1. Simplest Formula
Prepared by: Stephen Boylan
October 20, 2009
2. Simplest Formula.
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3. Simplest Formula -Simple001
A. Combustion in Excess oxygen
12.795 g. HC ----> 32.689 g. CO2+13.377 g. H2O
B. 5 Step Calculation
C. The Simplest Formula
.CxHy Oz
4. Molar Mass CO2
Element Number Atomic MassFormula
n Units, amuMass,
C 1 12.01 12.01
O 2 16.00 32.00
44.01grams per mole CO2
5. Molar Mass H2O
Element Number Atomic MassFormula
n Units, amuMass, n(amu)
H 2 1.008 2.016
O 1 16.00 16.00
18.02 grams per
mole H2O
6.
2.0 Calculate the grams of carbon, hydrogen and oxygen.
12.795g. HC --> 32.689 g CO2+13.377 g. H2O
C:
32.689 grams CO2 12.01 grams C =8.921 g. C
44.01 grams CO2
H:
13.377 grams H2O 2x1.008 grams H = 1.497 g H
18.02 grams H2O
O:
12.795 g HC - 8.921g C - 1.497 g H= 2.377 g O
7. Moles of carbon, hydrogen and oxygen.
C:8.921 g. C1 mole C =0.7429 moles C
12.01 grams C
H:1.497 g. H 1 mole H = 1.485 mole H
1.008 grams H
O:2.377 g. O 1 mole O=0.1485 mole O
16.00 grams O
8.RatiosDivide by smallest
C:0.7429 moles C1= 5.003~ 5 moles C
0.1485
H:1.485 mole H 1= 10 moles H
0.1485
O:0.1485 mole O1= 1 moles O
0.1485
