FINDING THE RESULTANT AMPLITUDE FROM INTERFERENCE OF WAVES TRAVELLING IN THE SAME DIRECTION

by Mine Sher

SUMMARY

When two waves that have the same wavelength, frequency, amplitude and direction are superimposed, finding the resulting amplitude is fairy simple.

All we need to do is find how many radians out of phase the two component waves are, and then use the equation, resulting A = 2Acos(phase/2)

PROBLEM

A wave is described in the graph below (wave-a). A second wave (wave-b) is superimposed on wave-a. Wave-b is described by the equation: x(1)= 3cos(pi/4). What is the amplitude of the resulting wave?

INFO

From the graph, we can find out what the period of the two component waves are.

We know the phase of wave-b, but not the phase of wave-a.

We can find the phase of wave-a by finding the phase constant for wave-a.

Note: for the general equation x(t) = Acos(wt+phi) x(t) = Acos(wt+phase constant) and x(t) = Acos(phase)

The equation described in slide two can be used to find amplitude once the difference in phase is calculated.

SOLVE

First, we see the period to be 12 seconds.

We can use 2pi/T to find w=pi/6

We can make an incomplete equation with the information so far.

x(t)=3cos((pi/6)+phase constant)

We can plug in a known point on the graph to calculate the phase constant, like the point (1,0)

x(1)=3cos((pi/6)(1)+phase constant)=0x(1)=cos((pi/6)+phase constant=0

pi/6+phase constant = +/- pi/2

when we solve for the phase constant we get two answers. Either pi/3 or -2pi/3

To check which of the answers apply to our graph, we can test wether the answer gives us a correct point on our graph.

Check pi/3 by using the coordinates (4,-3).x(4)=3cos((pi/6)(4)+pi/3)=-3yes, it works!

Using -2pi/3 in the equation would give the amplitude at that time to be 3, not what is on the graph.

Now we know the phase of wave-a at x(1) is(pi/6+pi/3), or (pi/2).

Compared to wave-b’s phase (pi/4), the phases are (pi/4) out of phase. (phase of wave-a minus phase of wave-b)

Using the equation for finding amplitude of resulting waves, we find A = A of component waves x 1.848.In other words, 5.543m.