103
Fluid Mechanics and Thermodynamics Weekly Assessed Tutorial Sheets, Student Sheets Student Sheets: WATS 2. The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information. The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution. FURTHER INFORMATION Please see http://tinyurl.com/2wf2lfh to access the WATS Random Factor Generating Wizard. © University of Hertfordshire 2009 This work is licensed under a Creative Commons Attribution 2.0 License .

WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Embed Size (px)

DESCRIPTION

The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information. The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution. What follows is a set of STUDENT UNIQUE SHEETS for WATS 2.

Citation preview

Page 1: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and ThermodynamicsWeekly Assessed Tutorial Sheets,Student Sheets

Student Sheets: WATS 2.

The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information.

The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution.

FURTHER INFORMATION

Please see http://tinyurl.com/2wf2lfh to access the WATS Random Factor Generating Wizard.

There are also explanatory videos on how to use the Wizard and how to implement WATS available at http://www.youtube.com/user/MBRBLU#p/u/7/0wgC4wy1cV0 and http://www.youtube.com/user/MBRBLU#p/u/6/MGpueiPHpqk.

For more information on WATS, its use and impact on students please contact Mark Russell, School of Aerospace, Automotive and Design Engineering at University of Hertfordshire.

© University of Hertfordshire 2009 This work is licensed under a Creative Commons Attribution 2.0 License.

Page 2: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 1

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 4.20 m high. If the top edge of the door is 3.40 m below the fluids free surface and the fluid has a density of 965 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.98 has partially filled the tank so that its free surface is 1.40 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number1

Page 3: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 2

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.70 m wide and 3.90 m high. If the top edge of the door is 2.10 m below the fluids free surface and the fluid has a density of 805 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.99 has partially filled the tank so that its free surface is 0.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number2

Page 4: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 3

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 6.60 m high. If the top edge of the door is 3.30 m below the fluids free surface and the fluid has a density of 990 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.97 has partially filled the tank so that its free surface is 1.30 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number3

Page 5: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 4

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 4.30 m high. If the top edge of the door is 4.70 m below the fluids free surface and the fluid has a density of 875 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.89 has partially filled the tank so that its free surface is 1.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number4

Page 6: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 5

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 5.60 m high. If the top edge of the door is 4.20 m below the fluids free surface and the fluid has a density of 980 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.96 has partially filled the tank so that its free surface is 2.00 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number5

Page 7: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 6

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 5.40 m high. If the top edge of the door is 2.60 m below the fluids free surface and the fluid has a density of 965 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.88 has partially filled the tank so that its free surface is 0.50 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number6

Page 8: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 7

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.10 m wide and 6.90 m high. If the top edge of the door is 3.00 m below the fluids free surface and the fluid has a density of 845 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.93 has partially filled the tank so that its free surface is 1.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number7

Page 9: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 8

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.20 m wide and 7.20 m high. If the top edge of the door is 1.50 m below the fluids free surface and the fluid has a density of 980 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.80 has partially filled the tank so that its free surface is 0.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number8

Page 10: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 9

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.50 m wide and 4.00 m high. If the top edge of the door is 1.70 m below the fluids free surface and the fluid has a density of 935 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.92 has partially filled the tank so that its free surface is 0.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number9

Page 11: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 10

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 4.20 m high. If the top edge of the door is 3.70 m below the fluids free surface and the fluid has a density of 805 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.94 has partially filled the tank so that its free surface is 1.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number10

Page 12: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 11

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 4.30 m high. If the top edge of the door is 3.60 m below the fluids free surface and the fluid has a density of 840 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.86 has partially filled the tank so that its free surface is 1.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number11

Page 13: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 12

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 7.40 m high. If the top edge of the door is 4.10 m below the fluids free surface and the fluid has a density of 890 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.89 has partially filled the tank so that its free surface is 1.20 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number12

Page 14: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 13

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.70 m wide and 6.80 m high. If the top edge of the door is 1.30 m below the fluids free surface and the fluid has a density of 860 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.87 has partially filled the tank so that its free surface is 1.50 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number13

Page 15: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 14

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 4.70 m high. If the top edge of the door is 3.30 m below the fluids free surface and the fluid has a density of 970 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.87 has partially filled the tank so that its free surface is 0.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number14

Page 16: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 15

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.70 m wide and 7.20 m high. If the top edge of the door is 2.60 m below the fluids free surface and the fluid has a density of 870 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.99 has partially filled the tank so that its free surface is 1.40 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number15

Page 17: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 16

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.10 m wide and 7.10 m high. If the top edge of the door is 1.60 m below the fluids free surface and the fluid has a density of 970 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.85 has partially filled the tank so that its free surface is 1.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number16

