)x

0 10

1 20

2 40

3 80

x y = 10(4)2x

0 10

.5 40

1 160

1.5 640

2 2560

2.5 10240

3 40960

x y = 10(2)4x

0 10

.25 20

.5 40

.75 80

1 160

1.25 320

1.5 640

1.75 1280

2 2560

2.25 5120

2.5 10240

2.75 20480

3 40960

doubled every quarter hour After each hour, it’s happened 4

times

Page 21: Equivalent exponential situations

A bacteria gets doubled every hour hours bacteria

0 10

1

2

3

Page 22: Equivalent exponential situations

A bacteria gets doubled every hour hours bacteria

0 10

1 20

2 40

3 80

Page 23: Equivalent exponential situations

A bacteria gets *1.4142135’d every half-hour hours bacteria

0 10

.5

1

1.5

2

2.5

3

Page 24: Equivalent exponential situations

A bacteria gets *1.4142135’d every half-hour hours bacteria

0 10

.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

Page 25: Equivalent exponential situations

A bacteria gets *1.4142135’d every half-hour hours bacteria

0 10

1 20

2 40

3 80

hours bacteria

0 10

.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

Page 26: Equivalent exponential situations

A bacteria gets *1.18920711’d every ¼ hour hours bacteria

0 10

.25

.5

.75

1

1.25

1.5

1.75

2

2.25

2.5

2.75

3

Page 27: Equivalent exponential situations

A bacteria gets *1.18920711’d every ¼ hour hours bacteria

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

Page 28: Equivalent exponential situations

A bacteria gets *1.18920711’d every ¼ hour hours bacteria

0 10

.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

hours bacteria

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

Page 29: Equivalent exponential situations

A bacteria gets *1.18920711’d every ¼ hour hours bacteria

0 10

1 20

2 40

3 80

hours bacteria

0 10

.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

hours bacteria

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

Page 30: Equivalent exponential situations

Are these 3 situations identical? hours bacteria

0 10

1 20

2 40

3 80

hours bacteria

0 10

.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

hours bacteria

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

Page 31: Equivalent exponential situations

Are these 3 situations identical? hours bacteria

0 10

1 20

2 40

3 80

hours bacteria

0 10

.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

hours bacteria

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

According to these tables, yes they are!

Page 32: Equivalent exponential situations

Let’s see what the algebra has to say: x

0 10

1 20

2 40

3 80

Page 33: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

Doubled every hour

Page 34: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

Doubled every hour

Page 35: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

= 10(1.4142135)1

= 10(1.4142135)2

= 10(1.4142135)3

= 10(1.4142135)4

= 10(1.4142135)5

= 10(1.4142135)6

Page 36: Equivalent exponential situations

= 10(1.4142135)1

= 10(1.4142135)2

= 10(1.4142135)3

= 10(1.4142135)4

= 10(1.4142135)5

= 10(1.4142135)6

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(1.41)2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

1.4142135’d every half hour

After each hour, it’s happened twice

Page 37: Equivalent exponential situations

= 10(1.4142135)1

= 10(1.4142135)2

= 10(1.4142135)3

= 10(1.4142135)4

= 10(1.4142135)5

= 10(1.4142135)6

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(1.41)2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

1.4142135’d every half hour

After each hour, it’s happened twice

Page 38: Equivalent exponential situations

= 10(1.4142135)1

= 10(1.4142135)2

= 10(1.4142135)3

= 10(1.4142135)4

= 10(1.4142135)5

= 10(1.4142135)6

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(2½ )2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

(2½ )’d every half hour

After each hour, it’s happened twice

Page 39: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(2½ )2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

x

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

Page 40: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

= 10(1.189207115) 1ji

= 10(1.189207115) 2ji

= 10(1.189207115) 3ji

=10 (1.189207115) 4ji

=10 (1.189207115) 12ji

Page 41: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(2½ )2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

x y = 10(1.189)4x

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

1.18920711’d every quarter hour After each hour, it’s happened 4

times = 10(1.189207115) 1ji

= 10(1.189207115) 2ji

= 10(1.189207115) 3ji

=10 (1.189207115) 4ji

=10 (1.189207115) 12ji

Page 42: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(2½ )2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

x y = 10(1.189)4x

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

1.18920711’d every quarter hour After each hour, it’s happened 4

times = 10(1.189207115) 1ji

= 10(1.189207115) 2ji

= 10(1.189207115) 3ji

=10 (1.189207115) 4ji

=10 (1.189207115) 12ji

Page 43: Equivalent exponential situations

Rule using x = #hrs, y = #bacteria x y = 10(2)x

0 10

1 20

2 40

3 80

x y = 10(2½ )2x

0 10

0.5 14.14

1 20

1.5 28.28

2 40

2.5 56.56

3 80

x y = 10(21/4)4x

0 10

.25 11.89

.5 14.14

.75 16.82

1 20

1.25 23.78

1.5 28.28

1.75 33.63

2 40

2.25 47.56

2.5 56.56

2.75 67.26

3 80

(21/4)’d every quarter hour After each hour, it’s happened 4

times