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r
f
n+ 1 f
f
n+ 1 f
n+ 1 f
r
n+ 1 f
r
n+ 1 f
-
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d¸ 0
d¸ 0
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d¸ 0
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r
d¸ 0
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n
r
r
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r
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r
f
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- (m+ 1)(n+1)¡1
- (m+1)(n¡d )
rm
f
- (m+ 1)(n+1)¡1
- (m+1)(n¡d )
- m = 1, 2
rm
f
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f
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f
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f
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d = 2
d = 2
d = 1
d = 1
d = 4
d = 4
rm
m > 2
rm
m > 2
rm
m > 2
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