Page 18: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 17

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.20 m wide and 5.50 m high. If the top edge of the door is 5.00 m below the fluids free surface and the fluid has a density of 920 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.93 has partially filled the tank so that its free surface is 1.00 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number17

Page 19: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 18

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.70 m wide and 7.10 m high. If the top edge of the door is 2.10 m below the fluids free surface and the fluid has a density of 990 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.99 has partially filled the tank so that its free surface is 1.00 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number18

Page 20: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 19

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.20 m wide and 4.40 m high. If the top edge of the door is 2.90 m below the fluids free surface and the fluid has a density of 805 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.92 has partially filled the tank so that its free surface is 1.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number19

Page 21: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 20

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 5.10 m high. If the top edge of the door is 2.80 m below the fluids free surface and the fluid has a density of 920 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.84 has partially filled the tank so that its free surface is 1.10 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number20

Page 22: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 21

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.20 m wide and 5.00 m high. If the top edge of the door is 4.80 m below the fluids free surface and the fluid has a density of 930 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.96 has partially filled the tank so that its free surface is 1.00 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number21

Page 23: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 22

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.50 m wide and 5.40 m high. If the top edge of the door is 1.70 m below the fluids free surface and the fluid has a density of 940 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.89 has partially filled the tank so that its free surface is 1.50 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number22

Page 24: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 23

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.60 m wide and 3.70 m high. If the top edge of the door is 2.40 m below the fluids free surface and the fluid has a density of 810 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.81 has partially filled the tank so that its free surface is 0.80 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number23

Page 25: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 24

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.10 m wide and 4.40 m high. If the top edge of the door is 2.60 m below the fluids free surface and the fluid has a density of 840 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.92 has partially filled the tank so that its free surface is 1.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number24

Page 26: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 25

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.50 m wide and 7.70 m high. If the top edge of the door is 1.30 m below the fluids free surface and the fluid has a density of 835 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.89 has partially filled the tank so that its free surface is 1.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number25

Page 27: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 26

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 7.30 m high. If the top edge of the door is 2.50 m below the fluids free surface and the fluid has a density of 980 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.97 has partially filled the tank so that its free surface is 0.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number26

Page 28: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 27

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.20 m wide and 7.10 m high. If the top edge of the door is 4.50 m below the fluids free surface and the fluid has a density of 850 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.98 has partially filled the tank so that its free surface is 0.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number27

Page 29: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 28

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 4.70 m high. If the top edge of the door is 3.40 m below the fluids free surface and the fluid has a density of 950 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.82 has partially filled the tank so that its free surface is 1.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number28

Page 30: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 29

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.60 m wide and 6.60 m high. If the top edge of the door is 1.20 m below the fluids free surface and the fluid has a density of 830 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.82 has partially filled the tank so that its free surface is 0.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number29

Page 31: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 30

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 5.00 m high. If the top edge of the door is 1.60 m below the fluids free surface and the fluid has a density of 825 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.90 has partially filled the tank so that its free surface is 1.50 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number30

Page 32: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 31

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 4.00 m high. If the top edge of the door is 4.00 m below the fluids free surface and the fluid has a density of 970 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.94 has partially filled the tank so that its free surface is 1.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number31

Page 33: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 32

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.70 m wide and 4.80 m high. If the top edge of the door is 1.60 m below the fluids free surface and the fluid has a density of 895 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.81 has partially filled the tank so that its free surface is 1.40 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number32

Page 34: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 33

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.60 m wide and 6.00 m high. If the top edge of the door is 3.80 m below the fluids free surface and the fluid has a density of 845 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.92 has partially filled the tank so that its free surface is 1.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number33

Page 35: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 34

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 4.80 m high. If the top edge of the door is 3.10 m below the fluids free surface and the fluid has a density of 850 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.96 has partially filled the tank so that its free surface is 1.80 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number34

Page 36: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 35

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 4.90 m high. If the top edge of the door is 4.90 m below the fluids free surface and the fluid has a density of 810 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.92 has partially filled the tank so that its free surface is 0.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number35

Page 37: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 36

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.70 m wide and 5.30 m high. If the top edge of the door is 1.30 m below the fluids free surface and the fluid has a density of 815 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.99 has partially filled the tank so that its free surface is 0.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number36

Page 38: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 37

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 5.30 m high. If the top edge of the door is 2.30 m below the fluids free surface and the fluid has a density of 855 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.91 has partially filled the tank so that its free surface is 0.70 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number37

Page 39: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 38

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.10 m wide and 6.50 m high. If the top edge of the door is 3.70 m below the fluids free surface and the fluid has a density of 810 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.90 has partially filled the tank so that its free surface is 1.00 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number38

