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! SHREE !
JAIN INTERNATIONAL SCHOOL
“SCIENCE “ Project
“ACID” “BASES”
&“SALT”
Acids & BasesAcids:
acids are sour tastingArrhenius acid: Any substance that, when dissolved
in water, increases the concentration of hydronium ion (H3O+)
Bronsted-Lowry acid: A proton donorLewis acid: An electron acceptor
Bases:bases are bitter tasting and slipperyArrhenius base: Any substance that, when dissolved
in water, increases the concentration of hydroxide ion (OH-)
Bronsted-Lowery base: A proton acceptorLewis acid: An electron donor
Lone Hydrogen ions do not exist by themselves in solution. H+ is always bound to a water molecule to form a hydronium ion
Brønsted-Lowry Theory of Acids & BasesConjugate Acid-Base Pairs
General Equation
Brønsted-Lowry Theory of Acids & Bases
Brønsted-Lowry Theory of Acids & Bases
Brønsted-Lowry Theory of Acids & Bases
Reversible reaction
Notice that water in both an Acid & a base = Amphoteric
ELECTROLYTESElectrolytes are species which conducts electricity when
dissolved in water. Acids, Bases, and Salts are all electrolytes.
Salts and strong Acids or Bases form Strong Electrolytes. Salt and strong acids (and bases) are fully dissociated therefore all of the ions present are available to conduct electricity.
HCl(s) + H2O H3O+ + Cl-
Weak Acids and Weak Bases for Weak Electrolytes. Weaks electrolytes are partially dissociated therefore not all species in solution are ions, some of the molecular form is present. Weak electrolytes have less ions avalible to conduct electricity.
NH3 + H2O NH4+ + OH-
Acids & Bases STRONG vs WEAK_ completely ionized _ partially ionized
_ strong electrolyte _ weak electrolyte
_ ionic/very polar bonds _ some covalent bonds
Strong Acids: Strong Bases:
HClO4 LiOH
H2SO4 NaOH
HI KOH
HBr Ca(OH)2
HCl Sr(OH)2
HNO3 Ba(OH)2
Acids & BasesOne ionizable proton:
HCl → H+ + Cl-Two ionizable protons:
H2SO4 → H+ + HSO4-
HSO4- → H+ + SO4
2-
Three ionizable protons:
H3PO4 → H+ + H2PO4–
H2PO4- → H+ + HPO4
2-
HPO42- → H+ + PO4
-3
Combined:H2SO4 → 2H+ + SO4
2-
Combined: H3PO4 → 3H+ + PO4
3-
Acids & BasesFor the following identify the acid and the base as strong or
weak .
a. Al(OH)3 + HCl
b. Ba(OH)2 + HC2H3O2
c. KOH + H2SO4
d. NH3 + H2O
Weak base Strong acid
Weak acid
Strong acid
Strong base
Strong base
Weak base Weak acid
Acids & BasesFor the following predict the product. To check your answer left click
on the mouse. Draw a mechanism detailing the proton movement.
a. Al(OH)3 + HCl
b. Ba(OH)2 + HC2H3O2
c. KOH + H2SO4
d. NH3 + H2O
3AlCl3 + 3 H2O
2Ba(C2 H3O2)2 + 2 H2O
2K2SO4 2 H2O
NH4+ + O H-
Acids & BasesFor the following Identify the conjugate acid and the conjugate base. The
conjugate refers to the acid or base produced in an acid/base reaction. The acid reactant produces its conjugate base (CB).
a. Al(OH)3 + 3 HCl AlCl3 + 3 H2O
b. Ba(OH)2 + 2 HC2H3O2 Ba(C2H3O2)2 + 2 H2O
c. 2 KOH + H2SO4 K2SO4 + 2 H2O
d. NH3 + H2O NH4+ + OH-
CB CA
CB CA
CB CA
CA CB
Conjugate Acid-Base Pairs
Conjugate Acid-Base Pairs
TITRATIONTitration of a strong acid with a strong base
ENDPOINT = POINT OF NEUTRALIZATION = EQUIVALENCE POINT
At the end point for the titration of a strong acid with a strong base, the moles of acid (H+) equals the moles of base (OH-) to produce the neutral species water (H2O). If the mole ratio in the balanced chemical equation is 1:1 then the following equation can be used.
