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Vector AdditionVector Addition
Concurrent and Equilibrant Concurrent and Equilibrant ForcesForces
DefinitionsDefinitions
Concurrent ForcesConcurrent Forces – Acting at the same – Acting at the same time and same placetime and same place
ResultantResultant – Sum of 2 or more vectors – Sum of 2 or more vectors Equilibrant ForceEquilibrant Force – –
A single, additional force that is exerted on an A single, additional force that is exerted on an objectobject
Same magnitude, but opposite direction of the Same magnitude, but opposite direction of the ResultantResultant
When combined with the Resultant, it When combined with the Resultant, it produces equilibriumproduces equilibrium
Net force = 0Net force = 0
Example ProblemExample Problem
Question: Find the Equilibrant force of Question: Find the Equilibrant force of these Concurrent forces these Concurrent forces analyticallyanalytically 12 N south, 31 N west, 29 N north, 56 N 12 N south, 31 N west, 29 N north, 56 N
westwest 2 ways to determine resultant2 ways to determine resultant
Simplify to 2 vectors (use Parallelogram Simplify to 2 vectors (use Parallelogram method to find resultant) method to find resultant) OROR
Draw all 4 Head-to-Tail (to find resultant – Draw all 4 Head-to-Tail (to find resultant – Start at the beginning and end at the end)Start at the beginning and end at the end)
Example ProblemExample Problem
12 N south, 31 N west, 29 N north, 12 N south, 31 N west, 29 N north, 56 N west56 N west
Simplify to 2 vectors (use Simplify to 2 vectors (use Parallelogram method to find Parallelogram method to find resultant)resultant) 12 N south + 29 N north = ?12 N south + 29 N north = ? (-12 N north) + 29 N north = 17 N (-12 N north) + 29 N north = 17 N
northnorth
31 N west + 56 N west = 87 N west31 N west + 56 N west = 87 N west
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
12 N south, 31 N west, 29 N north, 12 N south, 31 N west, 29 N north, 56 N west56 N west
Simplify to 17 N north and 87 N Simplify to 17 N north and 87 N westwest
Use Parallelogram method to find Use Parallelogram method to find resultantresultant
17 N
87 N
FR
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
17 N north and 87 N west17 N north and 87 N west Solve for FSolve for FRR using Pythagorean using Pythagorean
TheoremTheorem aa22 + b + b22 = c = c22
(17(1722) + (87) + (8722) =) = FFRR22
√√((7858) = 89 N7858) = 89 N17 N
87 N
FR = 89 N
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
Magnitude of FMagnitude of FRR = 89 N = 89 N To find direction (To find direction (ΘΘ)) we will use the we will use the
Tangent functionTangent function TOA: TOA: TTangent angent ΘΘ = = OOpposite/pposite/AAdjacentdjacent tan tan ΘΘ = (17 N) / (87 N) = (17 N) / (87 N) ΘΘ = tan = tan-1-1 (0.2) (0.2) ΘΘ = 11° = 11°
17 N
87 N (Adjacent)
FR = 89 N
ΘΘ = 11 = 11°°17 N
(Opposite)
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
Magnitude of FMagnitude of FRR = 89 N = 89 N Direction = ?Direction = ? 180° - 11° = 169°180° - 11° = 169°
Therefore FTherefore FRR = 89 N @ 169° = 89 N @ 169°
ΘΘ = 11 = 11°°0°180°
169°
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
FFRR = 89 N @ 169° = 89 N @ 169° Original Question - Original Question - Find the Find the
Equilibrant force of these Equilibrant force of these concurrent forces analyticallyconcurrent forces analytically
Equilibrant is same magnitude, Equilibrant is same magnitude, opposite direction of Resultantopposite direction of Resultant
0°180°
169°F
R
FE
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
FFRR = 89 N @ 169° = 89 N @ 169° FFEE = 89 N @ ?? = 89 N @ ?? Because we know that it is the exact Because we know that it is the exact
opposite direction – we can add 180opposite direction – we can add 180° ° to the direction of Fto the direction of FRR
169169°° + 180 + 180°° = 349 = 349°°
0°180°
169°F
R
FE
180°°
349°°
Example Problem – Example Problem – Not Drawn to ScaleNot Drawn to Scale
FFRR = 89 N @ 169° = 89 N @ 169° FFEE = 89 N @ = 89 N @ 349349°°
0°180°
169°F
R
FE
180°°
349°°
Solve Analytically – Using Solve Analytically – Using equationsequations
1.1. 30 N @ 030 N @ 0°° ; 40 N @ 90 ; 40 N @ 90°°
2.2. 20 N @ 18020 N @ 180°° ; 15 N @ 270 ; 15 N @ 270°°
3.3. 18 N @ 36018 N @ 360°° ; 22 N @ 270 ; 22 N @ 270°°
4.4. 44 N @ 27044 N @ 270°° ; 12 N @ 360 ; 12 N @ 360°°
5.5. 10 N @ 010 N @ 0°° ; 20 N @ 180 ; 20 N @ 180°° ; 14 N @ 90 ; 14 N @ 90°° ; 20 N @ ; 20 N @ 270270°°