Page 40: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 39

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 7.80 m high. If the top edge of the door is 2.50 m below the fluids free surface and the fluid has a density of 900 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.98 has partially filled the tank so that its free surface is 0.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number39

Page 41: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 40

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.60 m wide and 5.80 m high. If the top edge of the door is 4.50 m below the fluids free surface and the fluid has a density of 890 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.99 has partially filled the tank so that its free surface is 1.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number40

Page 42: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 41

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.00 m wide and 6.10 m high. If the top edge of the door is 2.60 m below the fluids free surface and the fluid has a density of 965 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.98 has partially filled the tank so that its free surface is 1.50 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number41

Page 43: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 42

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.10 m wide and 5.60 m high. If the top edge of the door is 3.20 m below the fluids free surface and the fluid has a density of 915 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.88 has partially filled the tank so that its free surface is 1.10 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number42

Page 44: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 43

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 4.80 m high. If the top edge of the door is 1.50 m below the fluids free surface and the fluid has a density of 960 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.88 has partially filled the tank so that its free surface is 1.50 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number43

Page 45: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 44

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 7.50 m high. If the top edge of the door is 1.00 m below the fluids free surface and the fluid has a density of 995 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.91 has partially filled the tank so that its free surface is 2.00 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number44

Page 46: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 45

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.90 m wide and 5.20 m high. If the top edge of the door is 4.70 m below the fluids free surface and the fluid has a density of 935 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.90 has partially filled the tank so that its free surface is 1.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number45

Page 47: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 46

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 4.80 m high. If the top edge of the door is 1.90 m below the fluids free surface and the fluid has a density of 945 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.93 has partially filled the tank so that its free surface is 0.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number46

Page 48: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 47

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 6.90 m high. If the top edge of the door is 1.80 m below the fluids free surface and the fluid has a density of 1000 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.80 has partially filled the tank so that its free surface is 1.60 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number47

Page 49: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 48

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.50 m wide and 6.20 m high. If the top edge of the door is 2.50 m below the fluids free surface and the fluid has a density of 835 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.98 has partially filled the tank so that its free surface is 0.80 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number48

Page 50: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 49

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 1.20 m wide and 5.80 m high. If the top edge of the door is 4.90 m below the fluids free surface and the fluid has a density of 855 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.89 has partially filled the tank so that its free surface is 0.80 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number49

Page 51: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

Fluid Mechanics and Thermodynamics.Weekly Assessed Tutorial Sheet 2.

Student Number 50

Name

Hand out date Hand in date

Q1. i) A rectangular door in the side of a fluid filled tank is 0.80 m wide and 7.40 m high. If the top edge of the door is 3.10 m below the fluids free surface and the fluid has a density of 945 kg/m3 calculate

i) the total force on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

Q2. Assuming now that the tank has been drained of the original fluid and that another fluid of relative density 0.90 has partially filled the tank so that its free surface is 1.90 m below the top of the door. Calculate

i) the total force now acting on the door (kN) (1 mark)ii) the position of the line of action (below the free surface) (m). (1 mark)

iii) If the door is now turned through 90° (i.e. it is still in the side of the tank but its width and height have now been transposed) at what depth would the top edge of the door have to be for the resulting force to be the same as that calculated for Q2 i)? (m)

(1 mark)

iv) Assuming now that the door has been moved so that it is located in the horizontal floor of the tank. Calculate the required depth of fluid in the tank if the door is only to be exposed to the same force as calculated in Q2 i) (m). (2 marks)

Q3. Please provide one hint or tip that would be useful to help future students tackle successfully the problems on this sheet. You will be awarded 3 bonus marks for providing a sensible hint or tip.

WATS 2. Student number50

Page 52: WATS 2 (1-50) Fluid Mechanics and Thermodynamics

CreditsThis resource was created by the University of Hertfordshire and released as an open educational resource through the Open Engineering Resources project of the HE Academy Engineering Subject Centre. The Open Engineering Resources project was funded by HEFCE and part of the JISC/HE Academy UKOER programme.

© University of Hertfordshire 2009

This work is licensed under a Creative Commons Attribution 2.0 License.

The name of the University of Hertfordshire, UH and the UH logo are the name and registered marks of the University of Hertfordshire. To the fullest extent permitted by law the University of Hertfordshire reserves all its rights in its name and marks which may not be used except with its written permission.

The JISC logo is licensed under the terms of the Creative Commons Attribution-Non-Commercial-No Derivative Works 2.0 UK: England & Wales Licence.  All reproductions must comply with the terms of that licence.

The HEA logo is owned by the Higher Education Academy Limited may be freely distributed and copied for educational purposes only, provided that appropriate acknowledgement is given to the Higher Education Academy as the copyright holder and original publisher.