MOLES OF ACID = MOLES OF BASE
nacid = nbase
Since M=n/V
MAVA = MBVB
TITRATIONMAVA = MBVB
1. Suppose 75.00 mL of hydrochloric acid was required to neutralize 22.50 mLof 0.52 M NaOH. What is the molarity of the acid?
HCl + NaOH H2O + NaCl
Ma Va = Mb Vb rearranges to Ma = Mb Vb / Va
so Ma = (0.52 M) (22.50 mL) / (75.00 mL)
= 0.16 M
Now you try:2. If 37.12 mL of 0.843 M HNO3 neutralized 40.50
mL of KOH, what is the molarity of the base?Mb = 0.773 mol/L
TITRATIONTitration of a strong acid with a strong base
ENDPOINT = POINT OF NEUTRALIZATION = EQUIVALENCE POINT
At the end point for the titration of a strong acid with a strong base, the moles of acid (H+) equals the moles of base (OH-) to produce the neutral species water (H2O). If the mole ratio in the balanced chemical equation is NOT 1:1 then you must rely on the mole relationship and handle the problem like any other stoichiometry problem.
MOLES OF ACID = MOLES OF BASE
nacid = nbase
TITRATION1. If 37.12 mL of 0.543 M LiOH neutralized
40.50 mL of H2SO4, what is the molarity of the acid?
2 LiOH + H2SO4 Li2SO4 + 2 H2O
First calculate the moles of base:0.03712 L LiOH (0.543 mol/1 L) = 0.0202 mol LiOHNext calculate the moles of acid:0.0202 mol LiOH (1 mol H2SO4 / 2 mol LiOH)=
0.0101 mol H2SO4
Last calculate the Molarity: Ma = n/V = 0.010 mol H2SO4 / 0.4050 L = 0.248
M
2. If 20.42 mL of Ba(OH)2 solution was used to titrate29.26 mL of 0.430 M HCl, what is the molarity of the barium hydroxide solution?
Mb = 0.308 mol/L
Molarity and Titration
Molarity and TitrationA student finds that 23.54 mL of a 0.122 M
NaOH solution is required to titrate a 30.00-mL sample of hydr acid solution. What is the molarity of the acid?
A student finds that 37.80 mL of a 0.4052 M NaHCO3 solution is required to titrate a 20.00-mL sample of sulfuric acid solution. What is the molarity of the acid?
The reaction equation is:H2SO4 + 2 NaHCO3 → Na2SO4 + 2 H2O + 2 CO2
WATER EQUILIBRIUM
WATER EQUILIBRIUMKw = [H+] [OH-] = 1.0 x 10-14
Equilibrium constant for water
Water or water solutions in which [H+] = [OH-] = 10-7 M are neutral solutions.
A solution in which [H+] > [OH-] is acidic
A solution in which [H+] < [OH-] is basic
A measure of the hydronium ion (PH)The scale for measuring the hydronium ion
concentration [H3O+] in any solution must be able to cover a large range. A logarithmic scale covers factors of 10. The “p” in pH stands for log.
A solution with a pH of 1 has [H3O+] of 0.1 mol/L or 10-1
A solution with a pH of 3 has [H3O+] of 0.001 mol/L or 10-3
A solution with a pH of 7 has [H3O+] of 0.0000001 mol/L or 10-7
pH = - log [H3O+]
The pH scaleThe pH scale ranges from 1 to 10-14
mol/L or from 1 to 14. pH = - log [H3O+]
1 2 3 4 5 6 7 8 9 10 11 12 13 14
acid neutral base
Manipulating pHAlgebraic manipulation of:
pH = - log [H3O+]
allows for:[H3O+] = 10-pH
If pH is a measure of the hydronium ion concentration then the same equations could be used to describe the hydroxide (base) concentration.
[OH-] = 10-pOH pOH = - log [OH-]
thus:pH + pOH = 14 ; the entire pH range!
Ankush KhatriSuyash Chopda
GauravNanwani
Ashish Agrawal
PRESEMTED BY
Kindness is a language which
the deaf can hear and the blind can
seeThank You